help with parallel lines please

well, the opening price was "x", which oddly enough is the 100%, however during the trading of the day the company gained 3.5%, so that'd be 100% + 3.5% = 103.5%, and we know that that is 16.56, so

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 16.56&103.5 \end{array}\implies \cfrac{x}{16.56}=\cfrac{100}{103.5}\implies 103.5x=1656 \\\\\\ x=\cfrac{1656}{103.5}\implies x=16[/tex]

from the conclusion that I'm of and dont I feel like the answer is letter C I'm not sure

Answer:

x=30 degrees

If you replace the x with 30, it will all equal 180 which is the total you should get when making the triangle in a straight line. (not good english)

Answer:

36 minutes

Step-by-step explanation:

100 boxes in 3 hours is a rate. It is how fast you are working in boxes per hour 100/3 boxesperhour.

But 3 doesn't go into 100 very neatly and its going to make all kinds of ugly fractions or decimals. But lets look at minutes. 3 hours is 3 × 60 minutes (bc there's 60 minutes in an hour) So you loaded 100 boxes in 180 minutes. That's 100/180 boxes per minute.

100/180 = 10/18

10/18 means 10 boxes in 18 minutes.

So times 2 on the top and the bottom gives you 20/36.

20/36 means 20 boxes in 36 minutes.

This is your answer. It will take 36 minutes to load 20 more boxes.

s + 2h = 7

s + 4h = 12

s = 12 - 4h

12 - 4h + 2h = 7

- 2h = -5

2h = 5

hotdog = $2.50

s = 12 - 10

soda = $2

Answer:

(i) 64°

(ii) 26°

Step-by-step explanation:

Answer:

(i) m<ADB = 64°

(ii) m<ACD = 26°

Step-by-step explanation:

I use this to mean the measure of angle ADC: m<ADC

(i)

m<BEC = 52°

<DEA and <BEC are vertical angles, so they are congruent.

m<DEA = m<BEC = 52°

Polygon ABCD is a rectangle. When the diagonals, AC and BD, of a rectangle are drawn, 4 triangles are formed. Each two opposite triangles are congruent, and all 4 triangles are isosceles.

Triangle ADE is an isosceles triangle with congruent sides ED and EA. That makes opposite angles ADB and DAC congruent. Also the sum of the measures of the angles of a triangle is 180°.

m<ADB + m<DAC + m<DEA = 180°

m<ADB = m<DAC; m<DEA = 52°

2m<ADB + 52° = 180°

2m<ADB = 128°

m<ADB = 64°

(ii)

Angles DEC and BEC form a linear pair. That means the angles are supplementary, and the sum of their measures is 180°.

m<DEC + m<BEC = 180°

m<DEC + 52° = 180°

m<DEC = 128°

Triangle DEC is an isosceles triangle with congruent sides ED and EC. That makes opposite angles ACD and BDC congruent.

m<ACD + m<BDC + m<DEC = 180°

2m<ACD + 128° = 180°

2m<ACD = 52°

m<ACD = 26°

Answer:

Constant of proportionality: [tex]\frac{1}{3}[/tex]

Equation: [tex]y=\frac{1}{3}x[/tex]

Step-by-step explanation:

The constant of proportionality is the ratio between y and x, according to the following formula

constant of proportionality = k = y/x

Take the given pairs and replace the data.

1.

[tex]k=\frac{\frac{2}{3}}{2}[/tex]

[tex]k = \frac{1}{3}[/tex]

2.

[tex]k = \frac{1}{3}[/tex]

3.

[tex]k=\frac{\frac{10}{3}}{10}[/tex]

[tex]k = \frac{1}{3}[/tex]

4.

[tex]k = \frac{4}{12}[/tex]

[tex]k = \frac{1}{3}[/tex]

As you can see, the constant is the same for all the pairs.

constant of proportionality = [tex]\frac{1}{3}[/tex]

Now, in order to know the equation make a graph of the given data.

The graph is in the picture

Since it is a line, use the equation of the line in point slope form

[tex]y- { y }_{ 1 } = m \left( x- { x }_{ 1 } \right)[/tex]

where (x1, y1) = any pair of the data

m = slope = constant of proportionality

Replace the data in the equation

[tex]y-1 = \dfrac{ 1 }{ 3 } \left( x-3 \right)[/tex]

Use the distributive property to multiply [tex]\frac{1}{3}[/tex] by x - 3

[tex]y-1=\frac{1}{3}x-1[/tex]

Add 1 to both sides

[tex]y = \dfrac{ 1 }{ 3 } x-1+1[/tex]

Add −1 and 1 to get 0

[tex]y=\frac{1}{3}x[/tex]

or

[tex]y=\frac{x}{3}[/tex]

Answer:

Train A is 168 tons and Train B is 122 tons

Step-by-step explanation:

Answer:

16.84?

Step-by-step explanation:

12.6/cos(29)=16.84

Answer:

(7, -3)

Step-by-step explanation:

If M is the midpoint you can use the same translation from A to M as M to B.

The movement from A to M is 5 units up and 3 units left, or (x+5, y-3). If we do the same movement to point M (Which is (2) +5, (0) -3) we will get (7, -3).

Answer:

the coordinates of B is B(7,-3)

Step-by-step explanation:

Solution,

Here, M(2,0) is the midpoint of a line segment joining the points A(-3,3)

and B(a,b)

Let,

(x,y)=(2,0)

(x1,y1)=(-3,3)

(x2,y2)=(a,b)

Now,

Using midpoint formula

[tex]x=\frac{x_1+x_2}{2} ,y=\frac{y_1+y_2}{2} \\\\2=\frac{-3+a}{2} ,0=\frac{3+b}{2} \\\\[/tex][Cross multiply]

[tex]4=-3+a,0=3+b\\\\4+3=a,0-3=b\\\\a=7,b=-3[/tex]

Answer:

y = -3

Step-by-step explanation:

y = x - 7

when x = 4

y = 4 - 7

y = -3

Answer:

See below.

Step-by-step explanation:

If x is 4, then replace x with 4 and simplify.

y=4-7

y=-3

-hope it helps

Answer:2.5

Step-by-step explanation:5/2=2.5

Answer:

Step 3 is right answer.

Step-by-step explanation:

He is substituting the values wrong. His 2nd step is right but as he moved to the 3rd step he put measure of angle n instead if measure if angle o

So Step 3 is right answer.

Answer:

no solution

Step-by-step explanation:

this statement states y=y

-x+3 is not equal to -x+5

Answer:

i think the answer is 12

Step-by-step explanation:

[tex] \text{Given Equation is } \frac{x}{1} = \frac{ \sqrt[3]{m + 1{ }} + \sqrt[3]{m - 1} }{ \sqrt[3]{m + 1} + \sqrt[3]{m - 1} }[/tex]

[tex]\text{On Applying componendo and dividendo, we get:-}[/tex]

[tex] \frac{x + 1}{x - 1} = \frac{( \sqrt[3]{m + 1} + \sqrt[3]{m - 1} )+ ( \sqrt[3]{m + 1}) - \sqrt[3]{m - 1} }{ (\sqrt[3]{m + 1} + \sqrt[3]{m - 1}) - ( \sqrt[3]{m + 1}) - \sqrt[3]{m - 1} } [/tex]

[tex] \implies \: \frac{x + 1}{x - 1} = \frac{2( \sqrt[3]{m + 1)} }{2( \sqrt[3]{m - 1)} } \\ \\ \implies \frac{ x + 1}{x - 1} = \frac{ \sqrt[3]{m + 1} }{ \sqrt[3]{m - 1} } [/tex]

[tex] \text{On Cubing both sides, we get} \\ \frac{(x + 1) {}^{3} }{(x - 1) {}^{3} } = \frac{m + 1}{m - 1} [/tex]

[tex]\text{Again, Applying componendo and dividendo, we get:-}[/tex]

[tex] \frac{(x + 1) {}^{3} + (x - 1) {}^{3} }{(x + 1) {}^{3} - (x - 1) {}^{3} } = \frac{m + 1 + m - 1}{m + 1 - (m - 1)} [/tex]

[tex] \implies \frac{ {x}^{3} + 1 {}^{3} + 3 {x}^{2} \times 1 + 3x \times {1}^{2} + ( {x}^{3} - 1 {}^{3} - 3x {}^{2} \times 1 + 3x \times 1 {}^{2} ) }{x {}^{3} + 1 {}^{3} + 3 {x}^{2} \times 1 + 3x \times {1}^{2} - (x {}^{3} - 1 {}^{3} - 3 {x}^{2} \times 1 + 3x \times {1}^{2}) } = \frac{2m}{2} [/tex]

[tex] \implies \frac{2x {}^{3} + 6x}{ {6x}^{2} + 2 } = \frac{m}{1} [/tex]

[tex] \implies \frac{2(x {}^{3 } + 3x) }{2(3 {x}^{2} + 1) } = \frac{m}{1} [/tex]

[tex] \implies \: x {}^{3} + 3x = 3m {x}^{2} + m \\ \\ \implies {x}^{3} - 3mx {}^{2} + 3x \\ = m[/tex]

Hope This Helps!!

Based on the calculations, the value of [tex]x^3-3mx^2+3x[/tex] is equal to m.

Given the following data:

[tex]x=\frac{\sqrt[3]{m+1} +\sqrt[3]{m-1}}{\sqrt[3]{m+1} +\sqrt[3]{m-1}}[/tex]

In order to simplify the given mathematical expression, we would apply the componendo and dividendo rule because it would the number of expansions as follows:

[tex]\frac{x}{1} =\frac{\sqrt[3]{m+1} +\sqrt[3]{m-1}}{\sqrt[3]{m+1} -\sqrt[3]{m-1}}\\\\\frac{x+1}{x-1} =\frac{(\sqrt[3]{m+1} +\sqrt[3]{m-1})+(\sqrt[3]{m+1} -\sqrt[3]{m-1})}{(\sqrt[3]{m+1} +\sqrt[3]{m-1})-(\sqrt[3]{m+1} -\sqrt[3]{m-1})}\\\\\frac{x+1}{x-1} =\frac{\sqrt[3]{m+1} +\sqrt[3]{m-1}+\sqrt[3]{m+1} -\sqrt[3]{m-1}}{\sqrt[3]{m+1} +\sqrt[3]{m-1}-\sqrt[3]{m+1} +\sqrt[3]{m-1}}\\\\\frac{x+1}{x-1} =\frac{2(\sqrt[3]{m+1})}{2(\sqrt[3]{m-1})} \\\\\frac{x+1}{x-1} =\frac{\sqrt[3]{m+1}}{\sqrt[3]{m-1}}[/tex]

Taking the cube of both sides, we have:

[tex](\frac{x+1}{x-1})^3 =(\frac{\sqrt[3]{m+1}}{\sqrt[3]{m-1}})^3\\\\\frac{(x+1)^3}{(x-1)^3}=\frac{m+1}{m-1}[/tex]

Applying the componendo and dividendo rule, we have:

[tex]\frac{(x+1)^3+(x-1)^3}{(x-1)^3-(x-1)^3}=\frac{m+1+(m-1)}{m-1-(m-1)}\\\\\frac{(x+1)^3+(x-1)^3}{(x-1)^3-(x-1)^3}=\frac{2m}{2} \\\\\frac{(x+1)^3+(x-1)^3}{(x-1)^3-(x-1)^3}=m\\\\\frac{2x^3+6x}{6x^2+2} =m\\\\\frac{2(x^3+3x)}{2(3x^2+1)} =m\\\\\frac{x^3+3x}{3x^2+1} =m\\\\x^3+3x=m(3x^2+1)\\\\x^3+3x=3mx^2+m\\\\x^3-3mx^2+3x=m[/tex]

Read more on componendo and dividendo here: https://brainly.com/question/134857

Answer: Check the picture below.

Make sure your calculator is in Degree mode.

the question "how long is the kite?" is not quite clear, i suppose it was asking how far it was from the ground (b) or horizontally (a). I calculated both, I hope this helps

an equal distance = arithmetic sequence

xn= a+d(n-1)⇒ x₁ = a

x₅ - x₁ = 80

x₁ + 4d - x₁ = 80

4d = 80

d = 20 cm

x₂₀ - x₁ = x

x₁ + 19d - x₁ = x

19d = x

19.20 = 380

Answer:

y = -2x -1

Step-by-step explanation:

y-5=-2(x+3)

Distribute -2 × x and -2 × 3

y - 5 = -2x -6

y + 5 = -2x -6

y = -2x - 1

Answer: D. -30

Step-by-step explanation: EDGE 2022 I GOT 100%

Answer:D

Step-by-step explanation:got it right on my test

Answer:

The answer is C i got a 100 on the test

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

b

Answer:

-2

-Step-by-step explanation:

As, -6+(-2)= -6-2=-8

Thus, solved.

Hope it helps...

Answer:

5m+4

Step-by-step explanation:

Open the bracket

i.e 5m+5-1

5m+4.

Answer:

[tex]{2}^{3} = 2 \times 2 \times 2 = 8[/tex]

Step-by-step explanation:

*We're focusing on 2 to the power of 3.

2^3 is represented as 2 x 2 x 2, 2 is being multiplied by itself 2 times.

When we multiply, we find the product of 8.

Therefore,

[tex] {2}^{3} = 2 \times 2 \times 2 = 8[/tex]

The expression is equivalent to [tex]5^2[/tex].

Given

Expression; [tex]\rm \dfrac{(5^2)^{-3}\times 5^4}{5^{-4}}[/tex]

The definition of exponential form is a way of writing a number that is multiplied by itself more than once.

To solve the exponential equation follow all the steps given below.

Therefore,

The expression is equivalent to;

[tex]\rm =\dfrac{(5^2)^{-3}\times 5^4}{5^{-4}}\\\\=\rm \dfrac{(5)^{-6}\times 5^4}{5^{-4}}\\\\=\rm \dfrac{(5)^{-6+4}}{5^{-4}}\\\\=\rm \dfrac{5^{-2}}{5^{-4}}\\\\=5^{-2+4}\\\\=5^2[/tex]

Hence, the expression is equivalent to [tex]5^2[/tex].

To know more about expression click the link given below.

https://brainly.com/question/11865504

Answer: i think that picture 2 is b

Step-by-step explanation: