40,840.7 kilometers the space shuttle have to travel to complete one orbit. In terms of a circle, this distance is termed as the circumference of the circle.
The circumference of a circle is the length measured around its edge. The diameter of a circle is the distance from the center to the outside.
Here we need to find the distance of the space shuttle that completed one circle, ie, the circumference of the orbit. The Circumference or distance covered by the space shuttle can be denoted by [tex]C_{SS}[/tex] and can be calculated by application of the below formula,
[tex]C_{SS}[/tex] = 2πr
where r is the radius of earth ie, 6500Km
Therefore, the equation becomes:
[tex]C_{SS}[/tex] = 2×π×r
= 2×π×6500
=40,840.7
So, the kilometer required to travel is 40,847.7Km
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What is the impulse of a car hitting another car if it's initial velocity was 50m/s
and it's velocity after hitting it is 4.4m/s? The car weighs 2168kg.
J=A P
AP=mvf-mvi
The impulse of the car after hitting is 98860.8 kg.m/s
In physics, the term "impulse" is used to characterize or measure the impact of force operating gradually to alter an object's motion. It is often stated in Newton-seconds or kilograms per second and is denoted by the symbol J.
J = m ( v-u)
where, m = 2168 kg
u = 50 m/s
v = 4.4 m/s
J = 2168 ( 4.4 - 50)
J = 2168(45.6)
J = 98860.8 kg.m/s
since the final velocity is decreasing the impulse is a vector term thus a negative sign will also be included in this.
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The cross product of two vectors (X and Y) is a negative vector when the angle between them is:
A. 0
B. 90
C. 180
D. 270
Answer:
C. 180
Explanation:
Answer:
Explanation:
The cross product:
[ a × b ] = | a | · | b | · sin α
sin α < 0 if α ∈ (180°, 360°)
Answer:
D. 270°
A cyclist travels a distance S from A to B consisting of three segments: s = S1 + $2 + $3, Time and speed over the segments are t1, t2, t3 and v1= 20(km/h), v2 = 15(km/h), V3= 10(km/h). Calculate the average speed over the distance s. Consider two cases: a) s1=s2=s3 b) t1=t2=t3
The average speed over the distance s consisting of three segments s1, s2, and s3 in first case a) s1 = s2= s3 is 13.85 km/h and in the second case b) t1 = t2 = t3 is 15 km/h.
In the first case where the distance for three intervals is the same a) s₁ = s₂ = s₃, the average speed for three segments is calculated by the formula:
Average speed = 3 ÷ ( 1/v₁ + 1/v₂ +1/v₃)
Average speed = 3 ÷ ( ¹/₂₀ + ¹/₁₅ + ¹/₁₀)
Average speed = 13.85 km/h
In the second case where the time taken for all three intervals is the same b) t₁ = t₂ = t₃, the average speed for three segments is calculated by the formula:
Average speed = (v₁ + v₂ +v₃) ÷ 3
Average speed = (20 + 15 + 10) ÷ 3
Average speed = 15 km/h
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It takes a continent approximately 250,000,000 years to move half-way around Earth, a distance of about 19,200 km or 1,920,000,000 cm. The speed of the continent in what per what can be found by dividing 1,920,000,000 cm by 250,000,000 years.
The speed of the continent is found to be 7.68 centimeters per hour when 1920000000cm is divided by 250000000years.
The distance travelled by the continent is 1920000000cm.
The time taken by the continent to complete its path is 250000000.
The speed S of the body,
S = D/T
Where,
D is the distance travelled by the body,
T is the time taken by the body to cover that distance.
The speed S of the continent is,
S = D/T
S = 1920000000cm/250000000year
S = 7.68 cm/year
Hence, the speed of the continent is 7.68 centimeters per year.
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The outer ear _____ sound waves
According to the research, the correct term to complete the statement is collect. The outer ear collects sound waves.
What is the outer ear?It is a structure that captures or collects sound or sound vibrations before channeling them to the middle ear.
In this sense, it is made up of the pinna that projects from the side of the head and the external auditory meatus that automatically amplifies sounds that pass inward to the tympanic membrane.
Therefore, we can conclude that the outer ear captures sound waves and conducts them to the middle ear, thus the correct term is collect.
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How is the direction of the velocity of a satellite differ from the direction of its acceleration?
PLEASE HELP!!!!!
The direction of the velocity of a satellite differ from the direction of its acceleration by an angle of 90° as they act perpendicular to each other.
In an orbital motion, the acceleration of the object is always directed towards the center of the orbit. This acceleration is called as centripetal acceleration. It is denoted by [tex]a_{c}[/tex].
[tex]a_{c}[/tex] = v² / r
In an orbital motion, the velocity of the object is always tangential to the orbit. It can be calculated in two ways,
v = 2 π r / T
v = r ω
Therefore, the direction of the velocity of a satellite differ from the direction of its acceleration by an angle of 90°.
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If the slope of a position versus time graph is negative, what does that imply about the motion of an object? A. The object has a negative acceleration. B. The object turned around. C. The object is moving in the negative direction. D. All of the above
ANSWER
A. The object has a negative velocity
EXPLANATION
We want to describe the slope of a position-time graph that is negative.
If the slope of a position-time graph is negative, it implies that the velocity is also negative. In other words, as time increases, the velocity also decreases.
As velocity decreases, it implies that the acceleration also decreases.
Therefore, we have that the acceleration of the object is negative.
The answer is option A.
The plow was an important invention for the Sumerian civilization because it:
A. made it easier for farmers to prepare land for farming.
B. simplified communication with other cultures.
C. allowed important information to be recorded.
D. protected city-states from foreign invaders.
I am in the middle of the test help pls
The plow was an important invention for the Sumerian civilization because it made it easier for farmers to prepare land for farming.
The plow made farming more efficient for the Sumerians, as people no longer had to waste time planting food by hand. The cart allowed people to carry goods back and forth from different civilizations in a much easier way as people did not have to carry the goods on their backs.
It is estimated that the ancient Sumerians invented the plow. The plow was designed to utilize domestic animals as a means of easing the workload on farmers. Oxen were harnessed to a wooden plow and pulled it through the fields to loosen the soil for easier planting of crops.
Plow, also spelled plough, most important agricultural implement since the beginning of history, used to turn and break up soil, to bury crop residues, and to help control weeds.
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how fast is the angle of depression of the telescope changing when the boat is 190 meters from the shore
ANSWER:
- 0.01943 rad/sec
STEP-BY-STEP EXPLANATION:
The first thing is to make a drawing of what is mentioned in the statement, it would be the following:
Now, we have the following information:
[tex]\begin{gathered} \frac{dy}{dt}=15\text{ m/s} \\ x=50\text{ m} \\ y=190\text{ m} \end{gathered}[/tex]In this right angle triangle formed by telescope of the boat, e can apply the tangent trigonometric ratio, like this:
[tex]\begin{gathered} \tan \theta=\frac{x}{y} \\ \text{ replacing} \\ \theta=\tan ^{-1}\mleft(\frac{x}{y}\mright) \end{gathered}[/tex]Now, we implicitly derive with respect to t:
[tex]\begin{gathered} \frac{d}{dt}(\theta)=\frac{d}{dt}(\tan ^{-1}(\frac{x}{y})) \\ \frac{d}{dt}(\theta)=\frac{1}{1+(\frac{x}{y})^2}\cdot\frac{d}{dt}(\frac{x}{y}) \\ \frac{d}{dt}(\theta)=\frac{y^2}{x^2+y^2}\cdot x\cdot(-\frac{1}{y^2}\cdot\frac{dy}{dt}) \\ \frac{d}{dt}(\theta)=\frac{-x}{x^2+y^2}(\frac{dy}{dt}) \\ \text{ replacing} \\ \frac{d}{dt}(\theta)=\frac{-50}{50^2+190^2}\cdot(15) \\ \frac{d}{dt}(\theta)=-0.01943 \end{gathered}[/tex]The angle of depression is changing at a rate of -0.01943 rad/sec when the boat is 190 m from the shore
An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a
mass of 5.8x 104 kg, and the force causes its speed to change from 6800 to 5600m/s. (a) What is the work done by the force? (b) If the
asteroid slows down over a distance of 2x 106 m determine the magnitude of the force.
The work done on the asteroid by the constant force is 4.06 × 10¹¹ joules and the force experienced by the asteroid is 1.89 × 10⁵ newtons
what is work energy theorem?
work energy theorem is an important phenomenon in physics which states that the change in kinetic energy is equal to the work done by the object.
This law is basic part of conservation of energy.
what is newtons law of motion?
Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be paraphrased as follows: A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force.
given:
mass of the asteroid = 5.8 x 10⁴ kg
initial speed of the asteroid v₁ = 6800m/s
final speed of the asteroid v₂ = 5600 m/s
displacement of the asteroid = 2 × 10⁶ meters
a)
using work energy theorem for the asteroid we get,
work done = change in kinetic energy
work done = 1/2 × m × (v₂) ² - 1/2 × m × (v₁) ²
work done by the force on the asteroid is = 1/2 × 5.8 x 10⁴ (1.4 × 10⁷)
work done by the force on the asteroid is = 4.06 × 10¹¹ joules
b)
first, we will have to find the acceleration of the asteroid,
using newtons third law of motion we get,
a = 14/4
a = 3.5 m/s²
therefore, the force can be calculated using relation f = m × a
here,
m is mass
a is acceleration
therefore, the force on the asteroid is = 5.8 x 10⁴ × 3.5
the force on the asteroid is = 1.89 × 10⁵ newtons
therefore, the work done on the asteroid by the constant force is 4.06 × 10¹¹ joules and the force experienced by the asteroid is 1.89 × 10⁵ newtons
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Question 11
5 pts
Gas Laws: A balloon is carefully filled with one breath of air (about 500ml) underwater at
a depth of 100ft, then tied shut. At this depth, the balloon is under 4 atmospheres of
pressure. Assuming negligible compression by the rubber of the balloon, what is the
volume of the air (in m³) once the balloon rises to the surface of the water and
experiences 1 atm of pressure? Modify the Ideal Gas Law to solve this conservation
problem.
1 Liter 0.001 Cubic Meter
1 atm = 1.01x 105 Pascals
The volume of the gas once it reaches the surface of water is 2 liters.
The volume of the air in balloon at depth of 100ft (30m) is 500ml.
The pressure at this point is 4 atm.
Assuming that the balloon have no compression by rubber of balloon the volume of air at the water surface is V.
The pressure at the surface of water is 1 atms.
As we know, from the ideal gas equation,
PV = nRT
Where,
P is the Pressure of gas,
V is the volume of the gas,
n is the number of moles,
R is the gas constant whose value is 0.082057 L atm mol-1 K-1,
T is the temperature.
Assuming that the temperature is constant,
We know,
PV = nRT
All quantities on the right side are constants,
So, we can write,
P₁V₁ = P₂V₂
Putting all the the values,
4(0.5) = 1V₂
V₂ = 2 Liters.
The volume of the air at the surface is 2 liters.
1 liter = 0.001 m
Hence,
2 liters = 0.002 m³
So the volume of air at the surface is 0.002m³.
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The cubic expansivity of mercury is 1.8×10^-4K^-1 and the linear expansivity of glass is 8.0×10^-6K^-1, calculate the apparent expansivity of mercury in a glass container?
Therefore,
[tex]Apparent\text{ cubic expansivity=}real\text{ cubic expansivity - cubic expansivity of the container}[/tex][tex]\begin{gathered} \text{ cubic expansivity of the container =3(}8.0\times10^{-6})=24\times10^{-6}=2.4\times10^{-5} \\ \text{note we converted linear expansivity to cubic expansivity} \end{gathered}[/tex]Finally,
[tex]\text{Apparent cubic expansivity=}1.8\times10^{-4}-2.4\times10^{-5}=1.56\times10^{-4}K^{-1}[/tex]**NEED USEFUL ANSWER ASAP, H.W QUESTION**
Given that hotter blackbodies produce more energy than cooler blackbodies, why do cooler red giants have much higher luminosities than much hotter white dwarfs?
Given that hotter blackbodies produce more energy than cooler blackbodies, cooler red giants have much higher luminosities than much hotter white dwarfs.
The hotter blackbodies emits more light as compared to the cooler blackbodies over all the wavelength. A blackbody emits light over all wavelength. the red giant is a star , hydrogen is fused to helium core to stat the fusion reactions. this hydrogen fusion caused the star to expand. the sun becomes red giant it will swell up to size of earth orbit. This gives a red color and make red giant much hotter. while the white dwarf comes after the red giant . white dwarf is also very hot but it is not hot enough to star fusion reaction in carbon and oxygen.
Thus, Given that hotter blackbodies produce more energy than cooler blackbodies, cooler red giants have much higher luminosities than much hotter white dwarfs.
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what is the difference between these two formulas [tex]fc = \frac{m(v {}^{2}) }{r} [/tex][tex]ac = \frac{v {}^{2} }{r} [/tex]and how would I apply them to a promblem?
One is centripetal acceleration (ac) and the other one is centripetal force (fc)
Since = F = m* a
F = force
m= mass
a= acceleration
For centripetal force (Fc), we use centripetal acceleration
Fc= m * ac
ac= centripetal acceleration = v^2 / r
r= radius
v= linear velocity
So, in the end, we have:
Fc = m * v^2 /r
You can apply the to find the Centripetal force of an object with a certain mass, that negotiates a certain radius curve, with a certain speed.
A football blocking sled has a mass of roughly 100 kg. If a football player applies a force of 500 N to the sled, and there is a 350 N frictional force acting on the sled, what is the acceleration of the sled?
The the acceleration of the sled of mass 100 Kg will be 1.5 m/s².
What is Friction?A drag is force that opposes the motion of an object by acting in the direction opposite to its motion. It is of two types namely - Static friction and kinetic friction. The static friction is given by - F[S] = μ[s] x η and the kinetic friction is given by F[K] = μ[k] x η.
Given is a football blocking sled which has a mass of roughly 100 kg. A football player applies a force of 500 N to the sled, and there is a 350 N frictional force acting on the sled.
Assume that the force applied by the player is - F[P] = 500 N and the force of friction is - F = 350 N.
Now, for the motion of the sled with acceleration [a], we can write -
F[P] - F = ma
a = {F[P] - F}/m
Substituting the values, we get -
a = (500 - 350)/100
a = 150/100
a = 15/10
a = 1.5 m/s²
Therefore, the the acceleration of the sled of mass 100 Kg will be
1.5 m/s².
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When you drop a 0.38 kg apple, Earth exerts a force on it that accelerates it at 9.8 m/s2 to- ward the earth’s surface. According to New-
Answer:
At the surface it is defined by 9.80665 m/s2.
Simpson s drives his car with an average velocity of 85 km/h eastward how long will it take him to drive 560 km on a perfectly straight highway?
Simpson will it take 112 / 17 km to drive 560 km on a perfectly straight highway.
What relationship does speed have with distance?You can replace this computation with d = rt, which stands for "distance equals rate times time." To calculate speed or rate, use the speed formula, s = d/t, which asserts that speed is equal to distance divided by time.
The difference between speed and velocity is the amount of distance an object covers in a given amount of time and in a certain direction. Speed is a scalar quantity while velocity is a vector.
We know that:
v = 85
d = 560
Substitute
v = 85
d = 560 into formula d = v x t :
560 = 85t
Cross out the common factor: 112 / 17 km
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assume that the brakes in your car create a constant deceleration if you double your driving speed how does this affect a0 the time required to come to a stop and b) the distance needed to stop?
For the moving car, if you double your driving speed;
a. the time required to come to a stop will increase by a factor of 2.
b. the distance needed to stop will increase by a factor of 2.
What is the formula relating acceleration, speed, time, and distance traveled?The formula relating to the acceleration, speed, time, and distance traveled of an object is a formula of the equations of motion.
The equations of motion are given below as follows:
v = u + at
s = ut + ¹/₂at²
v² = u² + 2as
where:
v = final speed
u = initial speed
t = time taken
s = distance traveled
a = acceleration
Considering the given scenario:
a. if the speed is doubled, the equation v = u + at applies for the time required to come to a stop;
t =2 * v - u / t
the time will be increase.
b. if the speed is doubled, the equation v² = u² + 2as applies for the distance needed to stop;
s = 2 * v² - u²
the distance will increase with an increase in speed.
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A boy walks 4 km east and then turns around and walks 1.5 km west. If east is taken as the positive direction and the west as the negative direction on a number line then what is the distance the boy covers and his displacement?
ANSWER
[tex]undefined[/tex]EXPLANATION
First, let us make a sketch of the question:
From the diagram, the blue circle represents his starting position while the black circle represents his final position.
The total distance the boy covers is the sum of his two journeys, to the east and then to the west.
That is:
[tex]\begin{gathered} 4+1.5 \\ 5.5\operatorname{km} \end{gathered}[/tex]The boy's displacement is the distance between his starting position and his final position.
Since the west is taken as negative direction and the east taken as the positive direction, it means that 4km east means +4km and 1.5
A rocket toy moves straight upward, starting from rest with an acceleration of 4 m/s2. It runs out of fuel at the end of 10 s and continues to coast upward, reaching a maximum height before falling back to earth
a. Find the rocket’s velocity and position at the end 10 s
B. Find the velocity before the rocket crashes on the ground
C. Find the time flight of rocke
An object is formed by attaching a uniform, thin rod with a mass of mr = 8kg and length L = 6 m to a uniform sphere with mass ms = 36.25 kg and radius R = 1.5m.1) What is the moment of inertia of the object about an axis at the left end of the rod?
ANSWER:
2167.68 kg*m^2
STEP-BY-STEP EXPLANATION:
Given:
mr = 8 kg
L = 6 m
ms = 36.25 kg
R = 1.5 m
Moment of inertia of sphere about its center is:
[tex]I_{CM}=\frac{2}{5}m_s\cdot R^2[/tex]Using paraller theorem, moment of inertia of shpere about end of rop is:
[tex]I_{\text{rod}}=m_s\cdot(R+L)^2+\frac{1}{3}m_r\cdot L^2[/tex]Therefore:
[tex]\begin{gathered} I=I_{cm}+I_{\text{rod}}_{} \\ I=\frac{2}{5}\cdot m_s\cdot R^2+m_s\cdot(R+L)^2+\frac{1}{3}\cdot m_r\cdot L^2 \end{gathered}[/tex]Replacing:
[tex]\begin{gathered} I=\frac{2}{5}\cdot36.25\cdot1.5^2+36.25\cdot(1.5+6)^2+\frac{1}{3}\cdot8\cdot6^2 \\ I=2167.69\text{ kg}\cdot m^2 \end{gathered}[/tex]The moment of inertia is 2167.68 kg*m^2
What if you had a leak in the refrigerant line. Explain in terms of energy and pressure and temperature.
The most frequent HVAC crises are gas leaks, clogged drain lines, electrical problems, refrigerant leaks, and problems with ventilation.
What happens if you have a refrigerant leak?Your system could not cool as effectively as it should due to refrigerant leakage. Your system can have trouble producing enough air cooling, which would keep your house from reaching the target temperature. This can lead to an increase in your monthly energy costs and makes your system work harder.Your system could not cool as effectively as it should due to refrigerant leakage. Your system can have trouble producing enough air cooling, which would keep your house from reaching the target temperature. This can lead to an increase in your monthly energy costs and makes your system work harder.The most frequent HVAC crises are gas leaks, clogged drain lines, electrical problems, refrigerant leaks, and problems with ventilation.To learn more about : Refrigerant
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Which of the following sources is most likely to be free of bias? OA. Textbook OB. Blog post c. Diary D. Video interview
Answer:
Textbook
Explanation:
Pretty obvious thi :v
Answer:
OA
Explanation:
Text books are often reviewed by experts hence, is likely to be biased.
A particle starts from rest of move with constant acceleration 4 m/s² along straight line then, Calculate velocity when it travel distance of 80 m step - by step explaination
Answer:
25.3 m/s
Explanation:
According to the laws of motion, the final velocity and the distance traveled by a particle moving at constant acceleration a m/s² is given by the equation
[tex]v^2 = v_0^2 + 2a(x - x_0)[/tex]
where
v= final velocity m/s
v₀ = initial velocity m/s
x = final position m
x₀ = initial position m
a = acceleration in m/s²
x - x₀ is called the displacement, d
We are given
v₀ = 0 since particle is starting at rest
d = 80 m
a = 4 m/s²
Plugging these values into the above equation.
v² = 0 + 2 x 4 x 80 m²/s²
v² = 640 m²/s²
v = √640 = 8√10 ≈ 25.3 m/s
If sound waves travel at 350 m/s on a warm humid day. And you are submerged underwater. Is the sound you hear while below the surface traveling faster, slower or at the same rate as the sound you hear above the water? Explain your answer
ANSWER:
Sound waves are faster in water
STEP-BY-STEP EXPLANATION:
Sound travels differently in water than it does in air.
Sound waves travel faster in denser substances because neighboring particles will more easily collide with each other.
Water is denser than air, which means that sound waves travel much faster in water than in air.
Although they travel faster in water, we must keep in mind that the human ear evolved to hear sounds in the air and is not as useful when submerged in water.
What is the specific heat c of a 0.500 kg metal sample that rises 5.40 C when 305J of heat is added to it?
ANSWER
[tex]\begin{equation*} 112.96\text{ }J\/kgK \end{equation*}[/tex]EXPLANATION
Parameters given:
Mass of sample, m = 0.5 kg
Temperature change, ΔT = 5.40 °C = 5.40 K
Heat energy, H = 305 J
To find the specific heat capacity of the sample, we have to apply the formula for heat energy:
[tex]H=mc\Delta T[/tex]Where c = specific heat capacity
Therefore, solving for c, the specific heat capacity of the metal sample is:
[tex]\begin{gathered} 305=0.5*c*5.4 \\ c=\frac{305}{0.5*5.4} \\ c=112.96\text{ }J\/kgK \end{gathered}[/tex]That is the answer.
Alex tickles his brother by stroking adjacent ________ spots on his skin.
Answer:
adjacent flat spots on his skin
Answer:
You didn't provide answer choices but I'd assume it's pressure.
A turntable turning at rotational speed 78 rpm stops in 45 s when turned off. The turntable's rotational inertia is 1.2 ×10−2kg⋅m2.
Determine the magnitude of the resistive torque that slows the turntable.
The magnitude of the torque that slows the turntable is equal to 2.17 × 10⁻³ N.m.
What is torque?Torque can be described as the measure of the force that can cause the rotation of an object about an axis. The force causes an object to accelerate similarly, torque causes an angular acceleration. Therefore, torque is the rotational equivalent of linear force.
Given, the rotational speed of the turntable, ω = 78 rpm = 8.16 rad/s
The time turntable takes to stop, t = 45 s
The rotational inertia of the turntable, I = 1.2 × 10⁻² Kg.m²
From the rotational kinetics equation, the angular acceleration:
[tex]\omega_f = \omega +\alpha t[/tex]
The final speed of the turntable = 0
[tex]\alpha =\frac{\omega_f-\omega}{t}[/tex]
[tex]\alpha =\frac{0-8.16}{45}[/tex]
[tex]\alpha =-0.1814 \;rad/s^2[/tex]
Calculation of torque by using inertia and angular acceleration:
[tex]\tau = I\alpha[/tex]
[tex]\tau =1.2 \times 10^{-2} \times (-0.1814)[/tex]
[tex]\tau = 2.17\times 10^{-3} \; N.m[/tex]
Therefore, the magnitude of the torque that slows the turntable is 2.17 × 10⁻³ N.m.
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If an astronaut weighed 200 pounds on the surface of the earth how much would the astronaut weigh 4000 miles above the earths surface. Show working equation
Recall that the gravitational pull is given by
[tex]F=G\frac{m_{}\cdot M_E}{r^2}[/tex]Where m is the mass of the astronaut, ME is the mass of Earth, r is the distance between them, and G is the gravitational constant.
The above relation states that the force of gravitation is directly proportional to the mass of two objects and is inversely proportional to the square of the distance between them.
If the astronaut weighs 200 pounds and the radius of the Earth is 4000 miles then
[tex]\begin{gathered} 200=G\frac{m\cdot M_E}{4000^2} \\ G\cdot m\cdot M_E=200\cdot4000^2 \end{gathered}[/tex]When the astronaut moves 4000 miles above the earth's surface then the distance between them is
4000+4000 = 8000 miles
The distance is measured from the center of the earth so the radius must be included.
So, the new force of gravitation is
[tex]\begin{gathered} F=\frac{G\cdot m_{}\cdot M_E}{r^2} \\ F=\frac{200\cdot4000^2}{8000^2} \\ F=50\: lb \end{gathered}[/tex]Therefore, the astronaut weighs 50 pounds 4000 miles above the earth's surface.
This makes sense because as you go further away from the center of the Earth then your weight becomes less due to less force of gravity.
Who exhibits more power?A) Bob transfer 2000 J in 3 minutes.B) Carl transfers 2 J in 0.1 s.C) Alan transfers 20 J in 0.5 s.
Given that:
A) Energy,
[tex]E_B=\text{ 2000 J}[/tex]The time is
[tex]\begin{gathered} t_B=3\text{ min} \\ =3\times60\text{ s} \\ =180\text{ s} \end{gathered}[/tex]B) Energy,
[tex]E_C=2\text{ J}[/tex]and time
[tex]t_C=0.1\text{ s}[/tex]C) Energy
[tex]E_A=20\text{ J}[/tex]and time
[tex]t_A=0.5\text{ s}[/tex]
We have to find the power for all three cases.
The formula to calculate power is
[tex]P=\frac{E}{t}[/tex]The power transferred by Bob will be
[tex]\begin{gathered} P_B=\frac{E_B}{t_B} \\ =\frac{2000}{180} \\ =11.11\text{ W} \end{gathered}[/tex]The power transferred by Carl will be
[tex]\begin{gathered} P_C=\frac{E_C}{t_C} \\ =\frac{2}{0.1} \\ =20\text{ W} \end{gathered}[/tex]The power transferred by Alan will be
[tex]\begin{gathered} P_A=\frac{E_A}{t_A} \\ =\frac{20}{0.5} \\ =40\text{ W} \end{gathered}[/tex]Thus, Alan exhibits more power.