Density is the mass per unit volume of any object. It is calculated by dividing the mass of an object by its volume. This is:
ρ = m/V
ρ = 4.05 g / 12 mL
ρ = 0.3375 g/mL
ρ ≅ 0.338 g/mLOPTION A
What the someone explain this to me
Answer:
the answer might be A and D if not sorry
Explanation:
When forces are balanced, what happens to the motion of the object?
Group of answer choices
Objects never have balanced forces.
Objects with balanced forces change motion.
Objects with balanced forces are able to change at will.
Objects with balanced forces remain unchanged.
Answer:
C-objects with balanced forces remain un changed
Explanation:
because the forces that act on the body cancel each other and the net force=0
The force involved in a collision is 1.0×10 to the second power newtons the duration of the impact is 1.0×10 to the fourth power seconds what is the value of the change in momentum
Knowing the force and the duration, we can simply multiply them to get the "impulse". This is really convenient for this question, because the impulse is also the change in momentum. So let's do it:
Change in momentum = (force) x (duration)
Change in momentum = (1 x 10² Newtons) x (1 x 10⁴ seconds)
Change in momentum = (100 N) x (10,000 seconds)
Change in momentum = 1,000,000 Newton-seconds
Change in momentum = 1,000,000 kg-m/s .
That sunawfulada momentum ! It's the same change in momentum as if you stopped a 4,000-kg truck that was going 550 mph, in 1 second !
There's gotta be something wrong here.
Notice the duration of the impact in the question: 1 x 10⁴ seconds.
That's 2 hours and 47 minutes ! Collisions don't normally take that long.
Call me batty, but I've got a hunch that the duration actually is supposed to be 1.0 x 10 to the NEGATIVE fourth power. Then, the change in momentum is
(100 N) x (0.0001 s) = 0.01 kg-m/s
That's still a slightly uncomfortable result, but it's definitely more realistic ... it could be the act of batting a fly or a mosquito out of the air.
I like that a lot better than a collision that takes almost 3 hours.
Add your answers to the table below.
Energy Sequence Table
Step 1
Step 2
Energy Form Energy Form
Step 3
Energy Form
Sequence Number
1: Turbine to Power Saw
2: Gas in Your Car
Thermal Chemical
3: Sunshine to Cows
4: Coal Power Plant
5: Wall Socket to Hair Dryer
Part 3: Journal Questions
Complete the following questions using what you learned in the Part 1 and 2 activity and in
Solve these two please its urgent, If i like your answer ill give brainly....
Answer: green car and red car
Explanation:
Answer:
it is white car for the first question and for the second it goes green slowest and white fastest red is in the middle
Un bloque de 20kg de masa se desplaza horizontalmente en la dirección de eje X por acción de una fuerza horizontal variable F = 6x, donde F se mide en Newton y "x" en metros. Si se desprecia el rozamiento determine: a) El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x=+10m hasta la posición x=+20m b) La rapidez del bloque en la posición x=+20m, si su rapidez en la posición x=+10m fue √10 m/s.
Answer:
a) El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.
b) La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.
Explanation:
a) El trabajo expermentado por el bloque ([tex]W[/tex]), medido en joules, es definida por la siguiente ecuación integral:
[tex]W = \int\limits^{x_{max}}_ {x_{min}} F(x) \, dx[/tex] (1)
Donde:
[tex]x_{min}[/tex], [tex]x_{max}[/tex] - Posiciones mínima y máxima del bloque, medidos en metros.
[tex]F(x)[/tex] - Fuerza horizontal aplicada al bloque, medida en newtons.
Si conocemos que [tex]F(x) = 6\cdot x[/tex], [tex]x_{min} = 10\,m[/tex] y [tex]x_{max} = 20\,m[/tex], entonces el trabajo realizado por esta fuerza es:
[tex]W = \int\limits^{20\,m}_{10\,m} {6\cdot x} \, dx[/tex] (2)
[tex]W = 6\int\limits^{20\,m}_{10\,m} x\, dx[/tex]
[tex]W = 3\cdot x^{2}\left|\limits_{10\,m}^{20\,m}[/tex]
[tex]W = 3\cdot [(20\,m)^{2}-(10\,m)^{2}][/tex]
[tex]W = 900\,J[/tex]
El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.
b) La rapidez final del bloque se determina mediante de Teorema del Trabajo y la Energía, es decir:
[tex]W = K_{f}-K_{o}[/tex] (3)
Donde son [tex]K_{o}[/tex], [tex]K_{f}[/tex] las energías cinéticas traslacionales inicial y final, medidos en joules.
Al aplicar la definición de energía cinética traslacional, expandimos y simplificamos la ecuación como sigue:
[tex]W = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})[/tex] (4)
Donde:
[tex]m[/tex] - Masa del bloque, medido en kilogramos.
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Rapideces inicial y final del bloque, medidos en metros por segundo.
[tex]\frac{2\cdot W}{m} = v_{f}^{2}-v_{o}^{2}[/tex]
[tex]v_{f} = \sqrt{\frac{2\cdot W}{m}+v_{o}^{2}}[/tex]
Si conocemos que [tex]W = 900\,J[/tex], [tex]m = 20\,kg[/tex] y [tex]v_{o} = \sqrt{10}\,\frac{m}{s}[/tex], entonces la rapidez final del bloque es:
[tex]v_{f} = \sqrt{\frac{900\,J}{2\cdot (20\,kg)}+10\,\frac{m^{2}}{s^{2}} }[/tex]
[tex]v_{f} \approx 5.701\,\frac{m}{s}[/tex]
La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.
Another name for semi-arid climate is
Answer: an steppe climate
Explanation:
The ball is pulled by a force called gravity. In what direction does gravity always pull the ball?
Answer:
Gravity always pulls the ball toward the center of earth (the ground).
Explanation:
Se lanza verticalmente hacia arriba un proyectil y alcanza una altura máxima de 100 metros de altura. ¿Cuál fue la velocidad hacia arriba con la que fue lanzada?
Answer:
v = 44,3 m/s
Explanation:
La velocidad la podemos hallar usando la siguiente expresión:
[tex] v_{f}^{2} = v_{0}^{2} - 2gh [/tex]
En donde:
h: es la máxima altura = 100 m
[tex]v_{f}[/tex]: es la velocidad final = 0 (en la altura máxima)
[tex]v_{0}[/tex]: es la velocidad inicial =?
g: es la gravedad = 9,81 m/s²
Resolviendo la ecuación anterior para v₀, tenemos:
[tex] v_{0} = \sqrt{2gh} = \sqrt{2*9,81 m/s^{2}*100 m} = 44,3 m/s [/tex]
Entonces, el proyectil fue lanzado hacia arriba con una velocidad de 44,3 m/s.
Espero que te sea de utilidad!
im a very dumb human being plz help
Answer:
so first is the clouds is presipitision then its the ocean one and then dirt and then the mud then the gray part
Explanation:
If you wake up in the morning, go to school, go to the grocery store, and then return to the same place where you woke up, what is your displacement for the day
Answer:
0 I think
Explanation:
A bullet is shot from a rifle with a speed of 3,015 feet per second. Assuming the billet moves at a constant velocity what is the time rescuers die the biller to strike a target 4,146 meters away
Answer:
Explanation:
Given
final speed v = 3015ft/s
initial speed = 0m/s
Distance S = 4146m/s
Required
Time
Using the equation of motion to get the time;
S = (v+u)/2 * t
since 1m = 3.28084ft'
4146m = 3.28084 * 4146 = 13,602.36264feet
13,602.36264 = 3015+0/2 * t
13,602.36264 = 1,507.5t
t = 13,602.36264/ 1,507.5
t = 9.023 secs
Hence it will take 9.023 seconds the rescuer die the biller to strike a target
What is its speed if it takes 0.5 seconds to cover the distance?
Answer:How far is the distance?
Explanation:
A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42°. What is the force of
static friction acting on the box if box has a gravitational force of 112.1 N ?
0 70 N
O 80 N
O 75 N
O 85 N
Mark this and return
Save and Exit
Next
Submit
Answer:
The correct option is;
75 N
Explanation:
The given parameters are;
The angle of inclination of the ramp, θ = 42°
The gravitational force of the box = m × g = 112.1 N
Let [tex]F_f[/tex] represent the force of static friction acting on the box
Given that the box is at rest, we have
The component of the gravitational force acting along the inclined plane = The force of static friction acting on the box, [tex]F_f[/tex]
We have that the component of the gravitational force acting along the inclined plane = m × g × sin (θ) = [tex]F_f[/tex]
[tex]F_f[/tex] = m × g × sin (θ)
Substituting the values, gives;
[tex]F_f[/tex] = 112.1 × sin (42°) ≈ 75.0095409728
∴ The force of static friction acting on the box = [tex]F_f[/tex] ≈ 75 N
Answer:
C: 75N
Explanation:
A penny is dropped from the 82nd Floor Observatory of the Empire State Building. The penny will fall for 8.1s before hitting the ground. 1. How far does the penny fall? 2. How fast is the penny going when it hits the ground?
Answer:
vf=79.38 m/s
y= 321.5 m
Explanation:
Free Fall Motion
A free-falling object falls under the exclusive influence of gravity. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
1.
The penny will fall for t=8.1 s before hitting the ground, thus the height from which it was dropped is:
[tex]\displaystyle y=\frac{9.8\cdot 8.1^2}{2}[/tex]
y= 321.5 m
2.
The final velocity is:
[tex]vf=9.8\cdot 8.1[/tex]
vf=79.38 m/s
An aircraft is descending with a constant velocity of 480 kmh at an angle of 2.0 to the horizontal. What is the vertical component of the plane's velocity
Answer:
Vy = 4.65 m/s
Explanation:
Since, the airplane is descending at a rate of 480 km/h at an angle of 2° from horizontal. Therefore, its vertical component of velocity shall be given as follows:
Vy = V Sin θ
where,
Vy = Vertical Component of Velocity = ?
V = Velocity of Plane = (480 km/h)(1000 m/1 km)(1 h/3600 s) = 133.33 m/s
θ = Angle = 2°
Therefore,
Vy = (133.33 m/s)(Sin 2°)
Vy = 4.65 m/s
If 4000J is used to move a charge through a potential difference of 0.078V, what is the charge?
Answer:
102564.103 C
Explanation:
From the question given above, the following data were obtained:
Energy (E) = 4000 J
Potential difference (V) = 0.078 V
Charge (Q) =?
Thus, we can obtain the charge as illustrated below:
E = ½QV
4000 = ½ × Q × 0.078
4000 = Q × 0.039
Divide both side by 4000
Q = 4000 / 0.039
Q = 102564.103 C
Thus, the charge is 102564.103 C.
how long will it take for a rock to fall 50 meters
Answer:
The force of gravity, g = 9.8 m/s2
Gravity accelerates you at 9.8 meters per second per second. After one second, you're falling 9.8 m/s. After two seconds, you're falling 19.6 m/s, and so on.
Time to splat: sqrt ( 2 * height / 9.8 )
It's the square root because you fall faster the longer you fall.
The more interesting question is why it's times two: If you accelerate for 1 second, your average speed over that time is increased by only 9.8 / 2 m/s.
Velocity at splat time: sqrt( 2 * g * height )
This is why falling from a higher height hurts more.
Energy at splat time: 1/2 * mass * velocity2 = mass * g * height
Explanation:
The time taken by the rock to fall will be 3 seconds.
What is velocity?Velocity is defined as the ratio of the distance moved by the object at a particular time. The velocity is a vector quantity so it needs both the magnitude and the direction.
The time taken for the freely falling body is calculated by the equations of motion. That is v² = u² + 2gs. By using the equation we can calculate the velocity and the time period.
The force of gravity, g = 9.8 m/s²
Gravity accelerates you at 9.8 meters per second per second. After one second, you're falling 9.8 m/s. After two seconds, you're falling 19.6 m/s, and so on.
Time to splat = √( 2 x height) / 9.8
Time to splat = √( 2 x 50 ) / 9.8
Time to splat = 3 seconds
Therefore, the time taken for the rock to fall will be 3 seconds.
To know more about Velocity follow
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The diagram below shows a wave with its wavelength indicated in red.
wavelength
What will happen to the wave's frequency if its wavelength is made twice as long?
A. It will stay the same.
B. It will go to zero
C. It will double.
D. It will decrease
Answer:
answer is D.it will decrease
Answer:
D. It will decrease
Explanation: Study island ;)
Which changes of state occur between solids and gases? Check all that apply.
vaporization
deposition
freezing
melting
sublimation
Answer:
deposition, sublimation
Explanation:
The changes of state occur between solids and gases during deposition and sublimation. The second and fifth option are correct.
What is sublimation?The conversion of solid to gas and gas to solid directly, as in case of solid ice made of carbon di oxide.
The change of state means changing the phase of the matter with the change in temperature and pressure of the surrounding.
The vaporization change liquid to gas or solid to liquid and vice versa. Freezing is converting liquid to solid. Melting is converting from solid to liquid.
The rest phenomenon are deposition and sublimation in which phase change between solid and gas.
Thus, second and fifth option are correct.
Learn more about sublimation.
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Forces have strength, or magnitude, and direction.
True
False
What is the final velocity of a car that has an initial velocity of 15.2 m/s and accelerates at 3.2 m/s^2 for 2.6 seconds?
Answer:
t=2.59s
Explanation:
v=23.5m/s u=15.2m/s a=3.2m/s^2 t=?
using equation v=u+at t=(v-u)/a t= (23.5-15.2)/3.2=8.3/3.2=2.59s
Frank has a liquid. It has a mass of 6 g and a volume of 9 ml. What is its density?
A 120-kg roller coaster cart is being tested on a new track, and a crash-test dummy
is loaded into it. The roller coaster starts from rest at point A which is 25 m above
point B. If the track near to point B is in the shape of a circle with a radius of 15 m,
and the cart is moving at 22 m/s at point B, what centripetal acceleration does the
cart experience at that point?
Answer:
32 m/s².
Explanation:
From the question given above, the following data were obtained:
Mass (m) of cart = 120 Kg
Radius (r) = 15 m
Velocity (v) = 22 m/s
Centripetal acceleration (a) =?
The centripetal acceleration experienced by the cart can be obtained as illustrated below:
a = v²/r
a = 22² / 15
a = 484 / 15
a = 32.27 ≈ 32 m/s²
Thus, the centripetal acceleration experienced by the cart is approximately 32 m/s².
Buster Posey hits a pop-up straight up. The velocity of the baseball as it leaves the bat is 42.5 m/s. Determine (a) the total time the baseball is in the air, and (b) the maximum height the baseball reaches. Assume the baseball is caught at the same height above the ground as it was hit. Draw an image of the baseball for each 1 second of time it is traveling, for each image include a labeled velocity and acceleration vector.
Answer:
part a: 4.25s
part b: 180.625m
Explanation:
part a:
what we know: vi=42.5m/s
t=?
vf=0
g= -10m/s^2
----------------------------------------------------------
equation: vf-vi/g=t
plug in: -42.5m/s/ - 10m/s^2 = 4.25s
-----------------------------------------------------------
part b: 42.5m/s x(times) 4.25s = 180.625m
Which planet do you think would be easiest for humans to colonize some day? Explain.
Answer:
I think that Mars would be the easiest planet for humans to colonize because they have already begun working on colonizing Mars and have made a ton of progress.
A small car uses about 130000J of energy in the form of gasoline. The car converts that energy to a kinetic energy of 53000J. What is the efficiency of this conversion?
Explanation:
Given parameters:
Energy input = 130000J
Energy output = 53000J
Unknown:
Efficiency of the conversion = ?
Solution:
Efficiency is the percentage of work output to work input;
Mathematically;
Efficiency = Energy output/ Energy input x 100
Efficiency = 53000/130000 x 100 = 40.8%
A man paces 2m
east and 3m north
while on the phone.
The entire trip
takes 13s. What is
the man's distance,
displacement,
average speed, and
average velocity?
C
yo
of
S
shc
do
you
Us
be
She wants to travel back to Madison by train. The distance from Chicago to Madison is 147 miles and takes 2.47 hours. If she makes no stops, what is her average speed?
Answer:
59.51 mph.
Explanation:
The following data were obtained from the question:
Distance (d) = 147 miles
Time (t) = 2.47 hours.
Speed (S) =?
Speed is defined as the distance travelled per unit time. Mathematically, it is expressed as:
Speed (S) = Distance (d) / time (t)
S = d/t
With the above formula, we can obtain the speed of the girl as illustrated below:
Distance (d) = 147 miles
Time (t) = 2.47 hours.
Speed (S) =?
S = d/t
S = 147 miles / 2.47 hours.
S = 59.51 miles per hour (mph)
Thus, the speed of the girl is 59.51 mph.
As shown in the figure, a 2.00-kg block is held in place against the spring by a 50-N horizontal external force. The external force is removed, and the block is projected with a velocity v1 = 1.2 m/s at as it separates from the spring. The block descends a ramp and has a velocity v2 = 2.0 m/s at the bottom. The track is frictionless between points A and B. The block enters a rough section at B, extending to E. The coefficient of kinetic friction between the block and the rough surface is 0.30. The velocity of the block is v3 = 1.4 m/s at C. The block moves on to D, where it stops.
A) What is the total energy of the spring block system before the block descends down the ramp.
B) How high is the ramp?
C) How far did the block move from B to C?
D) How far did the block move from C to D?
E) What is the work done by friction on the block from B to D?
F) What is the Mechanical energy of the spring-block system at E?
G) How much was the spring compressed by the external force
H) What is the spring constant?
Answer:
Explanation:
A ) Total energy of spring block system at height = kinetic energy at the bottom
= 1/2 m V²
= .5 x 2 x 2²
= 4 J
B )
height of ramp be h
mgh = 1/2 m ( v₂² - v₁² )
2 x 9.8 x h = 2² - 1.2²
19.6 h = 4 - 1.44
h = .1306 m
13.06 cm
C ) If distance between B and C be x₁
work done by friction = reduction in kinetic energy
= μ mg x₁ = 1/2 m ( 2² - 1.4² )
.3 x 9.8 x₁ = 1.02
x₁ = 34.7 cm
D )
If distance between C and D be x₂
work done by friction = reduction in kinetic energy
= μ mg x₂ = 1/2 m ( 1.4² - 0 )
.3 x 9.8 x₂ = .98
x₂ = 33.33 cm
E )
Total work done by friction
= 1/2 m v² - 0 , v = 2 m /s
= .5 x 2 x 2²
= 4 J .
F )
Mechanical energy of the system at E = 0
G ) 1/2 k x² = 1/2 m v²
kx = 50 N , where x is compression and k is spring constant
k²x² / 2k = 1/2 m v²
50² / k = 2 x 1.2²
k = 868.05 N / m
H ) kx = 50
x = 50 / k
= 50 / 868.05
= 5.76 cm .