The correct option is (A) $\dim E(10) = 0$
Given A = \[\left[\begin{matrix}10 & -20\\3 & -3\end{matrix}\right]\] The Eigen values of A can be obtained by solving the characteristic equation|A-λI| = 0\[|A-\lambda I|=\left|\begin{matrix}10-\lambda & -20\\3 & -3-\lambda\end{matrix}\right|\]\[\Rightarrow (10-\lambda)(-3-\lambda)-(-20)(3)=\lambda^2-7\lambda+12=0\]\[\Rightarrow \lambda_1=4,\lambda_2=3\]The spectrum of A is, A= {-2,1}.1. Basis of the eigenspace associated with 1 = -2Basis of eigenspace associated with -2 can be found by solving(A+2I)X=0 \[\Rightarrow\left[\begin{matrix}12 & -20\\3 & -1\end{matrix}\right]\left[\begin{matrix}x_{1}\\x_{2}\end{matrix}\right]=\left[\begin{matrix}0\\0\end{matrix}\right]\]By Echolon form\[\left[\begin{matrix}12 & -20\\3 & -1\end{matrix}\right]\Rightarrow \left[\begin{matrix}1 & \frac{-5}{3}\\0 & 0\end{matrix}\right]\]Taking X = t\[\Rightarrow B(-2)=\begin{Bmatrix}\begin{matrix}\frac{5}{3}\\1\end{matrix}\end{Bmatrix}\]2. Basis of the eigenspace associated with 1 = 1Basis of eigenspace associated with 1 can be found by solving(A-I)X=0\[\Rightarrow\left[\begin{matrix}9 & -20\\3 & -4\end{matrix}\right]\left[\begin{matrix}x_{1}\\x_{2}\end{matrix}\right]=\left[\begin{matrix}0\\0\end{matrix}\right]\]By Echolon form\[\left[\begin{matrix}9 & -20\\3 & -4\end{matrix}\right]\Rightarrow \left[\begin{matrix}1 & \frac{-20}{9}\\0 & 0\end{matrix}\right]\]Taking X = t\[\Rightarrow B(1)=\begin{Bmatrix}\begin{matrix}\frac{20}{9}\\1\end{matrix}\end{Bmatrix}\]3. dimension of eigenspace associated with 1 = 0 as the basis is an empty set. Hence the dimensions of E(-2), E(1), and E(10) are, \[dim\,E(-2)=1\]\[dim\,E(1)=1\]\[dim\,E(10)=0\]
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Tamika is making a flag design in the shape of a parallelogram. Which x- and y-values must she use in order to guarantee that the flag is in the shape of a parallelogram?
Answer:
x = 1/2
y = 3
Step-by-step explanation:
Remark
The diagonals of a parallelogram cut each other in half. That means that x lengths are equal and the y lengths are equal
Equations
3y = y + 6
10x = 6x + 2
Solution for x
10x = 6x + 2 Subtract 6x from both sides
10x - 6x = 6x - 6x + 2
4x = 2 Divide by 4
4x/4 = 2/4
x = 1/2
Solution for y
3y = y + 6
3y - y = y- y + 6
2y = 6
y = 3
Answer:
Step-by-step explanation:
HELP ASAPPPPPPPPPPPPPP
3.14 x 11 = 34.54
Pi = 3.14 so times by 11 = 34.54
can someone help plz ... mark brainliest ❤️
Answer:
Top:(4r⁹+3r³-5)
Bottom: r⁵
Step-by-step explanation:
can somebody help me please
Answer:
B
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
x² = 4² + ([tex]\sqrt{5}[/tex] )² = 16 + 5 = 21 ( take the square root of both sides )
x = [tex]\sqrt{21}[/tex] → B
Please help if you would want brianleist!! :D ^^
Answer:
384
Step-by-step explanation:
v= L x W x H
v= 4 x 2 x 1.2
v= 9.6
9.6 x 40 = 384
lmk if you have any questions :)
Answer:
A
Step-By-Step Explanation:
Step One: The first step is to figure out the volume of one. The volume formula is length times width times height. We have all the dimensions so: 4 times 2 times 1.2= 9.6.
Step Two: Now, we just mutiply the number by 40 since there are 40 slabs: 384.
what is the longitudinal position latitudinal position of Nepal
Step-by-step explanation:
I think that is your answer because in the Himalayas it lies between latitudes 26.
Please answer correctly I will mark you Brainliest!
Answer:
1047.12in³
Step-by-step explanation:
The volume of the sphere is:
V= 4/3 πr³
Where r is radius
Therefore the volume of each pinata is:
V= 4/3 x π x 5³
V= 523.6in³
The total:
V = 523.6 + 523.6 = 1047.12in³
Help me with this please
Answer:
x = 138
Step-by-step explanation:
Exterior angle thm:
68 + 70 = x
x = 138
10 points!! Please give me real help!!
Answer:
32
Step-by-step explanation:
Can someone help out? No BS please.
Answer:
Angle EHG
Step-by-step explanation:
If you want explanation tell me in comments
Answer:
the correct answer is angle EHB
Solve the inequality
*
2x^2+ 5x – 3 < 0.
Answer:
heres the answer I think
Step-by-step explanation:
-3 < x < 1/2
For a given confidence interval and significance level, and assuming a relatively small sample size, say 25, the relationship between a T critical value and a Z critical value can be best expressed as: a T-Value > Z-Value a True O False
T-value is not always greater than Z-value. Therefore, the statement is false
False. The relationship between a T critical value and a Z critical value is not that a T value is always greater than a Z value. The choice between using a T critical value or a Z critical value depends on the specific context and assumptions of the statistical analysis.
In general, when the sample size is small (typically below 30) and the population standard deviation is unknown, a T critical value is used. The T distribution accounts for the additional uncertainty introduced by the smaller sample size, resulting in wider confidence intervals and more conservative hypothesis tests compared to the Z distribution.
On the other hand, when the sample size is large (typically above 30) or the population standard deviation is known, a Z critical value is used. The Z distribution assumes a large sample size, and it is based on the known population standard deviation or the approximation of the sample standard deviation to the population standard deviation.
Therefore, it is incorrect to state that a T-value is always greater than a Z-value. The choice between T and Z critical values depends on the specific conditions and assumptions of the statistical analysis being performed.
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Please help me with the
Answer: i think its 10
Step-by-step explanation:
How many pints is 80 cups
Answer:
40
Step-by-step explanation:
2 cups = 1 pt
therefore
1/2 is the equation
...
80/2 = 40
Serenity is going to invest $850 and leave it in an account
for 5 years. Assuming the interest is compounded
annually, what interest rate, to the nearest hundredth of a
percent, would be required in order for Serenity to end up
with $1,130?
Answer:
5.86
Step-by-step explanation: its right on delta math
PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!
Answer:
pi, and square root of 2
I don't think you're ACTUALLY going to give me brainliest
OMG PLS HELP WITH THIS IM PANICKING OMG I GOT A F IN MATH MY MOM JUST YELLED AT ME IM CRYING PLS HELP WITH THS- PLSS TELL ME WHAT TO DRAW
Answer:
The answer to this question is $14,916
Step-by-step explanation:
18,469 - 3,553 = 14916
As he already has money for the car.
A bar model is shown in the linked picture.
Determine the surface area of a cereal box with these dimensions width: 3 inches length: 8 inches height: 12 inches
*HURRY* Kale purchased a new car. The car had a list price of $28,730. Kale made a down payment of $2,750 and financed the rest, paying 4.9% interest compounded monthly over a payment period of four years. If Kale also had to pay 8.4% sales tax, a $750 vehicle registration fee, and an $88 documentation fee, what is his monthly payment
Answer:
$5934
Step-by-step explanation:
The results of an empirical study reveal the following: n=27, sample mean = 3,000, sample standard deviation = 900. The 90% confidence interval of the true population mean is closet to: = = 2,400 and 3,400 1,200 and 4,800 2,700 and 3,300 0 2,000 and 4,000.
The 90% confidence interval is approximately 2,400 and 3,400.
The 90% confidence interval of the true population mean can be calculated using the formula: sample mean ± (critical value * standard error). Since the sample size is small (n=27), we need to use the t-distribution and its corresponding critical value. For a 90% confidence level with 26 degrees of freedom (n-1), the critical value is approximately 1.706.
Using the given values, the standard error is calculated as the sample standard deviation divided by the square root of the sample size: 900 / sqrt(27) ≈ 171.97.
Substituting the values into the formula, the 90% confidence interval is approximately 3,000 ± (1.706 * 171.97), which yields a range of approximately 2,424.5 to 3,575.5.
Therefore, the closest option to the 90% confidence interval is 2,400 and 3,400.
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i need help please explain to me the answer !
Answer:
If the triangle is similar then their ratio is also same
x = 8
6 4.8
X =8×6
4.8
x = 10 cm
hope this helps
good day mate
A tank contains 2380 L of pure water. A solution that contains 0.07 kg of sugar per liter enters a tank at the rate 7 U/min The solution is mixed and drains from the tank at the same rate. (a) How much sugar is in the tank initially? 0 (kg) (b) Find the amount of sugar in the tank after t minutes. amount = 166.6(1-e^(-t/340)) your answer should be a function of t) (kg) (c) Find the concentration of sugar in the solution in the tank after 33 minutes. concentration = 166.6 (kg/L)
The concentration of sugar in the solution in the tank after 33 minutes is approximately 0.00734 kg/L or 7.34 g/L.
(a) Initially, the tank contains pure water, so there is no sugar in the tank. Therefore, the amount of sugar in the tank initially is 0 kg.
(b) The amount of sugar in the tank after t minutes can be calculated using the formula:
amount = 166.6(1 - [tex]e^{-t/340}[/tex])
Here, t is the time in minutes. This formula is derived from the exponential decay model, where the rate of sugar leaving the tank is proportional to the amount of sugar present. The constant 166.6 represents the equilibrium amount of sugar in the tank.
As time passes, the term [tex]e^{-t/340}[/tex] approaches 1, and the amount of sugar in the tank approaches the equilibrium amount of 166.6 kg.
(c) To find the concentration of sugar in the solution in the tank after 33 minutes, we need to divide the amount of sugar by the volume of the tank. The volume of the tank is given as 2380 L.
First, let's calculate the amount of sugar in the tank after 33 minutes using the formula from part (b):
amount = 166.6(1 - [tex]e^{-33/340}[/tex])
amount ≈ 166.6(1 - 0.895)
amount ≈ 166.6(0.105)
amount ≈ 17.493 kg
Now, we can calculate the concentration:
concentration = amount / volume
concentration = 17.493 kg / 2380 L
concentration ≈ 0.00734 kg/L
Therefore, the concentration of sugar in the solution in the tank after 33 minutes is approximately 0.00734 kg/L or 7.34 g/L.
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Prove or disprove the following statement: if A, B, and C are
sets with finite cardinalities that satisfy A ∩ B ∩ C = ∅, then |A
∪ B ∪ C| = |A| + |B| + |C|.
The statement |A ∪ B ∪ C| = |A| + |B| + |C| is true, which means the statement is proven.
Let A, B, and C be sets with finite cardinalities that satisfy A ∩ B ∩ C = ∅.
We have to prove that |A ∪ B ∪ C| = |A| + |B| + |C|.
The addition law of sets states that the cardinality of a union of two finite sets is equal to the sum of the cardinalities of the sets minus the cardinality of their intersection.
Thus, we get: |A ∪ B ∪ C| = |A ∪ B| + |C| − |(A ∩ B) ∪ C| = (|A| + |B| − |A ∩ B|) + |C| − |(A ∩ B) ∩ C| = |A| + |B| + |C| − |A ∩ B ∩ C|.Since A ∩ B ∩ C = ∅, we get |A ∪ B ∪ C| = |A| + |B| + |C|.
Thus, the statement is proven.
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Suppose Nate loses 38% of all thumb wars.
(a) What is the probability that Nate loses two thumb wars in a row?
(b) What is the probability that Nate loses three thumb wars in a row?
(c) When events are independent, their complements are independent as well. Use this result to determine the probability that Nate loses three thumb wars in a row, but does not lose four in a row.
1. The probability that Nate loses two thumb wars in a row is: _______________
2. The probability that Nate loses three thumb wars in a row is:_____________
a. Probability of losing the second thumb war is also 0.38.
b. Probability of losing the third thumb war is also 0.38.
Given that Nate loses 38% of all thumb wars.
We can use the probability of losing the thumb war as
p=0.38.
The probability of winning is
1-0.38=0.62.
a) Probability of losing two thumb wars in a row is:
P(loses two in a row) = P(loses first) × P(loses second)
The probability of losing the first thumb war is 0.38.
The probability of losing the second thumb war is also 0.38
So,
P(loses two in a row) = (0.38) × (0.38)
= 0.1444
b) Probability of losing three thumb wars in a row is:
P(loses three in a row) = P(loses first) × P(loses second) × P(loses third)
The probability of losing the first thumb war is 0.38.
The probability of losing the second thumb war is also 0.38
The probability of losing the third thumb war is also 0.38.
So,
P(loses three in a row) = (0.38) × (0.38) × (0.38)
= 0.054872
c) When events are independent, their complements are independent as well.
If the probability of winning the thumb war is p, then the probability of losing the thumb war is 1-p.
The complement of "losing three in a row" is "not losing three in a row".
P(not loses three in a row) = 1 - P(loses three in a row)P(not loses three in a row)
= 1 - 0.054872
= 0.945128
The probability that Nate loses three thumb wars in a row, but does not lose four in a row is the probability of losing three minus the probability of losing four in a row.
P(loses three but not four in a row) = P(loses three in a row) - P(loses four in a row)
P(loses four in a row) = P(loses three in a row) × P(does not lose the next)
P(loses four in a row) = (0.38) × (0.38) × (0.38) × (0.62)
= 0.02081416
P(loses three but not four in a row) = 0.054872 - 0.02081416
= 0.03405784
The probability that Nate loses two thumb wars in a row is 0.1444
The probability that Nate loses three thumb wars in a row is 0.054872.
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this is 9th grade math.funfdjvnuvuv
y = -2/5 x + 22/5 is the required equation of the line passing the coordinates
Determining the equation of a lineThe equation of a line in slope intercept form is expressed as y = mx +b
where;
m is the slope
b is the y-intercept
Given the coordinate points (-4, 6) and (6, 2), the slope of the line is expressed as:
Slope = 2-6/6+4
Slope = -4/10
Slope = -2/5
For the y-intercept
2 = -2/5(6) + b
2 + 12/5 = b
b = 22/5
Hence the equation of the line passing the coordinate is y = -2/5 x + 22/5
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How many more gift card raffle tickets will
be entered than shopping spree raffle tickets
if there are 500 total raffle tickets?
Answer:
25 tickets
Step-by-step explanation:
If the answer is wrong, I don't know what to say because the answer I got is 25
The would be 25 more gift card raffle ticket than shopping spree raffle tickets if there are 500 total raffle tickets
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
The shopping spree raffle tickets is 35% while the gift card tickets is 40%. Hence for 500 tickets:
Difference = (40% - 35%) * 500 = 25 tickets
The would be 25 more gift card raffle ticket than shopping spree raffle tickets if there are 500 total raffle tickets
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Find the absolute maximum and absolute minimum of the function z = f(x, y) = 3x² – 12x + 3y2 – 12y on the domain D: x2 + y2 < 4. (Use symbolic notation and fractions where needed.)
The absolute maximum and minimum of the function z = f(x, y) = 3x² - 12x + 3y² - 12y on the domain x² + y² < 4 are not provided.
To find the absolute maximum and minimum of the function z = f(x, y) = 3x² - 12x + 3y² - 12y on the domain D: x² + y² < 4, we need to locate the critical points and examine the boundaries of the domain.
First, we find the critical points by taking the partial derivatives with respect to x and y, setting them equal to zero, and solving for x and y. However, in this case, the given function is a quadratic expression without any cross-terms, so it does not have critical points.Next, we consider the boundary of the domain D: x² + y² = 4, which represents a circle of radius 2 centered at the origin. To find the extreme values on this boundary, we can use methods like Lagrange multipliers or parametrize the boundary and evaluate the function.Since the absolute maximum and minimum values are not provided, further calculations are needed to determine these values for the given function on the given domain.
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Determine whether the following equation is separable. If so, solve the given initial value problem. dy/dt = 2ty +1, y(0) = -3 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The equation is separable. The solution to the initial value problem is y(t) = ___ B. The equation is not separable. 9.3.28
The equation is separable. The solution to the initial value problem is y(t) = y(0) = -3.
A. The equation is separable. The solution to the initial value problem is y(t) = ___
To determine whether the given differential equation is separable, we need to check if it can be written in the form dy/dt = g(t) * h(y), where g(t) is a function of t only and h(y) is a function of y only.
In this case, the equation is dy/dt = 2ty + 1. We can rearrange it as:
dy = (2ty + 1) dt
Now, we can see that we have both y and t terms on the right-hand side, indicating that the equation is not yet separable.
Therefore, the correct choice is B. The equation is not separable.
Unfortunately, no solution can be provided for the initial value problem y(0) = -3 since the equation is not separable.
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Find the particular solution determined by the given condition. ds/dt = 16t^2 + 9t - 6; s = 120 when t = 0 The particular solution that satisfies the given condition is s =
The particular solution that satisfies the given condition is s = (16/3)t³ + (9/2)t² - 6t + 120
To find the particular solution of the differential equation ds/dt = 16t² + 9t - 6 with the condition s = 120 when t = 0, we need to integrate the right-hand side of the equation with respect to t and then solve for the constant of integration using the given condition.
First, let's integrate the right-hand side of the equation:
∫(ds/dt) dt = ∫(16t² + 9t - 6) dt
Integrating term by term, we get:
s = (16/3)t³ + (9/2)t² - 6t + C
Now, we can use the given condition s = 120 when t = 0 to determine the value of the constant of integration C:
120 = (16/3)(0)³ + (9/2)(0)² - 6(0) + C
120 = C
Therefore, the particular solution that satisfies the given condition is:
s = (16/3)t³ + (9/2)t² - 6t + 120
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Test for equality of population means against the alternative that the means are different assuming normality, choosing ? 5% and using two samples of sizes 12 and 18, with mean 10 and 14, respectively, and equal standard deviation 3.
The p-value (0.0208) is less than the significance level (0.05), we reject the null hypothesis. This indicates that there is sufficient evidence to suggest the case.
Null hypothesis (H0): The population means are equal, μ1 = μ2.
Alternative hypothesis (Ha): The population means are different, μ1 ≠ μ2.
Select the significance level (α): In this case, α = 0.05.
Now, The test statistic for a two-sample t-test is given by:
t = (sample mean 1 - sample mean 2) / √((s1² / n1) + (s2² / n2))
where s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.
Here X₁ = 10, X₂ = 14, s= 3, n₁ =12, n₂ = 18
So, t= (10-14) / √(3²/12) + (3²/18) et:
t= (-4)/ √(3/4 + 1/2)
t= -4 / (5/4)
t= -2.7931
Now, degrees of freedom (df):
= (9/12 + 9/18)² / (((9/12)² / 11) + ((9/18)² / 17))
= 25.164
So, the p value will be 0.0208.
As, p-value is less than α (0.0208 < 0.05), we reject the null hypothesis.
Since the p-value (0.0208) is less than the significance level (0.05), we reject the null hypothesis. This indicates that there is sufficient evidence to suggest the case.
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