How many milliliters of 0.100 M HClO4 solution are needed to neutralize 50.00 mL of 0.0832 M NaOH?

Answers

Answer 1
HClO4 +NaOH -----> NaClO4 + H2O
moles of NaOH = (0.0832 x 50 ) /1000= 4.16 x10^-3 moles
since the mole ratio of HClO4 to NaOH is 1:1 the moles of HClO4 is also 4.16 x 10^-3 moles

volume of HClO4 is therefore = moles/ molarity
that is 4.16 x 10^-3mol/ 0.167 mol/L= 0.0249L
multiply by 1000 to convert to ml
0.0249 x 1000= 24.9 ml
Answer 2

The milliliters of 0.100 M HClO4 solution are needed to neutralize 50.00 mL of 0.0832 M NaOH is 24.9 ml.

What is neutralization?

Neutralization is defined as a chemical reaction in which an acid and a base quantitatively react with one another. Because it determines how acidic or basic a solution is, a solution's pH is crucial. The interaction of H+ ions and OH- ions produces water in a neutralization reaction, which occurs when an acid and a base react to form water and a salt.

Since the mole ratio of HClO4 to NaOH is 1:1, the moles of HClO4 are equal to 4.16 x 10-3 moles.

The moles of NaOH are equal to (0.0832 x 50) /1000.

Therefore, the volume of HClO4 is equal to the moles/molarity, which is 4.16 x 10-3mol/ 0.167 mol/L= 0.0249L.

This amount is then multiplied by 1000 to get ml: 0.0249 x 1000 = 24.9 ml.

Thus, the milliliters of 0.100 M HClO4 solution are needed to neutralize 50.00 mL of 0.0832 M NaOH is 24.9 ml.

To learn more about neutralization, refer to the link below:

https://brainly.com/question/27891712

#SPJ2


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yo fm on ig chs_luucy. ill give u brainleist .

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Alright bet! Say less

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Please Help :))) "A solution with a concentration of 5.7 x 10^-7M would be considered..."

Answers

Answer:

The solution is acidic.

Explanation:

To know which option is correct, we shall determine the pH of the solution. This can be obtained as follow:

Concentration of Hydrogen ion [H⁺] = 5.7×10¯⁷ M

pH =?

pH = –Log [H⁺]

pH = –Log 5.7×10¯⁷

pH = 6.2

pH scale reads as follow:

0 to 6.9 => Acidic

7 => Neutral

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The pH of the solution (i.e 6.2) falls between 0 and 6.9 which indicates acidic.

Therefore, the solution is acidic.

What is the pressure of nitrogen in atmospheres of a sample that is at 516.0 mm hg?
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Answers

Answer:

nitrogen in atmospheres of a sample is 0.679

The half-life of 3H (H-3) is 12 years. About how long does it take for 127/128 of a sample of that radionuclide to decay? (Hint: this means only 1/128 are left)
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Answers

Answer:

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Explanation:

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Answer:

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Answers

Answer:

pH is the number given to a substance of how powerful it is before 7 or beyond 7.

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Explanation:

Pls mark BRAINLIEST

Answer:

August 15, 1971

The nine sheikhdoms still had not agreed on terms of union by 1971, however, prompting Bahrain to declare itself fully independent on August 15, 197

1.A solution has a pH of 5, calculate the pOH, [H+], and [OH-]. Classify the solution as an acid, base, or neutral solution.

it's an acid

Explanation:

I hope that this helps

A sample of methane gas, CH4, occupies 3.25 L at temperature of 19.0 o C. If the pressure is held constant, what will be the temperature be if the volume expands to 10.00 L?

Answers

Answer:

625.46 °C

Explanation:

We'll begin by converting 19 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 19 °C

T(K) = 19 °C + 273

T(K) = 292 K

Next, we shall determine the Final temperature. This can be obtained as follow:

Initial volume (V₁) = 3.25 L

Initial temperature (T₁) = 292 K

Final volume (V₂) = 10 L

Final temperature (T₂) =?

V₁/T₁ = V₂/T₂

3.25 / 292 = 10 / T₂

Cross multiply

3.25 × T₂ = 292 × 10

3.25 × T₂ = 2920

Divide both side by 3.25

T₂ = 2920 / 3.25

T₂ = 898.46 K

Finally, we shall convert 898.46 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 898.46 K

T(°C) = 898.46 – 273

T(°C) = 625.46 °C

Therefore the final temperature of the gas is 625.46 °C

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Answers

Answer:

60.5 L

Explanation:

If the gas temperature is constant, we can use Boyle's law:

P1V1 = P2V2

V2 = P1V1 / P2

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Answers

Answer:

3.36 M

Explanation:

Step 1: Given data

Mass of CuSO₄.6H₂O (m): 25.2 gMolar mass of CuSO₄.6H₂O (M): 267.72 g/molVolume of solution (V): 28.0 mL (we will assume it is equal to the volume of water)

Step 2: Calculate the moles (n) of CuSO₄.6H₂O (solute)

We will use the following expression.

n = m/M

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Answer:

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Answers

Answer:

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Explanation:

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hope this is the answer you are looking for

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