How long (in seconds) would it take a machine to do 13,771 joules of work if the power rating of the machine is 0.38 horsepower? (Give the answer without units and round it to the nearest whole number.)

Answer:

Hertz is the answer for this question

Answer:

It is the combination of social and historical factors.

Answer:

You need to look up the figure for the energy released in the formation of one He atom, and then multiply that by the number of He atoms formed each second, and the result will be the total energy release that you seek.

Explanation:

Answer: 15 kg*m/s

Explanation:

Momentum = mass*velocity

Momentum = 3kg*5 m/s

Momentum = 15 kg*m/s

Answer:

15 kg m/s

Explanation:

Momentum = mass xvelocity

Momentum = 3kgx 5 m/s

Momentum = 15 kg m/s

Answer:

i do not know can i get brainliest im broke

Explanation:

Answer:

False

Explanation: not even light can escape through the event horizon from the black hole. At its center, each black hole is thought to have a singularity, a point of infinite density, and zero volume.

Answer:

S waves are transverse and cannot travel through liquids. P waves are longitudinal and can travel through liquids. When an earthquake happens on one side of the Earth, P and S waves can be detected all around the world.  S waves cannot be detected on the opposite side of the earth but can be detected at angles less than or equal to 90 degrees or slightly more. This is because there is a liquid core in the centre of the earth preventing the S waves from travelling to the direct opposite side of the Earth. P waves can be detected all around the world

Explanation:

BrainlyVIP <3

Answer:

tips to get you started

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Avoid recipes that need a special ingredient. ...

Look for seasonal recipes. ...

Plan to use leftovers.

Explanation:

sana po makatulong

Explanation:

A person invests money, or resources in a business .

The potential energy of the ball just before the kick was taken is zero (0).

Potential energy is the energy possessed by an object due to its position above the ground.

The Potential energy of the ball is calculated as follows;

P.E = mgh

where;

P.E = 1.5 x 9.8 x 0

P.E = 0

Thus, the potential energy of the ball just before the kick was taken is zero (0).

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Answer:

A 100 kg person who lives on the third floor

Explanation:

its ^ the answer above

Answer:

[tex]q / q_{1} = 2[/tex], assuming that [tex]q_{1}[/tex] and [tex](q - q_{1})[/tex] are point charges.

Explanation:

Let [tex]k[/tex] denote the coulomb constant. Let [tex]r[/tex] denote the distance between the two point charges. In this question, neither [tex]k[/tex] and [tex]r[/tex] depend on the value of [tex]q_{1}[/tex].

By Coulomb's Law, the magnitude of electrostatic force between [tex]q_{1}[/tex] and [tex](q - q_{1})[/tex] would be:

[tex]\begin{aligned}F &= \frac{k\, q_{1}\, (q - q_{1})}{r^{2}} \\ &= \frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\end{aligned}[/tex].

Find the first and second derivative of [tex]F[/tex] with respect to [tex]q_{1}[/tex]. (Note that [tex]0 < q_{1} < q[/tex].)

First derivative:

[tex]\begin{aligned}\frac{d}{d q_{1}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\right] \\ &= \frac{k}{r^{2}}\, \left[\frac{d}{d q_{1}} [q\, q_{1}] - \frac{d}{d q_{1}}[{q_{1}}^{2}]\right]\\ &= \frac{k}{r^{2}}\, (q - 2\, q_{1})\end{aligned}[/tex].

Second derivative:

[tex]\begin{aligned}\frac{d^{2}}{{d q_{1}}^{2}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q - 2\, q_{1})\right] \\ &= \frac{(-2)\, k}{r^{2}}\end{aligned}[/tex].

The value of the coulomb constant [tex]k[/tex] is greater than [tex]0[/tex]. Thus, the value of the second derivative of [tex]F[/tex] with respect to [tex]q_{1}[/tex] would be negative for all real [tex]r[/tex]. [tex]F\![/tex] would be convex over all [tex]q_{1}[/tex].

By the convexity of [tex]\! F[/tex] with respect to [tex]\! q_{1} \![/tex], there would be a unique [tex]q_{1}[/tex] that globally maximizes [tex]F[/tex]. The first derivative of [tex]F\![/tex] with respect to [tex]q_{1}\![/tex] should be [tex]0[/tex] for that particular [tex]\! q_{1}[/tex]. In other words:

[tex]\displaystyle \frac{k}{r^{2}}\, (q - 2\, q_{1}) = 0[/tex].

[tex]2\, q_{1} = q[/tex].

[tex]q_{1} = q / 2[/tex].

In other words, the force between the two point charges would be maximized when the charge is evenly split:

[tex]\begin{aligned} \frac{q}{q_{1}} &= \frac{q}{q / 2} = 2\end{aligned}[/tex].

WHAT? I DON'T UNDERSTAND WHAT ARE YOU SAYING

The kinetic energy of the circular disc in initial state is,

[tex]K^{1r} = \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]

The initial kinetic energy of the other disc dropped on the first disc is,

[tex]K^{2r} = \frac{1}{2}I^{b}(0)^{2}[/tex]

[tex] = > K^{2r} = 0J[/tex]

As both the disc in the final state are moving with the same angular velocity, thus, the net kinetic energy in the final state is,

[tex]E^{f} = \frac{1}{2}(I^{t} + I^{b})ω^{ \frac{2}{f} }[/tex]

The net kinetic energy in the initial state is,

[tex]E^{i} = K^{1r} + K^{2r}[/tex]

[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} } + 0[/tex]

[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} }[/tex]

Thus, the change in the kinetic energy during the change of state is,

[tex]dE = E^{f} - E^{i}[/tex]

[tex] = > dE = \frac{1}{2} (I^{t} + I^{b})ω^{ \frac{2}{f} } - \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]

[tex] = > dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]

This change in value of energy is the energy lost initially rotating the disk to friction.

Hence, the energy lost in the given case is [tex]dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]

The energy lost initially by the rotating disk to friction is equal to [tex]\frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]

Given the following data:

At the initial state, the kinetic energy of the circular disc is given by this formula:

[tex]K.E = \frac{1}{2} I_t\omega_i^2[/tex]

For the second disc, the initial kinetic energy is given by this formula:

[tex]K.E_2 = \frac{1}{2} I_b\omega_f^{2 }\\\\K.E_2 = \frac{1}{2} I_b(0)^{2 }\\\\K.E_2 = 0[/tex]

At the final state, the discs would move with the same angular velocity and the net kinetic energy is given by this formula:

[tex]E_f = \frac{1}{2} (I_t + I_b)\omega_f^2[/tex]

For the energy lost:

Also, the change in the kinetic energy is given by this formula:

[tex]\Delta E = E^f - E^i\\\\\Delta E = \frac{1}{2} (I_t + I_b)\omega_f^2 - \frac{1}{2} I_t\omega_i^2\\\\\Delta E = \frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]

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Answer:

T≈2.2876585681s

Explanation:

Since you were not given the degrees of amplitude or radians of amplitude, we assume that the degrees of amplitude are less than 20∘ or 20∘ and we also assume that this is a simple pendulum

The force required to keep the beam in equilibrium is 90 N.

It states that for a system at equilibrium, the sum of the clock-wise moment is equal to the sum of anti clock wise moment.

To calculate the magnitude of the force required to keep the beam at equilibrium, we use the Formula below.

Formula:

Where

Make f the subject of the equation

From the question,

Given:

Substitute the given values into equation 2

Hence, The force required to keep the beam in equilibrium is 90 N.

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Distance is the measure of the length of ground covered by an object during its motion. Distance is a scalar quantity. The car will travel 69 m while accelerating.

Distance is the measure of the length of ground covered by an object during its motion. While the displacement is defined as the shortest distance between the two paths.

Distance is a scalar quantity. While displacement is a vector quantity. Mathematically it is given as the product of speed and time.

The following data are given in the problem as

u is the initial  speed=5.0 m/sec

v is the final speed=21 m/sec

s is the distance covered by the car =?

a= Acceleration of car =3.0 m/sec²

According to Newton's third equation of motion, the formula derived will be

[tex]\rm{v^2=u^2+2as \\\\[/tex]

[tex]\rm s = \frac{v^2-u^2}{2a} \\\\\rm s = \frac{(21)^2-(5)^2}{2\times3.0} \\\\ \rm s=69 m[/tex]

Hence the car will travel 69 m while accelerating.

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STP is defined as the standard temperature and pressure. These are some standard values given in 1982. the approximate value of n according to the ideal gas law will be 0.986.

The ideal gas equation is derived from the Boyle and Charles law states that the product of pressure and volume is directly propotional to the temperature at STP.

It is mathematically given as

[tex]\rm pv=nRT[/tex]

P is the pressure =100kPa at STP.

R is universal gas constant=8.314 j/kgk

v is the volume=22.4 L=22.4×10³ m³

T is the temperature =273.15 K at STP

[tex]\rm pv=nRT\\\\\rm n=\frac{RT}{pv} \\\\\ \rm n=\frac{8.314\times273.15}{100\times10^3\times10^{-3}} \\\\\rm n=0.986[/tex]

Hence the approximate value of n according to the ideal gas law will be 0.986.

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Answer:

1

Explanation:

1 mol = 22.4 L

Answer:

8 valence electrons

Explanation:

Fluoride is F^-, so it has one additional electron, which is expected to be in a valence level (completing a closed-shell inert-gas structure). Thus fluoride should be 1s^2,2s^2,2p^6 , and have 8 valence electrons.

Answer:

that is the answer

Explanation:

look at it

Answer:

yes it do rises and then fall down due to gravitational

If the rod is in rotational equilibrium, then the net torques acting on it is zero:

∑ τ = 0

Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:

• at the left end,

τ = + (50 N) (2.0 m) = 100 N•m

• at the right end,

τ = - (200 N) (5.0 m) = - 1000 N•m

• at a point a distance d to the right of the pivot point,

τ = + (300 N) d

Then

∑ τ = 100 N•m - 1000 N•m + (300 N) d = 0

⇒   (300 N) d = 1100 N•m

⇒   d ≈ 3.7 m

Explanation:

he fell down with telling any one,

Answer:

[tex]30 \div 33750 = 0.008888[/tex]

Answer/Explanation:

The magnetic fields line are closer apart at other places. Hence, magnetic field is strongest at the poles. Magnetic Field has Direction The Magnetic Field lines are like closed curves They emerge from North Pole and Merge to South Pole.

Brainliest?!

Check out the Image below!

Answer:

Na: lose 1

O: gain 2

Al: lose 3

Be: lose 2

N: gain 3

Cl: depends on the limit of your study im grade nine and the energy level M can hold only eight electrons so i would have answered (gain 1)

Explanation:

The atoms according to the number of electrons it will lose or gain is matched as follows;

Sodium → lose 1

Nitrogen → gain 3

Sulphur → gain 2

Fluorine → gain 1

Boron → lose 3

Beryllium → lose 2

Atoms are the building block of matter. The outermost electron of an atom determines the number of electron an atom loose during bonding. Therefore,

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