Physics College

help please! what is the right answer ​

Help Please! What Is The Right Answer

Answers

Answer 1
i think the answer is D. the opponent process theory
Answer 2
the answer to this question is D

Related Questions

At the equator, the earth spins a distance of 25,992 miles every day. What speed does the earth spin at in mph?

Answers

A day is 24 hours so you divide the distance in a day by the number of hours in a day.
25,992/24=1083.

Answer: 1083 mph

At the equator, the earth spins a distance of 25,992 miles every day, which is equal to 1083 mph.

What is equator?

An equator is a hypothetical line that circles the center of a planet or other celestial body. It is located at 0 degrees latitude, midway between the north and south poles. The globe is divided into northern and southern hemispheres by an equator.

The diameter of the Earth is also larger at the Equator, resulting in a phenomenon known as an equatorial bulge. A circle's diameter is measured by a straight line that goes through its center and has its ends on the circle's edge. The diameter of latitudes such as the Equator and the Arctic Circle can be calculated by scientists.

At the equator, the earth spins a distance of 25,992 miles every day

This is equal to (25992 ÷ 24) miles per hour

= 1083 mph.

Learn more about equator here:

https://brainly.com/question/24203207

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A bat moving at 3.7 m/s is chasing a ying insect. The bat emits a 36 kHz chirp and receives back an echo at 36.79 kHz. At what speed is the bat gaining on its prey? Take the speed of sound in air to be 340 m/s.

Answers

Answer:

The speed the bat is gaining on its prey is 0.03m/s

Explanation:

Given;

speed of the bat, v₀ = 3.7 m/s

frequency of the bat, F₀ = 36 kHz

frequency of the source, Fs = 36.79

This is relative motion between a source of the sound and the observer.  The phenomenon is known as Doppler effect.

Apply the following equation to determine the speed of the insect which is the source;

[tex]F_0 = F_s[\frac{v+v_0}{v-v_s} ]\\\\\frac{F_0}{F_s} = [\frac{v+v_0}{v-v_s} ]\\\\\frac{36.79}{36} = \frac{340+3.7}{340-v_s}\\\\1.0219 = \frac{343.7}{340-v_s}\\\\ 340-v_s = \frac{343.7}{1.0219}\\\\340-v_s = 336.33\\\\v_s = 340-336.33\\\\v_s = 3.67 \ m/s[/tex]

The speed the bat is gaining on its prey = 3.7m/s - 3.67m/s = 0.03 m/s

Therefore, the speed the bat is gaining on its prey is 0.03m/s

Something that has many particles in a small space would have a ————- density


Fill in blank

Answers

Answer:

a high density i believe

Explanation:

Answer:

it may have a higher density

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