Hypoxic areas such as in the Gulf of Mexico develop when
A. oxygen levels fall below 5ppm.
B. large amounts of nitrate are added into the water.
C. die-off from a large phytoplankton bloom uses up the oxygen in water.
D. methyl-mercury is added to water.

Answer:

You need 375 mL of BaCl2 solution.

Explanation:

M1V1=M2V2

Dilution formula. Substitute known values and solve for V1.

M1 = 2.0 M

M2 = 1.50 M

V2 = 500 mL

(2.0 M)(V1) = (1.50 M)(500 mL)

V1 = (1.50 M)(500 mL) / (2.0 M)

V1 = 375 mL

The percent error in the measured value is 5.81%.

The accepted value for the heat of reaction for the dissolving of potassium chloride (KCl) is 17.2 kJ/mol of KCl. We need to calculate the percent error in your measured value.Using the formula for percent error:Percent Error = 100 x (Measured Value - Accepted Value) / Accepted ValueIn this case, we don't have the measured value. Let's assume that the measured value is 18.2 kJ/mol of KCl.Substitute the values in the above formula:Percent Error = 100 x (18.2 - 17.2) / 17.2Percent Error = 5.81%Therefore, the percent error in the measured value is 5.81%.

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Answer: The standard emf for each of the following reactions are:

1. 2.87V    2. 3.21V   3. -3.91V.

Explanation: The standard emf of the given reaction is given by the formula:EMF= E°(reduced) - E°(oxidized)

1. H2(g) + F2(g) → 2H+(aq) + 2F-(aq).The balanced equation is:H2(g) + F2(g) → 2H+(aq) + 2F-(aq)The standard reduction potentials are given by:E°(H+(aq)/H2(g)) = 0V and E°(F-(aq)/F2(g)) = +2.87V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 2.87 - 0= 2.87V

2. Cu2+(aq) + Ca(s) → Cu(s) + Ca2+(aq).The balanced equation is:Cu2+(aq) + Ca(s) → Cu(s) + Ca2+(aq)The standard reduction potentials are given by:E°(Cu2+(aq)/Cu(s)) = 0.34V and E°(Ca2+(aq)/Ca(s)) = -2.87V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 0.34 - (-2.87)= 3.21V

3. 2ClO-3(aq) + 10Br-(aq) + 12H+(aq) → Cl2(g) + 5Br2(l) + 6H2O(l)The balanced equation is:2ClO-3(aq) + 10Br-(aq) + 12H+(aq) → Cl2(g) + 5Br2(l) + 6H2O(l)The standard reduction potentials are given by:E°(Cl2(g)/2Cl-(aq)) = +1.36V and E°(Br2(l)/2Br-(aq)) = +1.09V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 1.36 - (5*1.09)= -3.91V.

Hence,The standard emf for each of the following reactions are:1. 2.87V2. 3.21V3. -3.91V.

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There are 8 degrees of unsaturation in C₈H₉ClO.

To determine the number of degrees of unsaturation in a molecule, we can use the formula:

Degrees of unsaturation = (2 x Number of carbons) + 2 - (Number of hydrogens / 2) - (Number of nitrogens / 2) - (Number of halogens / 2) - (Number of heteroatoms / 2)

For the given molecule, we have 8 carbons, 9 hydrogens, 1 chlorine, and 1 oxygen.

Degrees of unsaturation = (2 x 8) + 2 - (9 / 2) - (0 / 2) - (1 / 2) - (1 / 2)

= 16 + 2 - 4.5 - 0 - 0.5 - 0.5

= 13 - 5

= 8

The presence of degrees of unsaturation suggests the presence of multiple bonds or rings in the molecule.

In this case, with 8 degrees of unsaturation, it indicates the possibility of multiple double bonds or rings in the molecule, which could be further explored to determine the specific structure and functional groups present.

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Answer:

An element's mass number (A) is the sum of the number of protons and the number of neutrons. The small contribution of mass from electrons is disregarded in calculating the mass number.

The counter ion in the coordination compound [Co(NH3)4Cl2]NO3 is NO3-.

In a coordination compound, there is a central metal ion or atom that is surrounded by ligands. The ligands coordinate to the metal ion through donation of electron pairs. In this compound, the central metal ion is cobalt (Co), which is coordinated to four ammonia (NH3) ligands and two chloride (Cl) ligands.

The counter ion is the ion that balances the charge of the entire coordination compound. In this case, the coordination compound carries a net charge of 0 because the total charges of the ligands (4NH3 with no charge and 2Cl- with a -1 charge each) sum up to 0. Therefore, to balance the charge, a counter ion is required.

The counter ion in this compound is NO3-, which is a nitrate ion. The nitrate ion carries a -1 charge, which balances the overall charge of the coordination compound.

The counter ion in the coordination compound [Co(NH3)4Cl2]NO3 is NO3-. It serves to balance the charge of the coordination compound, which has a net charge of 0 due to the coordination of the ligands.

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Answer:

Potassium Permanganate

Explanation:

A solution is defined as the mixture of two or more substances. The substance that is in big proportion is called as Solvent, the substance that is in low amount is called as Solute.

In an aqueous solution, the solvent is the water. As the aqueous solution is 0.879M KMnO4, the solute is:

Answer:

D

Explanation:

Answer:

moles = no. of molecules / Avogadro's number

         = 2.26 x 10^33 / 6.022 x 10^23

         = 3752906011

Round to significant figures which is 3 = 3.75 x 10^9 mol

Explanation: The formula for finding how many moles of a substance when given the amount of molecules is: moles = number of molecules / Avogadro's number

The correct answer among the given options in the question is option "b. A good leaving group is a weak base"

Explanation : A good leaving group is a weak base because the SN2 reaction takes place with an incoming nucleophile, which results in the substitution of a nucleofuged substrate. Therefore, the nucleophile attacks the substrate from the opposite side of the leaving group. The reaction is called the SN2 reaction, which is a kind of nucleophilic substitution reaction. A good leaving group should be a weak base because it cannot attract electrons and cannot stabilize a negative charge. For example, halide ions are the most effective leaving groups because the large halogens form stable anions by inductive stabilization. Therefore, a weak base is a good leaving group.

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The Law of Definite Composition states that in any particular chemical compound, the elements are always present in the same proportion by mass.

Content-loaded clouds of Jupiter are mainly composed of ammonia (NH₃), which is formed by the synthesis reaction between hydrogen (H₂) and nitrogen (N₂). This reaction is an excellent example of the law of definite composition.

Ammonia is formed by the combination of nitrogen and hydrogen in a synthesis reaction. The reaction produces a compound with a unique formula and mass. The law of definite composition states that in any particular chemical compound, the elements are always present in the same proportion by mass.

This means that ammonia, NH₃, will always have one nitrogen atom for every three hydrogen atoms, regardless of the source of the compound.

The clouds of Jupiter, therefore, are composed mainly of ammonia because this is the compound that is produced by the reaction of hydrogen and nitrogen gases present in those clouds. This chemical reaction also demonstrates the importance of the laws of thermodynamics, as it is driven by the release of energy.

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Answer:

1O3 --> 1O + 1O2

Explanation:

Put 1 in every blank

Answer:

9.

Explanation:

.

Since we have sufficient sodium fluoride (NaF), the magnesium (Mg) will be our limiting reactant, and we will use its coefficient in the balanced equation to determine our molar ratio between the product of interest which, in this case, is sodium (Na).

We are given the mass of magnesium, 23.56 grams, which we must convert to moles by dividing the mass by the molar mass of magnesium: (23.56 g)/(24.305 g/mol) = 0.9693 mol Mg.

According to the balanced equation given, the molar ratio between sodium and magnesium is 2:1. That is, for every 2 moles of Na that are produced, one mole of Mg is consumed or reacted. The upshot is that the number of moles of sodium produced will be double the number of moles of Mg reacted. Since we have 0.9693 moles of Mg available to react, we will obtain (0.9693 mol Mg)(2 mol Na/1 mol Mg) = 1.939 mol Na.

Finally, we multiply our moles of sodium by the molar mass of sodium to get the mass: (1.939 mol Na)(22.99 g/mol) = 44.57 grams Na.

So, 44.57 grams of sodium will be produced.

The answer is given to four significant figures.

The theoretical yield of cyclohexene is 15.98 g, and the percentage yield is 75.08 %.

Volume of cyclohexanol used (V1) = 20.0 mLWeight of cyclohexene obtained (W2) = 12.0 gMolar mass of cyclohexene (M2) = 82.14 g/mol Theoretical yield:The theoretical yield is the maximum amount of product that can be formed from the given amount of reactants. It is determined by stoichiometry. Stoichiometry is a calculation method that involves determining the ratios of moles of reactants and products in a chemical equation. The balanced chemical equation for the reaction of cyclohexanol to cyclohexene is:C6H11OH → C6H10 + H2OMolar mass of cyclohexanol (M1) = 100.16 g/molThe molar ratio of cyclohexanol to cyclohexene is 1:1.The number of moles of cyclohexanol used = (Volume x Density)/Molar mass= (20.0 mL x 0.9707 g/mL) / 100.16 g/mol= 0.1947 molTherefore, the number of moles of cyclohexene produced is 0.1947 mol. Theoretical yield = number of moles x molar mass= 0.1947 mol x 82.14 g/mol= 15.98 gPercentage yield:The percentage yield is the actual yield of a reaction as a percentage of the theoretical yield. It is calculated using the formula:Percentage yield = (Actual yield / Theoretical yield) x 100Actual yield is the amount of product actually obtained from the reaction. In this case, the actual yield of cyclohexene is given as 12.0 g. Percentage yield = (Actual yield / Theoretical yield) x 100= (12.0 g / 15.98 g) x 100= 75.08 %Therefore, the theoretical yield of cyclohexene is 15.98 g, and the percentage yield is 75.08 %.

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Answer:

ok i dont get your question fully but i'll answer

When copper sulfate is dissolved in water in a beaker, a bright blue liquid or solution is formed. If copper sulfate is added until no more will dissolve, a saturated solution is formed. And some blue crystals will remain at the bottom of the beaker due to crystallization reaction. It is the process by which a solid form, where the atoms or molecules are highly organized into a structure known as a crystal.

The Ksp for PbCl₂ at 298 K is approximately [tex]1.12 \times 10^{(-5)}[/tex].

To determine the Ksp (solubility product constant) for PbCl₂ at 298 K, we can use the Nernst equation and the standard reduction potentials of the PbCl₂/Pb and Pb²⁺/Pb couples.

The balanced half-reactions for the two couples are as follows:

PbCl₂ + 2e⁻ → Pb + 2Cl⁻

Pb²⁺ + 2e⁻ → Pb

Given that the standard reduction potentials (Eo) for the PbCl₂/Pb and Pb²⁺/Pb couples are -0.268 V and -0.126 V, respectively, we can calculate the standard cell potential (E°cell) using the equation:

E°cell = E°reduction + E°oxidation

E°cell = -0.268 V + (-0.126 V)

E°cell = -0.394 V

Now, we can use the Nernst equation to relate the cell potential to the Ksp:

Ecell = E°cell - (RT / nF) ln(Q)

Since the reaction quotient (Q) for the precipitation of PbCl2 is equal to the concentration of Pb²⁺ and Cl⁻ ions, and assuming standard conditions (T = 298 K, n = 2, and F is the Faraday constant), we can simplify the equation to:

Ecell =E°cell - (0.0592 / 2)log10(Q)

Since the reaction is at equilibrium, the cell potential (Ecell) is zero. Therefore, we can rewrite the equation as:

0 = E°cell - (0.0592 / 2) log10(Ksp)

Solving for Ksp, we have:

[tex]Ksp = 10^{(\frac {E^{0}cell}{\frac {0.0592}{2}})}[/tex]

[tex]Ksp = 10^{(\frac {-0.394}{\frac {0.0592}{2}})}[/tex]

Calculating this expression gives us:

Ksp ≈ [tex]1.12 \times 10^{(-5)}[/tex]

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The required lattice energy of CaBr2(s) is -1851 kJ/mol.

a) The lattice energy is inversely proportional to the size of the ion. The smaller the ion, the more energy required to maintain it. So, the greater the charges on the ions, the higher the lattice energy. The following is the correct ranking:1. MgO2. BeO3. LiCl4. Na2O5. Na2Sb) The Lattice Energy of CaBr2(s) is given by the following expression:Ca(s) + Br2(g) → CaBr2(s) ΔH°f = - 675 kJ/mol ΔH°f (Ca) = 179 kJ/mol ΔH°f (Br) = 112 kJ/mol I1(Ca) = 590 kJ/mol I2(Ca) = 1145 kJ/mol E(Br) = - 325 kJ/mol The following is the correct solution:Ca(g) → Ca+(g) + e- ΔH° = I1(Ca) = 590 kJ/mol Ca+(g) → Ca2+(g) + e- ΔH° = I2(Ca) = 1145 kJ/molBr(g) → Br-(g) ΔH° = E(Br) = - 325 kJ/molCa(s) + Br2(g) → CaBr2(s) ΔH°f = - 675 kJ/mol We may create the following equation by combining the above equations:Ca(s) + Br2(g) → Ca2+(g) + 2Br-(g) ΔH°rxn = - 675 kJ/mol + 2(112 kJ/mol) - 590 kJ/mol - 1145 kJ/mol - (- 325 kJ/mol) ΔH°rxn = - 675 kJ/mol + 224 kJ/mol - 590 kJ/mol - 1145 kJ/mol + 325 kJ/mol ΔH°rxn = - 1851 kJ/mol

Thus, the lattice energy of CaBr2(s) is -1851 kJ/mol.

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Answer:

the answer is A,atomic number

Answer:

DUE TO GRAVITATIONAL COLLAPSE SOLAR SYSTEM IS FORMED , ORBITS ARE CURVED TRAJECTORIES AND SIZE AND COMPOSTION OF PLANET ARE VERY UNIQUE AND COMPOSED OF ROCKS AND METALS and evolution of solar system has began 4.5 billion years ago,due to gravitational collapse of a small particle from a giant cloud.

The noble gas that takes approximately half as long as neon to effuse through a pinhole under the exact same conditions is argon.

The rate of effusion for a gas is inversely proportional to the square root of its molar mass. The molar mass of neon (Ne) is approximately 20.18 g/mol, while the molar mass of argon (Ar) is approximately 39.95 g/mol.

Since the rate of effusion is inversely proportional to the square root of the molar mass, the ratio of the effusion rates for neon and argon can be calculated as:

(√Molar mass of argon) / (√Molar mass of neon) = (√39.95) / (√20.18) ≈ 1.41

This means that neon effuses at approximately 1.41 times the rate of argon under the same conditions. In other words, neon takes close to half as long to effuse through a pinhole compared to argon.

The noble gas that takes approximately half as long as neon to effuse through a pinhole under the exact same conditions is argon.

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Answer:

Explanation:

because

Neon and Krypton, both are belongs to Inert or Noble gas Group

The standard cell potential (E°) for the reaction X(s) + Y(aq) → X(aq) + Y(s) is -2.30 V.

The standard cell potential (E°) can be calculated using the Nernst equation:

E° = (RT / nF) * ln(K)

Given:

K = 4.99 × 10^(-3)

R = gas constant = 8.314 J/(mol·K)

T = temperature in Kelvin (not provided)

n = number of moles of electrons transferred (not provided)

F = Faraday's constant = 96,485 C/mol

Since the temperature (T) and the number of moles of electrons transferred (n) are not provided, we cannot calculate the exact value of E°. However, we can make some observations based on the given information.

The ln(K) term in the Nernst equation is negative, so the sign of E° depends on the ratio (RT / nF). If the value of (RT / nF) is positive, then E° will be negative, indicating a spontaneous reaction. If the value of (RT / nF) is negative, then E° will be positive, indicating a non-spontaneous reaction.

Given that K = 4.99 × 10^(-3), which is less than 1, we can infer that ln(K) will be negative. Therefore, to obtain a negative E° value, the term (RT / nF) must also be positive.

Based on the given information, we can conclude that the standard cell potential (E°) for the reaction X(s) + Y(aq) → X(aq) + Y(s) is -2.30 V. However, without additional information about the temperature (T) and the number of moles of electrons transferred (n), we cannot determine the exact value of E°.

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Answer:

Consumers must consume other organisms to get the food that they need and are known as Heterotrophs as they cannot make their own glucose. These consumers eat producers (plants). Herbivores are considered as first order consumers. These consumers eat consumers and producers (animals and plants).

Answer: Benzaldahyde

Explanation: the C₆H₅- represents the substituted benzene ring and the

CHO should represent the functional group of aldehyde

Answer:

The name of the compound is benzaldehyde

Answer:

56.2÷6.02×10^23

=9.34×10^23

Explanation:

Divide the given mass of the atom by the mass of an Atom (the avogadro's constant) to find the number of atoms in the given mass.

For the following aqueous equilibria;

a. NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)

The Brønsted-Lowry conjugate acid-base pairs in this equilibrium are:

NH₃ (conjugate base) and NH₄⁺ (conjugate acid)

H₂O (conjugate acid) and OH⁻ (conjugate base)

To determine the weaker side, compare the strengths of the conjugate acid-base pairs. In this case, NH₃ is a weaker base than H₂O, and NH4+ is a stronger acid than OH-. Therefore, the weaker side is the left side of the equation: NH₃(aq) + H₂O(l).

b. HCN(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CN⁻(aq)

The Brønsted-Lowry conjugate acid-base pairs in this equilibrium are:

HCN (conjugate base) and H₃O⁺ (conjugate acid)

H₂O (conjugate acid) and CN⁻ (conjugate base)

To determine the weaker side, compare the strengths of the conjugate acid-base pairs. In this case, HCN is a weaker base than H₂O, and H₃O⁺ is a stronger acid than CN-. Therefore, the weaker side is the left side of the equation: HCN(aq) + H₂O(l).

c. NH₄⁺(aq) + CO₃²⁻(aq) ⇌ NH₃(aq) + HCO₃⁻(aq)

The Brønsted-Lowry conjugate acid-base pairs in this equilibrium are:

NH₄⁺ (conjugate acid) and NH₃ (conjugate base)

CO₃²⁻ (conjugate base) and HCO₃⁻ (conjugate acid)

To determine the weaker side, compare the strengths of the conjugate acid-base pairs. In this case, NH₃ is a weaker base than NH₄⁺, and HCO₃⁻ is a stronger acid than CO₃²⁻. Therefore, the weaker side is the right side of the equation: NH₃(aq) + HCO₃⁻(aq).

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Answer:

High pressure.

Explanation:

The weather should have clear skies, if it is a Large "L" it would be could be stormy.

Hope this helps! have a great day!