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Answer:

2r5r

jr = 986 which is 459=100 equals wrong

The factorization of the given expression [tex]55z^{17}+121z^{34}[/tex] is [tex]11z^{17}(5+11z^{17})[/tex].

"Factorization is a method of finding factors for any polynomial or any algebraic expression."

The given expression is

[tex]55z^{17}+121z^{34}[/tex]

By factorizing it, we get:

[tex]55z^{17}+121z^{34}\\= 11z^{17}(5+11z^{17})[/tex]

Learn more about factorization of an expression here: https://brainly.com/question/11994062

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Answer:

7

Step-by-step explanation:

In most cases the first step is to create an equation to solve for the missing variable

But in this case we are already given the equation

(7.25h + 5 = 6.5h + 10.25)

All we have to do is solve for h

7.25h + 5 = 6.5h + 10.25

Step 1 subtract 5 from both sides

7.25h = 6.5h + 5.25

Step 2 subtract 6.5h from both sides

0.75h = 5.25

Step 3 divide both sides by .75

h = 7

So at 7 hours the cost will be the same for both instructors

Answer:

ans : x in terms of p is 15/p and if p is -5 than x= -3

Step-by-step explanation:

4( px +1 ) = 64

( Px + 1 ) = 64/4

px = 16 - 1

x = 15/p

and , if p= -5 than,

x = 15 / (-5)

= - 3

Answer:

The family of possible values for [tex]p[/tex] are:

[tex](-\infty, -4) \,\cup \,(7, +\infty)[/tex]

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

[tex]\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}[/tex] (1)

Where:

[tex]\theta[/tex] - Angle between vectors, in sexagesimal degrees.

[tex]\|\vec a\|, \|\vec b \|[/tex] - Norms of vectors [tex]\vec {a}[/tex] and [tex]\vec{b}[/tex]

If [tex]\theta[/tex] is acute, then the cosine function is bounded between 0 a 1 and if we know that [tex]\vec {a} = (p, 3, -7)[/tex] and [tex]\vec {b} = (p, -p, 4)[/tex], then the possible values for [tex]p[/tex] are:

Minimum ([tex]\cos \theta = 0[/tex])

[tex]\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0[/tex]

Maximum ([tex]\cos \theta = 1[/tex])

[tex]\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1[/tex]

With the help of a graphing tool we get the family of possible values for [tex]p[/tex] are:

[tex](-\infty, -4) \,\cup \,(7, +\infty)[/tex]

The dot product between the two vectors is the product of the magnitude between them times cosine angle.

The possible values for [tex]p[/tex] is (7,-4), when the angle is acute between [tex]a[/tex] and [tex]b[/tex].

To find the value of [tex]p[/tex] we need to perform the dot product of two equation.

The dot product between the two vectors is the product of the magnitude between them times cosine angle

Given information-

The vector equation given in the problem is,

[tex]a = p\hat i +3\hat j - 7\hat k[/tex]

[tex]b = p\hat i - p\hat j +4\hat k[/tex]

For acute angle, the dot product of [tex]a,b[/tex] less than equal to zero.

Thus,

[tex]a .b<0[/tex]

Put the values,

[tex](p\hat i +3\hat j - 7\hat k)(p\hat i - p\hat j +4\hat k)<0[/tex]

In the dot product the multiplication of different unit vector is zero. Thus,

[tex]p^2-3p-28<0[/tex]

Factorize above equation using the split the middle term method as,

[tex]p^2-7p+4p-28<0\\(p-7)(p+4)<0[/tex]

As the factor of the above equation is 7 and -4.

Thus the possible values for [tex]p[/tex] is (7,-4), when the angle is acute between [tex]a[/tex] and [tex]b[/tex].

Learn more about the dot product here;

https://brainly.com/question/9956772

Answer:

4 will replace?

Step-by-step explanation:

as 3-2=1

6-4=2

4-1=3

8-2=6

again

3-2=1

so

6-x=2

6-2=x

4

plz mark it as brainliest answer

Answer:

distance between the points is 8.602325267 units

Step-by-step explanation:

(5 , 8)=(x1 , y1)

(-2 , 3)=(x2 , y2)

use formula:[tex]\sqrt{(x2-x1)^2 + (y2-y1)^2}[/tex]

=[tex]\sqrt{(-2-5)^2 + (3-8)^2}[/tex]

=[tex]\sqrt{(-7)^2 + (-5)^2}[/tex]

=[tex]\sqrt{49 + 25}[/tex]

=[tex]\sqrt{74[/tex]

=8.602325267 units

11

Step-by-step explanation:

2 times 5 +1=11

Answer:

2n+1=-5

2n=-5-1

2n=-6

n=-6÷2

n=-3

Answer:

Step-by-step explanation:

Let the number of cucumber = x

And the cost of the cucumber = y

Cost of the cucumber will be directly proportional to the number of cucumbers.

y ∝ x

y = kx [Here, k = proportionality constant]

Since, market sells 3 cucumbers for $1.2

1.2 = k(3)

k = 0.4

Therefore, equation for this situation will be,

y = 0.4x

Part A

If x = 1,

y = 0.4(1)

  = 0.4

For x = 2,

y = 0.4(2)

  = 0.8

For x = 3,

y = 0.4(3)

  = 1.2

Number of cucumbers            Cost($)

          1                                          0.4

          2                                         0.8

          3                                          1.2

Part B

Equation representing relation between number of cucumbers and the cost will be,

y = 0.40x [Option A]

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation:}[/tex]

[tex]\mathbf{4\times \dfrac{2}{3}}[/tex]

[tex]\huge\textbf{Simplifying it:}[/tex]

[tex]\mathbf{4\times \dfrac{2}{3}}[/tex]

[tex]\mathbf{= \dfrac{4}{1}\times\dfrac{2}{3}}[/tex]

[tex]\mathbf{= \dfrac{8}{3}}[/tex]

[tex]\rightarrow\large\text{Finding out what is equal to: }\rm{\dfrac{8}{3}}\leftarrow[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[tex]\huge\text{Option A.}[/tex]

[tex]\mathbf{6\times \dfrac{2}{3}}[/tex]

[tex]\mathbf{= \dfrac{6}{1}\times\dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{6\times1}{1\times3}}[/tex]

[tex]\mathbf{= \dfrac{6}{3}}[/tex]

[tex]\mathbf{= 2}[/tex]

~~~~~

[tex]\rm{\bf 2 \neq \dfrac{8}{3}}[/tex]

~~~~~~

[tex]\huge\text{Option B.}[/tex]

[tex]\mathbf{10\times \dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{10}{1}\times\dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{10\times1}{1\times 3}}[/tex]

[tex]\mathbf{= \dfrac{10}{3}}[/tex]

~~~~~~

[tex]\rm{\bf \dfrac{10}{3} \neq \dfrac{8}{3}}[/tex]

~~~~~~

[tex]\huge\text{Option C.}[/tex]

[tex]\mathbf{2\times\dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{2}{1}\times\dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{2\times1}{1\times3}}[/tex]

[tex]\mathbf{= \dfrac{2}{3}}[/tex]

~~~~~

[tex]\rm{\bf \dfrac{2}{3} \neq \dfrac{8}{3}}[/tex]

~~~~~

[tex]\huge\text{Option D.}[/tex]

[tex]\mathbf{8\times\dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{8}{1}\times\dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{8\times1}{1\times3}}[/tex]

[tex]\mathbf{= \dfrac{8}{3}}[/tex]

~~~~~

[tex]\rm{\dfrac{8}{3} = \dfrac{8}{3}}\large\checkmark[/tex]

~~~~~

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\frak{Option\ D. 8\times \dfrac{1}{3}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

10x is equal to 100 so 100+6=106

then

Step-by-step explanation:

4x is equal to 8 so 4+18=22

so it's 128

Answer:

15 girls

Step-by-step explanation:

Girls  : Boys

5              3

To get to 9 boys multiply by 3

Girls  : Boys

5*3         3*3

15               9

There are 15 girls

Answer:

It will take him 4 hours.

Step-by-step explanation:

7x4= 28 miles

Answer:

( k-4)(k+2)

Step-by-step explanation:

k² - 2k - 8

What 2 numbers multiply to -8 and add tp -2

-4*2 = -8

-4+2 = -2

( k-4)(k+2)

Refer to the attachment for steb-by-step explanation.

Answer:

x = 10

Step-by-step explanation:

We can use ratios to solve

Side over bottom

5         5+3

---- = --------

x         16

Using cross products

5 * 16 = (5+3)*x

80 = 8x

Divide by 8

10 = x

x = 10.  This is a dilation. To find x, you must first find what you are dilating and by how much. 8 is the starting value, and 5 is the newer value. 5 divided by 8 is .625. Then multiply.625 by 16, to get 10, or x

Answer:

60

Step-by-step explanation:

[tex]\frac{300}{5}[/tex]

60

Hence, 60 is the answer

Answer:

60 mph

Step-by-step explanation:

For this problem, we are looking at the rate, miles per hour. We know that Andrea traveled 300 miles in 5 hours, but how many miles did she travel in one hour? Let's do the math:

[tex]300[/tex]÷[tex]5=60[/tex] miles.

So, in one hours, Andrea travels 60 miles. We get the rate, 60mph.

Andrea was driving at 60 mph.

I hope this helps! Please let me know if you have any questions :)

Answer:

The loss on the sale of 50 type M cars is $8000, and the loss is decreasing at the rate of $500 per 50 type M car sold.

Step-by-step explanation:

Given

[tex]L(50) = 8000[/tex]

[tex]L'(50) = -500[/tex]

Required

Interpret

From the question, we understand that:

[tex]x \to[/tex] Number of cars

[tex]L(x) \to[/tex] Profit on x cars

Using the above as a point of reference,

[tex]L'(x) \to[/tex] Rate of loss per x cars

So, the interpretations are:

[tex]L(50) = 8000[/tex]

A loss of 8000 on 50 cars

[tex]L'(50) = -500[/tex]

The loss rate is a reduction of 500 per 50 car

Answer:

7.2 =x

Step-by-step explanation:

We know that

sin theta = opp / hyp

sin 41 = x/y

sin 41 = x/11

11 sin 41 =x

7.216649319 =x

Rounding to 1 decimal place

7.2 =x

Answer:

you on the games

Step-by-step explanation:

Answer:

I think its 58

Step-by-step explanation:

1/2

Hope this helps! :)

______________

Answer:

1/2

Step-by-step explanation:

you use rise/run so its  (0,1) and (2,2) you move to the right 2 points and rise 1 so its 1/2 so its 0.50

Answer:

[tex]\dfrac{7}{10}[/tex]

Step-by-step explanation:

Given that,

Carlos walk to school on the 14th of 20 days in February.

We need to find the equivalent to the fraction of school days in February that Carlos walk to school.

Required percentage is given by :

[tex]\%=\dfrac{14}{20}\times 100\\\\=14\times 5\\\\=70\%[/tex]

or

[tex]=\dfrac{7}{10}[/tex]

So, the required fraction is equal to [tex]\dfrac{7}{10}[/tex].

Answer:

median = 25. that's the answer

Answer:

Mean - 25

median - 25

range - 10

mode - 25

Answer:

7

Step-by-step explanation:

(4·2)+4-5

8+4-5

12-5=

7

Answer:

lower quartile would be Q1 and the upper quartile would be Q3