How can we explain the motion of objects?

Answers

Answer 1
All things move based on how much mass they have and it’s relevance to gravity/distance from the ground. As objects moved, force is moving them. An example would be a wagon on a hill. If the wagon is on wheels at the top of the hill and someone uses force to make the wheels move, the wagon will roll down the hill due to inertia and other elements.

Related Questions

Fill in the reaction type and predicted products for:

Fe3O4 (s) → ??

Type in the IUPAC name or formula for each product.
Write subscripts as normal numbers.
If there is no second product, type "nothing".
The reaction type is
Question Blank 1 of 3

.
The correct products are:
Question Blank 2 of 3

and
Question Blank 3 of 3

Answers

Needs more explaining

please help, i will mark you as brainliest​

Answers

Hey , This photo is only a small part , you can find it on gg, search Reactivity Series , it will show all^^

How would I Determine the number of moles in 3.51 x 10^23 formula units of CaCl2

Answers

Answer:

by using this formula you will get it

Explanation:

number of mole = number of particles÷ Avogadro's number

n=3.51×10^23÷ 6.02×10^23

n = 0.58 moles

There are 3 reactions of Calcium Carbonate, CaCO₃, that can be formed in this particular problem:

Reaction 1: Calculate the ΔH₁
Reaction 2: ΔH₂ = -635.1 kJ
Reaction 3: ΔH₃ = 178.3 kJ

Answers

ΔH₁ = ΔH₂ - ΔH₃

ΔH₁ = -635.1-(178.3) KJ

ΔH₁ = -813.4 KJ

In the reaction A+B - C+D, if element B is in excess, then-

Answers

Answer:

Explanation:

Determining the Limiting Reagent

One reactant (A) is chosen, and the balanced chemical equation is used to determine the amount of the other reactant (B) necessary to react with A. If the amount of B actually present exceeds the amount required, then B is in excess, and A is the limiting reagent.

An engine cylinder contains 175 mL of gas at a pressure of 1.0 atm. As the engine runs, it compresses the cylinder, reducing the volume of the gas to 15 mL. What is the new pressure of the gas at this volume?

Answers

This problem is providing the initial volume and pressure of a gas in an engine cylinder and asks for the final pressure once the volume of the gas has decreased due to a compression. At the end, the result turns out to be 11.7 atm.

Boyle's law

In chemistry, gas laws allow us to calculate pressure, volume, temperature or moles depending on a specified change and based on the concept and equation of the ideal gas, which derives the well-known gas laws; Boyle's, Charles', Gay-Lussac's and Avogadro's.

Thus, since this problem provides initial and final volume and initial pressure for us to calculate the final pressure, we understand we need to apply the Boyle's law as a directly proportional relationship between these two:

[tex]P_1V_1=P_2V_2[/tex]

Thus, we solve for the final pressure, P2, to get:

[tex]P_2=\frac{P_1V_1}{V_2}=\frac{1.0atm*175mL}{15mL}\\ \\ P_2=11.7atm[/tex]

Learn more about ideal gases: brainly.com/question/8711877


What is the relationship between temperature and kinetic energy?

Answers

Answer:

substance is related to the average kinetic energy of the particles of that substance

Explanation:

Answer:

As stated in the kinetic-molecular theory, the temperature of a substance is related to the average kinetic energy of the particles of that substance. When a substance is heated, some of the absorbed energy is stored within the particles, while some of the energy increases the motion of the particles.

Explanation:

hope it will help you have a great day bye and Mark brainlist if the answer is correct

[tex]kai6417[/tex]

#carry on learning

can you please help me out with this​

Answers

Answer:

Explanation:uum i cant see anything but yeah I think its c

1) How many moles of gas occupy 58 L at a pressure of 2.2 atmospheres and a temperature
of 313 K?

Answers

Here, we need to solve this problem using Ideal gas law ( PV=nRT).

Where –

P = Pressure in atmV = Volume in Ln = moles R = Ideal gas law constant T = Temperature in K

Now, according to the question

V = 58 L P = 2.2 atmT = 313 KR = 0.0821 atm L/ mol K

Calculation

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf PV = nRT}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf n = \dfrac{PV}{RT}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf n = \dfrac{ 2.2 \: \:\times 58 \: } {0.0821 \times 313}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf n = \dfrac{ 2.2 \times 58}{0.0821 \times 313} [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf n =\dfrac{127.6}{25.7}[/tex]

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf n = 4.9656 \: moles }[/tex]

_______________________________________

Given Information ,

Volume ,V = 58 LPressure ,P = 2.2 atmTemperature ,T = 313

We have to find the number of moles .

We use here " Ideal Gas Equation" which is

PV = nRT

where

n is number of moles

R is universal gas Constant

T is temperature

P is pressure

V is volume

On substituting the value we get

➣ 2.2 × 58 = n × 0.0821 × 313

➣ 127.6 = n × 25.70

➣ 127.6/25.70 = n

➣ 4.96 = n

➣ 5 ≈ n

So, the number of moles are 5 .

Identify the following reactions as combination, decomposition, or combustion reactions


C7H8 + 9O2 → 7CO2 + 4H2O ______________

2NaHCO3 → Na2CO3 + H2O + CO2 ___________

CH4 → C + 2H2O ________________

P4O10 + 6H2O → 4H3PO4 ______________

FeSO4 → FeO + SO3 _______________

CaCO3(s) → CO2(g) + CaO(s) _________________

Answers

Answer:

1. combustion

2. decomposition

3. decomposition

4. combination

5. decomposition

6. decomposition

Explanation:

combination of a reaction is when 2 more or elements/ compounds combine to form a compound. example: (A+B→AB)

decomposition of a reaction is when a chemical breakdown. example: (AB→A+B)

a combustion reaction is when an element/ compound reacts with oxygen to form the product of water and carbon dioxide.

example: ( [tex]C_{x}[/tex] [tex]H_{y}[/tex] + [tex]O_{2}[/tex] → [tex]H_{2}[/tex]O + [tex]CO_{2}[/tex] )

Please help! THIS IS DUE IN A HOUR!
I will give you brainliest if you help me! I’ll vote and heart it.

1. Calculate the energy of an X-ray photon if the wavelength is 5.00x10^-10m?

2. (use picture) Determine the energy related to an electron occupying the ground state a Hydrogen atom given its bright-line spectrum below (the one to the left with least frequency):

3. A laser used to detach retinas produces radiation with a frequency of 4.6x10^14 Hz. What is the wavelength of this light?

Answers

[tex]\bold{\huge{\pink{\underline{ Answer }}}}[/tex]

Concept Used :-

Here, we will use the concept of planks quantum theory .

According to planks quantum theory :-

The radiant energy is emitted discontinuously in the form of small packets of energy called quantaIn case of lights, It is called photons The amount of energy with each quantum of radiation is directly proportional to the frequency of light That is, E = hv or E = hc/ λThe total amount of energy emitted or a absorbed will be whole number multiple of quantum That is, E = nhv or nhc/λ

Answer 1 :-

Here,

We have to calculate the energy of an X photon

The wavelength is 5.00 × 10^-10The value of planks constant h is 6.626 × 10^-34 .

According to the planks quantum theory of radiation :-

[tex]\bold{\pink{ E = hv }}[/tex]

[tex]\sf{ E = h}{\sf{\times{\dfrac{c}{λ}}}}[/tex]

The value of c is 3 × 10^8

Subsitute the required values,

[tex]\sf{ E = 6.626 × 10^{-34} }{\sf{\times{\dfrac{3 × 10^{8}}{5 × 10^{-10}}}}}[/tex]

[tex]\sf{ E = }{\sf{\dfrac{19.87× 10^{-26}}{5 × 10^{-10}}}}[/tex]

[tex]\sf{ E = 3.974 × 10^{-36}}[/tex]

Hence, The energy of an X ray photon is 3.974 × 10^-36

Answer 2 :-

We have ,

Frequency = 4.57 × 10^14 HzPlanks constant = 6.626 × 10^-34

According to the planks quantum theory,

[tex]\bold{\pink{ E = hv }}[/tex]

Subsitute the required values,

[tex]\sf{ E = 6.626 × 10^{-34}× 4.57 × 10^{14}}[/tex]

[tex]\sf{ E = 30.28 × 10^{- 20}}[/tex]

[tex]\sf{ E = 3.028 × 10^{ - 19}}[/tex]

Hence, The energy related to an electron occupying the ground state of hydrogen atoms is 3.028 × 10^-19

Answer 3 :-

We have ,

Frequency = 4.6 × 10^14 Hz

We know that,

[tex]\bold{\pink{ v = }}{\bold{\pink{\dfrac{ c }{λ}}}}[/tex]

[tex]\sf{ λ = }{\sf{\dfrac{ c }{v}}}[/tex]

Subsitute the required values,

[tex]\sf{ λ = }{\sf{\dfrac{ 3 × 10^{8} }{4.6 × 10^{-14}}}}[/tex]

[tex]\sf{ λ = 0.65 × 10^{22}}[/tex]

Hence, The of this light is 0.65 × 10^22 .

[ Note :- Kindly refer answer in the app]


How many moles (of molecules or formula units)
are in each sample?
75.83 g CF2Cl2

Answers

0.627 moles. Use dimensional analysis grid as shown (multiply across, divide by the bottom number)

1. Consider the following reaction where Kc = 1.29×10-2 at 600 K.

COCl2(g) CO(g) + Cl2(g)

A reaction mixture was found to contain 9.87×10-2 moles of COCl2(g), 2.19×10-2 moles of CO(g), and 3.79×10-2 moles of Cl2(g), in a 1.00 liter container.

Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?

The reaction quotient, Qc, equals _____
The reaction:
A. must run in the forward direction to reach equilibrium.
B. must run in the reverse direction to reach equilibrium.
C. is at equilibrium.

2. Consider the following reaction where Kc = 55.6 at 698 K.

H2(g) + I2(g) 2HI(g)

A reaction mixture was found to contain 2.59×10-2 moles of H2(g), 4.38×10-2 moles of I2(g) and 0.294 moles of HI(g), in a 1.00 liter container.

Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?

The reaction quotient, Qc, equals ____

The reaction:
A. must run in the forward direction to reach equilibrium.
B. must run in the reverse direction to reach equilibrium.
C. is at equilibrium.

Answers

Answer:

Consider the following reaction where Kc = 1.29×10-2 at 600 K:

COCl2(g) <=> CO(g) + Cl2(g)

A reaction mixture was found to contain 9.85×10-2 moles of COCl2(g), 2.61×10-2moles of CO(g), and 3.71×10-2 moles of Cl2(g), in a 1.00 Liter container.

Indicated true (T) or false (F) for each of the following:

How are water particles affected by the movement of a wave?

The wind pushes the water particles down to deeper depths.
O The wave pushes the water particles back and forth.

The water particles move in an upward motion through the wave.
The water particles move in a circular pattern.

Answers

Answer:

The water particles move in an upward motion through the wave.

Explanation:

When water particles become part of a wave they start to move up or down.

Answer:

u deleted my answer before so

Explanation:

What is the mass in grams of 3.01 X 1023 atoms of the element chlorine, Cl? (Please show step by step)!

Answers

Answer: the mass of 3.01 atoms of chlorine is 35.46/2 = 17.73 g.

Explanation: hope its correct

step by step: molar mass: (2 x 35.46) g/mol = 70.92 g/mol

1 mole chlorine = 6.02 x 10^23 molecules of chlorine.

Mass of 6.02 x 10^23 molecules chlorine = 70.92 g

Mass of 3.01 x 10^23 molecules chlorine = 70.92 x(3.01 x 10^23)/(6.02 x 10^23)g

= 35.46 g

Which chemicals are only present at point “x”?

Answers

Is 5 check my pin to view

A radioactive isotope that can be followed through a chemical reaction or industrial process is called a/an what? (needs answer asap!!!!!)

Answers

a radioactive isotope that can be followed through a chemical reaction or industrial process is called a radiotracer

i’m trying to figure out how to convert 6 moles KCL to particles.

Answers

Answer:

How many moles KCl in 1 grams? The answer is 0.013413582325

1 mole is equal to 1 moles KCl, or 74.5513 grams.

447.3078 is the answer

Explanation:

~Cornasha_Weeb

what is the conversion factor for in^3 to cm^3

Answers

You multiply by 16.3871

According to the following reaction, how many grams of oxygen gas are required for the complete reaction of 21.2 grams of hydrogen sulfide?

hydrogen sulfide (g) + oxygen (g) water (l) + sulfur dioxide (g)

_____grams oxygen gas

Answers

Answer:

29.9g please refer to the picture for work

If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical formula

Answers

he required empirical formula based on the data provided is Na2CO3.H2O.

What is empirical formula?

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : https://brainly.com/question/11588623

What’s (CH3)2CHCCCH3.

Answers

Answer:

4-methly-2-pentyne

Explanation:

the inner part of the ovary that contains an egg is the ovule
true or false

Answers

Answer:

The answer is true

Explanation:

the ovary is a tubular structure and contains ovules

hi everyone, I am getting stuck in this question can you tell me it please ,what are the property's of a metal and a non-metal​

Answers

Answer:

Explanation:

Properties of Metal

1. Metals are ductile. ...

2. Metals are a good conductor of heat and electricity.

3. Metals have high tensile strength. .

4. Metals are sonorous.
5. Metals are hard.


Properties of non metal

1. High ionization energies.

2. High electronegativities.

3. Poor thermal conductors.

4. Poor electrical conductors.

5. Brittle solids—not malleable or ductile.

6. Little or no metallic luster.

7. Gain electrons easily.

true or false: chemical reactions are usually written left to right

Answers

True:

it is always reaction-> product

H2+O-> H2O

Given that for Fe2O3 (s) the standard enthalpy of formation is −824.2 kJ/mol and the enthalpy of reaction is −851.5 kJ/mol, what is the enthalpy of formation for Al2O3 (s)?

Answers

This problem is providing us with the enthalpy of formation of Fe2O3 (s) and the enthalpy of reaction when it reacts with Al to form Al2O3 (s) and Fe. Thus, the enthalpy of formation of Al2O3 (s) is required and found to be -1675.7 kJ/mol as follows.

Enthalpy of reaction.

In chemistry, the heat involved in a chemical process can be quantified via the difference in the overall enthalpy of products minus that of reactants:

[tex]\Delta H_r=\Delta H_{products}-\Delta H_{reactants}[/tex]

Now, with the given reaction:

[tex]Fe_2O_3 (s) + 2 Al (s) \rightarrow 2 Fe (s) + Al_2O_3 (s)[/tex]

One can see both Al and Fe have zero as their enthalpies of formation for they are elements. In such a way, one can rearrange the previous formula as:

[tex]\Delta H_r=\Delta H_{Al_2O_3}-\Delta H_{Fe_2O_3}[/tex]

And hence plug in the given energies in order to find the required:

[tex]-851.5kJ/mol=\Delta H_{Al_2O_3}-(-824.2kJ/mol)\\\\\Delta H_{Al_2O_3}=-851.5kJ/mol+(-824.2kJ/mol)\\\\\Delta H_{Al_2O_3}=-1675.7kJ/mol[/tex]

Learn more about enthalpy of reaction: https://brainly.com/question/8055290

Carbon substances can have very different properties because...
O A. carbon is almost never found as an element
O B. carbon atoms are very unstable
O c. carbon atoms can be arranged in different ways
O D. carbon atoms are not attracted to each other

Answers

Answer:

Calculate the volume (in mL) of the 1.356 M stock NaOH solution needed to prepare 250.0 mL ... Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar ... g of glucose in enough water to make 500.0 mL of solution. • Step 2: Transfer 18.6 mL of the

Explanation:

The rate of the given reaction is 0.840 M/s.
A +4B - 2C
What is the relative rate of change of each species in the reaction?

Answers

This problem is providing the rate of the given reaction as 0.840 M/s and asks for the relative rate of change of each species. At the end, the results turned out to be -0.840 M/s, 0.210 M/s and 0.420 M/s for A, B and C respectively.

Relative rate of change

In chemical kinetics, when chemical reactions take place, it turns out possible for us to quantify in what extent a reaction is proceeding over time, by overseeing the change in the concentration as the time goes by.

In such a way, when given the rate of reaction, one can calculate the relative rate of change of each species by using the following equation, involving their stoichiometric coefficients in the reaction:

[tex]r_A=\frac{r}{-1} \\\\r_B=\frac{r}{-4} \\\\r_C=\frac{r}{2}[/tex]

Where these coefficients are negative for reactants and positive for products. In such a way, one can plug in the given rate of reaction to obtain each species' as follows:

[tex]r_A=\frac{0.840M/s}{-1} =-0.840M/s\\\\r_B=\frac{0.840M/s}{-4} =0.210M/s\\\\r_C=\frac{0.840M/s}{2}=0.420M/s[/tex]

Learn more about chemical kinetics: brainly.com/question/26351746

Solve for the molecular/formula mass of the following compounds.

1. Silicon dioxide, SiO2
2. Sodium hydroxide, NaOH
3. Calcium carbonate, CaCO3
4. Sodium carbonate, Na2Co3
5. Silver nitrate, AgNO3
6. Iron oxide, FeO.
7. Phosphoric acid, H2PO4
8. Sodium bicarbonate, NaHCO3
9. Acetic acid, CH3COOH
10. Sodium fluoride, NaF​​

Answers

Answer:

what you need to do is,

you take the relative atomic mass of each element and multiply it by the no of atoms it has. do this for all the elements present, and add the values. that's it!

Explanation:

try to do the last one by yourself, it is easy and you will be using the molecular/formula mass mostly everywhere in chemistry.

Calculate the mass of aluminium oxide which contains double the number of oxygen atoms in 192 g of oxygen gas.​

Answers

Answer:

648

Explanation:

what you're going to do your first is to convert the 192g to number of atoms

firstly you are going to convert 192 to moles using the formula reacting mass all over molar mass, into it that you're going to get 12 as your answer, you Dey multiply the 12 to avocados constant

in doing that you have I've gotten the number of atoms present in 192 g of oxygen

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