he wavelength of blue light is approximately 4.0 x 10 -7 meters. calculate the frequency of blue light in hertz. a. 2.5 x 10 7 b. 1.2 x 102 c. 3.3 x 10 -9 d. 7.5 x 1014 e. 1.2 x 10 1

In a volumetric pipette which has an uncertainty of 0. 01 cm³, for a measurement of 0. 20cm3, the lowest possible value is 0.195 cm³

and highest possible value is 0.205 cm³.

Measurement uncertainty = 0.01 cm³

Error = uncertainty value/2 = 0.01/2  = 0.005 cm³

The formula to calculate the possible values for a volumetric pipette with uncertainty0.01 cm³ is give below.

Possible values = measured value ± Error.

Lowest possible value = 0.20 - 0.005

                                     = 0.195 cm³

Highest Possible Value = 0.20 + 0.005

                                      = 0.205 cm³

Thus, for a volumetric pipette, the lowest possible value is 0.195 cm³ and highest possible value is 0.205 cm³.

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The time of flight is 0.4 sec, The range is 1.6 m and maximum height is 3.2 meter.

Calculation:-

The initial vertical speed is u = 5m/s×sin53° = 4m/s

Time of flight = u/g

= 4/10

= 0.4 second

so if the final vertical velocity is v at a height h then v² = u² −2gh will give us v = [tex]\sqrt{16-20*0.45} = \sqrt{7} m/s[/tex]

The horizontal velocity remains constant and is given as Vx = 5m/s Cos53° = 3m/s

so the speed at the said instant will be V = [tex]\sqrt{v_{x} ^{2} +v^{2} } = \sqrt{9+7} = 4m/s[/tex]

Range = horizontal velocity× 0.4 second

= 4 × 0.4

= 1.6 m

Height = UT- 1/2at²

= 1.6 - 0.4 × 10 × 0.16

= 3.2 m

The horizontal velocity of the projectile is constant. There is the vertical acceleration due to gravity. Its value is 9.8 m/s/s, and the projectile's vertical velocity changes at 9.8 m/s per second. The horizontal movement of the projectile is independent of vertical movement. Horizontal acceleration is always zero because nothing accelerates the projectile horizontally.

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Iodine sublimates and reacts with the compounds on the produced TLC plate when it is placed in the chamber and covered, producing yellow-brown spots.

Iodine interacts with many different chemical molecules to produce colorful complexes, which causes coloration. About half of the possible chemicals will work with this stain. For every step see attached file.

Because complexation is reversible and the original chemical will eventually remain on the TLC plate when the iodine has evaporated, this procedure is regarded as "semi-destructive." It is potentially feasible to utilize a different visualization method on the TLC plate after the coloring fades, though it's likely the compound may already have evaporated by then.

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The magnitude of the average force exerted by the block on the bullet during that time is 202,304.147m N (m stands for bullet mass)

We got some values here,

v = 439 m/s

t = 2.17 ms = 2.17 × [tex]10^{-3}[/tex] s

First, we should find the acceleration of the car. We assume that final speed of bullet after impact is 0 m/s, so here we go

a = v/t

a = [tex]v_{1}[/tex] - [tex]v_{0}[/tex] / [tex]t_{1}[/tex]  - [tex]t_{0}[/tex]

a = 0 - 439 / 2.17 × [tex]10^{-3}[/tex]  - 0

a = -439 / 2.17 × [tex]10^{-3}[/tex]

a = -439,000 / 2.17

a = -202,304.147 m/[tex]s^{2}[/tex]

What actually happens when the result is negative is not the acceleration after the bullet hits the target, but the deceleration.

Now we got the amount of deceleration. We can found the force by the formula of: F = m.a but in the question there is no mass value of the bullet. So, we can answer this question by this way (we can ignore negative values)

F = m.a

F = m × 202,304.147 m/[tex]s^{2}[/tex]

F = 202,304.147m N

Acceleration (a) is the change of velocity (Δv) over the change of time (Δt), and here is the formula, a = Δv/Δt. This formula allows you to measure how quick velocity changes in meters per second squared (m/s. Acceleration is also a vector quantity, so it includes both magnitude and direction.

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Bohr atomic model can not predict spectra for multielectron atom.

What is Bohr atomic model?

The Bohr model postulates  that  the electrons are orbit the nucleus at fixed energy if levels. Orbits further from to the nucleus to exist at highest energy levels.

Sol-

Bohr’s theory was unable to  explained the followings observations :
i) Bohr’s model could not explain the spectra of atoms containing more than one of  electron.

ii) It never not explain the Zeeman effect.
In presence of the magnetic of field, each of  spectral line gets split up to into fine lines, the phenomenon is known as Zeeman effect.

iii) It could not explain the to Stark effect.
In presence of the electric of field, each spectral line gets split up into fine lines, the phenomenon is known as as the Stark effect.

iv) The main objection to the Bohr’s model was raised by Heisenberg’s uncertainty principle.
According to the  Heisenberg’s uncertainty principle, it is impossible to determine the simultaneously the exact position and the momentum of a small moving particle like an electron.

But, according to Bohr’s model electron moves in well-defined orbits around the nucleus, and hence its position, as well as momentum, can be determined simultaneously, which is against the of  uncertainty principle.

So, electron moves in well-defined orbits around to the nucleus is impossible.

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The effect on K₁/K₂ on changing the quantities are :

a)If the mass of 1 is double the mass of 2, and the speeds are the same, then ratio is 2 times

b)If the speed of 1 is double the speed of 2, and the masses are the same, then ratio becomes 4 times.

c)If The mass of 2 is double the mass of 1, and the speeds are the same, then ratio becomes half.

d)If The speed of 2 is double the speed of 1, and the masses are  same, then ratio becomes 1/4 times.

e)If The speed of 1 is double the speed of 2, and the mass of 2 is double the mass of 1,then ratio becomes half.

We know that kinetic energy of any body is given by (1/2)mv² where m is the mass of the body and v is the velocity of the body.

Hence, the ratio of K₁/K₂ is changing  on  changing one or both of these parameters

a) when mass of first body is doubled then K₁ becomes 2 times of initial kinetic energy, then ratio will become twice of the initial value.

b)when speed of first object is doubled then kinetic energy of first object will becomes 4 times of initial energy ,therefore the ratio becomes 4 times of initial ratio.

c) If The mass of 2 is double the mass of 1, and the speeds are the same then in that kinetic energy of 2nd object will become twice of initial kinetic energy, therefore ratio  will become half.

d)  If The speed of 2 is double the speed of 1, and the masses are  same then ratio becomes 1/4 times of initial ratio.

e) If The speed of 1 is double the speed of 2, and the mass of 2 is double the mass of 1, then in that case ratio becomes half of initial ratio,

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(Complete question) is:

Kinetic energy depends on both the mass of an object and on its speed.  Ki the kinetic energy. Using the ratio K₁/K₂ to see how changing one or both of these parameters changes the kinetic energy. Match each case with the correct value of ratio K₁/K₂. 1) The mass of 1 is double the mass of 2, and the speeds are the same.2) The speed of 1 is double the speed of 2, and the masses are the same.  3) The mass of 2 is double the mass of 1, and the speeds are the same. 4) The speed of 2 is double the speed of 1, and the masses are the same. 5) The speed of 1 is double the speed of 2, and the mass of 2 is double the mass of 1.

The sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length) is mentioned below

1. First heart sound

2. Second Heart sound

3.  Third heart sound

4. Fourth heart sound

Therefore, the sounds of each of the following heart valves in terms of intensity (loudness,) pitch (frequency) and duration (length) is mentioned above

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The core of a red giant is contracting, but the outer layers are expanding as a result of hydrogen fusion in a shell outside the core

Nuclear fusion of hydrogen to form helium happens evidently in the solar and different stars. It takes area best at extremely high temperatures. Scientists are attempting to find methods to create controlled nuclear fusion reactions on earth.

Researchers at Lawrence Livermore countrywide Laboratory's country-wide Ignition Facility in California have spent over a decade perfecting their method and the feature now showed that the landmark test conducted on eight August 2021 did, in fact, produce the primary-ever successful ignition of a nuclear fusion reaction.

People had been capable of cause fusion, but in methods that might be uncontrolled, like in thermonuclear guns sometimes called hydrogen bombs. Fusion has additionally been proven in laboratories, but below conditions that eat a long way, extra strength than the reaction produces.

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Coefficient of friction is calculated to be 0.4. Therefore, a) will be the correct answer .

Frictional force is that force which is generated by two surfaces that contact and slide against each other. Factors affecting the frictional force are the surface texture and the amount of force impelling them together.

The frictional force is said to be a contact force as frictional force occur when two surfaces come in contact with each other.

Given applied force = 60 N

weight of object = 50N;  friction force = 20N

As we know that, Coefficient of friction =  force of friction/normal force

= 20/50

Coefficient of friction = 0.4

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The top five books must be pushed off the bottom one with 5 N of horizontal force.

The word "force" has a specific meaning in science. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. Each of the six books weighs five pounds, therefore we need to slide five of them.

them, where 55 = 25N

The following formula can then be used to get the friction force.

F = N μ

where F is the frictional force, N is the force, and is the static friction coefficient

F= (25 N) (0.2) (0.2)

F= 5 N

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Equation A. P A i + P B i = P A f + P B f and D.ΔPA + ΔPB=0. correctly states the principle of conservation of momentum.

Momentum is the product of the mass and pace of an object. it's miles a vector quantity, owning a magnitude and a route. If m is an item's mass and v is its velocity, then the object's momentum is p.

Momentum is manufactured from the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both value and path. Isaac Newton's 2d regulation of motion states that the time price of trade of momentum is the same as the pressure performed at the particle. See Newton's legal guidelines of movement.

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Disclaimer:- your question is incomplete, please see below for the comlete question.

Bumper cars a and b undergo a collision during which the momentum of the combined system is conserved. which equation(s) correctly states the principle of conservation of momentum? check all that apply.

A. P A i + P B i = P A f + P B f

B. P A i + P A f = P B i + P B f

C. ΔPA = ΔPB

D. ΔPA + ΔPB=0

The magnetic field 35.0 cm away from the middle of the straight cord, in the plane of the two wires is 1.96 T j

A magnetic field is a vector field that explains the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force that is perpendicular to both its own velocity and the magnetic field.

The magnetic field is a technique used to describe how magnetic force is distributed in the space surrounding and within something magnetic in nature.

Given,

A long household extension cord's two conductors carry equal 5.00-a currents in opposite directions at the same time.

And also given that the two wires are 3.00 mm apart.

Let B₁ be inside the plane and B₂ be outside the plane.

It is required to calculate the magnetic field at point A

The directions of the magnetic field  at A can be calculated using Right hand rule.

[tex]B_{net}[/tex] = B₂ -B₁

[tex]B_{net}[/tex]=μ₀I/2Π(0.35-(3×10⁻³)/5) - μ₀I/2Π(0.35+(3×10⁻³)/5)

[tex]B_{net}[/tex]= 1.96×10⁻⁹ TJ

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If a 69.87 kg person ate 181 calories worth of sugar and they converted all of that energy to heat immediately, the change in temperature of that person  is 3.609 ºC.

What is calorie?

To calculate the change in temperature resulted from the intake of food calories or energy generated in Joules we use the formula,

Energy(Joules) = mass of the body (g) x specific heat of the body(J/gºC.) x change in temperature (ºC)

Let us assume that the average specific heat of the person's body is 3.00 J/gºC.

Using the above formula we find the change in temperature as-

181 x 1000 cal/ 1cal x 4.18 J/1 cal = 69.87 x 1000 x  3.00 J/gºC. x ΔT

ΔT = 181 x 1000 x 4.18/ 69.87 x 1000 x 3

     = 3.609

Hence, the change in temperature of that person is 3.609 ºC.

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The shaved camel has more evaporation than unshorn camel so it needs more water.

In order to lower the bog, the sweat, or more specifically its evaporation, cools the air around the body.

why does camels produce little sweat and urine?

A camel can easily withstand extreme temperatures.

Most of a camel's fat is deposited in its humps, unlike many other mammals, allowing for improved thermoregulatory.  It is easier for them to release heat from their bodies in warmer climates. Camels seldom ever perspire. They are far better able to withstand the heat than we are.

During the day, their body temperature fluctuates, rising with the greater outside warmth and falling at midnight when it is colder. Although it may seem odd that camels have fur when they live in such desert areas, their hairs really act as insulation to keep them cool.

Therefore, The shaved camel has more evaporation than unshorn camel so it needs more water.

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The shaved camel has more evaporation than unshorn camel so it needs more water. In order to lower the bog, the sweat, or more specifically its evaporation, cools the air around the body.

Why does camels produce little sweat and urine?

A camel can easily withstand extreme temperatures. Most of a camel's fat is deposited in its humps, unlike many other mammals, allowing for improved thermoregulatory.  It is easier for them to release heat from their bodies in warmer climates. Camels seldom ever perspire. They are far better able to withstand the heat than we are.

During the day, their body temperature fluctuates, rising with the greater outside warmth and falling at midnight when it is colder. Although it may seem odd that camels have fur when they live in such desert areas, their hairs really act as insulation to keep them cool.

Therefore, the shaved camel has more evaporation than unshorn camel so it needs more water.

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The work done by tension force of 14N applied on the laptop by a rope as it moves 2.0 mm up the slope is 0.028 J

W = F d cos θ

W = Work done

F = Force

d = Displacement

θ = Angle between force and displacement vector

F = 14 N

d = 2 mm = 0.002 m

θ = 0

W = 14 * 0.002 * 1

W = 0.028 J

Work done is the change in energy of an object. So if an object moves a certain distance, work is done on the object. If the force and displacement are perpendicular to each other there is no work done on the object.

Therefore, the work done by tension on the laptop is 0.028 J

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Such an orbit places a satellite at a height of around 35,786 km (22,236 mi) above mean sea level. At relation to the surface of the Earth, it remains in the same place.

A prograde, low-inclination orbit with a period of 23 hours, 56 minutes, and 4 seconds is known as a geosynchronous orbit (GEO). Even if it may seem to move north and south, a spacecraft in geosynchronous orbit appears to stay above Earth at a constant longitude.

what is geosynchronous orbit?

The word "geosynchronous" describes the satellite's orbital period, which allows it to be in phase with the rotation of the Earth ("geo-"). In addition to the criteria for orbital time, the satellite must also be situated in an orbit that places it close to the equatorial in order to qualify as geostationary.

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Such an orbit places a satellite at a height of around 35,786 km (22,236 mi) above mean sea level. At relation to the surface of the Earth, it remains in the same place.

What is geosynchronous orbit?

The word "geosynchronous" describes the satellite's orbital period, which allows it to be in phase with the rotation of the Earth ("geo-"). In addition to the criteria for orbital time, the satellite must also be situated in an orbit that places it close to the equatorial in order to qualify as geostationary.

A prograde, low-inclination orbit with a period of 23 hours, 56 minutes, and 4 seconds is known as a geosynchronous orbit (GEO). Even if it may seem to move north and south, a spacecraft in geosynchronous orbit appears to stay above Earth at a constant longitude.

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If the Sun had been born with a smaller, lower-mass companion star, would that star be a red dwarf today or would it already be dead, it would still be a red dwarf today regardless of how much less mass than the Sun it has, since its lifetime would be inherently longer than the Sun's.

Stars sparkle and shine—they appear to have an incandescence of their own even when they are bathed in the spotlight—so it stands to reason that they are stars. However, they are "stars" in a much more specific sense because they are a product of the long-standing Western cultural tendency to equate humanity with the heavenly.

Not all celebrities live alone. About half of all stars in our galaxy, the Milky Way, have a companion and journey through space in a binary system.

Now, the long-lost partner of the Sun could be found anywhere in the Milky Way. According to a team of Harvard astronomers, our solar system was once a binary system because the Sun formerly had a companion star.

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Answer: Transition metals

Explanation:

The final temperature of the gas is obtained as 2700 K or 2472° C.

We know that when the temperature of a gas is increased, the speed of the gas is also increased. Given that we have the initial temperature of the gas as  27° C or 300 K.

Given that;

[tex]V_{1}[/tex]/[tex]V_{2}[/tex] = √[tex]T_{1}[/tex]/[tex]T_{2}[/tex]

Where the [tex]V_{1}[/tex] and [tex]V_{2}[/tex] refers to the initial and the final velocities while the [tex]T_{1}[/tex] and the [tex]T_{2}[/tex] refer to the initial and the final temperatures.

[tex]V_{1}[/tex]/3 [tex]T_{1}[/tex]   = √300/ [tex]T_{2}[/tex]

1/3 = √300/ [tex]T_{2}[/tex]

1/9 = 300/ [tex]T_{2}[/tex]

[tex]T_{2}[/tex] = 2700 K or 2472° C

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For a frictionless pulley with mass connected by a light string, the acceleration for the system when released is equal to 6.5m/s²

Using the formula a = (m₂ - m₁)g/(m₁ + m₂)

Where a = acceleration, m = mass and g = gravity

m₁  = 2kg

m₂ = 10kg

g = 9.8m/s²

Applying to the formula, a = (m₂ - m₁)g/(m₁ + m₂) to find the acceleration of a frictionless pulley when released;

a = (10 - 2)(9.8)/(2 + 10)

a = 8(9.8)/12

a = 6.5m/s²

Therefore the system's acceleration 6.5m/s²

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When the object is a sphere of Radius R and mass M the 60% of its total kinetic energy is its translational kinetic energy.

The kinetic energy of an object is termed as the energy it posses because of its motion.

The translational kinetic energy is the energy required to move or accelerate the object from its position of rest.It is described as the effort required to move a mass-determined body from rest to the indicated velocity.

The moment of inertia of the object will be⇒I =2/3MR2

Sphere is rolling without slip ,v=Rω (v= speed of centre of mass and ω is angular speed)

Translational KE =1/2Mv2

Rotational KE = 1/2Iω2=1/2(2/3MR2)x(V/R)2=1/3Mv2

Total KE= 1/2Mv2 +1/3Mv2 =5/6 Mv2

Now % of Translational Energy= 1/2Mv2 ÷ 5/6 Mv2 x100 = 60%

Hence, when the object is a sphere of Radius R and mass M the 60% of its total kinetic energy is its translational kinetic energy.

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The total work done if a system gains 612 KJ of heat, resulting in internal energy of the system equals to 246 KJ  would be -366 KJ

What is the internal energy of the system?

Internal energy can be defined as the property that defines the energy of a substance in the absence of effects due to capillarity,  external electric and magnetic fields

In the above case

Let Change in internal energy ΔU = 246 kJ

Let Heat gained by the system (q) = 612 kJ

Using the  First law of thermodynamics

ΔU = q + w

Where:

ΔU  represent  change in internal energy

q represents  heat added to the system

and w is work done.

Let plug in the formula

246 kJ = 612 kJ + w

w = 246 kJ - 612 kJ

w= - 366 kJ

Here the negative sign means  that work is done by the system.

Therefore, The total work done if a system gains 612 KJ of heat, resulting in internal energy of the system equals to 246 KJ  would be -366 KJ

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To learn about the focal length and magnification to solve this problem.

What is focal length?

The focal length of a narrow lens in air is measured from the lens's center to its primary foci, also known as focal points. The focal length of a converging lens, such as a convex lens, is positive and determines how far a collimated light beam must travel to focus on a single point.

What is magnification?

The size of a picture in relation to the size of the item that created it is known as magnification in optics. The term "linear" magnification—also referred to as "lateral" or "transverse" magnification—describes the ratio of image length to object length as measured in planes perpendicular to the optical axis.

Given U₀ = 3cm, f₀= 2.5cm, v₀=mage distance for objective lens

1/f₀= 1/v₀- 1/u₀

1/v₀=1/f₀+1/u₀=1/2.5-1/3

v₀= 3*2.5/3-2.5= 15cm

Object distance for eye piece =20−15=5cm

Given Ue= -5cm, Fe= 6cm, Ve = image formed by eye piece

1/Ve= 1/Fe +1/ Ue= 1/6-1/5

Ve=-30cm

magnification m = -L/F₀*25/Fe

where L is the length of the microscope

here L= 20 cm

m= -20/25*25/6= -33.33

Therefore, the focal length is 15cm and the magnification is 33.33 cm.

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The item is pushing against it with a force of 30.4 N in a downward direction.

Since there is no net gravitational pull in the earth's center, the weight will be zero but the mass will not change. Thus, 50 kg will be the mass of the earth's core.

When two objects of mass M1 and M2 are separated by R, the gravitational force between them is expressed as follows:

F = G*(M1*M2)/R^2

G = 6.674*1(-11) m3/(kg*s2), where G is the gravitational constant.

M1, the object's mass, is 50 kg, and R is its distance, in.

F = G*(M1*M2)/R^2

G = 6.674*1(-11) m3/(kg*s2), where G is the gravitational constant.

M1, the object's mass, is known to be 50 kg.

This distance, R, is 25,600 kilometers.

However, keep in mind that this should be stated in meters and

1km = 1000m

Consequently, 25,600km equals (25,600*1000)m, or 25,600,000 m.

M2 is the equivalent of 5.972*10(24) kg, which is the mass of the Earth.

F = (6.674*1(-11) m3/(kg*s2))*(50kg*5.972*10(24) kg)/ (replacing all of those in the force equation) ( 25,600,000 m)

^2\sF = 30.4 N

Given that the gravitational force is attracting, it will act in a manner that is favorable to the 50 kg item.

Consider the following as the second Newton's law:

F = M*a

Accordingly, the acceleration brought on by the item on Earth is 30.4N = 5.972*10(24) kg*a

a = 30.4N/((5.972*10(24) kg)) = 5.09*10(-24) m/s

Nearly everyone can feel the acceleration.

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Acceleration will be constant while speed will not. The third option describes the motion.

Force can simply be defined as a pull or push. It is the product of mass and velocity and it is measured in Newton.

If a wooden block resting on a table is given a push, the block of mass m will accelerate with acceleration a and stop due to friction

One of the following options that describe the motion of the block a moment after the push is the third option. That is, accelerates at a positive, constant rate.

Since the block will be accelerating, the speed of the block can never be constant.

Therefore, accelerates at a positive, constant rate is the option that describe the motion of the block a moment after the push.

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Answer:

Explanation:

Given:

R = 18 Ohm

U = 9.0 V

__________

I - ?

Ohm's law:

I = U / R

I = 9.0 / 18 = 0.5 A

The conservation of momentum can be used to determine the final velocity. The block and bullet system's velocity after the collision will be 2.5 m/s.

For example, a circular path's direction is always perpendicular to a line from the point to the circle's center. A point always moves in a direction that is tangent to its path (a radius). Using the momentum principle,

Where,

= bullet weight, 20 g, or 0.2 kilogram

250 m/s is the bullet's speed before colliding.

= block weight = 2 kg

= velocity following impact =?

Fill out the formula with the values,

Therefore, the block and bullet system's velocity following the collision will be 2.5 m/s.

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Light bends around the obstacles like the waves and this bend cause the diffraction pattern. single slit shows a diffraction pattern because of the path length difference from waves originating at different parts of the slit.

The double-slit experiment demonstrates that mild and remember can show traits of each classically described wave and debris; moreover, it presents the fundamentally probabilistic nature of quantum.

Mechanical phenomena. young's authentic double-slit experiments have been in fact the primary to illustrate the phenomenon of interference. when he shone mildly via two slender slits and determined the sample created on the display screen, the younger did not locate brilliant regions similar to the slits, however as an alternative noticed vivid and darkish fringes.

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(a) The force of gravity acting on the person is 519.4 N.

(b) The normal force acting on the person is 519.4 N.

(c) The force of friction acting on the person is 192.18 N.

(d) The acceleration of the person in the sleeping bag is 3.25 m/s².

The force of gravity acting on the person is calculated as follows;

W = mg

where;

W = 53 kg  x   9.8 m/s²

W = 519.4 N

The normal force acting on the person is calculated as follows;

Fn = W

where;

Fn = 519.4 N

The force of friction acting on the person is calculated as follows;

Ff = μFn

where;

Ff = 0.37 x 519.4 N = 192.18 N

The net force on the person is calculated as follows;

F(net) = F cosθ  -   Ff

where;

F(net) = 476 x cos(40)  -  192.18

F(net) = 172.46 N

The acceleration of the person in the sleeping bag is calculated as follows;

a = F(net) / m

a = (172.46) / (53)

a = 3.25 m/s²

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