How fast can Usain Bolt run if it takes him 9.9 s to run 100m?​

True. The force of the car on the bug will be equal to the force of the bug on the car.

This statement is true according to Newton's third law of motion.

According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction.

In this case, the action is the force of the car on the bug, and the reaction is the force of the bug on the car.

Therefore, the force of the car on the bug is equal in magnitude and opposite in direction to the force of the bug on the car.

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Answer:Increasing the concentration of CO2

Explanation:

I might be wrong, don't try so sorry if i'm wrong!

The changes to the Earth's atmosphere would increase the greenhouse effect and it is caused by

Green house effect refers to different release of greenhouse gases like co2 to the atmosphere in large quantities therefore affection the atmosphere and ozone layer leading to the release of dangerous radiations.

Therefore, The changes to the Earth's atmosphere would increase the greenhouse effect and it is caused by

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Answer:

It's "C"

Explanation:

Friction slows things down.

"Friction always slows a moving object down. The amount of friction depends on the materials from which the two surfaces are made. The rougher the surface, the more friction is produced. Friction also produces heat. "

-Google

Answer:

Velocity ratio & input work

Explanation:

If u input velocity u can work the ratio...;D ;D ;D xD

Answer:

carbon monoxide

Explanation:

Answer:

Assumption: the acceleration of this bus is constant while the brake was applied.

Acceleration of this bus: approximately [tex]\left(-6.0\; \rm m \cdot s^{-2}\right)[/tex].

It took the bus approximately [tex]1.7\;\rm s[/tex] to come to a stop.

Explanation:

Quantities:

Consider the following SUVAT equation:

[tex]\displaystyle x = \frac{1}{2}\, \left(a\, t^2\right) + u\, t[/tex].

On the other hand, assume that the acceleration of this bus is indeed constant. Given the initial and final velocity, the time it took for the bus to stop would be inversely proportional to the acceleration of this bus. That is:

[tex]\displaystyle t = \frac{v - u}{a}[/tex].

Therefore, replace the quantity [tex]t[/tex] with the expression [tex]\displaystyle \left(\frac{v - u}{a}\right)[/tex] in that SUVAT equation:

[tex]\displaystyle x = \frac{1}{2}\, \left(a\, \left(\frac{v -u}{a}\right)^2\right) + u\, \left(\frac{v - u}{a}\right)[/tex].

Simplify this equation:

[tex]\begin{aligned}x &= \frac{1}{2}\, \left(a\, {\left(\frac{v -u}{a}\right)}^2\right) + u\, \left(\frac{v - u}{a}\right) \\ &= \frac{1}{2}\left(\frac{{(v - u)}^2}{a}\right) + \frac{u\, (v - u)}{a} =\frac{1}{a}\, \left(\frac{{(v - u)}^2}{2} + u\, (v - u)\right)\end{aligned}[/tex].

Therefore, [tex]\displaystyle a= \frac{1}{x}\, \left(\frac{{(v - u)}^2}{2} + u\, (v - u)\right)[/tex].

In this question, the value of [tex]x[/tex], [tex]u[/tex], and [tex]v[/tex] are already known:

Substitute these quantities into this equation to find the value of [tex]a[/tex]:

[tex]\begin{aligned} a &= \frac{1}{x}\, \left(\frac{{(v - u)}^2}{2} + u\, (v - u)\right) \\ &= \frac{1}{10\; \rm m}\times \left(\frac{{\left(0\; \rm m \cdot s^{-1} - 10\; \rm m \cdot s^{-1}\right)}^2}{2} + \left(0\; \rm m \cdot s^{-1} - 10\; \rm m \cdot s^{-1}\right)\times 10\; \rm m \cdot s^{-1}\right)\\ &\approx -6.0\; \rm m \cdot s^{-2}\end{aligned}[/tex].

(The value of acceleration [tex]a[/tex] is less than zero because the velocity of the bus was getting smaller.)

Substitute [tex]a \approx -6.0\; \rm m \cdot s^{-2}[/tex] (alongside [tex]u = 10\; \rm m \cdot s^{-1}[/tex] and [tex]v = 0\; \rm m \cdot s^{-1}[/tex]) to estimate the time required for the bus to come to a stop:

[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{0\; \rm m \cdot s^{-1} - 10\; \rm m \cdot s^{-1}}{-6.0\; \rm m \cdot s^{-2}} \approx 1.7\; \rm s\end{aligned}[/tex].

Answer:

0.04kg

Explanation:

Explanation in pics:

The formula for kinetic energy is KE = 1/2mv². So now the question asks for the mass, not KE. So we need to rearrange the formula so that we are calculating the mass. So, the formula for mass is m=KE/(1/2v²). Now we just substitute the values into the formula. Then just follow what it shows in the pic

Answer and Explanation:

Using a = F/m, we get:

Acceleration for Road A = 480/62 = ~7.74 m/s^2

Acceleration for Road B = 240/62 = ~3.87 m/s^2

Acceleration for Road C = 600/62 = ~9.68 m/s^2

If the net force becomes higher than 600N and the mass stays constant, the acceleration will increase proportionally to how much the force increases and the acceleration will be greater than the acceleration when the force is 600N.

I hope this helps! :)

Answer:

A. 39.2 m/s

B. 78.4 m

Explanation:

Data obtained from the question include:

Time (t) = 4 s

Acceleration due to gravity (g) = 9.8 m/s²

A. Determination of the brick's velocity.

Time (t) = 4 s

Acceleration due to gravity (g) = 9.8 m/s²

Velocity (v) =?

v = gt

v = 4 × 9.8

v = 39.2 m/s

Thus, the brick's velocity after 4 s is 39.2 m/s

B. Determination of how far the brick fall in 4 s.

Time (t) = 4 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

h = ½gt²

h = ½ × 9.8 × 4²

h = 4.9 × 16

h = 78.4 m

Thus, the brick fall 78.4 m during the time.

The velocity after 4 seconds is 40 m/s and the height is 80 m.

From the equations of motion under gravity;

v = u + gt

V = final velocity of the brick

u = initial velocity of the brick

g = acceleration due to gravity = 10 ms-2

t = time taken

Note that, u = 0 m/s because the brick was dropped from a height.

v = 0 + 10(4)

v = 40 m/s

The height is obtained from;

h = ut + 1/2 gt^2

u = 0 m/s because the brick was dropped from a height.

h =  1/2 gt^2

h = 1/2 × 10 × (4)^2

h = 80 m

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Answer:

Explanation: Afdjkldjf

Answer:

A

Explanation:

0-2         1.0

2-4         0.5

4-6         0

The table of velocity of toy car is drawn below.

What is velocity ?

velocity is defined as rate of change of displacement of the object with respect to rate of change in time. In mathematics It is written as :

                                           [tex]\begin{aligned}v= \frac{\Delta d}{\Delta t}=\frac{d_{2}-d{1}}{t_{2}-t_1}\end{aligned}[/tex]

considering time interval from t=0 sec to t=2 sec the distance travelled by the toy car is d=0m to d=2m. therefore, the velocity will be :

                                      [tex]\begin{aligned}v&=\frac{d_{2}-d{1}}{t_{2}-t_1}\\&=\frac{2-0}{2-0}\\&=1 \text{\:m/s}\end{aligned}[/tex]

similarly for interval t = (2sec - 4sec ) and t = (4sec - 6sec) is also calculate and written in table below.

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Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of options. However, the charge of a nucleus was discovered by Ernest Rutherford. The nucleus is located in the centre of an atom and it contains protons and neutrons. The protons are positively charged while the neutrons have no charge, thus the charge of the nucleus is positive because the neutrality of the neutron does not affect the charge of the proton.

The charge of an electron was first measured by Robert Millikan. Electrons are negatively charged subatomic particles that balance out the positive charge of the protons.

Acceleration points in the same direction as the net force, so to the left.

The direction of velocity can't be determined from this information alone, though. If the object is at rest, it will being moving to the left. If the object is already moving to the left, it will continue doing so and speed up. If it starts off moving to the right, it will continue to move to the right but eventually slow to a stop before starting to move to the left. There are more cases to consider if you're talking about motion in more than one dimension.

Answer:

The cat's speed when it slid off the table was 2.53 m/s

Explanation:

Horizontal Motion

When an object is thrown horizontally at a speed v, from a height h, it describes a curved path ruled by gravity, until it hits the ground.

the range or maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

The situation described in the problem fits into the concept of a horizontal launch when the cat slides off the table and gets to the ground some distance ahead.

It's given the range as d=1.3m and the height h=1.3 m, thus we can find the cat's speed by solving the equation for v:

[tex]\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}[/tex]

Where [tex]g=9.81\ m/s^2[/tex]

Substituting values:

[tex]\displaystyle v=1.3\cdot\sqrt{\frac {9.81}{2\cdot 1.3}}[/tex]

[tex]\displaystyle v=1.3\cdot\sqrt{\frac {9.81}{2.6}}[/tex]

Calculating:

v = 2.53 m/s

The cat's speed when it slid off the table was 2.53 m/s

Answer:

Explanation:

hope it helps:)

Answer:

c) an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity.

Explanation:

When the boy throws the ball upward, there are two forces acting on the ball. First one is the force of gravity, which is constant and equal tot he weight of the ball, acting down. The second force is the force with which the boy throws the ball. This force acts upward and decreases as the ball moves up. This force becomes zero when the ball reaches highest point.

While, on its way down the ball has only one force acting on it. That force is the constant force of gravity acting downward. This gravity force is equal to the weight of the ball.

Hence, the correct option is:

c) an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity.

The force acting on the ball is an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity. Thus the option C is the correct option.

Given,

Force exerted by the air is negligible.

Now the forces acting on the ball after the realese,

            [tex]W=mg[/tex]

Now after reaching the highest point, the ball starts to come down. In this case, only one force will act on it which is the gravity force and this is equal to the weight of the body.

Hence, the force acting on the ball is an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity. Thus the option C is the correct option.

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I think it because of UV rays ultra violet ray which can make their colors different

Answer:

Curve in spine can effect his or her other body parts too in addition to spine. The neck or head can be tilted forward, shoulder could be hunched, hip bone can be uneven, ribs can be effected leading to disorder of lung.

Explanation:

Answer:

Acceleration

Explanation:

Its speed or velocity change

Answer:

true

Explanation:

just took the test

Answer:

True

Explanation:

Answer:

Rhinoceroses are odd-toed ungulates native to sub-Saharan Africa and southern Asia, though all five living species have hugely contracted in range and number due to the influence of humans. Despite their titanic, tank-like bulk, rhinos can be amazingly swift: The fastest may reach at least 50 kilometers per hour (31 mph).

Explanation:

sana makatulong

Answer:

In a chemical reaction, only the atoms present in the reactants can end up in the products. No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange amd form new bonds to make the products.

Answer:

1 hour

Explanation:

The tailwind usually adds to the speed of airplanes while the headwind normally decreases the speed of airplanes.

For the initial journey of 200 mph with a 40 mph tailwind speed for 480 miles:

Total speed = 200 + 40 = 240 mph

Also,

Speed = distance/time

time = 480/240 = 2 hours

For the return journey of 200 mph with a 40 mph headwind for 480 miles:

Total speed = 200 - 40 = 160 mph

time = 480/160 = 3 hours

The initial flight took 2 hours while the flight back home took 3 hours. Hence it took 1 hour longer to get back home

Answer: 4.9 m/s

Explanation:

Answer:

the ball's Stored energy 2. The balls altitude slowly comes to a stop going back into potential Energy

Explanation:

Answer:

The answer is: C. the star must be close enough to the Sun to show measurable parallax.

Explanation:

In the field of astronomy, parallax is called stellar parallax in distant stars.

The stars for which parallax measurements have been made are those that are relatively close to the sun on the galactic scale.

The answer is: C. the star must be close enough to the Sun to show measurable parallax.

Answer:

Yes

Explanation:

Yes, this is a random error generating because of statistical constraint. We only have finite number of data points. As per this, if we plot our observation we will get a gaussian (inverse bell ) shaped curve with mean equal to central value.

Answer:

[tex]Force = 13.8N[/tex]

Explanation:

Given

[tex]Mass = 0.6kg[/tex]

[tex]Acceleration = 23m/s^2[/tex]

Required

Determine the applied force

From the question, we understand that no other force acts on the ball.

i.e. the only applied force on the ball is the force applied by the striker.

So, we apply Newton's second law to solve this question.

And this implies that:

[tex]Force = Mass * Acceleration[/tex]

[tex]Force = 0.6kg * 23m/s^2[/tex]

[tex]Force = 13.8N[/tex]

Hence, the applied force by the striker on the ball is 13.8N