How many moles of oxygen, are needed to react with excess propane, C3H8, to produce 15.0 moles of water?

Answer:

Metal, Copper, and Alluminum

Explanation: It is what it is

Answer:

Explanation:

Chemicals to produce NH₃ ( ammonia )

1 ) Ammonium chloride ( NH₄Cl )

2 ) Calcium hydroxide  Ca(OH)₂

2NH₄Cl + Ca(OH)₂ = CaCl₂ + 2NH₃ + 2H₂O.

Net Ionic equation

2NH₄⁺ ( aq ) + 2OH⁻ (aq )  = 2NH₃(g)  + 2H₂O .

Answer:

8.279

Explanation:

The pH can be determined by hydrolysis of a conjugate base of weak acid at the equivalence point.

At the equivalence point, we have

[tex]$n_{NaOH}=n_{HNO_2}$[/tex]

           = 25.00 x 0.200

           = 5.00 m-mol

           = 0.005 mol

Volume of the base that is added to reach the equivalence point is

[tex]$\frac{0.005}{1.00} \times 1000= 5.00 \ mL$[/tex]

Number of moles of [tex]$NO^-_{2}=n_{HNO_2}$[/tex]

                                           = 0.005 mol

Volume at the equivalence point is 25 + 5 = 30.00 mL

Therefore, concentration of [tex]$NO^-_{2}= \frac{5}{30}$[/tex]

                                                        = 0.167 M

Now the ICE table :

            [tex]$NO^-_2 + H_2O \rightarrow HNO_3 + OH^-$[/tex]

I (M)       0.167                   0            0

C (M)         -x                      +x          +x

E (M)      0.167-x                  x           x

Now, the value of the base dissociation constant is ,

[tex]$K_w=K_a \times K_b$[/tex]            [tex]$(K_w \text{ is the ionic product of water })$[/tex]

[tex]$K_b =\frac{K_w}{K_a}$[/tex]

[tex]$K_b =\frac{1 \times 10^{-14}}{4.6 \times 10^{-4}}$[/tex]

    = [tex]$2.174 \times 10^{-11}$[/tex]

Base ionization constant, [tex]$K_b = \frac{\left[HNO_2\right] \left[OH^- \right]}{\left[NO^-_2 \right]}$[/tex]

[tex]$2.174 \times 10^{-11}=\frac{x^2}{0.167 -x}$[/tex]

[tex]$x= 1.9054 \times 10^{-6}$[/tex]

So, [tex]$[OH^-]=1.9054 \times 10^{-6 } \ M$[/tex]

pOH =- [tex]$\log[OH^-]$[/tex]

       = [tex]$- \log(1.9054 \times 10^{-6} \ M)$[/tex]

        =5.72

Now, since pH + pOH = 14

           pH = 14.00 - 5.72

                = 8.279

Therefore the ph is 8.279 at the end of the titration.

Titration is a chemical process used to determine the concentration of an unknown sample from the known sample. At the equivalence point, the pH is 8.279.

In titration, the point at which the titrant neutralizes the unknown analyte solution is called the equivalence point.

The moles of equivalence point of sodium hydroxide and nitrous acid are:

[tex]\begin{aligned}\rm n_{NaOH} &= \rm n _{HNO_{2}}\\\\&= 25.00 \times 0.200\\\\&= 0.005 \;\rm mol\end{aligned}[/tex]

The volume of the added base is 5.00 mL.

The moles of nitrogen dioxide are 0.005 moles and the volume at the equivalence point is 30 mL.

The molar concentration of nitrogen dioxide will be, 0.167 M.

From the ICE table, the base dissociation constant is calculated as:

[tex]\begin{aligned}\rm K_{w} &= \rm K_{a} \times K_{b}\\\\\rm K_{b} &= \dfrac{1 \times 10^{-14}}{4.6 \times 10^{-14}}\\\\&= 2.174 \times 10^{-11}\end{aligned}[/tex]

The ionization constant of the base is given as,

[tex]\begin{aligned}\rm K_{b} &= \rm \dfrac{[HNO_{2}][OH^{-}]}{[NO_{2}^{-}]}\\\\2.174 \times 10^{-11} &= \rm \dfrac{x^{2}}{0.167- x}\\\\&= 1.905 \times 10^{-6} \end{aligned}[/tex]

Now, pOH is calculated as:

[tex]\begin{aligned} \rm pOH &=\rm - log [OH^{-}]\\\\&= \rm -log (1.905 \times 10^{-6})\\\\&= 5.72\end{aligned}[/tex]

The pH of the titration is calculated as:

[tex]\begin{aligned} \rm pH + pOH &= 14\\\\\rm pH &= 14.00 - 5.72\\\\&= 8.279\end{aligned}[/tex]

Therefore the pH is 8.27.

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Answer:

-7.6755

Explanation:

Calculate

I calculate it

Answer:

0.07 M

Explanation:

Given data:

Volume of NaOH = 50.0 mL

Molarity of NaOH = 0.2 M

Volume of H₃PO₄ =  50.0 mL

Concentration of H₃PO₄ = ?

Solution:

3NaOH + H₃PO₄    →   Na₃PO₄  +  3H₂O

Number of moles of NaOH react:

Molarity = number of moles / volume in L

0.2 M = number of moles = 0.05 L

Number of moles = 0.01 mol

Now we will compare the moles of NaOH  with  H₃PO₄ .

          NaOH        :       H₃PO₄

             3             :          1

           0.01          :       1/3×0.01 = 0.0033

Concentration of H₃PO₄:

Molarity = number of moles / volume in L

Molarity = 0.0033 mol / 0.05 L

Molarity = 0.07 M

Answer:

A.) 0.07M

Explanation:

I got it right in class!

Hope this Helps!! :))

Answer:

C

Explanation:

CO2 is a molecule because it is compose of atoms which made it a molecule, it can also be call a compound.

Answer:

I believe it is c. Molecule, Pure compound

Explanation:

this is because it is composed of atoms which create molecule.

Answer:

I think it's b because I heard the others

The correct answer is option A: acetone.

For a substance to be classified as an alcohol it must posses the -OH functional group. Compounds that posses this -OH functional group usually have the ending -ol.

Acetone is a ketone, this is evidenced by the ending -one. It has the functional group -C=O.

Hence, acetone is not alcohol. The structure of acetone is shown in the image attached.

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Answer:

[tex][Cu^{2+}]=0.041 M[/tex]

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

[tex][Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}[/tex]

[tex][Cu^{2+}]=0.041 M[/tex]

Best regards!

Answer: One of the foods was sour and one was sweet

Explanation:

The sweet one has changed because it has more sugar then the sour one, It either got moldy or melted.

Answer:

B

Explanation:

Answer:

this is not chemistry

Explanation:

not chemistry

The pascal is sorthand for N/m^2

Answer:

5.7 moles of O2

Explanation:

We'll begin by writing the balanced decomposition equation for the reaction. This is illustrated below:

2KClO3 —> 2KCl + 3O2

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Next, we shall determine the number of mole of O2 produced by the reaction of 3.8 moles of KClO3.

Since 100% yield of O2 is obtained, it means that both the actual yield and theoretical yield of O2 are the same. Thus, we can obtain the number of mole of O2 produced as follow:

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Therefore, 3.8 moles of KClO3 will decompose to produce = (3.8 × 3)/2 = 5.7 moles of O2.

Thus, 5.7 moles of O2 were obtained from the reaction.

Answer:

[Ne] 3s² 3p¹

Explanation:

Answer:

so here is the answer

Explanation:

Kinetic is the answer.

Answer:

Mass ratio: 71:112

Atomic ratio: 2:7

Explanation:

1. To get the mass ratio of of the compound Cl2O7, the following steps are followed:

- The atomic mass of Cl = 35.5g/mol, O = 16g/mol

- The mass of each element in the compound is as follows:

Cl2 = 35.5(2) = 71g

O7 = 16(7) = 112g

The mass ratio is the ratio of one mass of an element to another in the compound, hence, the mass ratio is 71:112

- The molar mass of the compound, Cl2O7, is determined:

71 + 112 = 183g/mol

- The mass percent of each element is determined by dividing the mass of each element present by the Molar Mass:

Cl = 71/183 = 0.3879 × 100 = 38.8%

O = 112/183 = 0.612 × 100 = 61.2%

2. Atomic ratio is the ratio of one atom in a molecule to another. It can be calculated this:

In Cl2O7, there are 9 total atoms (2 atoms of Cl + 7 atoms of oxygen).

Hence, that atomic ratio of Cl to oxygen in Cl2O7 is 2:7

The mass ratio of Cl₂O₇ is 71:112 and atomic ratio of Cl₂O₇ is 2:7.

Mass ratio define as the ratio of the masses of constitute particles of the compound and atomic ratio is define as the ratio of the numbers of atoms present in that compound.

Given compound = Cl₂O₇

Mass of chlorine = 2×35.5 = 71g

Mass of oxygen = 7×16 = 112g

Mass ration of Cl₂O₇ is 71:112

And atomic ratio of Cl₂O₇ is 2:7

Hence, 71:112 is the mass ratio and atomic ratio is 2:7.

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Answer:

Gas D

Explanation:

liters at 30 °C

Answer:

a. 0.17 M

b. 0.066 M

Explanation:

a.

Step 1: Given and required data

Pressure of CO₂ (P): 5.0 atm

Henry's law constant for CO₂ (k): 3.3 × 10⁻² M atm⁻¹

Step 2: Calculate the molar concentration (C) of CO₂

We will use Henry's law.

C = k × P

C = 3.3 × 10⁻² M atm⁻¹ × 5.0 atm

C = 0.17 M

b.

Step 1: Given and required data

Pressure of CO₂ (P): 2.0 atm

Henry's law constant for CO₂ (k): 3.3 × 10⁻² M atm⁻¹

Step 2: Calculate the molar concentration (C) of CO₂

We will use Henry's law.

C = k × P

C = 3.3 × 10⁻² M atm⁻¹ × 2.0 atm

C = 0.066 M

Answer:

a. 100%

b. 133%

c. 300%

Explanation:

To find yield first we need to determine theoretical yield converting each reactant to moles and find limitng reactant for each reaction:

Moles A:

4.5g * (1mol / 150g) = 0.03 moles

Moles B:

4.0g * (1mol / 100g) = 0.04 moles

a. For a complete reaction of 0.03 moles of A are needed:

0.03 moles A * (1 mole B / 3 moles A) = 0.01 moles of B

As there are 0.04 moles of B, A is limiting reactant.

Theoretical moles and mass of C are:

0.03 moles A * (1 mole C / 3 moles A) = 0.01 moles of C.

0.01 moles of C * (200g / mol) = 2g are produced.

Yield is:

2g / 2g * 100 = 100%

b. For a complete reaction of 0.03 moles of A are needed:

0.03 moles A * (3 mole B / 2 moles A) = 0.045 moles of B

As there are 0.04 moles of B, B is limiting reactant.

Theoretical moles and mass of C are:

0.04 moles B * (1 mole C / 3 moles B) = 0.0133 moles of C.

0.0133 moles of C * (200g / mol) = 2.67g are produced.

Yield is:

2.67g / 2g * 100 = 133%

c. For a complete reaction of 0.03 moles of A are needed:

0.03 moles A * (1 mole B / 1 moles A) = 0.03 moles of B

As there are 0.04 moles of B, A is limiting reactant.

Theoretical moles and mass of C are:

0.03 moles A * (1 mole C / 1 moles A) = 0.03 moles of C.

0.03 moles of C * (200g / mol) = 6g are produced.

Yield is:

6g / 2g * 100 = 300%

Answer:

I think that gravity can be considered a force.

Explanation:

As the object falls, it moves faster and faster. Gravity is considered a universal force because it acts between any two masses anywhere in the universe. For example, there is a gravitational pull between the Sun and the Moon. Even small masses attract one another.

Hope this helped! :)

Answer:

Oxygen and simple sugars.

Explanation:

Water, sunlight and carbon dioxide is taken in to photosynthesise and the product would be oxygen that is breathed out through the stomata and simple sugars that are used as fuel for the plant.  

Answer:

a. the lithosphere

Explanation:

google

Answer:

λ = 5.68×10⁻⁷ m

Explanation:

Given data:

Energy of photon = 3.50 ×10⁻¹⁹ J

Wavelength of photon = ?

Solution:

E = hc/λ

h = planck's constant = 6.63×10⁻³⁴ Js

c = 3×10⁸ m/s

Now we will put the values in formula.

3.50 ×10⁻¹⁹ J =  6.63×10⁻³⁴ Js × 3×10⁸ m/s/ λ

λ =  6.63×10⁻³⁴ Js × 3×10⁸ m/s / 3.50 ×10⁻¹⁹ J

λ =  19.89×10⁻²⁶ J.m / 3.50 ×10⁻¹⁹ J

λ = 5.68×10⁻⁷ m

Answer:

4.2x10⁻⁴ M or 0.032 g/L.

Explanation:

Hello!

In this case, for solubility product problems, we apply the concepts of equilibrium because an insoluble salt is ionized until a certain point limited by the solubility product constant, Ksp. Thus, we first write the ionization reaction of aluminum hydroxide at equilibrium:

[tex]Al(OH)_3(s)\rightleftharpoons Al^{3+}(aq)+3OH^-(aq)[/tex]

Next, we write the corresponding equilibrium expression:

[tex]Ksp=[Al^{3+}][OH^-]^3[/tex]

Which in terms of [tex]x[/tex], the reaction extent, is:

[tex]Ksp=x*(3x)^3[/tex]

Because [tex]x[/tex] also represents the molar solubility of aluminum hydroxide at the considered temperature; now, we can write:

[tex]8.1x10^{-13}=x*(3x)^3[/tex]

Which can be solved for x as follows:

[tex]x=\sqrt[4]{\frac{8.1x10^{-13}}{27} } \\\\x=4.2x10^{-4}M[/tex]

Thus, the solubility is 4.2x10⁻⁴ M or mol/L and in g/L we have:

[tex]4.2x10^{-4}\frac{mol}{L}*\frac{78g}{1mol} =0.032\frac{g}{L}[/tex]

Best regards!

Answer:

A

Explanation:

as the temperature and speed is higher pressure will be higher

as the temperature is higher particles will be more active

and as speed is they will collide with more force

so the pressure will be higher in container B

Answer:

". It will mark the time since humans began altering Earth. Starting about 10,000 years ago, it is tentatively being called the Anthropocene."

i dont know if tht will help

100,000 years in the geologic history of Earth would be considered

as Anthropocene .

The first and most recent geological epoch in Earth's history when human life began to have a noticeable influence on the planet's climate, including ecosystems, and ecosystems, is referred to as the Anthropocene Epoch. This term refers to an undefined unit of geologic time.

It would be the first time since people started changing the planet. It must be tentatively referred to as the Anthropocene and began around 10,000 years ago.

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Answer:

Explanation:

29.4 mL of nitric acid having molarity of .187M reacts with 22.7 mL of potassium hydroxide .

moles contained in nitric acid solution

= .0294 x .187 moles

= 5.5 x 10⁻³ moles

This must have been reacted with same amount of moles of base

moles of sodium hydroxide in 22.7 mL of solution = 5.5 x 10⁻³ moles

molarity of base solution = 5.5 x 10⁻³ / 22.7 x 10⁻³

= .24 M .