how to find the circumference with a radius​

Balance the reaction:

a FeS₂ + b O₂   =>   c Fe₂O₃ + d SO₂

Matching up the atoms on either side gives the system of equations

• Fe: a = 2c

• S: 2a = d

• O: 2b = 3c + 2d

We have 3 equations with 4 unknowns. Suppose we fix one of the variables, say a = 2. Then

2 = 2c   ===>   c = 1

2•2 = d   ===>   d = 4

2b = 3•1 + 2•4   ===>   b = 11/2

and so the balanced reaction is

2 FeS₂ + 11/2 O₂   =>   Fe₂O₃ + 4 SO₂

or

4 FeS₂ + 11 O₂   =>   2 Fe₂O₃ + 8 SO₂

Look up the molar masses of each component element:

• Fe: 55.845 g/mol

• S: 32.06 g/mol

• O: 15.999 g/mol

Then the molar masses of the reactants are

• FeS₂: 119.965 g/mol

• O₂: 31.998 g/mol

Convert the given masses to moles:

• (882 g FeS₂) (1/119.965 mol/g) ≈ 7.35 mol FeS₂

• (528 g O₂) (1/31.998 mol/g) ≈ 16.5 mol O₂

In the balanced reaction, 4 moles of FeS₂ combine with 11 moles of O₂, or equivalently 1 mol FeS₂ is needed for every 11/4 = 2.75 mol O₂. Now,

(16.5 mol O₂) / (2.75 mol O₂) = 6

while

(7.35 mol FeS₂) / (1 mol FeS₂) = 7.35

which means the reaction consumes all of the available O₂ and we're left with 7.35 - 6 = 1.35 mol FeS₂.

For every 11 mol O₂ among the reactants, 2 mol Fe₂O₃ are produced. Then 16.5 mol O₂ makes for

(11 mol O₂) / (2 mol Fe₂O₃) = (16.5 mol O₂) / x

===>   x = 3.00 mol Fe₂O₃

which has a mass of

(3.00 mol Fe₂O₃) (160. g/mol) ≈ 479 g Fe₂O₃

To find the mass of Fe2O3 produced, we convert the given masses of FeS2 and O2 into moles and use the molar ratio in the balanced chemical equation. The mass of Fe2O3 produced is 1170.68 grams.

To solve this problem, we need to convert the given masses of FeS2 and O2 into moles. From the balanced chemical equation, we can see that the molar ratio between FeS2 and Fe2O3 is 1:1.

This means that the number of moles of Fe2O3 produced will be equal to the number of moles of FeS2. We can use the molar mass of Fe2O3 to convert moles to grams.

First, we calculate the number of moles of FeS2 and O2:

Moles of FeS2 = 882 g / 120.17 g/mol = 7.34 mol

Moles of O2 = 528 g / 32 g/mol = 16.5 mol

Since the molar ratio between FeS2 and Fe2O3 is 1:1, we know that 7.34 moles of FeS2 will produce 7.34 moles of Fe2O3.

Now, we can calculate the mass of Fe2O3:

Mass of Fe2O3 = Moles of Fe2O3 x Molar mass of Fe2O3

Mass of Fe2O3 = 7.34 mol x 159.69 g/mol = 1170.68 g

Therefore, 1170.68 grams of Fe2O3 are produced.

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Answer:

  A) 20 pounds

  B.2) (increasing) 60 pounds per minute

Step-by-step explanation:

A) The graph shows the container has 20 pounds in it at x=0 minutes.

__

B) The graph goes up to the right (is increasing).

At minute 0, the container has 20 pounds.

At minute 1, the container has 80 pounds.

The increase in one minute is 80-20 = 60 pounds per minute.

The initial amount of candy in the container is 2 pounds.  As time increases, the amount of candy in the container decreases at a rate of 1 pound per minute.

A.) The amount of candy in the container at 0 minutes is 2 pounds.

B1.) As time increases, the amount of candy in the container decreases. The rate at which the amount of candy is decreasing is 1 pound per minute.

B2.) As time increases, the amount of candy in the container increases. However, this option is not applicable in this case as the graph shows a decreasing trend.

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Answer:

207,974.375

I'm not sure if you need an explanation, and I myself, am not sure I can explain it to you, so I'll just give the answer to you.

Hope this helps!

Answer:

20.5

Step-by-step explanation:

Use Pythagorean theorem,

[tex]x^2 = 14^2 +15^2 \\\\\implies x^2 =421\\\\\implies x =\sqrt{421}\\\\\implies x =20.5[/tex]

Answer/Step-by-step explanation:

[tex]\frac{1-\cos \left(x\right)}{\sin \left(x\right)}=\frac{\sin \left(x\right)}{1+\cos \left(x\right)}[/tex]

When you have an equation like this, you can start from either side. So, let us start from the left side.

[tex]\underline{\mathrm{Left\:side:}} \quad\frac{1-\cos \left(x\right)}{\sin \left(x\right)}[/tex]

[tex]\sf{Rewrite\: using \:Trig \:identities=\frac{\sin \left(x\right)}{1+\cos \left(x\right)}}\\\\\mathrm{Therefore,\: it \:is \:true}[/tex]

Answer:

x < -6

Step-by-step explanation:

-2x - 4 > 8

the first step is to add 4 to both sides since we need to get x alone on one side

-2x - 4 > 8

      +4  +4

so we are left with -2x > 12

we still need to get x alone so we have to divide -2 from both sides

always remember that if you divide by a negative number the inequality flips!! so instead of > it will be <.

-2x/-2 = x

12/-2 = -6

so the answer is x < -6

Answer:

9 x + 42.

Step-by-step explanation:

Answer:

72x+178" role="presentation" style="outline: 0px; display: inline-block; line-height: 0; text-indent: 0px; text-align: left; text-transform: none; font-style: normal; font-weight: normal; font-size: 17.017px; letter-spacing: normal; overflow-wrap: normal; word-spacing: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; position: relative;">72x+17872x+178

Answer:

Step-by-step explanation:

Assuming the string is straight (it will not be so due to gravity and wind load)

θ arcsin(354 / (200(3)) = 36°

Answer:

a) 2400m on the 20th day for Charlie.

1) 728.41m of 20th day for Daniella.

Didn't find n, sorry.

Charlie ran 2400m on day 20 of his fitness program and Daniella ran 728m on day 20 of her fitness program.

It is given that Charlie and Daniella on day one both ran 500m on each subsequent day.

Charlie ran 100m more than the previous day.

Daniella increased her distance by 2% of the distance run on the previous day.

It is required to calculate how far Charlie and Daniella ran on day 20 and the value of n.

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

Charlie ran 500m on the first day:

[tex]\rm a_1 = 500[/tex]

[tex]\rm a_2 =600[/tex] ( because charlie ran 100m more than the previous day)

It is an arithmetic progression in which the difference between two consecutive terms:

d = 600 - 500 ⇒ 100

and [tex]\rm a_n = a+d(n-1)[/tex]

[tex]\rm a_2_0 = 500+100(20-1)\\\\\rm a_2_0 = 2400m[/tex]( ∵ n = 20 )

Daniella ran 500m on the first day:

[tex]\rm b_1 = 500[/tex]

[tex]\rm b_2 = 500+ 500\times2 \%[/tex]  (because Daniella increased her distance by 2% of the distance run on the previous day)

We can write [tex]\rm n^t^h[/tex] terms:

[tex]\rm b_n= 500(1+2\%)^n^-^1[/tex]

[tex]\rm b_2_0= 500(1+2\%)^2^0^-^1[/tex]

[tex]\rm b_2_0= 500(1+0.02)^1^9\\\\\rm b_2_0 = 500\times 1.02^1^9\\\\\rm b_2_0 = 500\times1.456 \Rightarrow 728.40 \approx 728 m[/tex]

[tex]\rm b_n > a_n[/tex]  (given in the question)

[tex]\rm500(1+2\%)^n^-^1 > 500+100(n-1) \ \ or \\\\\rm500(1+2\%)^n^-^1 > 100n+400[/tex]

The above expression is not true for all the values of 'n' ie. 'n' can not be determined.

Thus, Charlie ran 2400m on day 20 of his fitness program and Daniella ran 728m on day 20 of her fitness programme.

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Answer:

she could spend up to $225 on more supplies

Step-by-step explanation:

the total amount of supplies and labor has to be less than or equal to $500. If she spent $150 and $125=$275 on supplies and labor, the equation would be 150+125+x≤ 500. Isolate x, to get x≤ $225. The value of x has to be less than or equal to $225.

Answer:

54,400

Step-by-step explanation:

Answer:

Answer: The answer is $20

Multiply 400 by .05 or 5%.

If you wanna know 6 years it would be 536 usd

Explanation:

This would be an compound interest. Meaning that your gain every year would increase exponentially.

The equation to calculate this would be: Kn = K0⋅

(1+p100)n Kn is your savings after the period nK0 is your starting deposit p is the percentage n is the period of interest for your example we would have.

Kn=400⋅

(1+5100)6

Step-by-step explanation:

CREDIT FOR ANSWER GOES TO  

calderonj4588

Answer:

Just go to the 6 on the bottom line, and add a point

Answer:

see below

Step-by-step explanation:

(6,0)

 The first coordinate is the x coordinate.  Since it is positive we go to the right 6 units.  The second coordinate is the y coordinate.  We go up zero units

Answer:

9 units²

Step-by-step explanation:

Parallelogram area = base × height

Base = 3 units

Height = 3 units

Area = 3 × 3

Area = 9

The area of the parallelogram is 9 units².

Here, we have,

We know that,

Parallelogram area = base × height

here, from the given figure we get,

Base = 3 units

Height = 3 units

so, we get,

Parallelogram area = base × height

Area = 3 × 3

Area = 9

Hence, The area of the parallelogram is 9 units².

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Answer:

-115/69

Step-by-step explanation:

12(6x + 10) + x = 9x + 5(1 - x)

72x + 120 + x = 9x + 5 - 5x

73x + 120 = 4x + 5

69x = 5 - 120

69x = -115

x = -115/69

One, two, three, four, five, six, seven, eight, nine, ten, eleven, twelve, thirteen, fourteen, fifteen, sixteen, seventeen, eighteen, and nineteen/Uno, dos, tres, cuatro, cinco, seis, siete, ocho, nueve, diez, once, doce, trece, catorce, quince, dieciséis, diecisiete, dieciocho y diecinueve

Answer:

-3

Step-by-step explanation:

using pemdas, we first divide -18 by 6 to get -3. next, we subtract -3 from -6: -6-(-3)=-6+3=-3

Answer: -3

Step-by-step explanation:

For this, you want to use PEDMAS

This is Parentheses, Exponents, Division, Multiplication, Addition, and Subtraction. The first step would be to divide -18/6. This will come out to -3

Answer:

no its not a proportion

Step-by-step explanation:

because the line has to be straight unless the graph is scrap

Answer:

"Yes, it is a proportional relationship because the graph is a straight line"

Step-by-step explanation:

Your welcome ^^

Usando técnicas de conteo, se encuentra que

1. Un cliente puede ordenar una comida de 784 formas.

2. 420 grupos de 4 letras se pueden formar con las letras de la palabra TECNICA.

3. 840 números de 4 dígitos se pueden formar con los primeros 7 números naturales.

4. 10 partidos distintos se pueden realizar.

5. Pueden colocarse de 3,628,800 formas.

6. 1260 señales distintas pueden indicarse.

Item 1:

La técnica usada es el principio fundamental de conteo, que afirma que si hay n cosas, cada una con [tex]n_1, n_2, \cdots, n_n[/tex] maneras de seren realizadas, el número total de maneras de ser realizadas es:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

En este problema, [tex]n_1 = 14, n_2 = 8, n_3 = 7[/tex], por eso:

[tex]T = 14 \times 8 \times 7 = 784[/tex]

Un cliente puede ordenar una comida de 784 formas.

Item 2:

El orden es importante, ya que TECN es una palabra diferente de NCET, por lo tanto, la fórmula de permutaciones se usa para resolver este problema.

Fórmula de permutaciociones:

El número de permutaciones de x elementos en un conjunto de n elementos es dada por:

[tex]P_{n,x} = \frac{n!}{(n - x)!}[/tex]

En este problema, 4 letras de 7, enconteces:

[tex]P_{7,4} = \frac{7!}{3!} = 840[/tex]

La letra C se repite dos veces, o sea:

[tex]T = \frac{P_{7,4}}{2} = \frac{840}{2} = 420[/tex]

420 grupos de 4 letras se pueden formar con las letras de la palabra TECNICA.

Item 3:

Permutaciones de 4 dígitos de 7, sin repeticiones, o sea:

[tex]P_{7,4} = \frac{7!}{3!} = 840[/tex]

840 números de 4 dígitos se pueden formar con los primeros 7 números naturales.

Item 4:

El orden no es importante, ya que Time 1 x Time 2 es la misma partida de Time 2 x Time 1, por lo tanto, la fórmula de combinaciones se usa para resolver este problema.

Fórmula de combinaciones:

El número de combinaciones de x elementos en un conjunto de n elementos es dada por:

[tex]C_{n,x} = \frac{n!}{x!(n - x)!}[/tex]

En este problema, combinaciones de 2 elementos de un conjunto de 5, entonces:

[tex]C_{5,2} = \frac{5!}{2!3!} = 10[/tex]

10 partidos distintos se pueden realizar.

Item 5:

El número de arreglos de n elementos viene dado por

[tex]A_n = n![/tex]

En este problema, arreglo de 10 elementos, o sea:

[tex]A_{10} = 10! = 3628800[/tex]

Pueden colocarse de 3,628,800 formas.

Item 6:

El número de arreglos de n elementos, con repeticiones de [tex]n_1, n_2, \cdots n_n[/tex] elementos viene dado por

[tex]A_n^{n_1,n_2,\cdots,n_n} = \frac{n!}{n_1!n_2! \cdots n_n!}[/tex]

En este problema, [tex]n = 9, n_1 = 3, n_2 = 2, n_3 = 4[/tex], por eso:

[tex]A_9^{3,2,4} = \frac{9!}{3!2!4!} = 1260[/tex]

1260 señales distintas pueden indicarse.

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35.6 355⅝5555555555555555555545455555555

Step-by-step explanation:

OOOO

BYE

Answer:

5 hours

Step-by-step explanation:

The distance Pilar's bike travel when the wheel makes  10 complete rotations is 753.6 inches

Since the wheel is circular in nature, we will take the circumference to determine the distance travelled for 1 revolution

Circumference of a circle = πr²

r is the radius of the wheel.

Given that d = 24 in, r = 24/2 = 12in

C = 2(3.14)(12)

C = 75.36 in

Hence the distance completed by 1 revolution is 75.36. If Pilar's bike makes 10 revolutions, hence the required distance will be:

D = 10 * 75.36

D = 753.6in

Hence the distance Pilar's bike travel when the wheel makes  10 complete rotations is 753.6 inches

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Answer:

Answer is C, 40

Step-by-step explanation:

(100)-(60)

Answer:

I don't see any statements, but Tamara paid less. She paid 19.8 after the discount. David spent a little more at 19.95

y=3/4x+1/4

I hope this helped :)

Answer:

Step-by-step explanation:

two points on the line are (-3,-2) and (5,4)

slope=(4-(-2))/(5-(-3)=(4+2)/(5+3)=6/8=3/4

eq. of line is

y+2=3/4(x+3)

4y+8=3x+9

4y=3x+9-8

4y=3x+1

y=3/4 x+1/4