I dropped the ball from the roof of a building the speed when I hit the ground is 52 m/s how tall is the building

Answers

Answer 1

Answer:

Height of building = 135.2 m

I Dropped The Ball From The Roof Of A Building The Speed When I Hit The Ground Is 52 M/s How Tall Is

Related Questions

An object at rest has no net force acting on it.
True or False​

Answers

That’s True bc an unbalanced force would need to keep and object in motion at a constant velocity.

Answer:

True

Explanation:

The object is at rest, which means it's not moving, so there is no net force on it, according to Newton's First Law.

Which of the following is a unit of acceleration?

Answers

[tex]{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}[/tex]

[tex]\longrightarrow[/tex] The rate of change of velocity per unit time is called acceleration.

[tex]\longrightarrow[/tex] Its SI unit is m/s².

[tex]\huge\boxed{\fcolorbox{blue}{red}{Thank you}} [/tex]

g. Write the merits and demerits of ultraviolet rays.

Answers

Answer:

UV rays aid in the production of Vitamin D. But it can also give you cancer.

Explanation:

i am a scientist

(HELP PLEASE)What are some reasons people produce synthetic materials?

Answers

Answer:

Explanation:

Synthetic fabrics, such as nylon and polyester, are produced entirely from chemicals. Natural fabrics, such as cotton, silk, and wool are made of fibres from plants and animals. Synthetic fabrics are useful because they have very different or enhanced (improved) properties in comparison to natural materials.

A racecar is driving around a circular track. The car is moving with a speed of 49.7 m/s, and the track has a radius of 114 m. What is the magnitude of the centripetal acceleration of the car?

Answers

Answer:

21.67 m/s²

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 49.7 m/s

Radius (r) = 114 m

Centripetal acceleration (a) =?

The centripetal acceleration can be obtained by using the following formula:

a = v²/r

a = 49.7² / 114

a = 2470.09 / 114

a = 21.67 m/s²

Therefore, the centripetal acceleration of the car is 21.67 m/s²

Which of the following best describes the difference between type a and type b

Answers

Is there supposed to be a picture? Next time try putting a picture

in addition to genetics, and blank and blank may also cause premature gray hair?

Answers

Answer: heretidey and stress

Explanation:

Which best represents the appearance of the moon on July 25, 2011

Answers

Answer:

Its the third quarter or waning quarter

  Hope this helps :3

a squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy

What is the squirrels mass

Answers

Answer:

yeet yeet yeet yeet

Explanation:

Kinetic energy (K.E):-

So, the Mass of the Squirrel is 0.51 Kg (or) 510 grams.

A squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy.

What is the squirrel’s mass?

Answer: 0.51 kg

what is the correct answer?

Answers

Answer:

harder daddy

Explanation:

What is thermodynamics?
a) the way energy changes
b) the classification of energy
c) the movement of energy
d) the movement of heat

Answers

Answer:

I think it is D

Explanation:

Answer:

D :D lol

Explanation:

- During a certain period, the angular position of a rotating object is given by: = − + , where  is in radian and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the rotating object at = Sec.

Answers

The question is not complete. The complete question is :

During a certain period of time, the angular position of a rotating object is given by [tex]$\theta =2t^2 +10t+5$[/tex], where θ is in radians and t is in seconds.  Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.

Solution :

Given :

Displacement or angular position of the object, [tex]$\theta =2t^2 +10t+5$[/tex]

∴ Angular speed is   [tex]$\omega = \frac{d \theta}{dt}$[/tex]

                                 ω = 10 + 4t

And angular acceleration is [tex]$\alpha = \frac{d \omega}{dt}$[/tex]

                                              α = 4

a). At time, t = 0.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(0)^2 +10(0)+5$[/tex]

                                               = 5 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(0)

                                     = 10 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

b). At time, t = 3.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(3)^2 +10(3)+5$[/tex]

                                               = 53 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(3)

                                     = 22 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

                                   

                                           

Feathers and a bowling ball are dropped in a vacuum, airless environment. Which one will hit the ground first?


Feathers

Bowling Ball

They will float

At the same time

Answers

Answer: at the same time

Explanation: in a vacuum, there isnt air, right? so there isnt gravity pushing down on the heavier object, so they will both land at the same time.

good? :)

PLEASE HELP! FOR BRAINLIEST!!!

Answers

Answer:

I think it's C I'm so sorry if I'm wrong.

Explanation:

Answer:

A or Alex > Chai > Jimmy > Sanni

Explanation:

__________________________________________________________

Here's why this is the answer,

__________________________________________________________

Alex's Range = 3.20 - 0.90 = 2.30

Sanni's Range = 1.35 - 1.30 = 0.05

Chai's Range = 2.10 - 1.05 = 1.05

Jimmy's Range = 2.20 - 1.55 = 0.65

__________________________________________________________

Greatest to Least

Alex > Chai > Jimmy > Sanni

Here's why this is correct.

Alex = 2.30

Chai = 1.05

Jimmy = 0.65

Sanni = 0.05

I do not see the answer I have on this question so I think it is A.

__________________________________________________________

Hope this helps! <3

__________________________________________________________

a 10 kilogram steel ball is dropped from the top of a tower 100 meters high the kinetic energy of the ball just before it sttikes the ground is most nearly​

Answers

Explanation:

If we assume negligible air resistance and heat loss, we can assume that all of the Gravitational potential energy of the ball will turn into Kinetic energy as it falls toward the ground.

Therefore our Kinetic energy = mgh = (10kg)(9.81N/kg)(100m) = 9,810J.

What is the height of a shelf that has 15 kg objects with 450 J of gravitational potential energy

Answers

PE=mgh
450J=15kg•9.8m/s2squared
450=147h
—— ——
147 147

h=3.0612m

A car with a mass of 900 kg is traveling at a
speed of 25 m/s. What is the kinetic energy
from the car's motion?

Answers

Explanation:

Kinetic Energy

= 0.5mv²

= 0.5(900kg)(25m/s)²

= 281,250J.

help pls its been a day

Answers

Answer:

161.28m

Explanation:

The resultant is calculated using the formula

R² = dx²+dy²

R = √dx²+dy²

From the diagram. dx = 101cos60°+85

dx = 101(0.5) + 65

dx = 50.5 + 85

dx = 135.5m

For the vertical component dy

dy = dsin theta

dy = 101 sin 60

dy = 101(0.8660)

dy = 87.47

R = √135.5²+87.47²

R = √18,360.25+7,651.0009

R = √26,011.2509

R = 161.28m

Hence the magnitude of the sum of the vectors is 161.28m

Answer:

The sum of the two vectors is 161.278 m.

Explanation:

Given;

vector, B = 101 m inclined at angle 60⁰

vector, A = 85 m inclined at angle 0⁰

Y-component of the vectors;

[tex]R_y = 101(sin \ 60^0) + 85(sin \ 0^0) =87.466 \ m[/tex]

X-component of the vectors;

[tex]R_x = 101(cos \ 60^0) + 85(cos \ 0^0)\\\\R_x = 50.5 + 85 = 135.5 \ m[/tex]

Sum of the two vectors;

[tex]R = A+ B\\\\R = \sqrt{R_y^2 + R_x^2} \\\\R = \sqrt{87.466^2 \ + \ 135.5^2} \\\\R = \sqrt{26010.55} \\\\R = 161.278 \ m[/tex]

Therefore, the sum of the two vectors is 161.278 m.

Calculate the magnitude and direction of the centripetal acceleration of the following objects moving in a circle:

A 2000 kg truck drives along a circular round a bout with a radius of 20 m at a constant speed of 10 m/s.

Answers

Answer:

The magnitude and direction of the centripetal acceleration will be:

[tex]a_c=5[/tex] m/s²   (towards the center of the circle).

Explanation:

Given

v = 10 m/sr = 20 m

Using the formula to determine the centripetal acceleration

[tex]a_c=\frac{v^2}{r}[/tex]

[tex]a_c=\frac{\left(10\right)^2}{20}[/tex]

[tex]\:a_c=\frac{100}{20}[/tex]

[tex]a_c=5[/tex] m/s²

As the truck is moving in a circle, therefore the direction is towards the center of the circle.

Hence, the magnitude and direction of the centripetal acceleration will be:

[tex]a_c=5[/tex] m/s²   (towards the center of the circle).

Which of the following situations is an example of kinetic energy being transformed into potential energy? Throwing a ball high into the air Dropping a ball from a ladder Rolling a ball on the ground Holding a ball in the air without moving it

Answers

Answer: holding the ball in the air without moving it

Explanation:

When the ball goes up it’s potential energy

Throwing a ball high into the air is an example of kinetic energy being transformed into potential energy.

What is kinetic energy ?

"Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy."

What is potential energy ?

"Potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors."

Know more about potential energy here

https://brainly.com/question/24284560

#SPJ2

What equation would you use to solve for voltage?

Answers

Answer:

It depends upon what you have given in the question but according to Ohm's law,

[tex]\boxed{V\:= I × R}[/tex]

where, V = voltage (v)

I = current (amperes)

R = resistance (Ω)

Other formulas are:

V = P/IV = √P × R

Hope it helps!<3

You bought a helium balloon for a friend’s winter birthday. The outside temperature was -34 degrees C. The store was at a comfortable 298K. The volume of the balloon immediately after the store clerk filled it was 6 liters. What was the volume after you brought it outside? Show your work. Make sure to include units.

Answers

Answer:

4.81 L

Explanation:

From the question given above, we obtained the following information:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = – 34 °C

Final Volume (V₂) =?

Next, we shall convert – 34 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = – 34 °C

T(K) = – 34 + 273

T(K) = 239 K

Thus, –34 °C is equivalent to 239 K

Finally, we shall determine the final volume of the balloon as follow:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = 239 K

Final Volume (V₂) =?

V₁ / T₁ = V₂ / T₂

6 / 298 = V₂ / 239

Cross multiply

298 × V₂ = 6 × 239

298 × V₂ = 1434

Divide both side by 298

V₂ = 1434 / 298

V₂ = 4.81 L

Thus, the volume of the balloon when it was brought outside the store was 4.81 L.

mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that planet ?? ​

Answers

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, [tex]v_e[/tex], for the planet is [tex]v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }[/tex]

Where;

[tex]v_e[/tex] = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, [tex]M_E[/tex]

r = The radius of the planet = 3 × The radius of Earth, [tex]R_E[/tex]

The escape velocity for Earth, [tex]v_e_E[/tex], is therefore given as follows;

[tex]v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }[/tex]

[tex]\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E[/tex]

[tex]v_e[/tex] = 16 × [tex]v_e_E[/tex]

Given that the escape velocity for Earth, [tex]v_e_E[/tex] ≈ 11,186 m/s, we have;

The escape velocity on the planet = [tex]v_e[/tex] ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

A body moving in a straight line has a uniform motion if it travels ---------- distance in -------- intervals og time

Answers

Answer:

uniform an uniform

please fill it like yhis

Why do you think it is colder during the winter than the summer?

Answers

Answer:

As the earth travels around the sun during the year it maintains this tilt. Because of this tilt, in the summer we (north of the equator) are slanted more directly towards the sun so it's hotter. In the winter, we're slanted away so the sun's rays are less direct, making it colder.

show your work. john uses a 25N force to push a boulder off a cliff that is 312m tall. What is the work done on the boulder?​

Answers

Answer:7800

work=force x distance

Force in Newtons

Distance in Meters

Work in Joules

A 10 kg object experiences an acceleration of 2 m/s squared. What net force was applied to the object?

Answers

F = ma

= 10kg × 2m/s

= 20N

Answer : 20N

Explanation :

F = Force (N)

m = mass (kg)

a = acceleration (m/s)

why watchman does no work but gets tired ?​

Answers

Answer: the body is trained to wake up when the sun rises and get the energy from the sun and sleep and it is night on when the sun is not there. So when a watchman works at night there is no sun first of all to give him any kind of energy and secondly the body clock resists him waking up thus making him tired.

Explanation:

a ball bounce on the ground. at what position (A,B,C)does the ball have the greatest potential energy? kinetic energy? explain your answer.​

Answers

Answer:

What is the meaning of the kinetic I think the answer is both the ball has both Kinetic and potential energy so I think is the answer is true

How long will it take an object traveling at 7 m/s to reach a distance of 26 meters

Answers

Answer:

3 hours 71 minutes

Explanation:

As because Speed= distance/time taken

so time taken= 3.71

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