HELP WILL MARK BRAINIEST
What is the median for the set of data?
71
70
72
74

HELP WILL MARK BRAINIESTWhat Is The Median For The Set Of Data?71707274

Answers

Answer 1

Answer:

Step-by-step explanation:

To find the median, we need to arrange the data in ascending order:

70, 71, 72, 74

Since the data set has an even number of values, the median is the average of the two middle values. In this case, the two middle values are 71 and 72. Therefore, the median is:

(71 + 72) / 2 = 143 / 2 = 71.5

So, the median for the given set of data is 71.5.

Answer 2
71.5 is the answer for this question

Related Questions

A submarine hovers at 66 and two-thirds yards below sea level. If it ascends 24 and StartFraction 1 over 8 EndFraction yards and then descends 78 and three-fourths yards, what is the submarine’s new position, in yards, with respect to sea level?

Answers

-2911/24 = -121 7/24
The correct answer is -121 7/24
Give him brainlest he deserves it honestly

And like did you know we’re on a moving rock going through endless space

Select all shapes below that are nets of a pentagonal-based pyramid.

Answers

The answer to this one is D.

Answer:

A and B

Step-by-step explanation:

I took some paper and cut it to the shapes and folded them to see which ones are the answer and got those 2. :3

help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee plsssssssssssssssss

Answers

I can’t read bring it closer on a new post
I can’t really see but i’ll be sure to help you if you could bring it closer !

What is the difference of the fractions? Use the number line and equivalent fractions to help find the answer.

Negative 2 and one-half minus (negative 1 and three-fourths)
A number line going from negative 3 to 0 in increments of One-fourth.

Answers

The difference of the given fraction is Negative three-fourths.

Sum and difference of fractions

Given the following fraction difference as shown:

[tex]\sf -2 \dfrac{1}{2} - \huge \text(-1 \dfrac{3}{4} \huge \text)[/tex]

Convert to improper fraction

[tex]\sf -\dfrac{5}{2} + \dfrac{7}{4}[/tex]

Find the LCM

[tex]\sf 2(-5)+\dfrac{7}{4}[/tex]

[tex]\sf -10+\dfrac{7}{4}[/tex]

[tex]\sf -\dfrac{3}{4}[/tex]

Hence, the difference of the given fraction is Negative three-fourths.

Learn more on fraction difference at: https://brainly.com/question/30489902

Does the series converge or diverge? if it converges, what is the sum? SHOW YOUR WORK!!!!!!
equation is in picture.

Answers

Answer:  It converges to   -3

=============================================

Reason:

This is a geometric series with

a = -4 = first termr = -1/3 = common ratio

The template is [tex]a(r)^{n-1}[/tex]

If -1 < r < 1, then the infinite geometric series converges to a finite number. This is because we add on smaller and smaller pieces, which prevents the sum going off to infinity.

In the case of r = -1/3, it fits the interval  -1 < r < 1. In other words -1 < -1/3 < 1 is true.

We'll plug those values into the formula below to wrap things up.

[tex]S = \frac{a}{1-r}\\\\S = \frac{-4}{1-(-1/3)}\\\\S = \frac{-4}{1+1/3}\\\\S = \frac{-4}{3/3+1/3}\\\\[/tex]

[tex]S = \frac{-4}{4/3}\\\\S = -4 \div \frac{4}{3}\\\\S = \frac{-4}{1} \times \frac{3}{4}\\\\S = \frac{-4*3}{1*4}\\\\S = -3\\\\[/tex]

Therefore,

[tex]\displaystyle \sum_{n=1}^{\infty} -4\left(-\frac{1}{3}\right)^{n-1} = -3[/tex]

The final answer is -3.

You can verify the answer by generating partial sums with a spreadsheet. The partial sums should steadily get closer to -3.

Here's a few partial sums.

[tex]\begin{array}{|c|c|c|} \cline{1-3}\text{n} & \text{a}_{\text{n}} & \text{S}_{\text{n}}\\\cline{1-3}1 & -4 & -4\\\cline{1-3}2 & 1.333333 & -2.666667\\\cline{1-3}3 & -0.444444 & -3.111111\\\cline{1-3}4 & 0.148148 & -2.962963\\\cline{1-3}5 & -0.049383 & -3.012346\\\cline{1-3}6 & 0.016461 & -2.995885\\\cline{1-3}7 & -0.005487 & -3.001372\\\cline{1-3}8 & 0.001829 & -2.999543\\\cline{1-3}9 & -0.00061 & -3.000153\\\cline{1-3}10 & 0.000203 & -2.99995\\\cline{1-3}\end{array}[/tex]

The interesting thing is that the partial sums [tex]S_n[/tex]  bounce around -3 while also getting closer to it.

Yes the partial sums should get closer to -3.
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