he image shows two air fronts moving in a region. The cold front is moving faster than the warm front.



Which will likely happen if the cold front continues to advance faster than the warm front?


Cold air will pass over the warm air, causing dry weather in the region.
Cold air will pass over the warm air, causing dry weather in the region.

Cold air will push up the warm air, resulting in heavy rainfall in the region.
Cold air will push up the warm air, resulting in heavy rainfall in the region.

Cold air will push up the warm a

Answer:

[tex]\boxed {\boxed {\sf 8.07 *10^{24} \ particles}}[/tex]

Explanation:

To convert from moles to representative particles, Avogadro's number: 6.02*10²³ is used. This number tells us the amount of particles in 1 mole of a substance. We can use it as a ratio.

[tex]\frac {6.02*10^{23} \ particles}{1 \ mol \ CO_2}}[/tex]

Multiply by the given number of moles.

[tex]13.4 \ mol \ CO_2 *\frac {6.02*10^{23} \ particles}{1 \ mol \ CO_2}}[/tex]

The moles of carbon dioxide will cancel out.

[tex]13.4 *\frac {6.02*10^{23} \ particles}{1}}[/tex]

The denominator of 1 can be ignored and this becomes a simple multiplication problem.

[tex]13.4 * {6.02*10^{23} \ particles[/tex]

[tex]8.0668*10^{24} \ particles[/tex]

The original number of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 6 in the thousandth place tells us round the 6 to a 7.

[tex]8.07 *10^{24} \ particles[/tex]

13.4 moles of carbon dioxide has approximately 8.07*10²⁴ particles.

Answer: 1. [tex]2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)[/tex]

2. The volume of carbon dioxide gas that is produced is 537 L

Explanation:

1. Combustion is defined as the type of chemical reaction where a hydrocarbon is combusted in the presence of oxygen to give carbon dioxide and water.

The balanced reaction for combustion of octane is:

[tex]2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)[/tex]

2.

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]   [tex]\text{Moles of octane}=\frac{0.330\times 1000g}{114.23g/mol}=2.89moles[/tex]

According to stoichiometry:

2 moles of octane produce = 16 moles of carbon dioxide

2.89 moles of octane produce = [tex]\frac{16}{2}\times 2.89=23.1moles[/tex] of carbon dioxide

According to ideal gas equation:

[tex]PV=nRT[/tex]

P = pressure of gas = 1 atm

V = Volume of gas = ?

n = number of moles = 23.1

R = gas constant =[tex]0.0821Latm/Kmol[/tex]

T =temperature =[tex]10.0^0C=(10+273)K=283K[/tex]

[tex]V=\frac{nRT}{P}[/tex]

[tex]V=\frac{23.1\times 0.0821Latm/K mol\times 283K}{1atm}=537L[/tex]

Thus the volume of carbon dioxide gas that is produced is 537 L

Answer:

-4.88 × 10⁴ kJ/mol

Explanation:

Step 1: Calculate the heat gained by the calorimeter (Qcal)

We will use the following expression.

Qcal = C × ΔT

where,

Qcal = 9.001 kJ/°C × 25.0°C = 225 kJ

Step 2: Calculate the heat released by the fuel

According to the law of conservation of energy, the sum of the heat released by the fuel (Qf) and the heat absorbed by the calorimeter is zero.

Qf + Qcal = 0

Qf = -Qcal = -225 kJ

Step 3: Calculate the heat of reaction in kJ/mol

3.00 g of a fuel (MW = 650.0 g/mol) released 225 kJ of heat. The heat of reaction is:

-225 kJ/3.00 g × 650.0 g/mol = -4.88 × 10⁴ kJ/mol

Answer:

Lead  sulfide.

Explanation:

Answer : if you have time for learning and is in 6th grade the anwser is crocodilians

Explanation: i got it right

Explanation:

[tex]6.42 \times \frac{1}{30} \times \frac{1}{1} \times \frac{46}{1} = 9.844[/tex]

[tex]8.53 \div 9.844 \times 100 = 86.65\%[/tex]

Answer:

1.3-bromo,2-chloro,4-floro hexane

3.bromocyclo pentane

Explanation:

Water is called the "universal solvent" because it is capable of dissolving more substances than any other liquid. This is important to every living thing on earth. It means that wherever water goes, either through the air, the ground, or through our bodies, it takes along valuable chemicals, minerals, and nutrients.

Answer:

false

Explanation:

Answer:

equal number of ions

Explanation:

They cancel each other out that's why there is none

Answer: You have a solution of potassium chlorate containing 4 g at 65º C. How many additional grams of solute must be added to it, to make the solution saturated ? approximately 26 more grams [the solubility of potassium chlorate is ... water. The solution is allowed to cool. At what new temperature would crystals begin to.

Explanation:

Answer:

96%

Explanation:

To find the percent yield, we can use this equation

[tex]\frac{Actual}{Theoretical} *100[/tex]

The actual yield of aspirin is 3.0 and the theoretical is 3.14 in this case, so just plug the numbers in.

[tex]\frac{3.0}{3.14} *100\\\\ =96[/tex]

Thus the percent yield is 96%

;)

Answer:

4.255 J/ K

Explanation:

Given data :

mass of Gallium = 16 gm

molar mass = 69.723 g/mol

hence no of moles = 16 / 69.723 = 0.23 moles --------- ( 1 )

Δh ( heat fusion ) = 5.59 KJ/mol

Temperature = 29.8°C = 302.8 k

Determine the entropy change of gallium

Δs ( entropy change ) =  heat fusion / temperature

 = ( 5.59 * 1000) J/mol / 302.8 = 18.46 J/k*mol

Hence entropy change of gallium

= Δs * no of Gallium moles

= 18.46 * 0.23 = 4.255 J/ k

I hope this is right haha

Answer: The value of the equilibrium constant for this reaction is [tex]2.8\times 10^{-5}[/tex]

Explanation:

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

Moles of  [tex]Ni(CO)_4[/tex] = [tex]\frac{0.597g}{170.7g/mol}=0.0035moles[/tex]

Moles of  [tex]Ni[/tex] =  [tex]\frac{12.7g}{58.7g/mol}=0.216moles[/tex]

Moles of  [tex]CO[/tex] =  [tex]\frac{1.98g}{28.01g/mol}=0.071moles[/tex]

Volume of solution = 2.7 L

Equilibrium concentration of [tex]Ni(CO)_4[/tex] = [tex]\frac{0.0035mol}{2.7L}=1.29\times 10^{-3}M[/tex]

Equilibrium concentration of [tex]Ni[/tex] = [tex]\frac{0.216mol}{2.7L}=0.08M[/tex]

Equilibrium concentration of [tex]CO[/tex] = [tex]\frac{0.071mol}{2.7L}=0.026M[/tex]

The given balanced equilibrium reaction is,

                            [tex]Ni(CO)_4\rightleftharpoons Ni+4CO[/tex]

The expression for equilibrium constant for this reaction will be,

[tex]K_c=\frac{[Ni]^1\times [CO]^4}{[Ni(CO_4]^1}[/tex]

Now put all the given values in this expression, we get :

[tex]K_c=\frac{(0.08)^1\times (0.026)^4}{(1.29\times 10^{-3})^1}[/tex]

[tex]K_c=2.8\times 10^{-5}[/tex]

Thus the value of the equilibrium constant for this reaction is [tex]2.8\times 10^{-5}[/tex]

Answer:

e. Dilute a solution of commercial vinegar to prepare it for titration.

a. Perform a scout colorimetric titration of diluted vinegar with NaOH.

b. One pair performs a careful colorimetric titration of diluted vinegar with NaOH and the other pair performs a potentiometric titration of diluted vinegar with NaOH.

c. Perform a scout colorimetric titration of HCL with NaOH.

d. One pair performs a careful colorimetric titration of HCL with NaOH and the other pair performs a potentiometric titration of HCL with NaOH.

Explanation:

Titration is a process in which acid and base are introduced together to determine unknown concentration of acid or base. This is also known as neutralization reaction. The chemical process form salt and water as by products because acid molecules react with base molecules.

The experimental steps for the Acid-Base Equilibria in the correct order is e, a, b, c and d.

Titration is a process in which we determine the concentration of any unknown acid and base by titrating them with the standard known concentration of base or acid.

In potentiometric titration, in the place of indicator potential difference is used across the analyte of electrolytic solution. And in colorimetric titration, absorbance of light is measured by the solution. Process of method which is involved in the titration is:
e. Dilute a solution of commercial vinegar to prepare it for titration.

a. Perform a scout colorimetric titration of diluted vinegar with NaOH.

b. One pair performs a careful colorimetric titration of diluted vinegar with NaOH and the other pair performs a potentiometric titration of diluted vinegar with NaOH.

c. Perform a scout colorimetric titration of HCL with NaOH.

d. One pair performs a careful colorimetric titration of HCL with NaOH and the other pair performs a potentiometric titration of HCL with NaOH.

Hence correct sequence is e, a, b, c and d.

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If greenhouse gases in the atmosphere continues to increase, then the  

average temperature of Earth will increase too.

Greenhouse gases such as carbon dioxide and methane deplete the ozone

layer which shields the earth from radiations from the Sun. An increase in

these gases will therefore allow for more radiations to get to the earth.

This therefore brings about an increase in the average temperature of the

earth.

Read more about greenhouse gases on https://brainly.com/question/20349818

Answer:

2.9 g of water are produced by 9.6 g of ammonium perchlorate

Note: The question is incomplete. The complete question is given below:

Ammonium perchlorate (NH₄ClO₄) is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen gas (N₂) , chlorine gas (Cl₂), oxygen gas (O₂), water (H₂O) , and a great deal of energy. What mass of water is produced by the reaction of 9.6 g of ammonium perchlorate? Be sure your answer has the correct number of significant digits.

Explanation:

The reaction of ammonium perchlorate (NH₄ClO₄) to produce nitrogen gas (N₂) , chlorine gas (Cl₂), oxygen gas (O₂), water (H₂O) is shown in the balanced chemical equation given below:

2 NH₄ClO₄ →  N₂ +  Cl₂ + 2 O₂ + 4 H₂O

From the equation, 2 moles of ammonium perchlorate produces 4 moles of water, i.e. mole ratio of NH₄ClO₄ to H₂O = 2 : 4 = 1 : 2

molar mass of ammonium perchlorate, NH₄ClO₄ = (14 + 4 * 1 + 35.5 +16 * 4) = 117.5

molar mass of water,  H₂O = (2 * 1 + 16) = 18.0 g

mass of water produced = moles of ammonium perchlorate * 2 * molar mass of water

moles of perchlorate = mass / molar mass = 9.6/117.5

mass of water produced = 9.6/117.5 * 2 * 18.0 g  = 2.94 g of water

Therefore, 2.9 g of water are produced by 9.6 g of ammonium perchlorate

Answer:

the radius is half the diameter

The radius of a circle is equal to half the diameter.

Answer:

The height of A is 900

Explanation: Beside A, there is a number which explains what the height is so the answer is A.

Answer:

Q = -22.9 kJ

Explanation:

Given that,

Mass of water, m = 150.3 g

Water gets cool from 25.60°C to -10.70°C.

The specific heat of water, c = 4.2 J/g°C

The formula for heat needed is given by :

[tex]Q=mc\Delta T\\\\Q=150.3\times 4.2 \times (-10.7-25.6)\\\\Q=-22914.738\\\\or\\\\Q=22.9\ kJ[/tex]

So, 22.9 kJ of heat is needed to be removed to cool.

Considering the definition of mass molar and Avogadro's Number, there are 3.0115×10²⁹ molecules in 1 ton of hydrogen.

First, the molar mass of hydrogen H₂, that is, the amount of mass that a substance contains in one mole, is 2 g/mole.

In this case, being 1 ton = 1,000,000 grams, the number of moles that 1 ton of hydrogen contains is calculated as:

[tex]1,000,000 gramsx\frac{1 mole}{2 grams} = 500,000 moles[/tex]

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole.

Then, the number of molecules that 500,000 moles of hydrogen contains is calculated as:

[tex]500,000 molesx\frac{6.023x10^{23} molecules }{1 mole}[/tex]= 3.0115×10²⁹ molecules

Finally, there are 3.0115×10²⁹ molecules in 1 ton of hydrogen.

Learn more about:

Answer:

the wind and the temperature of water both drive ocean currents

Answer:

B. Write 'T' for true or 'F' for false statements :

1. Publisher works only with document in fixed shapes and sizes.

2. Viewing tools are only for editing purpose.

3. Text box icon is found in Styles group.

4. Publisher does not allow you to add images to your document.

5. Margin guides are blue lines that mark the edges.

Answer:

C: They become more dense near the Sun's surface.

Explanation:

I got it correct on EDG

I hope this helps!!!!!!!!

Can I have a brainliest

According to convection, the statement which describes how fluids change as they travel through the convection zone is  that they become more dense near the Sun's surface.

Convection works by areas of a liquid or gas heating or cooling greater than their surroundings, causing differences in temperature. These temperature differences then cause the areas to move as the hotter, less dense areas rise, and the cooler, more dense areas sink.

Often the areas of heating and cooling are fixed, and allow convective cycles or currents to become established. For example, a saucepan of water over a flame may develop convective currents as the water is heated from below, rises to the surface, and cools. Once cooled enough, the water then sinks back to the bottom of the saucepan where the cycle is repeated, and the convective overturning continues.

Learn more about convection,here:

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#SPJ6

The given statement is correct or true.  

• The alignment of electrons in an atom is termed as the electronic configuration.  

• The electrons in an atom seem to assume the alignment, which gives the atoms the least possible energy.  

• This alignment of electrons is the most stable alignment and is known as the atom's ground-state electronic configuration.  

• In the ground state of an atom, the electron first enters the lowest energy orbital and later subsequent electrons are aligned in order of increasing energy. This is known as the Aufbau principle.  

Thus, the given statement is true or correct.

To know more about:

https://brainly.com/question/16562099

Answer: 1. [tex]CO[/tex] is the limiting reagent and [tex]O_2[/tex] is the excess reagent.

2. 2.91 g of excess reagent

3. 4.66 g of carbon dioxide produced.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} CO=\frac{2.98g}{28g/mol}=0.106moles[/tex]

[tex]\text{Moles of} O_2=\frac{4.62g}{32g/mol}=0.144moles[/tex]

[tex]O_2+2CO\rightarrow 2CO_2[/tex]  

According to stoichiometry :

2 moles of [tex]CO[/tex] require = 1 mole of [tex]O_2[/tex]

Thus 0.106 moles of [tex]CO[/tex] will require=[tex]\frac{1}{2}\times 0.106=0.053moles[/tex]  of [tex]O_2[/tex]

Thus [tex]CO[/tex] is the limiting reagent as it limits the formation of product and [tex]O_2[/tex] is the excess reagent.

Amount of excess reagent = ( 0.144-0.053) moles = 0.091 moles

Mass of excess reagent [tex]O_2=moles\times {\text {Molar mass}}=0.091moles\times 32g/mol=2.91g[/tex]

As 2 moles of [tex]CO[/tex] give = 2 moles of [tex]CO_2[/tex]

Thus 0.106 moles of [tex]CO[/tex] give =[tex]\frac{2}{2}\times 0.106=0.106moles[/tex]  of [tex]CO_2[/tex]

Mass of [tex]CO_2=moles\times {\text {Molar mass}}=0.106moles\times 44g/mol=4.66g[/tex]

Answer:

See explanation

Explanation:

Let us see what happens when each solution is mixed;

a) AlCl3(aq) + K3PO4(aq) ------> 3KCl(aq) + AlPO4(s)

A precipitate is formed here

b) RbCO3(aq) + NaCl(aq) -------> This is an impossible reaction hence no solid precipitate is formed here

c) MnCl2(aq) + Na2CO3(aq) → 2NaCl(aq) + MnCO3(s)

A precipitate is formed.

d) K2S(aq) + 2NH4Cl(aq) ------> 2KCl(aq) + (NH4)2S(aq)

No solid precipitate is formed

e) CaCl2(aq) + (NH4)2CO3(aq) → CaCO3(s) + 2NH4Cl(aq)

A solid precipitate is formed

Answer:

5542.37 K

Explanation:

Given that,

Initial volume, V₁ = 590 mL

Initial temperature, T₁ = -55°C = -55 + 273 = 218 K

Final volume, V₂ = 15 L

We need to find the final temperature of the gas. The relation between the volume and the temperature is given by :

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

Where

T₂ is final volume of the gas

Put all the values in above relation,

[tex]T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{15\ L\times 218\ K}{590\times 10^{-3}\ L}\\\\T_2=5542.37\ K[/tex]

So, the required temperature is equal to 5542.37 K.

Answer:

Ununoctium

Explanation:

It's at the very end of the periodic table

Answer:

Ununoctium

Explanation:

Ununoctium is the last chemical element int the periodic table.