How is the independent variable affected by the dependent variable

Answers

Answer 1

Answer:

A dependent variable is a variable that is tested in an experiment. An independent variable is that can be modified. Depending on what you are testing, the dependent variable will change accordingly to the dependent variable.

- I'm reading this back and it doesn't make much sense, if you want me to reword this I can


Related Questions

☆ Correct and rewrite the following statements:
_____
e). electroplating is based on magnetic effect of electricity.

f). an electric bulb glows due to the chemical effect of electricity.
_______________________

#No spam
#No Internet answers, please #Explanation needed​

Answers

Answer:

e)Question:-Electroplating is based on magnetic effect of electricity.Answer:-It's incorrect sentence As we know that, while electroplating there are two rods, one becoming cathode and another one becoming anode. During electroplating, when electricity is given through the rods, the anode produces positive ions which gets received at the cathode rod and negative ions produced at cathode collects at anode rod which results to the plating of the desired substance. Here, it is a chemical effect of electricity resulting to plating.

So correct sentence is:

Electroplating is based of chemical effect of electricity.

f)Question:-An electric bulb glows due to the chemical effect of electricity.Answer:-It's incorrect sentence As we know that, in an electric bulb there is a filament. When electricity is given in that filament of the electric bulb, the filament gets intensely heated up and results to the emission of light. Due to this heating of the filament due to electricity the electric bulb glows.

So correct sentence is:

An electric bulb glows due to the heating effect of electricity.

define nuclear energy​

Answers

Answer:

Nuclear energy is the energy stored in atoms that can produce electricity.

Hope that helps. x

I desperately need help with my Physics Exam I am failing this class will mark Brainliest to whoever helps the most: PART 1 (I don't want to overwhelm anyone so I'm posting my questions in parts) Also the questions marked are incorrect, so just work with the 3 remaining answers.
10000000 thank you's

Answers

Option 2nd is correct

last option is correct

what is the energy (in j) of a photon required to excite an electron from n = 2 to n = 8 in a he⁺ ion? submit an answer to three signficant figures.

Answers

Answer:

Approximately [tex]5.11 \times 10^{-19}\; {\rm J}[/tex].

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: [tex]R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}[/tex].

Look up the speed of light in vacuum: [tex]c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}[/tex].

Look up Planck's constant: [tex]h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}[/tex].

Apply the Rydberg formula to find the wavelength [tex]\lambda[/tex] (in vacuum) of the photon in question:

[tex]\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}[/tex].

The frequency of that photon would be:

[tex]\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}[/tex].

Combine this expression with the Rydberg formula to find the frequency of this photon:

[tex]\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}[/tex].

Apply the Einstein-Planck equation to find the energy of this photon:

[tex]\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}[/tex].

(Rounded to three significant figures.)

Which statement best describes the energy changes that occur while a child is riding on a sled down a steep, snow-covered hill?

a
Kinetic energy decreases and potential energy increases.
b
Both potential energy and kinetic energy decrease.
c
Both potential energy and kinetic energy increase.
d
Kinetic energy increases and potential energy decreases.

Answers

Answer: When a child is riding on a sled down a steep, snow-covered hill, his elevation decreases and hence Kinetic energy increases and potential energy decreases.

i think this will help you

A 1,500 kg car is traveling at 25 m/s. The driver suddenly applies the brakes causing the car to skids to a stop. If the average braking force between the tires and the road is 7,100 N, how far does the car slide before it comes to rest?​

Answers

By Newton's second law, the car slows down with an average acceleration a such that

-7100 N = (1500 kg) a   ⇒   a ≈ -4.7 m/s²

If we treat the car as accelerating uniformly with this magnitude, then the car slides a distance ∆x such that

0² - (25 m/s)² = 2a ∆x   ⇒   ∆x ≈ 66 m

The car slide before it comes to rest will be 66 m. Newton's second equation of motion is applied in this problem.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

The acceleration is found as;

F=ma

-7100 N = (1500 kg) a

a= -4.7 m/s²

If we assume that the automobile accelerates uniformly with this magnitude, the car slides x distance. From the Newton's second equation of motion;

v²=u²+2as

v²-u²=2as

0² - (25 m/s)² =2×(-4.7) s  

s=66 m

Hence,the car slide before it comes to rest will be 66 m.

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BRAINLIST!!!
Two metallic balls A and B carry the charges QA= 16×10^-9C and QB=-8×10^-9C.
We fixed balls A and B 5cm apart. Given e=1.6×10^-9C and k=9×10^9 S.I unit.
1) identify the ball that has excess of electrons.
2) calculate the number of deficit and excess of electrons on both balls.
3) calculate the force exerted by A on B.

Answers

QB=-8×10^-9C.QB=-8×10^-9C.We fixed balls A and B 5cm apart. Given e=1.6×10^-9C and k=9×10^9 S.I unit.

Recoil is noticeable if you throw a heavy ball while standing on roller skates. If instead you go through the motions of throwing the ball but hold onto it, your net recoil velocity will be

Answers

Answer:

Since there is no external force, there is no change (movement) in the center of mass. Internally, the center of mass might change position, but the external result is still zero net velocity.

The net recoil velocity must be zero.

Which best describes why a liquid needs a container when a solid does not?
O Solids fill their containers, and liquids have definite shapes.
Solids have definite shapes, and liquids fill their containers.
Solids particles will expand to fill their containers, and liquid particles will expand as well.
O Solids particles expand to fill their containers, and liquid particles do not.

Answers

Answer: Solids have definite shapes and liquids fill their containers.

Explanation: Liquids have got further apart molecules than solids, so the liquid molecules have a higher degree of locomotion than solid molecules, hence able to fill the container though without a definite volume, which is not the case for solid molecules.

what is the necessary condition for the conservation of angular momentum

Answers

Answer:

The conservation of momentum of a system is a fundamental principle in classical mechanics. The only condition for this principle being valid is that the system should be an isolated one, i.e. It should not be acted upon by any external force.

What are the three different social perspectives on sport

Answers

Answer:

functionalist theory,feminist theory. discipline of sociology

what has to increase in order for an object to accelerate?

Answers

Answer:

Answer: B. Explanation: For an object to accelerate the force on it must be increased. According to Newton's second law of motion.

Explanation:

I do Accelerate to good luck

A rock is lying on a rock ledge that is 3 m high. The rock as 120 J of potential energy. What is the mass of the rock?

Have a great day!

Answers

[tex]\\ \sf\Rrightarrow PE=mgh[/tex]

[tex]\\ \sf\Rrightarrow m(10)(3)=120[/tex]

[tex]\\ \sf\Rrightarrow 30m=120[/tex]

[tex]\\ \sf\Rrightarrow m=4kg[/tex]

Mass=4kg

If a spaceship travels at an average speed of 6x10^10 kilometers per year, how many years will it take the spaceship to travel 3x10^30 kilometers? Show work or explain your logic for full credit. a) 5x10^2 b) 5x10^19 c) 5x10^20 d) 5x10^21

Answers

First, you need to find out the speed of 6x10^10. Then find out the value of 3x10^30 after you do that, Make this visual,

3x10^30. 5x10 to the 19 power

_______.

6x10^10

The answer is c

If the spaceship travels a distance of 6 × 10¹⁰ kilometers with an average speed the time taken to travel 3 × 10³⁰ kilometers is 5 × 10¹⁹ years. Thus, option a is correct.

What is speed?

Speed is a physical quantity associated with a moving body. It is the measure of distance travelled per unit  time . Thus, mathematically it is the ratio of distance to the time.

If we have the time and speed known we can find the distance travelled and vice versa. As the speed increases, the distance covered per unit time will be higher.

Here the spaceship travels  6 × 10¹⁰ kilometers . Thus the time taken to travel 3 × 10³⁰ kilometers can be calculated as follows:

1 year   -    6 × 10¹⁰ km

  ?           -  3 × 10³⁰ km

Cross multiply them we get, 3 × 10³⁰ km/  6 × 10¹⁰ km = 5 × 10¹⁹ years.Hence, option a is correct.

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A horizontal force F~ is applied to a block of mass m = 1 kg placed on an inclined
at θ = 30◦ plane. The coefficients of static and dynamic friction are µs = 0.3 and µ = 0.2, respectively. Find F such that the block is moving up the slope with a constant speed.

Answers

Hi there!

To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.

Recall:

[tex]\large\boxed{F_D = \mu N}}[/tex]

The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.

[tex]\large\boxed{N = Mgcos\theta + Fsin\theta}}[/tex]

We can plug in the known values to solve for one part of the normal force:

N = (1)(9.8)(cos30)  + F(.5) = 8.49  + .5F

Now, we can plug this into the equation for the dynamic friction force:

Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F

For a block to move with constant speed, the summation of forces must be equivalent to 0 N.

If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:

Fcosθ = 1.697 + .1F

Solve for F:

Fcos(30) - .1F = 1.697

F(cos(30) - .1) = 1.697

F = 2.216 N

Scientific notation of 1,750

Answers

1.75 x 10^3
hopes this helps if not im really sorry

You want to replace the resistor in your
boiler with a more efficient one during win-
tertime. Would you replace it with another
one double the length or half the length?

Answers

To make the boiler more efficient, we would replace the resistor with another double the length.

We know that the resistance of the resistor in the boiler is given by R = ρl/A where

ρ = resistivity, l = length of resistor and,A = cross-sectional area of resistor.

Also, the power generated by the resistor is P = i²R where

i = current and R = resistance.

If i is constant, we see that P ∝ R.

So, to increase the efficiency, the value of the resistance has to increase.

Also, since R = ρl/A and ρ and A are constant, we see that R ∝ l.

Since P ∝ R and R ∝ l P ∝ l.

So, to increase the efficiency, we would double the length of the resistor.

So, to make the boiler more efficient, we would replace the resistor with another double the length.

Learn more about resistors here:

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A massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface. The mass hangs over a
frictionless pulley. When the mass is released, the cartaccelerates to the right
2.45 m/s2
4.90 m/s
9.80 m/s?
19.6 m/s

Answers

Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]

Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.

Let M = 1kg and m = 3 kg

Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.

When the mass is released, the cart accelerates to the right can be calculated  from Newton' second law of motion. That is,

M( g + a) = m(g - a)

1(9.8 + a) = 3( 9.8 - a)

9.8 +a = 29.4 - 3a

collect the like terms

4a = 19.6

a = 19.6/4

a = 4.9 m/[tex]s^{2}[/tex]

Therefore, the cart accelerates to the right with a magnitude of 4.9 m/[tex]s^{2}[/tex]. The correct answer is 4.90 m/[tex]s^{2}[/tex]

Learn more about dynamics here: https://brainly.com/question/24994188

what is the theory relativity by Einstein? ​

Answers

:MAIN ANSWER:

determined that the laws of physics are the same for all non-accelerating observers

Explanation:

Albert Einstein, in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels, according to Wired.

HOPE IT HELPS

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HAPPY HOLIDAYS DEC 2021

A water balloon is hovering directly above the line join points ANB which are 4.6 km apart if the angles of elevation to the balloon from point a to B or 28.8° and 52.2 respectively find the altitude of the balloon

Answers

Answer:

Drawing the triangle:

H / x = tan 52.2 = 1.29

H / (4.6 - x) = tan 28.8 = .550

H = 1.29 x

H = .55 * 4.6 - .55 x

1.84 x = 2.53        combining equations

x = 1.38

4.6 - 1.38 = 3.22

Total base of triangle = 1.38 + 3.22 = 4.6

H / x = tan 52,2 = 1.29

H = 1.29 * 1.38 = 1.78 height of triangle

Check:

1.78 / 3.22 = tan 28.9    

This agrees with the given value of 28.8

what is the cost of monthly (30 days) electric bill of ana if her city's cost of electricity is 0.05$ per kwh and she uses three refrigerators running in 600-watt power rating and open 24 hours

Answers

Answer:

1kW = 1000W

600W = 0.6kW

Cost of electric bill = 0.6kWh × 24 × 30 × $0.05

                               = $21.60

SOMEONE, PLEASE HELP ME AS FAST AS YOU CAN, I WOULD GIVE MORE POINTS BUT THIS IS THE REST OF MY POINT, PLEASE SOMEONE WHO IS SUPER KIND HELP ME.

Answers

Answer:

1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time

2. 36÷4= 9

(formula) Speed = distance ÷ time

3. Meter (M) centimeter (cm) kilometers (km)

4. Seconds , Hour, Minute

5. 65÷13=5 (object A)

125÷ 25= 5 (object B)

their both Equal of the amount of speed, so they are travelling at the same speed

Hope I helped

how do you think the liquid density affects the buoyancy of objects placed in the liquid?

Answers

Answer:

density can be written as:

d = F / V  (weight density) or M / V (mass density)

Since F in the first equation can be written as

B = d V where B is the buoyant force and is proportional to the

weight of the liquid displaced

For a given volume the weight of the liquid displaced is proportional to the density and hence the buoyant force

is it possible for an object moving around a circular path to have both centripetal and tangential acceleration?

Answers

Answer:

A major difference between tangential acceleration and centripetal acceleration is their direction. Centripetal means “center seeking”. ... Tangential acceleration results from the change in magnitude of the tangential velocity of an object. An object can move in a circle and not have any tangential acceleration.

The direction of acceleration is a key distinction between tangential acceleration and centripetal acceleration. Centripetal is defined as "center-seeking." The amount of an object's tangential velocity changes, which causes tangential acceleration. Without experiencing any tangential acceleration, an item can move in a circle.

What is Acceleration?

Acceleration is the rate at which the speed and orientation of a moving object change over time. When a spot or object moves faster or slower along a straight line, it is said to be accelerated. Even though the speed is constant, motion on a circle accelerates so because the direction is always shifting. Both by and to acceleration for all other types of motion.

It is a vector quantity because it has both magnitude and direction.

Any object's rotation experiences tangential acceleration, which is the speed at which the tangential velocity fluctuates. When an object is moving, it behaves in a tangential direction. An object moving in a circle will also experience the very same tangential velocity action.

To know more about Acceleration:

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With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s

Answers

initial velocity=u=20km/h=5.5m/sAcceleration=a=8m/s^2Time=t=10s

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(30.25)[/tex]

[tex]\\ \sf\longmapsto s=55+121[/tex]

[tex]\\ \sf\longmapsto s=176m[/tex]

what does the geocentric model of the solar system look like

Answers

In the geocentric system, the Earth is considered to be the center of the solar system. The Moon, the planets, the Sun, and the stars all rotate around the Earth (which stays still), with uniform circular motion.

please help me !! i’ll give you brainliest if you get the answer right!

Answers

Answer: 25N to the right

Explanation: 35N - 10N = 25N

During which time does Jamal have the greatest momentum?

Answers

Answer:

Momentum Packet Answer KEY - Science Online

YOU WILL SEE THE PDF

a body of mass 10 kg is moving with velocity of 10ms-1.a force acts for 5 seconds to reduce its velocity to 2ms-1.find the momentum of the body before and after application of the force on it

Answers

Answer:

momentum before: 100kgm/s

momentum after: 20kgm/s

Explanation:

initial velocity: 10

final velocity: 2

p=mv

before: 10kg×10m/s

after:10kg×2m/s

I'm not 100% sure btw

What is the gravitational force between two objects of masses 20kg and 50kg separated by a distance of
4m?

Answers

Answer:

4.16875×10^-9

Explanation:

given,

mass(M1)=20kg

mass(M2)= 50kg

distance(d)=4m

gravitational constant value (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×20×50)÷4^2

=(6.67×10^-8)÷16

= 4.16875×10^-9

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