It will take 1.6s for the ice to melt.
First we have to write the expression for the heat balance equation for the system
Q supply = Qgain/
t= mLf/t
Here, m is the ice,
Lf is the latent heat of fusion
and t is the time taken to melt the ice.
Now we have to substitute the required value in the above expression to determine the value of time.
636 kJ/s = (3 kg)(334 kJ/kg) / tt =1.575 s
What is latent heat?
The heat or energy that is absorbed or released during a substance's phase shift is known as latent heat. It could go from a solid to a liquid or from a liquid to a gas, or vice versa. Enthalpy, a characteristic of heat, is connected to latent heat.
Therefore, the closest option is 1.6s
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The temperature of jordan lake is determined to be 13. 9ºc when an iron block is dropped in. The iron block is at 400 k and has a mass of 60 kg. Determine the heat transfer in kj of this process that is allowed to reach equilibrium.
This study reveals that only if the flow conditions in the holding tube are provided for comparison with commercial HTST systems can continuous laboratory and pilot-scale pasteurizers be utilized to evaluate the inactivation of microorganisms.
In order to make sure that laboratory or pilot-scale HTST apparatus meets the Pasteurized Milk Ordinance standards for pasteurizing milk and can be used for obtaining thermal inactivation data, we present a method in this study for calculating the fastest moving particle (FMP) and residence time distribution (RTD) in a pilot-scale high temperature, short time (HTST) pasteurizer.
The plate used in the pasteurizer had overall measurements of 75 x 115 mm, a thickness of 0.5 mm, and an effective diameter of 3.0 mm. The pasteurizer had standard hold tubes measuring 21.5 and 52.2 seconds, and its variable flow capacity ranged from 0 to 20 L/h.
FMP durations were established using tracer investigations, and flow parameters were established using RTD data. In comparison to the nominal timings of 21.5 and 52.2 s, respectively, the FMP times for the short and long holding sections using brine milk as the tracer were 18.6 and 36 s, respectively, at 72 degrees C.
According to the RTD investigation, the short hold section for whole milk at 72 degrees C had 45% back mixed and 55% plug flow.
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A boy pulls a 47.5 kg crate with a rope. The rope makes an angle of 28.0° to the horizontal.
The coefficient of kinetic friction for the crate and the deck is 0.300. The boy exerts a force of
185 N. What is the acceleration of the crate?
Answer:
1.044 m/s^2
Explanation:
Fcosθ - u(mg - Fsinθ) = ma = 185cos28 - 0.3(47.5*9.81 - 185sin28) = 49.61N
a = 1.044
a 0.10-kg ball is moving at 7.0 m/s when it is hit by a bat, causing it to reverse direction and have a speed of 12.0 m/s. what is the change in the magnitude of the momentum of the ball?
Change in momentum = -1.9 kg m/s
Momentum is the vector quantity because it has both magnitude and direction.
Momentum is given as the product of mass and velocity. It is represented as P = mv. Here, P is the momentum, m is the mass and v is the velocity.
Given,
Mass = 10 kgInitial velocity (U) = 7 m/sFinal velocity (V) = 12 m/sMomentum = MV
Initial momentum = MUFinal momentum = MVThe difference between the initial and final momentum will be the change of magnitude of the momentum.
To find the change in momentum,
Change in momentum = MV - MUTaking M as common
= M (V - U)
= 0.10 (-12 - 7)
= 0.10(-19)
= -1.9 kg m/s
Hence, the change in magnitude of momentum is -1.9 kg m/s.
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the eye works similar to a camera in the sense that it has an ideal framerate for visualizing motion. for instance, the monitor on your laptop has a refresh rate of 60 hz so that image transitions look smooth to the human eye. given the formula for the frequency output of a 555 timer and using only the values you have available to you, what is a possible combination of resistors and capacitors that will get you as close as possible to this value (note: you may use resistor values that could be made if you configure a set of resistors in series or parallel)?
The brain, not the eye, is what actually sees. Information is sent from the eye to the brain, but certain aspects of the signal are lost or changed in the process.
How fast can the human eye see?The human eye can perceive between 30 and 60 frames per second, according to some scientists. Some claim that the human eye cannot actually comprehend more than 60 frames per second.
Higher rates are seen as motion by the human visual system, which can process 10 to 12 pictures per second and perceive each one separately. The majority of participants in studies see modulated light (such a computer display) as steady when the rate is more than 50 Hz.
The screen will look smoother to the human eye the higher the number. This implies that a 120Hz display, which updates itself 120 times per second, would seem noticeably smoother and more natural than your typical 60Hz screen, which refreshes itself just 60 times each second.
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what is the difference between the dense, hot disks seen around some stars and the low-density, cold disks seen around some other stars? (select all that apply.)
The low-density, cold disks seen around some stars are distinct from the dense, hot disks found around some other stars because of their varied densities, temperatures, and positions.
- About circumstellar disc :
- A circumstellar disc (or circumstellar disk) is an accretion disk of matter in orbit around a star that has the shapes of a torus, pancake, or ring. It is made up of gas, dust, planetesimals, asteroids, or impact fragments. They are the sources of material where planets may form around the young stars.
- Gaseous clouds gradually collapse under the pull of gravity to become stars. As they fall toward the protostar, the atoms and molecules in the gas impart a slight rotation. The protoplanetary disk, a rotating plate of gas and dust, is produced by this rotation, which also gives the star its spin.
- A rotating circumstellar disk of dense gas and dust known as a protoplanetary disk surrounds a young, newly formed star, a T Tauri star, or a Herbig Ae/Be star.
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Select the correct answer. What is the average velocity of the particle from rest to 9 seconds? A. 1 meter/second B. 2 meters/second C. 3 meters/second D. 4 meters/second
The average velocity is 2 meters/second. Option B.
Explanation:
This average velocity can be found using the following formula:
v = x / DT
where:
x = displacement = 18 [meters]
dt = time interval = 9 [seconds ]
v = 18 / 9
v = 2 [m/s]
The average velocity of a particle moving from one point to another over a time interval is equal to the ratio of the displacement between the two points to the time it takes the particle to move that displacement. To find the average speed take the total distance traveled divided by the time interval. To find the average velocity. Since the displacement is always less than or equal to the distance traveled, the magnitude of the average velocity is always less than or equal to the average velocity.
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an empty spherical weather balloon with a mass of 5.00 kg has a radius of 2.879 m when fully inflated with helium. it is to carry a small load of instruments with a mass of 10.0 kg. taking the density of air to 1.16 kg/m^3 and the density of helium to be 0.160 kg/m^3, will the balloon get off the ground?
Buoyant force is greater than the Net Weight. Thus it will get off the ground.
What is Density?Density is the substance which is defined as the measurement of the given mass per unit volume. It is represented by the formula
D = m/v
Where,
D = Density
m = Mass
v = Volume
Now
Helium Mass = Density × Volume
[tex]= 0.160\ kg/m^3 \times \frac{4}{3} \times \pi \times r^3\ m^3[/tex]
= 15.99 kg
Total Mass of the Balloon = Mass of the given Instruments + Mass of the given Helium Filled + Empty Mass of the given Balloon
Total Mass of the Balloon will be = 10.0 kg + 15.99 kg + 5.00 kg
= 30.99 Kg
Displaced air mass = Density × Volume
Displaced air mass [tex]= 1.16\ kg/m^3 \times \frac{4}{3} \times \pi \times r^3\ m^3[/tex]
= 115.89 Kg
Now,
Buoyant Force = Mass × 9.8
= 115.89 Kg × 9.8
Net Force = Mass × 9.8
= 30.99 kg × 9.8
Thus from the above conclusion we can say that the Buoyant force is greater than the Net Weight. Thus it will get off the ground.
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the work function of silver metal is 6.9 × 10-19 j. if a crystal of silver is exposed to a pulse of blue light with a wavelength of 450 nm, will electrons be ejected, and if so, what kinetic energy will they have?
Determine the energy of an ultraviolet photon with a wavelength of 250 nm using E = hc/(wavelength) . After that, deduct the Cs work function energy, e* (work function in volts)
The entire mass of a nucleus is described in Section 44.1's discussion of 12C is smaller than the total of each nucleon's separate masses. The confined system's (the nucleus') energy is lower than the sum of the rest energies of the nucleon separation. The binding energy of this difference in energy the nucleus and can be understood as the additional energy required for a nucleus.
To separate it into its constituent parts. Consequently, to divide a nucleus into protons and neutrons, the system needs to be supplied with energy. Energy conservation and the mass-energy equivalence principle of Einstein demonstrate that any nucleus's binding energy, measured in MeV, is where mn is the mass of the neutral hydrogen atom and M(H) is its atomic mass.
nuclear, M(AZX) is a representation of the isotope A's atomic mass.
and the ZX Atomic mass units are used for all masses. The weight of the Z electrons in M (H) within a narrow range, cancels the mass of the Z electrons in the phrase M(AZX).
Discrepancy related to the electrons' atomic binding energy. Because
nuclear binding energies and atomic binding energies are both generally several electron volts.
With energies in the millions of electrons volts range, this difference is small.
Using the formula E = hc/(wavelength), calculate the energy of a UV photon having a wavelength of 250 nm (wavelength). Subsequently, subtract the Cs work function energy, e* (work function in volts)
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To be launched, a glider is uniformly accelerated from rest by a cable pulled by a motor that exerts a horizontal force on the glider throughout the launch. The glider reaches its launch speed of 51.0 m/s after accelerating for 17.0 s. Assume that the glider moves horizontally until it leaves the ground. Calculate the total distance travelled by the glider before it leaves the ground.
The total distance travelled by the glider before it leaves the ground is 867 meters.
Velocity is the change in displacement divided by time taken. Here the displacement is unknown. The glider reaches its launch speed of 51.0 m/s after accelerating for 17.0 s. The velocity of the glider is 51.0 m/s and time taken is 17.0 s. The equation to calculate the total distance travelled by the glider before it leaves the ground is given below.
velocity = displacement/time
displacement = velocity*time
displacement = 17.0*51.0 = 867 meters
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the gas which is supplied to the heating system in flat has 400 kj of chemical potential energy. of this, 320 kj is transferred to the thermal store of the fluid inside the radiators in the flat. calculate the efficiency of the heating system
The efficiency of the heating system is 80%.
Efficiency is the regularly measurable capacity to keep away from losing substances, energy, effort, cash, and time in doing something or in producing the desired end result. In a greater popular experience, it is the capability to do things nicely, efficaciously, and without waste.
Heat pumps are the most efficient way to heat pretty much any enclosed area, they are quiet and comfy, they decrease your heating invoice considerably, and they double as an air-conditioning gadget in the summer. Fuel heating systems can be fueled with the aid of both herbal fuel and propane with easy adjustments accounting for the one-of-a-kind traits of every. We seek advice from each fuel as genuinely "gasoline." The maximum commonplace styles of structures encompass compelled air, warm water, steam, and localized space heating.
efficiency = output/input × 100
= 320 / 400 × 100
= 80 %
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alice and bill are at the top of a cliff of height h. both throw a ball with initial speed v0, alice straight down and bill straight up. the speeds of the balls when they hit the ground are va and vb. if there is no air resistance, which is true?
Alice and bill throw the ball with same speed [tex]V_{A}[/tex]=[tex]V_{B}[/tex].
What is the speed ?The speed at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Given that it just has a direction and no magnitude, speed is a scalar number.
Okay, so let's imagine that there are two persons, Bob and Alice, standing on the edge of a cliff. We want to know how the speeds compare when the balls strike the ground so that as throws her ball downward at a speed of v and bill throws his ball upward at a speed of v from the same height.
Bill's will therefore rise to this height, strike 0 at that point, and then descend again. When it reaches this height, it will really be moving at the same speed as when it left Bill's hand, just in the opposite direction.
As a result, it will appear as though you tossed it straight down at the same speed, which implies When they both strike the ground, Alice's and Bill's balls will do so at the same pace.
The trajectory of Bill's ball will be symmetrical about this point in terms of the velocity or have the same speed going up as it did coming down or coming down as it did up, if you look at it because there is essentially no air resistance or anything.
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The complete question is:
"Alice and Bill are at the top of a cliff of height H. Both throw a ball with initial speed v0, Alice straight down and Bill straight up. The speeds of the balls when they hit the ground are [tex]V_{A}[/tex] and [tex]V_{B}[/tex]. If there is no air resistance, which is true? A)[tex]V_{A}[/tex] <[tex]V_{B}[/tex] B) [tex]V_{A}[/tex]=[tex]V_{B}[/tex] C) [tex]V_{A}[/tex]>[tex]V_{B}[/tex] D) impossible to tell"
what is the average angular acceleration of a blu-ray disc as it plays an 6.0-h set of movies? (assume the disk is scanned starting at its inner radius moving outward. express your answer to two significant figures.)
The average angular acceleration of a Blu-ray disc is 0.089 rad/s².
Angular acceleration refers to the time price of exchange of angular speed. As there are types of angular velocity, namely spin angular velocity and orbital angular velocity, Angular speed is the rate of change of angular displacement and angular acceleration is the rate of trade of angular pace.
Angular Acceleration is described as the time rate of change of angular velocity. it is usually expressed in radians in keeping with second in line with second. as a result, α = d ω d t. Angular acceleration is also known as rotational acceleration.
t = time duration = 6 h = 6 x 3600 sec
α = angular acceleration = (Wmax - Wmin )/t = (315 - 121)/(6 x 3600 ) = 0.089 rad/s²
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two tiny particles having charges 20.0 μc and -8.00 μc are separated by a distance of 20.0 cm. what are the magnitude and direction of electric field midway between these two charges? (k
Between these two charges, there is an electric field with a magnitude and direction of 10.8 x 105 N/C along AB.
In this issue, we must charge the fee. Twenty micro colums make up Q 1, and eight micro coulons make up Q 2. There is a 20 centimeter gap between these two charges. At point p, which is the intersection of the two charges, we must determine the net electric field. The electric field at point p points away from the charge because of the positive charge. He, let's assume that the electric field is even and that it is caused by the second charge, electric field point along the charge: q 2- and that is the electric field e 2.
The net electric field at point p is now equal to e 1 plus 2 and is represented by the symbol a. Consider the direction away from Question 1 as positive; hence, the direction to the right is a positive direction. The electric field owing to eq, 1 equals the column, constant k times, k 1 over 0.5 times r square, and similarly for eq, 2, where q, 1 and q 2 are the absolute magnitude of the charge, the net electric field at point p equals p over 0.5 r square 0.5 r square times.
The net electric field at point at the midpoint between the 2 charges, equals 2.52 times 10 to the 7 newtons co coulan and the direction will be towards the negative charge towards the minus 8 coulomb judge micro cholum charge. The sum of the absolute magnitude of the 2 charges and the electric field at point p equals 9 times 10 to the 9 newton meter square per column square over 0.5 times 0.2 meter square times, 20 plus 8 times 10 to the minus 6 couul Thus, at the halfway point between the t charges, this will be the net electric field.
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A clay ball (mass = 0.25kg) has a rightward momentum of +1.75 kg∙m/s. A second clay ball (mass = 0.25 kg) has a leftward momentum of -1.75 kg∙m/s. The two collide, stick together, and come to a complete stop after the collision.1) What was the total energy of the system before the collision?a- Not enough information to determineb- 6.13 Jc- 0 Jd- 12.25 J2) What was the total energy of the system after the collision?a- 6.13 Jb- 12.25 Jc- Not enough information to determined- 0 J3) What was the total momentum before the collision?a- 6.13 kg∙m/sb- 12.25 kg∙m/sc- Not enough information to determined- 0 kg∙m/s4) What was the total momentum after the collision?a- Not enough information to determineb- 0 kg•m/sc- 6.13 kg•m/sd- 12.25 kg•m/s
1)
[tex]\begin{gathered} E1=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_1v_2^2 \\ where: \\ m_1=m_2=0.25kg \\ v_1=7m/s \\ v_2=-7m/s \\ so: \\ E1=\frac{1}{2}0.25(7^2)+\frac{1}{2}0.25(7^2) \\ E1=6.125+6.125 \\ E1=12.25J \end{gathered}[/tex]Answer:
d. 12.25J
------------------------
2)
According to the conservation of energy:
[tex]\begin{gathered} E1=E2 \\ so: \\ E2=12.25J \end{gathered}[/tex]Answer:
b. 12.25
-------------------------------
3)
[tex]P1=m_1v_2+m_2v_2=+1.75-1.75=0[/tex]
Answer:
d. 0 kg∙m/s
-----------------------------------------
4)
Using conservation of momentum:
[tex]\begin{gathered} P1=P2 \\ so: \\ P2=0 \end{gathered}[/tex]Answer:
b. 0 kg•m/s
to prevent shoplifting, stores install security mirrors at the ceiling. a spherical mirror has a focal length of 25 cm. find its radius of curvature in cm.
Security mirrors are placed above the ceiling of establishments to deter stealing. A spherical mirror has a 25 cm focal length. R = 50 cm is the radius of curvature.
It has been found that the radius of curvature for spherical mirrors with small apertures is equivalent to double the focal length. R therefore equals 2f. It is evident that the main focus of a spherical mirror is located in the middle, halfway between the curvature's centre and the pole. A curve's radius of curvature at any given location is, roughly speaking, the radius of the circle that fits the curve there the best. One divided by the radius of curvature is the curvature, indicated by the symbol. You must locate the circle that fits that point the best in order to calculate the curvature there. The osculating circle is what's known as this. The reciprocal of the curve's curvature at that point is known as the osculating circle radius.
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a rifle bullet (mass ? 1.50 g) has a velocity of 7.00 ? 102 mph. what is the wavelength associated with this bullet?
3.13×10^2 metre is the wavelength associated with this bullet.
[tex]\lambda=(h)/(mv)[/tex]
Here, lambda is the wavelength, m is the mass, v is the velocity of the particle, and h is Planck's constant
The mass of a rifle bullet is 1.50g and its velocity is 7×10^2 mph
First convert the values to SI units as follows:
[tex][m=1.50 g*1kg/10^3g,[=1.50 *10^-3kg][/tex]
[tex][v=7.00 *10^2mph*(0.447m/s/1mph],[=3.13*10^2m/s][/tex]
De Broglie wavelength refers to the wavelength of a wave that is connected to a moving particle, such as the matter-wave or de Broglie wave. It is derived from: =h/mv In this equation, m stands for the particle's mass, v for its speed, and h for the Planck constant.
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A 1,075 N sky diver has opened his parachute to slow his descent to a constant
speed the parachute applies 1,469 N of force. What deceleration does he
experiences?
The deceleration experienced by the 1075 N sky diver as he opened his parachute is 13.39 m/s²
How to determine the decelerationForce = mass × acceleration
We know that deceleration is the acceleration of stopping objects. Thus,
Force (F) = mass (m) × deceleration (a)
Thus, we can obtain the deceleration of the sky diver as follow:
Weight of diver (W) = 1075 NForce (F) = 1469 NAcceleration due to gravity (g) = 9.8 m/s²Mass of diver = W / g = 1075 / 9.8 = 109.69 KgDeceleration (a) =?Force = mass (m) × deceleration (a)
1469 = 109.69 × a
Divide both sides by 109.69
a = 1469 / 109.69
a = 13.39 m/s²
Thus, the deceleration is 13.39 m/s²
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what gauge pressure is required in the city water mains for a stream from a fire hose connected to the mains to reach a vertical height of 16.0 m ? (assume that the mains have a much larger diameter than the fire hose.)
Gauge pressure required in city water mains for a stream is 147,150 Pa
What is the Bernoulli's theorem for pressure?In fluid mechanics, Bernoulli's principle states that an increase in fluid velocity occurs simultaneously with a decrease in pressure or a decrease in the fluid's potential energy. This principle is named after the Swiss mathematician Daniel his Bernoulli published it in his 1738 book Fluid Mechanics.
According to the Bernoulli's Equation:
P₁ + ρgy₁ + ([tex]\frac{1}{2}[/tex])ρv₁² = P₂ + ρgy₂ + ([tex]\frac{1}{2}[/tex])ρv₂²
where, y₁ = initial height
y₂ = final height
Initial height is 0 meters and final height is 15 meters.
The problem states that the mains have a much larger diameter than the hose, so v₁ = 0
Once our water reaches a 15 m. altitude, it stops going anymore higher. Therefore, v₂ also be 0.
P₁ = P₂ + ρgy₂
Since, we are solving for gauge pressure, we can assume that the pressure at the top of our column of water is zero.
P₁ = ρgy₂
P₁ = 1000 × 9.8 × 15
P₁ = 147,150 Pa
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Compare and contrast cassette tapes versus mp3 players. If you were to make copies of the musical content, which would sound better on the 6th
copy?
O Cassette tapes would have better sound quality because they have digital signals to produce sound, which do not deteriorate over time.
O Mp3 players would have better sound quality because they use analog signals to produce sound.
O Both would sound the same because they both use analog signals to produce sound.
O Mp3 players would have better sound quality because they have digital signals to produce sound, which do not deteriorate over time.
If we were to make copies of musical content up to the 6th time, Mp3 players would have better sound quality because they have digital signals to produce sound, which do not deteriorate over time.
Cassette tapes work on analog magnetic tape recording format for recording audio and playback whereas mp3 is a type of digital technology that has digital signals to produce sound. This is the reason why cassettes do not sound better than digital mp3 players.
Cassette tapes being magnetic type media suffer from print which causes to hear a bit of sound before the sound is even started and result in deterioration over time whereas digital signals do no deteriorate over time.
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help me please thanks
Sound and thermal energy are kind of energy which involve movement.
What is energy?Energy is defined as the capacity of a physical system to perform work.
When a force, such as sound or pressure, causes an item or substance to vibrate, the result is sound energy. Waves of that energy pass through the substance. We refer to the sound waves as kinetic mechanical energy.
The energy present in a system that determines its temperature is referred to as thermal energy. Thermal energy flows as heat.
Sound energy and thermal energy are involve movement of the particle.
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A cold duck slides down a snow covered hill inclined at an angle of 35° to the horizontal. If the ducks speed is a constant 5m/s, determine the horizontal and vertical components of its velocity.
Given data:
* The angle of the inclined plane is,
[tex]\theta=35^{\circ}[/tex]* The speed of the duck along the inclined plane is v = 5 m/s.
Solution:
The diagrammatic representation of the given case is,
From the triangle ABO,
[tex]\angle ABO=180^{\circ}-\angle AOB-\angle OAB[/tex]Substituting the known values,
[tex]\begin{gathered} \angle ABO=180^{\circ}-90^{\circ}-35^{\circ} \\ \angle ABO=55^{\circ} \end{gathered}[/tex]Thus, the inclined plane makes an angle of 55 degrees with the negative of the y-axis.
Similarly, the angle of the velocity of the duck along the inclined plane with the negative y-axis is 55 degrees.
Thus, the vertical component of the velocity is,
[tex]\begin{gathered} v_y=-v\cos (55^{\circ}) \\ v_y=-5\times\cos (55^{\circ}) \\ v_y=-2.88\text{ m/s} \end{gathered}[/tex]The horizontal component of the velocity is,
[tex]\begin{gathered} v_x=v\sin (55^{\circ}) \\ v_x=5\sin (55^{\circ}) \\ v_x=4.096\text{ m/s} \end{gathered}[/tex]Thus, the horizontal component of velocity is 4.096 meters per second, and the vertical component of velocity is -2.88 meters per second.
one way future space stations may create artificial gravity is by rotating the station at constant speed. consider a cylindrical space station 380 m in diameter that is rotating about its central axis. astronauts walk on the inside surface of the space station. if the centripetal acceleration at the wall of the station is to be equal to the acceleration due to gravity on the surface of the earth (ac
As a result, neither the astronauts nor the others sharing the space station can feel the force that supports them from the structure's solid surface.
Space stations are constantly in a free-fall situation, which means their acceleration is the same as the local gravitational acceleration. As a result, neither the astronauts nor the other space station residents can feel the support force generated by the station's solid surface.
Thus, by rotating the space station around its center, we produce center-directed forces from the space station's wall in the absence of gravity.
Gravitational acceleration is equal to centripetal acceleration.
A = g
r2 = g r 2 = /g r 2 = 9.81 m s 2/ 55 m 2 = 0.178 r a d 2 s/ 2 = 0.422 r a d / s
Therefore, the angular speed of the space station is 0.422 rad/s.
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it takes a car 6.o seconds to slow down to a stop, and it travels 90 meters during this time. What was its initial velocity?
The initial velocity of the car, given that it takes 6.0 seconds to slow down to a stop is 30 m/s
How do I determine the initial velocity?The initial velocity of the car can be obtained by doing the following:
First, we list out the given parameters from the question. This is given below:
Time (t) = 6 secondsDistance (s) = 90 mFinal velocity (v) = 0 m/sInitial velocity (u) = ?Finally, we shall determine the initial velocity of the car as illustrated below:
s = (v + u)t / 2
90 = [(0 + u) × 6] / 2
90 = [u × 6] / 2
90 = 6u / 2
Cross multiply
6u = 90 × 2
6u = 180
Divide both sides by 6
u = 180 / 6
u = 30 m/s
From the calculations made above, we can conclude that the initial velocity of the car is 30 m/s
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curler pushes a stone to a speed of 3.0 m/s over a time of 2.0 s . ignoring the force of friction, how much force must the curler apply to the stone to bring it up to speed? a curler pushes a stone to a speed of 3.0 over a time of 2.0 . ignoring the force of friction, how much force must the curler apply to the stone to bring it up to speed? 3.0 n 15 n 30 n 300 n
The force required by the curler will be 30 N
we see that the stone is pushed from rest to a certain velocity
initial velocity (u) = 0 m/s
final velocity (v) = 3 m/s
mass of the stone (m) = 20 kg
Time for which the stone is pushed (t) = 2 s
Now , for calculating the force required (without taking into account the friction) we first need to calculate the acceleration
therefore , a = [tex]\frac{v-u}{t}[/tex]
a = (3- 0)/ 2
a = 1.5 m/s²
Now , we know that
Force = mass x acceleration
F = 20 x 1.5
F = 30 N '
So the force required will be 30 N .
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study a uniformly charged conducting sphere of 1.2 m diameter has a surface charge density of 8.1 mc/m2. (a) find the net charge on the sphere. (b) what is the total electric flux leaving the surface of the sphere?
The net charge on the sphere is 3.7×10⁻⁵C and the total electric flux leaving the surface of the sphere is 4.1×10⁶ N.m²/C.
What are electric flux and its measure?The distribution of the electric field or the velocity at which the electric field moves through a specific area can both be measured as electric flux. The Greek letter is used to represent electrical flux. Voltmeters (Vm), often known as Nm 2 C – 1, is the SI unit for electric flux.
Procedure:
(a) The charge on the surface of the sphere is the product of the surface charge density σ and the surface area of the sphere which is 4πr².
Thus, q=4πr²σ
= 4π(1.2m/2)²(8.1×10⁻⁶)
=3.7×10⁻⁵C
(b) We select a spherical-shaped Gaussian surface with a slightly greater radius that is concentric with the conducting sphere.
∅=q/∈°
= 4.1×10⁶ N.m²/C
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How much work is done when a car is pushed 8 m with 160 N of force?
Answer: 1280 J
Explanation: Work is calculated by multiplying the displacement (8m) by the force (160 N) which will give you 1280 J (joule)
how much charge is on each plate of a 4.00-mf capacitor when it is connected to a 12.0-v battery? (b) if this same capacitor is connected to a 1.50-v battery, what charge is stored?
A charge of 4.8 x 10 5 C is present on each capacitor plate.
B. The capacitor has a 4.5 x 10 6 J energy capacity.
Describe the capacitor.
A capacitor is a device used to store electrical power and charge. It is composed of at least two separated electrical conductors. Although usually referred to as "electrodes," these electrical conductors are actually "capacitor plates." A capacitor is referred to as a "vacuum capacitor" if the space between capacitors is nothing more than a vacuum. However, the space is often filled with a dielectric, an insulating material. How much storage space a capacitor has is determined by its capacitance attribute.
A. Establishing the charge
Capacitor (C) = 4 F = 4 10 6
Voltage = 12 volts.
Charge (Q) = ?
Q = CV
Q = 4×10¯⁶ × 12
Q = 4.8×10¯⁵ C
B. Measuring the amount of energy the capacitor has stored.
Voltage (V) equals 1.5 V.
Energy (E) =? E = 12CV Capacitor (C) = 4 F = 410 6
²\sE = ½ × 4×10¯⁶ × 1.5²
E = 2×10¯⁶ × 2.25\sE = 4.5×10¯⁶ J
A. There is 4.8 x 10 5 C B of charge on each capacitor plate. The capacitor has 4.5 x 10 6 J of stored energy.
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when you weigh yourself on good old terra firma (solid ground), your weight is 545 n . in an elevator your apparent weight is 470 n . what is the magnitude of the elevator's acceleration?
The magnitude of the elevator's acceleration is 18.25 m/s².
What is the acceleration of the elevator?The acceleration of the elevator is calculated as follows;
R = Fa - Fg
R = ma - mg
R = m(a - g)
where;
R is the apparent wight on elevatorm is your massa is your accelerationg is acceleration due to gravitym = W/g
m = (545 N) / (9.8 m/s²)
m = 55.61 kg
ma = R + mg
ma = R + W
a = (R + W) /m
a = (470 + 545) / 55.61
a = 18.25 m/s²
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At what temperature will wood and iron apper equally hot or equally cold to our body?
They will feel equally hot or cold at the same temperature.
What do you mean by temperature?
Temperature is a physical parameter that describes how hot stuff or radiation is. There are 3 different types of temperature scales: those described in regards to the average translational kinetic energy per freely moving microscopic substance in a body, such as a atom, compound, or anion, such as the SI scale; those that rely solely on purely macroscopic properties and thermodynamic principles, such as Kelvin's original definition; and those that are not defined by theoretical principles, but are defined by convenient empirical properties of particulate matter.
If they are the same temperature as the area of your body that is touching them, they will feel equally hot or cold. There will be no heat movement if the wood and iron at the same temperature as the skin, and the iron's higher thermal conductivity will be irrelevant. The specific temperature cannot be specified because if you touch the materials with your fingertips, the wood and iron must match that temperature, and if you test them with your tongue, which is often considerably warmer than your hands, the wood and iron must be warmer.
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An automobile travels for 90 minutes along a highway. The graph shows the progress of the automobile, with its start point designated as distance = 0 km.
As shown on the graph, at which two points does the automobile change speed?
points P and Q
points B and P
points A and B
points A and P
The change in the speed of the automobile occurred at points A to B.
What is change in speed of an object?
The change in the speed of an object is the rate at which the distance traveled by the object changes with time.
The change in speed of the object from point O to A is calculated as follows;
ΔV = Δx/Δt
where;
Δx is change in position of the objectΔt is change in timeΔV = (5 - 0) / (15 - 0)
ΔV = 0.333 km/min
The change in speed of the object from point A to B is calculated as follows;
ΔV = (15 - 5) / (30 - 15)
ΔV = 0.67 km/min
From this we can conclude that speed of the automobile changed at points O to A, A to B and B to P.
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