help pls and thank you​

Help Pls And Thank You

Answers

Answer 1

Answer:

7x3=21 3x7=21

Answer 2

Answer:

two correct answers are:

1 x 21= 21

3 x 7= 21


Related Questions

I have a Statistics question​

Answers

Answer:

okayyyyyyyyyyyyyyyy

Step-by-step explanation:

have a nice day

okkkkkkkkkkkkkkkkkkkkkkkk

What is the constant of proportionality in xy-11=5?

Answers

Answer:

xy-11=5

ANSWER:

=16

Step-by-step explanation:

hope it helps to you

mark me as a brainlest please

Maya solved 1/4 of a crossword puzzle before dinner and a part of it after dinner. If Maya solved 3/4 of the crossword in all, what fraction of the puzzle did she solve after dinner?
Choose the equation that matches the word problem.

Answers

Answer:2/4

Step-by-step explanation: you would just subtract 3/4 by 1/4 to get 2/4

Help me with this question thanks so much

Answers

It would be 6^8 or 1,679,616
Since it’s times 6 each time and the base is 6 it can be written as an exponent 6*6*6...
Hope that helps :)

100 POINTS AND BRANIEST
3) Compare the two groups of data. Which BEST describes data? A) on average boys are 3 centimeters taller than girls B) on average boys are 6 centimeters taller than girls C) on average boys are 9 centimeters taller than girls D) on average boys are 12 centimeters taller than girls

Answers

B

Step-by-step explanation:

calculate how long the lines are

Answer:

A 3-column table with 4 rows. Column 1 is labeled Number of Girls with entries 2, 8, 0, 4. Column 2 is labeled Height in Inches with entries 51, 52, 53, 54. Column 3 is labeled Total Height with entries 102, 416, 0, 216. The national average height for girls in the sixth grade is also 52 inches. Find the average height of the girls in this class. The total number of girls is . The total height of the girls is inches. The expression to find the mean is . The average height of the girls in this class is inches.

Step-by-step explanation:

mark me brainliest ok

. There are 11 boys and 5 girls that tried out to
sing a duet in a chorus concert. If the
director must choose two, what is the
probability that both students chosen are
boys?

Answers

We want to find the probability that the two students chosen for the duet are boys. We will find that the probability that both students chosen for the duet are boys is 0.458

If we assume that the selection is totally random, then all the students have the same probability of being chosen.

This means that, for the first place in the duet, the probability of randomly selecting a boy is equal to the quotient between the number of boys and the total number of students, this is:

P = 11/16

For the second member of the duet we compute the probability in the same way, but this time there is one student less and one boy less (because one was already selected).

Q = 10/15

The joint probability (so both of these events happen together) is just the product of the individual probabilities, this will give:

Probability = P*Q = (11/16)*(10/15) = 0.458

So the probability that both students chosen for the duet are boys is 0.458

If you want to learn more, you can read:

https://brainly.com/question/1349408

Find the area of the circle whose diameter is 68 cm​

Answers

Answer:

1156πcm²

Step-by-step explanation:

Diameter = 68cm

Therefore radius = 68 ÷ 2 = 34cm

Area of a circle = πr²

= π × 34cm × 34cm

= π × 1156cm

= 1156πcm²

NOTE: In case you're given the value of pi, substitute it into the formula to get your answer

find the number of outcomes when n = 6 and r = 3. n!
(n−r)!r!

Answers

Answer:

20

Step-by-step explanation:

This is the formula for a combination. Substitute the values and evaluate the expression.

[tex]\frac{n!}{r!(n-r)!}\\\\\frac{(6)!}{(3)!(6-3)!}\\\\\frac{(6)!}{(3!)(3!)}\\\\\frac{(6\cdot5\cdot4\cdot3\cdot2\cdot1)}{(3\cdot2\cdot1)(3\cdot2\cdot1)}\\\\\frac{720}{(6)(6)}\\\\\frac{720}{36}\\\\ 20[/tex]

Question is in image below
A lamppost is 6 feet high and casts and 8 foot shadow. At the same time of day, a flagpole near the lamppost cast a 20 foot shadow. Using the properties of similar triangles, find the height, H, of the flagpole

Answers

Answer:

15 ft.

Step-by-step explanation:

I will assume that either both objects are standing straight. We can use similar triangles.

We can see that the side 8 is similar to the side 20, since they are both shadows. Therefore, we can set up an equation:

[tex]\frac{6}{8} =\frac{x}{20}[/tex]

we can cross multiply and get:

8x=120

solve for x:

x=15

Therefore, the lamppost must be 15 feet tall (unless it fell down but we won't talk about that)

A store makes $9500 a month in sales. They pay $3325 a month in rent. What percent of their sales is used to pay rent

Answers

Answer:

35%

Step-by-step explanation:

We can use the equation "is over over" to give up 3325/9500*?/100, after simplifying your answer is 35%

Brainliest would be appreciated. :-)

3325/9500 shows the decimal .35 and then to make it a percent you multiples .35x100 and that equals 35%

7 x [(7 + 7) = 7
Help plz

Answers

Answer:

[tex] \frac{1}{14} [/tex]

Step-by-step explanation:

7 x (7+7)=7

7x [(14)]=7

x=

[tex] x = \frac{1}{14} [/tex]

2) Oil with ρ= 876 kg/m3 and μ= 0.24 kg/m · s is flowing through a 1.5 cm diameter pipe that discharges into the atmosphere at 88 kPa. The absolute pressure 15 m before the exit is measured to be 135 kPa. Determine the flow rate of oil through the pipe if the pipe is (a) horizontal, (b) inclined 8° upward from the horizontal, and (c) inclined 8° downward from the horizontal.

Answers

The pressure in a fluid flowing with laminar flow through a pipe is given by

Hagen-Poiseuille equation.

The correct responses are;

(a) If the pipe is horizontal, the flow rate is approximately 1.622 × 10⁻⁵ m³/s(b) If the pipe is inclined upwards, the flow rate is approximately 1.003 × 10⁻³ m³/s(c) If the pipe is inclined 8° downwards, the flow rate is approximately 2.24 × 10⁻⁵ m³/s

Reasons:

When the flow is a steady incompressible flow through pipe, the flow rate

can be derived from the Hagen-Poiseuille equation as follows;

[tex]\displaystyle \dot V = \mathbf{\frac{\left[\Delta P - \rho \cdot g \cdot L \cdot sin\left(\theta \right) \right] \cdot \pi \cdot D^4 }{128 \cdot \mu \cdot L}}[/tex]

ΔP = 135 kPa - 88 kPa = 47 kPa

The density of the oil, ρ = 876 kg/m³

μ = 0.24 kg/(m·s)

L = 15 m

The diameter of the pipe, D = 1.5 cm = 0.015 m

(a) When the pipe is horizontal, we have;

θ = 0°

Which gives;

[tex]\displaystyle \dot V = \mathbf{\frac{\left[47 \times 10^3 - 876 \, kg/m^3 \times 9.81 \, m/s^2 \times 15 \, m \cdot sin\left(0^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m}}[/tex]

[tex]\displaystyle \dot V = \frac{\left[47 \times 10^3\, Pa - 128903.4\, Pa \cdot sin\left(0^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m}[/tex]

[tex]\displaystyle \dot V = \frac{\left[47 \times 10^3\, Pa - 128903.4 \, Pa \cdot sin\left(0^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m} =\frac{0.002379357\cdot \pi}{460.8}[/tex]

[tex]\displaystyle \dot V=\frac{0.002379357\cdot \pi}{460.8} = \mathbf{1.622 \times 10^{-5}}[/tex]

The flow rate when the pipe is horizontal, [tex]\displaystyle \dot V[/tex] = 1.622 × 10⁻⁵ m³/s

(b) When the pipe is inclined 8°, we have;

[tex]\displaystyle \dot V = \mathbf{\frac{\left[47 \times 10^3\, Pa - 128903.4\, Pa \cdot sin\left(8^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m}} = 1.003 \times 10^{-5} \, m^3/s[/tex]

The flow rate of oil through the pipe if the pipe is inclined 8° upwards from the horizontal, [tex]\displaystyle \dot V[/tex] = 1.003 × 10⁻⁵ m³/s

(c) If the pipe is inclined 8° downward from the horizontal, we have;

[tex]\displaystyle \dot V = \frac{\left[47 \times 10^3\, Pa - 128903.4\, Pa \cdot sin\left(-8^{\circ} \right) \right] \times \pi \times (0.015 \, m)^4 }{128 \times 0.24 \, kg/(m \cdot s) \times 15 \, m} = 2.24\times 10^{-5} \, m^3/s[/tex]

If the pipe is inclined 8° upwards from the horizontal, the flow rate of oil through the pipe is, [tex]\displaystyle \dot V[/tex] = 2.24 × 10⁻⁵ m³/s

Learn more about flow through pipes here:

https://brainly.com/question/6858718

A courtyard has the shape of a rectangle 45 ft and 28 ft wide. How long is a sidewalk from one corner diagonally to the opposite corner?
56 ft

47 ft

50 ft

53 ft

Answers

Answer:

53

Step-by-step explanation:

We use the pythagorean theorem, a^2 + b^2 = c^2. We can fill a and b for 45 and 28. 45^2 is 2025, and 28^2 is 784. Adding them up gives us 2809. The square root of 2809 is 53.

...................................................................

Answers

plz write your proper question

Recall the method that the video showed to solve Gavin’s word problem. The video showed how we can use numerical expressions (with the help of a diagram) to arrive at a solution.

Compare the expression method from the video with the equation method that uses the variable b. Do both methods use the same sequence of operations?

Answers

Answer:    

There are three ways to solve systems of linear equations in two variables: graphing. substitution method. elimination method.

Step-by-step explanation: hope this helps :)

Kripa’s father is 35 years younger than her grandfather, and 40 years older than her. If the sum of the ages of the three is 160 years, let’s find her grandfather’s age?

Answers

Answer:

90 years

Step-by-step explanation:

if Kripa's age = x

Father's age = x + 40

Grandfather's age = (x + 40) + 35 = x + 75 (father is 35 years younger than grandfather i.e. grandfather is 35 years older than father)

x + x + 40 + x + 75 = 160

=> 3x = 160 - 115

=> x = 45/3 = 15

grandfather's age = x + 75 = 90 years

Answer:

90 years

Step-by-step explanation:

x + x + 40 + x + 75 = 160

=> 3x = 160 - 115

=> x = 45/3 = 15

Grandfather's age = x + 75 = 90 years

Can the sum or multiplication of two palindromic numbers be another palindromic number?​

Answers

Answer: No.

Step-by-step explanation:

If you multiply 1001 by 1001 it's not another palindromic number.

John and Jennifer want to split a bag of candy, and decide to use the divider-chooser method. The bag contains 100 Snickers, 100 Milky Ways, and 100 Reese's, which John values at $1, $4, and $5 respectively.

If John is the divider, find a possible division that is consistent with his value system.

Answers

If John is the divider then $5 is the consistent value with his share system.

What is a divider chooser?

The essential concept is that an object is divided into pieces by a divider. The remaining participants, referred to as choosers, make bids on the pieces they believe represent fair portions. Each chooser receives the portion that, in their opinion, represents a fair share, with the remaining portion going to the divider.

Given that the bag contains 100 Snickers, 100 Milky ways and 100 Reese's which john values at $1 , $4 and $5 respectively.

That means 1 Snicker, 1 Milky way and 1 Reese's for $0.01 , $0.04 and $0.05 respectively.

Suppose, John splits a bag of candy

a) first half : 50 Snickers, 50 Milky ways and 50 Reese's

b) second half :  50 Snickers, 50 Milky ways and 50 Reese's

The value of both of the half in John's terms ;

50 (0.01) + 50 (0.04) + 50 (0.05) = 0.5 + 2 + 2.5 = 5

Therefore, if John is the divider then $5 is the consistent value with his share system.

To learn more about the divider chooser;

https://brainly.com/question/16963612

#SPJ1                                                      

Explain how to find the distance between two integers using the difference.

Answers

Answer:

read explanation for answer

Step-by-step explanation:    Finding the distance between any two integers is obtained by;

Taking the absolute value of the difference between the two integer values.

For instance :

Point A = - 10

Point B = 5

The distance between the two integer points is :

Difference = Point A - Point B = - 10 - 5 = - 15

Absolute value = |-15| = 15

Therefore, This procedure works for any pair of integer distances.

Answer:Find the difference between two integers by adding the additive inverse. The distance is the absolute value of the difference. Check the distance by plotting the original two integers on a number line and counting the units between them.

Step-by-step explanation:

PLEASE LAST FEW SETS OF QUESTIONS FOR SEMESTER PLEASE HELP 2

Answers

Problem 1

Answer:  C) 132.6

--------------------

Explanation:

a1 = 1.7 = amount of concrete for the first step

a4 = x = amount of concrete for the fourth step

Sn = sum of the first n terms of an arithmetic sequence

Sn = (n/2)*(a1 + an)

S4 = (4/2)*(a1 + a4)

S4 = 2(1.7+x)

S4 = 2x+3.4

S4 = 17

2x+3.4 = 17

2x = 17-3.4

2x = 13.6

x = (13.6)/2

x = 6.8

We need 6.8 cubic feet of concrete for the fourth step. We'll use this value to help us find the common difference d

an = nth term of an arithmetic sequence

an = a1 + d(n-1)

a4 = a1 + d(4-1)

a4 = a1 + 3d

6.8 = 1.7 + 3d

6.8-1.7 = 3d

5.1 = 3d

(5.1)/3 = d

1.7 = d

d = 1.7

Coincidentally, the common difference is the same as the first term. This won't always happen.

Now we can compute the 12th term

an = a1 + d(n-1)

a12 = 1.7 + 1.7(12-1)

a12 = 20.4

which is then used to find the sum of the first 12 terms

Sn = (n/2)*(a1 + an)

S12 = (12/2)*(a1 + a12)

S12 = 6(1.7 + 20.4)

S12 = 132.6

=============================================================

Problem 2

Answer: C) [tex]x^2 + (y-10)^2 = 225\\\\[/tex]

--------------------

Explanation:

The center is (h,k) = (0,10) which is where the nozzle is located.

The distance from (0,10) to (0,25) is 15 units, so r = 15.

Also, the distance from (0,10) to (0,-5) is also 15 units.

Plug those values into the equation below.

[tex](x-h)^2 + (y-k)^2 = r^2\\\\(x-0)^2 + (y-10)^2 = 15^2\\\\x^2 + (y-10)^2 = 225\\\\[/tex]

That equation represents the boundary of the circle, which is where the water can reach.

=============================================================

Problem 3

Answer:  B) 2.336 ft

--------------------

Explanation:

a1 = height 1st bounce = 6.7 fta2 = height 2nd bounce = 81% of a1 = 81% of 6.7 = 0.81*6.7 = 5.427a3 = height 3rd bounce = 81% of a2 = 81% of 5.427 = 0.81*5.427 = 4.39587

Or note that,

a3 = 0.81*(a2) = 0.81*(0.81a1) = a1*(0.81)^2 = 6.7*(0.81)^2 =  4.39587

which must mean,

a4 = a1*(0.81)^3a5 = a1*(0.81)^4a6 = a1*(0.81)^5

This is based off the idea that [tex]a_n = a(r)^{n-1}[/tex]

So,

a6 = a1*(0.81)^5

a6 = 6.7*(0.81)^5

a6 = 2.33614554867

a6 = 2.336

Find the values of x and y

Answers

Answer:

  x = 25, y = 19

Step-by-step explanation:

The external angle is supplementary to the adjacent internal angle.

  2x +130 = 180

  2x = 50 . . . . . . . subtract 130

  x = 25 . . . . . . . divide by 2

__

The external angle is equal to the sum of the remote internal angles.

  130 = 54 +4y

  76 = 4y . . . . . . . subtract 54

  19 = y . . . . . . . divide by 4

Mr.Plump lost 30 pounds from his original weight of 240 pounds. What percent weight loss did her achieve?

Answers

Answer:

12.5%

Step-by-step explanation:

I divided 30 (the amount he lost) by 240 (his original weight). I get 0.125, but need to move the decimal over 2 places to get the percentage.

12.5 because when you divide 30 by 240 you get 0.125 but all I had to do is move the decimals 2 spaces over and that would change the answer too 12.5

Select the values that make the inequality -4 g< 64 true. Then write an equivalent inequality, in terms of g

Answers

Answer:

g > -16

Step-by-step explanation:

-4 g< 64 (Given)

g > -16 (Sign flips sing you divided by a negative number)

What is the slope of the line tangent to the graph of y = (9x^2)/(x+2) at x = 1 ?

Answers

Using derivatives, it is found that the slope of the line tangent to the graph of y at x = 1 is of 5.

The equation is:

[tex]y(x) = \frac{9x^2}{x + 2}[/tex]

The slope of the line tangent to the graph of y at x = 1 is [tex]y^{\prime}(1)[/tex].

Applying the quotient rule, we have that:

[tex]y^{\prime}(x) = \frac{[9x^2]^{\prime}(x + 2) - [x + 2]^{\prime}(9x^2)}{(x + 2)^2}[/tex]

[tex]y^{\prime}(x) = \frac{18x(x + 2) - 9x^2}{(x + 2)^2}[/tex]

[tex]y^{\prime}(x) = \frac{9x^2 + 36x}{(x + 2)^2}[/tex]

Then, when x = 1:

[tex]y^{\prime}(1) = \frac{9(1)^2 + 36(1)}{(1 + 2)^2} = \frac{45}{9} = 5[/tex]

The slope of the line tangent to the graph of y at x = 1 is of 5.

You can learn more about the use of derivatives to find the slope of a tangent line at https://brainly.com/question/10580177

If you live 1.5 miles from school and you walk at a rate of 3mph, when should you leave home in order to arrive at school by 9:00?

Answers

Answer is  8:30

Work Shown:

time = distance/speed

time = (1.5 miles)/(3 mph)

time = (1.5/3) hours

time = 0.5 hours

time = 30 minutes

It takes 30 minutes to walk to school, so you should leave a half hour before 9:00. Subtracting 30 minutes from 9:00 gets you to 8:30. If anything, you should start a little bit before 8:30 just in case something might slow you down for one reason or another.

(−3, −1), (−1, 5) Find the slope of the line that passes through the pair of points.

Answers

[tex]slope = \frac{ 5 - ( - 1)}{ - 1 - ( - 3)} \\ [/tex]

[tex]slope = \frac{5 + 1}{ - 1 + 3} \\ [/tex]

[tex]slope = \frac{6}{2} \\ [/tex]

[tex]slope = 3[/tex]

what is 5÷ 3 1/3 on khan academy

Answers

Answer:

1.5

Step-by-step explanation:

Hope this helped!

Find an expression with represents the sum of 5X -8 and 2X +2 in simplest terms

Answers

Solution: 7x-6
Step by step solution:
5x-8+2x+2
Then combine like-terms
5x+2x+2-8
7x-6
Hope that helps :)

Renee worked a total of 16 1/5 hours last week. She spent 1/3 of that time reviewing reports. How many hours did she spend reviewing reports?

Answers

Answer:

Step-by-step explanation:

First 1 ÷ 5 ×16

= 3.2

Then 3.2 × 1 ÷ 3

= 1.06

how do i solve for this?

Answers

Answer:

see explanation

Step-by-step explanation:

(16)

The mid segment ZW is half the sum of the parallel bases

ZW = [tex]\frac{38+20}{2}[/tex] = [tex]\frac{58}{2}[/tex] = 29

(17)

The lower base angles are congruent , so

∠ UYX = ∠ VXY = 35°

(18)

Any lower base angle is supplementary to any upper base angle , then

∠ VUY = 180° - ∠ UYX = 180° - 35° = 145°

(19)

[tex]\frac{UV+XY}{2}[/tex] = ZW

[tex]\frac{3x-1+7x+1}{2}[/tex] = 10 ( multiply both sides by 2 to clear the fraction )

10x = 20 ( divide both sides by 10 )

x = 2

Then

XY = 7x + 1 = 7(2) + 1 = 14 + 1 = 15

(20)

The legs are congruent , so

UY = VX

5a - 6 = 3a + 2 ( subtract 3a from both sides )

2a - 6 = 2 ( add 6 to both sides )

2a = 8 ( divide both sides by 2 )

a = 4

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