How can you tell that x and y are NOT directly proportional? A) x is 0 when y is 0. B) y is getting farther away from x. C) x is increasing by the same amount. D) y is increasing by different amounts.
x y
0 0
1 3
2 5
3 9

Answer:

28?

Step-by-step explanation:

4x=2x+56 (equal angles)

2x=56 (divide both sides by 2)

x=28 (angle)

Answer:

∠B = 112°

Step-by-step explanation:

1) ∠B and ∠D are congruent because they are alternate interior angles (same side interior) so they equal the same

2) Set the two expressions equal to each other:

2x+56 = 4x

56 = 2x

x=28

3) Plug 28 in for x in the expression (2x+56) and get 112°

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[tex]\huge{\underline{\underline{\boxed{\sf{\ref{Answer}}}}}}[/tex]

[tex]\large\huge\green{\sf{♥ Explanation♥}}[/tex]

∴Hence, at standard it is 13.00-4 =99.00 STD talk

off reached at Manila +8 Zone at 20.00

∴Hence at standard & 2000 -8

reached.⇒ 12.00 STD

(i) Time at Manila, whicle Plane de parts

12-3+8 ⇒9+8 → 17.00

(ii) duration = 3 hours.

(iii) in dubai 13.00 + 3 = 16,00

_____________________

Ans

i)17.0.0 (ii) 3 hours (iii) 16.00

________________________

♕ hence we done:) xD

Rita will earn $897 for working 52 hours.

Word problems in mathematics are mathematical operations that are applied to solve real life cases.

From the information given:

If Rita worked for 22 hours, she earns $379.50

Now, if Rita worked for 52 hours, the amount Rita will earn can be expressed by using the relation:

[tex]\mathbf{= \dfrac{52 \ hours \times \$379.50}{22 \ hours} }[/tex]

= $897

Learn more about word problems in mathematics here:

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Answer: I say the answer is 20 years old, 30 years old

Step-by-step explanation: If rachel is 10 years old than her sister in six years from now, the sum of their ages will be 40. So rachel is 10 years older than her sister so the younger sister has to be 20 years old and and rachel is 30 years old.

[tex] {x}^{2} + 8x + 12 = 0 \\ = > {x}^{2} + 6x + 2x + 12 = 0 \\ = > x(x + 6) + 2(x + 6) = 0 \\ = > (x + 2)(x + 6) = 0 \\ = > x = - 2 \: \: or \: \: - 6[/tex]

[tex]3x + 6 = 0 \\ = > 3x = - 6 \\ = > x = \frac{ - 6}{3} \\ = > x = - 2[/tex]

Here, the common solution is -2.

Answer:

x = -2.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

y=8 x+2

Step-by-step explanation:

Answer:

2. The two interior opposite angles of an exterior angle of a triangle are and . Find the measure of the exterior angle. 

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\frac{2}{3}[/tex] + [tex]\frac{1}{4}[/tex] = [tex]\frac{8+3}{12}[/tex] = [tex]\frac{11}{12}[/tex] ≈ 1

The correct answer is the last one (C)

Answer:

asdasd

Step-by-step explanation:

asdasdasd

Answer:

37

Step-by-step explanation:

All angles of a triangle have to add up to 180 degrees

180 - 113 - 30 = 37

37+113+30 = 180

Answer:

297 J

Step-by-step explanation:

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

Answer:

Step-by-step explanation:

Given:

x1 = -2

y1 = 1

slope (m) = 3/2

Solution:

y - y1 = m ( x - x1 )

y - 1 = 3/2 ( x - (-2) )

y - 1 = 3/2 ( x + 2 )

y - 1 = 3/2x + 3

y = 3/2x + 3 + 1

y = 3/2x + 4

Answer:

18

Step-by-step explanation:

6*6/2

Answer:

Step-by-step explanation:

     MARKS  

        %    Max   Actual  

Hindi 50%    100 50  

English 75%     140 105  

Math              160 90  

(245/400)

Answer:

Step-by-step explanation:

I just did this question and it is 100% correct

It should be noted that all the solids have the same volume.

Volume is a measure of three-dimensional space. It is often quantified numerically using SI derived units or by various imperial or US customary units. It should be noted that the definition of length is interrelated with volume.

Here, the three solids below have the same height. The cross-sections of the parallel planes have equal areas. They all have same volume.

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If its easy, why don’t you do it yourself??

Using proportions, it is found that Ankita's share is of [tex]\frac{x}{4}[/tex], considering that the total rent is of x Rp.r.

The rule of three is:

4 people - x

1 people - a

Applying cross multiplication:

[tex]4a = x[/tex]

[tex]a = \frac{x}{4}[/tex]

Ankita's share is of [tex]\frac{x}{4}[/tex], considering that the total rent is of x Rp.r.

You can learn more about proportions at https://brainly.com/question/24372153

[tex]\huge\color{skyblue}\boxed{\colorbox{black}{Answer♡}}[/tex]

[tex]a \: number \: x \: is \: reduced \: by \: 25\%[/tex]

[tex]25\% \: of \: x \: means \: ( \frac{25}{100} )(x) = 0.25x \\ \\=> x - 0.25x \\ = > 0.75x[/tex]

hope helpful~

The reduced quantity if x is reduced by 25% is 0.75x.

A percentage, often known as percent, is a division by 100. Percentage, which means "per 100," designates a portion of a total sum. 45 out of 100 is represented by 45%, for instance. Finding the percentage of a whole in terms of 100 is what percentage calculation is. Both manual calculation and the use of internet calculators are options.

Given:

x is reduced by 25%,

Calculate the 25% of x as shown below,

25 / 100 × x

0.25x

Calculate the reduced quantity,

Reduced quantity = x - 0.25x

Reduced quantity = x(1 - 0.25)

Reduced quantity = 0.75x

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Answer:

65°

Step-by-step explanation:

x=180°-40°-75°

x=65°

Given that

log (x+y)/5 =( 1/2) {log x+logy}

We know that

log a+ log b = log ab

⇛log (x+y)/5 =( 1/2) log(xy)

We know that log a^m = m log a

⇛log (x+y)/5 = log (xy)^1/2

⇛log (x+y)/5 = log√(xy)

⇛(x+y)/5 = √(xy)

On squaring both sides then

⇛{ (x+y)/5}^2 = {√(xy)}^2

⇛(x+y)^2/5^2 = xy

⇛(x^2+y^2+2xy)/25 = xy

⇛x^2+y^2+2xy = 25xy

⇛x^2+y^2 = 25xy-2xy

⇛x^2+y^2 = 23xy

⇛( x^2+y^2)/xy = 23

⇛(x^2/xy) +(y^2/xy) = 23

⇛{(x×x)/xy} +{(y×y)/xy} = 23

⇛(x/y)+(y/x) = 23

Therefore, (x/y)+(y/x) = 23

Hence, the value of (x/y)+(y/x) is 23.

Answer:

a^2 + b^2 + c^2 +2ab + 2ac + 2bc

The best prediction of Riley’s height is 65.84 inches and it can be determined by using the linear regression equation.

Bryce wrote the linear regression equation,

[tex]\rm y=1.123x-6.443[/tex]

To predict the arm span, y, of a person who is x inches tall.

Riley has an arm span of 67.5 inches.

Which is the best prediction of Riley’s height?

To predict the arm span, y, of a person who is x inches tall.

Riley has an arm span of 67.5 inches.

[tex]\rm y=1.123x-6.443[/tex]

Where the arm span, y, of a person who is x inches tall.

Riley has an arm span of 67.5 inches,

Then,

The best prediction of Riley’s height is,

[tex]\rm 67.5 = 1.123x -6.443\\\\67.5+6.443=1.123x\\\\ 73.943 = 1.123x\\\\ x = \dfrac{73.943}{1.123}\\\\ x = 65.84 \ inches[/tex]

Hence, The best prediction of Riley’s height is 65.84 inches.

For more details about the Equation refer to the link given below.

https://brainly.com/question/9540093

let something = x

[tex]8 \times 7=x \times 0.1 \\ x = \frac{8 \times 7}{0.1} \\ x = \frac{8 \times 7 \times 10}{1} \\ x = 560[/tex]

therefore, something = 560

Answer:

Step-by-step explanation:

It can end with a 0.

For example 12 * 5 = 60.

Answer:

1.05x I think

Answer:

1

Step-by-step explanation:

x + 2y = 6, multiply by 2 = 2x + 4y = 12

2nd equation:                    2x - 3y = 26

It has one solution

Answer: One solution

Step-by-step explanation:

Convert both equations into slope-intercept form:

x+2y=6

2y=6-x

[tex]y=\frac{6-x}{2}[/tex]

Slope = 6/2 = 3

2x-3y=26

y=2x-26/3

Slope = 2/3

Therefore, he system of equations have one solution because their slopes are not equal.  

Step-by-step explanation:

Length of the Rectangular piece of the land = 12 + 1/2 m = 25/2 m

Breadth of the Rectangular piece of the land = 5 + 1/5 m = 26/5 m

If 4 small square flower bed of side length 1 m are made at center.

To find: Area of the rectangular land , Perimeter of the rectangle and Area of land left when flower bed are mad.

Perimeter of the rectangle = 2 × ( length + breadth )

= 2 × ( 25/2 + 26/5 )

= 2 × ( 177/10 )

= 177/5 m

= 35.4 m

Area of the rectangular land = Length × Breadth

= 25/2 × 26/5

= 5 × 13

= 65 m²

Area of a flower bed = side × side = 1 × 1 = 1 m²

Area of 4 flower bed= 4 × 1 = 4 m²

Area left in the land = 65 - 4 = 61 m²

Therefore, Perimeter of the land is 35.4 m

Area of land is 65 m²

Area of the land left after flower beds is 61 m²