Based on the amount you paid for the shares and the selling price as well as the number of years, the total return would be -51.9%
The annual return would be -16.7%
How to find the total return?The total return on the stock can be found by finding the difference in stock prices for the 4 years and dividing by the buying price:
= (1,300 - 2,700) / 2,700 x 100%
= -1,400 / 2,700 x 100%
= 0.51851851851851851851851851851852 x 100%
= -51.9%
The annual return can be found as:
= ((1,300 / 2,700) ^ 1/4 - 1) x 100%
= -16.7%
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find the domain of f(x)=ln(cosx)
x ∈ ( -π/2 + 2kπ ; π/2 + 2kπ) ; k ∈ Z
The domain of f(x)=ln(cosx) = x ∈ ( -π/2 + 2kπ ; π/2 + 2kπ) ; k ∈ Z
Solution:The domain of a function is the set of values that can be plugged into it. This set contains the x values in a function like f (x). A function's range is the set of values that the function can take.Given function,
f(x)=ln(cosx)
When cos(x) is positive, the domain is.
(cos(x)) > 0
since,
cos0 = 1
cos π/2 = 0
cos π = -1
cos 3π/2 = 0
cos 2π = 1
cos 3π/2 = 0
The values of cos(x) are then between -1 and 1.
That is domain of f(x)=ln(cos x)
= cos x ∈ (0;1] -> x ∈ ( -π/2 + 2kπ ; π/2 + 2kπ) ; k ∈ Z
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Please help me ASAP!! I will not hesitate to give brainliest to the best answer!!
Answer:
The correct answers are below, if you want a more in depth explanation let me know and I will provide
Step-by-step explanation:
- The Diver surfaced 3 min before the Watcher
- When the noticed was received, the Diver was 20 ft deeper than the watcher
- 3 Min after receiving the notice, the diver and the watcher are at the same depth
A shop has a sale that offers 20% off all prices. On the final day they reduce all the sale prices by 25%. Linz buys a radio on the final day
Work out the overall percentage reduction on the price of the radio.
The overall percentage reduction in the price of the radio is 40%.
What is the overall decline?Percentage is the fraction of an amount expressed as a number out of hundred. Percentage is a measure of frequency. The sign that is used to represent percentages is %.
Let's assume that that initial price of the radio is 100.
Price of the radio after the 20% decline in price = (1 - 0.2) x 100
0.8 x 100 = 80
Price of the radio after the 25% decline in price = (1 - 0.25) x 80
0.75 x 80 = 60
The percentage decline in price = (initial price / final price) - 1
(60 / 100) - 1 = 0.4 = 40%
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Consider the following system of equations 4x + 6=24 and 2x + 3y=8 How many solutions does this system have? Justify your answer. Part B If we triple each side of the first equation 4x+6y=24, we have 12x+18y=72. Explain why the new system 12x+18y=72 and 2x+3y=8 has the same number of solutions as the original system.
The solution of the given system of equation will have infinite many solutions.
In the above question, the following equations are given
4x + 6y = 24
2x + 3y = 8
Now, we need to find the number of solutions that this system of equation will have
We know that,
a1 x + b1 y = c1
a2 x + b2 y = c2
is the general system of equation, and
[tex]\frac{a1}{a2} \neq \frac{b1}{b2}[/tex] then unique solution, or
[tex]\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}[/tex] then there will be infinite solutions or,
[tex]\frac{a1}{a2} = \frac{b1}{b2} \neq \frac{c1}{c2}[/tex] then there will be no solution
Now, we'll check for the given system of equations
a1 = 4, b1 = 6 , c1 = 24
a2 = 2, b2 = 3 , c2 = 8
[tex]\frac{a1}{a2} = \frac{b1}{b2} \neq \frac{c1}{c2}[/tex] = 2 = 2 [tex]\neq[/tex] 3
As this condition satisfies the third condition, the solution of the given system of equation will have infinite many solutions.
Now as we multiply the first equation 4x + 6=24 by 3 we get we have 12x+18y=72, the system will still have same solutions as only the equations are multiplied by a constant k = 3 which does not affect the solution.
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I need help with this
[tex] { 3 }^{ - 1} \times {3}^{x + 1} - { 3}^{x - 2} + {3}^{ - 2} \times { 3}^{x + 3} = 35 \\ {3}^{ - 1 + x + 1} - {3}^{x - 2} + {3}^{ - 2 + x + 3} = 35 \\ {3}^{x} - {3}^{x - 2} + { 3}^{ - 2 + 3 + x} = 35 \\ { 3 }^{x} - {3}^{x - 2} + {3}^{x + 1} = 35 \\ {3}^{x} - {3}^{x} \times {3}^{ - 2} + {3}^{x} \times {3}^{1} = 35 \\ {3}^{x} (1 - {3}^{ - 2} + 3) = 35 \\ {3}^{x} (3 + 1 - \frac{1}{9}) = 35 \\ \\ {3}^{x} (4 - \frac{1}{9} ) = 35 \\ {3}^{x} ( \frac{35}{9} ) = 35 \\ \frac{ {3}^{x}( \frac{35}{ 9 } )}{ \frac{35}{9} } = 35 \div ( \frac{35}{9} ) \\ {3}^{x} = 9 \\ {3}^{x} = { 3 }^{2} \\ x = 2[/tex]
ATTACHED IS THE SOLUTION.
I USED THE LAWS OF EXPONENTS.
GOODLUCK.
6 in. 4 in 6 in 10 in
we have that the figure of a rectangle and a triangle. So the area of this figure is:
[tex]A=6\cdot10+\frac{4\cdot4}{2}=60+8=68[/tex]so the answer is 68 in^2
what is a relation function?
Answer: A relation is just a relationship between x and y-coordinates. It maps inputs to outputs. A function is just a special kind of relation: any input has exactly one output.
Step-by-step explanation:
Which point shown in the graph below is the image of point P after a counterclockwise rotation of 90° about the origin? Please help me
We can see that if we rotate P 90° counterclockwise it would be located in the first quadrant. So it can be A or B. But A forms a 90° with the position of point P. So, the answer is A.
If Amy Van swam her recordbreaking 50 m by swimming to one end of the pool, then turning around and swimming back to her starting position, what would her average velocity be
Answer:
zero
Step-by-step explanation:
You want Amy Van's average velocity when she swims 50 m to the end of the pool and back.
Average velocityAverage velocity is the ratio of the change in position to the amount of time over which that change occurs. When Amy ends up where she started, she has not changed position at all, so her average velocity is ...
Vave = (change in position)/time = 0/time = 0
Her average velocity is zero.
Help me to answer 1b, solve the problem in detail, thank you
Hello
we are given a function and asked to find the reminder when it is divided by a binomial
According to the remainder theorem, f(a) would be the remainder from dividing f(x) by x -a
[tex]\begin{gathered} x-a=x-2 \\ a=2 \end{gathered}[/tex]but our f(x) is given as
[tex]\begin{gathered} f(x)=2x^3+7x^2-8x+3 \\ a=2 \\ \end{gathered}[/tex][tex]f(a)=f(2)=2(2)^3+7(2)^2-8(2)+3=31[/tex]From the calculation above, the answer to this question is 31
Jose hopes to earn $1400 in interest in 3.4 years times from $56,000
To solve this problem, we will use the formula for compound interest:
[tex]r=k\cdot((\frac{P_N}{P_0})^{1/(NK)}-1).[/tex]Where:
• Pₙ = principal amount after N years,
,• P₀ = initial principal amount,
,• r = interest ratio in decimals,
,• k = compound periods per year.
From the statement, we know that:
• N = 3.4 years,
• P₀ = $56,000,
• Pₙ = P₀ + interest = $56,000 + $1,400 = $57,400,
,• r = ?,
,• k = 4 (the interest is compounded quarterly.
Replacing these values in the formula above, we get:
[tex]r=4\cdot((\frac{57400}{56000})^{1/(3.4\cdot4)}-1)\cong0.00727=0.73\%.[/tex]AnswerThe annual interest must be 0.73%.
HELP ME WITH THESE THREE QUESTIONS PLEASE (GIVING BRAINLIEST TO THE BEST ANSWER.) 90 points
The perimeter of the figure is 18 units. Complete the statements to find the side lengths.
1. Find the distance from A to B. Explain how you found this distance.
2. Add the distances of the vertical and horizontal segments. These are the distances from A to B, B to C, and C to D. Show how you found the total.
3. Use the perimeter to find the length of segment AD. This is the distance from A to D. Explain how you found your answer.
Answer:
1. 6 units
2. 13 units
3. 5 units
Step-by-step explanation:
I need help identifying the coordinates
The z-score values for the given quantile are found.
What is defined as the z-score?A Z-Score is a measurable statistic of a score's connection to the mean among a set of scores.A Z-score can tell a trader whether a value is usual for a given data set or atypical.In contrast, the Z-score is the amount of standard deviations a provided data point is from the mean. The Z-score is negative for data points that fall below the mean. 99% of values in most large data sets have a Z-score among -3 and 3, indicating that they are three deviations above and below mean.For the given question;
The given normal quantile plot are-
-1.28, -0.52, 0.00, 0.52, 1.28
The corresponding z-score taken from the positive and negative z table are-
-1.28 = 0.101-0.52 = 0.3050.00 = 0.500.52 = 0.6981.28 = 0.899The z-score values for the given quantile are found.
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4.5 un 5.5 6 y 0.5 0.6 0.8 Which is most likely the equation of the line of best fit for the data given in the table? A y = 0.34 x - 09 B y = 0.25x - 0.7 y =0.45x-1 D y = 0.50x -0.6
The Solution.
The correct answer is y = 0.34x - 0.9 (option A ).
Step 1:
First, we shall determine the slope of the line by picking two coordinates from the table.
Save-A-Lot Bank is advertising a rate of 2.5% interest compounded annually.If $2000 is invested, how much money, to the nearest cent, will be inthe account after 10 years.
Question on Compound Interest.
The formula below can be used to calculate the compound interest;
[tex]\begin{gathered} A\text{ = p(1+}\frac{r}{100})^n \\ \text{Where A = amount,(\$) (that is, the money that will be in the account)} \\ r=\text{interest rate per annum, (\%)} \\ P=Pr\text{incipal, (\$), ( that is, the money invested)} \\ n=\text{ number of periods, years, } \end{gathered}[/tex]Where A= ? , P =$2000, r =2.5% and n = 10 years
Substituting these values into the formula above, we get
Note that: Amount = Principal + Interest, though not needed in this question.
[tex]\begin{gathered} A=P(1+\frac{r}{100})^n_{} \\ \\ A=2000(1+\frac{2.5}{100})^{10} \\ \\ A=2000(1+0.025)^{10} \\ A=2000(1.025)^{10}\text{ }=\text{ 2560.169 }\approx\text{ \$2560.17} \end{gathered}[/tex]Thus, the correct answer is $2560.17
A submarine sandwich shop surveyed a group of 20 prospective customers surveyed would be willing to pay a maximum of $4.01 to $5
A. 20 %
B.30%
C.5%
D.10%
Answer: 10%
Step-by-step explanation:
2 out of 20 people are willing to pay a maximum of 4.01 to 5 which is 0.10 which equals 10%
Which best describes the relationship between the line that passes through the points (2, 3) and (5,8) and the line that passes through the points (-7, 5) and (-12, 8)?A. same lineB. parallelC. neither perpendicular nor parallelD. perpendicular
Given the line which passes through the points (2, 3) and (5,8) and the line that passes through the points (-7, 5) and (-12, 8).
To determine the relationship which best describes the line, the first thing we do is find the gradients of the lines.
For point A and B with coordinates:
[tex]A(x_1,y_1),B(x_2,y_2)[/tex][tex]\text{Gradient, m= }\frac{y_2-y_1}{x_2-x_1}[/tex]For points (2, 3) and (5,8)
[tex]\text{Gradient, m= }\frac{8-3}{5-2}=\frac{5}{3}[/tex]For the points (-7, 5) and (-12, 8)
[tex]\text{Gradient, m= }\frac{8-5}{-12-(-7)}=\frac{3}{-5}=-\frac{3}{5}[/tex]• Two lines are said to be ,parallel, ,if their gradients are the same.
,• Two lines are said to be ,perpendicular ,if the ,product of the gradients is -1.
Product of the two gradients
[tex]\begin{gathered} =\frac{5}{3}\times-\frac{3}{5} \\ =-1 \end{gathered}[/tex]Since the product of the gradients is -1, the two lines are said to be perpendicular.
The correct option is D
If you have 10 white slips of paper, 6 red slips of paper, and 4 blue slips of paper, writing the ratio of red slips compared to the total number of slips. How many red slips do you have? How many slips of paper do you have?
Answer:
6:20 - 2:4 (simplified)
Step-by-step explanation:
20 total slips
6 red slips
What is a constant rate of change
Answer:A rate of change is a rate that describes how one quantity changes in relation to another quantity. Constant rate is also called as uniform rate which involves something travelling at fixed and steady pace or else moving at some average speed. For example, A car travels 3 hours.
Step-by-step explanation:
Is the sequence described as 3,5,8,12,17...... arithmetic. Explain your answer
Based on the sequence given of 3,5,8,12,17, it would be incorrect to say that the sequence is arithmetic. The sequence is not arithmetic.
What is an arithmetic sequence?In an arithmetic sequence, one would find that the number that separates each of the figures in the sequence is the same. In other words, the common difference between each figure is the same.
For instance, 2, 5, 8, 11, 14 has the common difference of 3 so this is an arithmetic sequence.
The sequence given of 3,5,8,12,17 is not arithmetic because the difference between each number is not common and instead increases.
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Write the quadratic equation whose roots are 3 and 6, and whose leading coefficient is 2.
pls help l need to finish this
Answer:
y = 3x+3
Step-by-step explanation:
The rate of change, or slope, in this case, is 3, as we can either count the increase in y-values or perform the Δy/Δx (slope equation: [tex]\frac{9-3\\}{2-0}[/tex])to yield three, meaning that the (3x) in this equation would be the slope. Since the y-intercept is the constant in the equation and the y-intercept is always when x=0 (when the graph crosses the y-axis) on the XY plane, we can just subtract 3 from the x=1 coordinate, meaning that the y-intercept/x=0 coordinate would be (0, 3), leaving 3 as the constant.
Therefore,
the equation is y = 3x+3.
3 1/4 - 3 1/6 uhmmm yeahh
Given the Subtraction:
[tex]3\frac{1}{4}-3\frac{1}{6}[/tex]You can identify that the denominators are different, then, you need to follow these steps in order to find the Difference (the result of the Subtraction):
1. Find the Least Common Denominator (LCD):
- Decompose the denominators into their Prime Factors:
[tex]\begin{gathered} 4=2\cdot2=2^2 \\ 6=2\cdot3 \end{gathered}[/tex]- Multiply the common and non-common factors with the largest exponents:
[tex]LCD=2^2\cdot3=12[/tex]2. Divide the LCD by each original denominator and multiply the Quotient by the corresponding numerator:
[tex]\begin{gathered} =3\frac{1\cdot3}{12}-3\frac{1\cdot2}{12} \\ \\ =3\frac{3}{12}-3\frac{2}{12} \end{gathered}[/tex]3. Subtract the whole number parts and then subtract the fractions. You get:
[tex]\begin{gathered} =0\frac{3-2}{12} \\ \\ =\frac{1}{12} \end{gathered}[/tex]Hence, the answer is:
[tex]=\frac{1}{12}[/tex]help me please is when all The sides are right
Not true, true, true, true, true, true, true, not true, true, true
See explanation below
Explanation:From the diagram, we noticed a change in lengths when all four vertex was dragged.
This means the 4 sides will not always be the same (congruent).
Not always true: The four sides are congruent
From both diagrams. we found the opposite sides are the same (congruent)
Always true: The opposite sides are congruent
Since they opposite sides arecongruent, this also means the opposite sides are parallel
Always true: opposite sides are parallel
All four angles from both diagrams are equal (congruent)
Always true: all four angles are congruent
SInce all four angles areequal, then the angles opposite each other will also be equal.
Always true: opposite angles are congruent
The diagonals of both shapes bisect each other. Hence, they are congruent.
Always true: Diagonals are congruent
Always true: diagonals bisect each other
Diagonals of a square (the shapethat has all sides equal ) intersect at a right right angle.
Diagonals of a rectangle ( the shape with opposite sides equal) don ot intersect at right angle.
Not always true: Diagonals intersect at a right angle
The interior angles were split by the two diagonals in both shapes.
Always true: Diagonals bisect interior angles
The sum of angles in a quadrilateral is equal to 360°
Both shapes are quadrilaterals. Hence, the sumof their angles is 360°.
Always true: sum of all angles equal 360°
Kali just started a new sales floor job to save for college. She earns 15.75 plus a flat fee of 50 . She wants to earn between 200 and 400 . The following inequality represents her earning potential
200 ≤ 15.75x + 50 ≤ 400 Solve the inequality PLEASE HELP ASAP
!!
Kali needs to work between 10 to 22 hours to earn an income between 200 and 400
Flat fee earned by Kali = 50
Earning per hour of Kali = 15.75
Required income is between 200 and 400
Inequality: Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
Inequality represents the equation:
200<=15.75x + 50<=400
200<= 15.75x + 50
150<= 15.75x
x = 9.52
So, she needs to work a minimum of 10 hours
15.75x+50<=400
15.75x <=350
x <= 22.22
So, she can work a maximum of 22 hours
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Connor deposited $84 into his checking account. If his new balance is $51. what was his balance before the deposit?'
Answer: -33
Step-by-step explanation: I guess he had like debt to pay lol but he would've had to have -33 dollars and added $84 to get a total of $51
For right triangle ABC, find the sine ratio of angle θ.Opition - three fifthsthree fourthsfour fifthsfour thirds
For any given angle in a right triangle that is not the 90° angle its sine is given by the quotient between its opposite side and the hypotenuse. For triangle ABC the hypotenuse is BC and the opposite side to theta is AB. Then the sine of this angle is given by the following equation:
[tex]\sin\theta=\frac{AB}{BC}=\frac{4}{5}[/tex]AnswerThen the answer is the third option, 4/5.
Which function in vertex form is equivalent to f(x) = x² + x +1?
Answer:
f(x) = (x + 1/2)² + 3/4
===============================
Vertex form of quadratic equation:
f(x) = a(x - h)² + kConvert the given expression into vertex form by completing the square:
f(x) = x² + x + 1 = x² + 2*(1/2)x + (1/2)² + 1 - (1/2)² = (x + 1/2)² + 1 - 1/4 = (x + 1/2)² + 3/4Answer:
[tex]f(x)=\left(x+\dfrac{1}{2}\right)^2+\dfrac{3}{4}[/tex]
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{5.6 cm}\underline{Vertex form of a quadratic equation}\\\\$y=a(x-h)^2+k$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the vertex. \\ \phantom{ww}$\bullet$ $a$ is some constant.\\\end{minipage}}[/tex]
To find the vertex form of the given function, complete the square.
Given function:
[tex]f(x)=x^2+x+1[/tex]
Add and subtract the square of half the coefficient of the term in x:
[tex]\implies f(x)=x^2+x+\left(\dfrac{1}{2}\right)^2+1-\left(\dfrac{1}{2}\right)^2[/tex]
[tex]\implies f(x)=x^2+x+\dfrac{1}{4}+1-\dfrac{1}{4}[/tex]
[tex]\implies f(x)=x^2+x+\dfrac{1}{4}+\dfrac{3}{4}[/tex]
Factor the perfect square trinomial formed by the first three terms:
[tex]\implies f(x)=\left(x+\dfrac{1}{2}\right)^2+\dfrac{3}{4}[/tex]
i need help with my homework PLEASE CHECK WORKnumber 4
ANSWER:
Option c
[tex]h=-\frac{\operatorname{\ln}(0.62)}{0.079}[/tex]STEP-BY-STEP EXPLANATION:
The function given in the statement is the following:
[tex]D(h)=615\cdot\:e^{-0.079h}[/tex]If D(h) = 383, we substitute and solve for h, just like this:
[tex]\begin{gathered} 383=615\cdot \:e^{-0.079h} \\ \\ e^{-0.079h}=\frac{383}{615} \\ \\ \ln(e^{-0.079h})=\ln\left(\frac{383}{615}\right) \\ \\ -0.079h=\ln(0.62) \\ \\ h=-\frac{\ln(0.62)}{0.079} \end{gathered}[/tex]Therefore, the correct answer is option c.
Find the exact values of the remaining trigonometric functions of if terminates in Quadrant IV and tan() = −3/4.
We know that the angle terminates in the fourth quadrant and that the tangent of it is -3/4.
Angles that are on the fourth quadrant have a negative sine and a positive cosine.
We can start with the cot():
[tex]\cot\theta=\frac{1}{\tan\theta}=\frac{1}{-\frac{3}{4}}=-\frac{4}{3}[/tex]We can relate the cosine with the tangent as:
[tex]\begin{gathered} \tan\theta=\frac{\sin\theta}{\cos\theta}=\frac{\sqrt{1-\cos^2\theta}}{\cos\theta} \\ -\frac{3}{4}=\frac{\sqrt{1-\cos^2\theta}}{\cos\theta} \\ -\frac{3}{4}\cos\theta=\sqrt{1-\cos^2\theta} \\ (-\frac{3}{4}\cos\theta)^2=1-\cos^2\theta \\ \frac{9}{16}\cos^2\theta=1-\cos^2\theta \\ (\frac{9}{16}+1)\cos^2\theta=1 \\ \frac{9+16}{16}\cos^2\theta=1 \\ \frac{25}{16}\cos^2\theta=1 \\ \cos^2\theta=\frac{16}{25} \\ \cos\theta=\sqrt{\frac{16}{25}} \\ \cos\theta=\frac{4}{5} \end{gathered}[/tex]We can now calculate the sine of the angle as:
[tex]\begin{gathered} \sin\theta=\tan\theta\cdot\cos\theta \\ \sin\theta=-\frac{3}{4}\cdot\frac{4}{5}=-\frac{3}{5} \end{gathered}[/tex]We can now calculate the sec() and csc() as:
[tex]\begin{gathered} \sec\theta=\frac{1}{\cos\theta}=\frac{5}{4} \\ \\ \csc\theta=\frac{1}{\sin\theta}=-\frac{5}{3} \end{gathered}[/tex]Answer:
sin() = -3/5
cos() = 4/5
cot() = -4/3
sec() = 5/4
csc() = -5/3