Hi my teacher gave me this and i have absolutely no idea how to complete this please helpNumber 1

33.136 grams of ethylene glycol should be mixed with  375 ml of Water to make a 7.50% by Mixture.

Density is the measure of how much “stuff” is in a given amount of space.

DENSITY = MASS / VOLUME

We have :-

→ Density of ethylene glycol = 1.09 g/mL

→ Volume of water = 375 mL

→ Concentration (v/v %) = 7.50 %

Let the volume of ethylene glycol (solute) be 'x' mL .

So, volume of the solution = Volume of solute + Volume of solvent

                                              = (x + 375) mL

Concentration (v/v %) = Vol. of solute/Vol. of solution × 100

⇒ x/(x + 375) × 100 = 7.5

⇒ 100x = 7.5(x + 375)

⇒ 100x = 7.5x + 2812.5

⇒ 100x - 7.5x = 2812.5

⇒ 92.5x = 2812.5

⇒ x = 2812.5/92.5

⇒ x = 30.4 mL

Mass of ethylene glycol = Volume × Density

                                          = 30.4 × 1.09 = 33.136 g

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Answer ans explanation

2.51x10^4 - 1.5x10^3 = 2.36^4

Answer

2.36^4

Answer:

Explanation:

Here, we want to get the maximum amount of ammonia that can be produced

From the question, we have it that:

1 mole nitrogen gave 2 moles ammonia

Thus:

4 mole nitrogen will give 8 moles ammonia

Furthermore:

3 moles of hydrogen gave 2 moles of ammonia

5 moles of hydrogen will give:

The maximum amount of ammonia that can be produced is thus 8.0 moles

Answer:

8

Explanation:

All noble gases have 8 electrons in their outermost shell and are in an octet state.

−791.4 kJ is the standard enthalpy change for the reaction.

Given,

SO2(g) → S(s) + O2(g)

ΔH° = +296.8 kJ

2SO2(g) + O2(g) → 2SO3(g)

ΔH° = −197.8 kJ

Modified equation:

S(s) + 2O2(g) → 2SO2(g)

ΔH° = −593.6 kJ, multiply by 2 and flip

2SO2(g) + O2(g) → 2SO3(g)

ΔH° = −197.8 kJ here no change

The 2SO2 will balance out by canceling it when the equations are added. Add the enthalpies for the final answer:

−593.6 + (−197.8) = −791.4 kJ

The change in enthalpy of a compound when one mole of the compound is generated from all components of the same constituent is known as the standard enthalpy of formation, also known as the standard heat of formation.

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Assuming all the HCl presend in the 24.06mL reacted, we can follow the steps:

1 - Use the concentration and the volume to calculate the number of moles of HCl that reacted

2 - Apply the stoichiometry ratios to calculate the number os moles of Fe that reacted

3 - Use the tomic weight of Fe to calculate the mass of that amount of number of moles of Fe.

1 - The concentration is given by the equation:

The number of moles of solute is the same as the number of moles o HCl, because it is the solute in this case:

So, we have:

2 - The coefficients of Fe and HCl are 1 and 2, respectively, so we have the following relation between their number of moles:

Fe --- HCl

1 --- 2

3 - The atomic weight of Fe can be checked on a periodic table:

So, we have:

So, there was approximately 3.76 g of Fe.

Answer

Explanation

Part A

Given:

a) N₂ (g) + 3H₂ (g) -----> 2NH₃ (g)

[N₂ ]eq = 1.50 M, [H₂ ]eq = 2.00 M, [NH 3 ]eq = 0.01 M

Solution:

i. The equilibrium constant expression for the reaction is

Explanation:

Iron (III) nitrate is a soluble salt. When dissolved in water it will dissociate into its ions: Iron (III) and nitrate.

Fe(NO₃)₃ (aq) ----> Fe³⁺ (aq) + 3 NO₃⁻ (aq)

Answer: Fe³⁺ and NO₃⁻.

Answer:

What??

I dont understand the questii

The core is denser than the mantle.

The Earth is partitioned into three primary layers. The hot inner core, the molten outer core, the mantle, and  where the thin crust, support all life within the known universe. Most of the Earth's insides are made up of the mantle, the layer of molten rock underneath the strong outside, and the hot, dense core. As the mass and  the volume of the mantle are greater than the core's mass which  leads the mantle of  having a low density. as a result the core is considered to be  having  more density than the mantle in spite of the  mantle having  more mass.

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The heat capacity corresponds to the energy needed to raise one degree of temperature for one gram of substance. That is, the greater the heat capacity, for the same mass, the greater the energy required to raise the temperature of the material.

Therefore, between the two metals with the same mass, the same initial temperature, and the same heat added, we can say that the one with the higher heat capacity will present a lower final temperature.

A competitive inhibitor physically mimics the substrate for a specific enzyme and engages in binding competition with the substrate at the enzyme's active site.

A noncompetitive inhibitor can bind to either the free enzyme or the enzyme-substrate complex and binds at a location different from the active site.

The substrate cannot attach to the active site because the competitive inhibitor is bound there. The noncompetitive inhibitor attaches to a different spot on the enzyme.

The inhibitor binds at an allosteric location apart from the active site of substrate binding in noncompetitive inhibition. Therefore, in noncompetitive inhibition, the inhibitor can attach to its target enzyme even if a bound substrate is present.

Inhibitors that are non-competitive can bind to both the enzyme and the enzyme-substrate complex. Uncompetitive inhibitors only bind to the complex of the enzyme and substrate.

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To determine the percentage of oxygen in the molecule we must first know its structure and how many oxygen atoms are contained in it. The structure of aluminum phosphate is AlPO4.

It means that there are 4 oxygen atoms, 1 Aluminum atom, and 1 phosphate atom.

Now we will determine the weight of the molecule AlPO4 by adding the atomic weights of the elements as follows:

Element Atomic mass # of atoms Mass

Al 26.9815 1 26.9815

P 30.9738 1 30.9738

O 15.999 4 63.996

Total mass of AlPO4 = 26.9815+30.9738+63.996 = 121.9513 g/mol

Now we will determine the mass percentage with the following equation:

We replace the known terms:

So, the percentage of oxygen in aluminum phosphate is 52.477%

1) Identify the curve of the solute.

2) Look for the grams of solute in the vertical axis.

3) Go down looking for the temperature

The minimum temperature at which 59 g of NH4Cl would completely dissolve in 100 g H2O is 70ºC.

Calcium carbonate (CaCO3) is not an organic substance since it only contains one of the two elements—carbon or hydrogen.

To identify whether a compound is organic, it is important to check:

If a compound contains one of two elements, that is Carbon or Hydrogen, then it is not an organic compound.

Carbohydrates are a common type of organic compound. Carbohydrates contain the chemical formula (CH2O)n.

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To analyze the equilibrium and how it shifts aaccording to Le Châtelier’s principle, we have to see how the system reacts to the change.

The change is an increase in the volume of the container. Since all the compounds on equilibrium are in gaseous state, their volume is the same as its container, so an increase in the volume of the container increase the volume of the compounds.

The reactant is SI₃, but we have 2 of them for each reaction.

The products are 2 molecules of SO₂ and one molecule of O₂.

In total for each reaction, we have 2 molecules in the reactant part and 3 molecules in the product part.

Since they are all in gaseous form, this means that the products occupy more space than the reactants, that is, an increase in the volume will favor the products, because this increase will left more space for them to occupy.

Thinking in preassure, an increase in the volume will decrease pressure, because, by the Boyle's Law, they are inversely proportional (assuming ideal gas). Since there are more molecules per reaction on the products side, this will favor the products, since more molecules make more pressure and now it has been decreased.

Thus:

Increase in volume -> decrease in pressure -> favors the products.

This matches alternative B.

Answer:

Explanation:

Here, we want to get the metric prefix m value

This means we want to get power to which it would be raised

Mathematically,we have this as the milli

The milli refers to thousandth

From what we have here, this is the power of -3

So the prefix m represents :

The volume of a substance at STP for one mole is 22.4 L. The volume of oxygen required to react with excess of carbon sulphide to produce 4 L of carbon dioxide 4.0 L is 12 L.

Volume of a substance is the space occupied by the particles of the substance. As the temperature increase, volume also increases. The volume of one mole of every substance at standard temperature and pressure is 22.41 L

According the balanced reaction given, 3 moles of O₂ is required to produce one mole carbon dioxide. One mole of O₂ is 22.4 L. Thus volume of 3 moles of oxygen is calculated as follows:

Volume of O₂= 3×22.41 =67.2 L.

Thus, 67.2 L of O₂ produces one mole or 22.4 L of carbon dioxide.

The volume O₂ required to produce 4 L of carbon dioxide is calculated as follows:

Volume of O₂ = (67.2 L × 4 L) / 22.41 L

                       = 12 L.

Therefore, the volume of oxygen molecule required to produce 4 L of carbon dioxide on the reaction with excess of carbon sulphide is 12 L.

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The mass of lithium nitrate that needs to de dissolved in 30.0g of water in order to make 18% solution is 6.58 grams.

The Percentage Concentration of a solution is the calculation of concentration of an element in a solution using the masses of solute/solvent and solution. It can be defined by the formula:

=> Percentage = (Mass of solute/Mass of solution)*100

The density of water is 1 gm/cm³, so the mass of 30.0g of water is 30ml. 18% concentration is given. The formula for percentage of concentration is given as

Percentage = (Mass of solute/Mass of solution) × 100

Here, Mass of solute is m, Mass of solution is m+30, and percentage is 18, So we get

=> 18 = (mass of solute/Mass of solution) × 100

=> 18 = (m/m+30)*100

=> 18(m+30) = m

=> 18m + 540 = 100m

=> 82m = 540

=> m = 6.58

Hence, the mass of lithium nitrate dissolved in 30g water to make 18%  solution is 6.58g.

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Answer:

Aluminium, Thorium, Barium and Strontium. Nonmetals will be : Fluorine, Phosphorus and Krypton. Metalloids will be : Gallium and Tellurium.

The kind of bonds that can be formed between each of the atoms is;

The ionic bond is the kind of bond that is formed between two atoms in a compound when there is a complete transfer of electrons between the atoms in the compound.

A covalent bond is said to be formed between two atoms when there is a sharing of the electrons that can be found between two atoms. We know that a bond is ionic when the difference in the electronegativity of the atoms is high.

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BaSO₄. Option C is correct

The substances that dissolve readily in water are ionic compounds and polar covalent compounds. Examples of ionic compounds that dissolve in water are salts, oxides, hydroxides, sulfides, and the majority of inorganic compounds.

The molecules in a polar solvent have a dipole, like water, one side is more negative and one is more positive.

Ionic compounds are composed of a positive ion, normally a metal, and a negative ion, normally a nonmetal, so their forces are attracted to their charge difference.

Thus, a polar solvent dissolves each ion with its corresponding parts, dissociating the two ions of the ionic compound.

Since sulfides are ionic compounds hence the substance that will dissolve most readily in water is BaSO₄. The molecule is formed by one barium cation Ba2+ and one sulfide anion S2-. The two ions are bound through an ionic bond.

Answer:

Dry ice becoming vapor.

Explanation:

In a physical change, the substance is the same, but in this case, it changes state from solid to vapor.

Answer

Mass of carbon = 4.069 g

Explanation

Given:

Number of atoms = 2.04x10^23 atoms

Required: Mass of carbon

Solution

Step 1: Find the number of moles of carbon

1 mole = 6.022x10^23 atoms

x moles = 2.04x10^23 atoms

Solve for x

x = (2.04x10^23 atoms x 1 mole)/6.022x10^23 atoms

x = 0.339 mol

Step 2: From the moles, calculate the mass of carbon

m = n x M where m is the mass, n is the moles and M is the molar mass of carbon

m = 0.339 mol x 12,011 g/mol

m = 4.069 g

Answer

D) CO₃²⁻, F⁻

Explanation

A Brønsted-Lowry acid is a compound that supplies a hydrogen ion in a reaction. A Brønsted-Lowry base, conversely, is a compound that accepts a hydrogen ion in a reaction. Thus, the Brønsted-Lowry definitions of an acid and a base focus on the movement of hydrogen ions in a reaction, rather than on the production of hydrogen ions and hydroxide ions in an aqueous solution.

HCO₃⁻ (aq) + F⁻ (aq) = CO₃²⁻ (aq) + HF (aq)

Therefore, in the reaction above, the species that is/are Bronsnsted-Lowry base(s) are CO₃²⁻ and F⁻

Thus, the correct answer is: D) CO₃²⁻, F⁻

A drop of water is denser than a ping-pong ball.

Usually, water is made of particles that are firmly pressed together. In differentiation, plastic (the material ping pong balls are made of) may be a lightweight fabric and the particles are not as firmly stuffed together.

The thickness of a ping pong ball is 0.0840 g/cm³, though water’s thickness is 997 kg/m³. Subsequently, ping pong balls aren’t about as thick as water and will continuously coast and surface greatly quickly.

The ping pong ball appears to oppose gravity and coast within the air.

Ping-pong balls drift within the water since they are amazingly lightweight, empty, and filled with air. Too, the water’s surface pressure makes it simple for the ping pong ball to drift.

In expansion, water is denser than ping pong balls, making them look for the most noteworthy point of water.

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The standard electrode potential value of a cell can be calculated from the reduction potentials of the electrodes. The standard electrode potential  E⁰ of the voltaic cell with Ni electrode and iron electrode is 0.19 V.

The reduction potential of an electrode at standard conditions that is at 298 K and 1 bar pressure is called standard electrode potential.

There are two types of electrodes in a cell called cathode and anode. Cathode is the electrode at which reduction occur where as the electrode which undergo oxidation is called anode.

The standard electrode potential of a cell can be measured  as follows.

[tex]E^{0} _{cell} = E^{0} _{cathode} - E^{0} _{anode}[/tex]

Here, the anode is Fe electrode with a standard electrode potential  of -0.44 V and the anode is Ni electrode having -0.25 V reduction potential.

Thus the standard electrode potential of the voltaic cell can be calculated as follows:

[tex]E^{0} _{cell} = E^{0} _{Ni^{2+}/Ni} = E^{0} _{Fe/Fe^ {2+}}[/tex]

       = (-0.25 v) - (-0.44 v)

       = 0.19 V.

Hence, the standard electrode potential of the cell E⁰ containing Ni electrode and Fe electrode is 0.19 V.

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