for every 3 girls taking classes at a martial arts school there are 4 boys who are taking classes. suppose there are 236 boys taking classes at the school. write a proportion that could be used to predict the number of girls taking classes at the school. Use x to represent the number of girls, and find it

The possible combinations are

Combinations are mathematical operations that count the number of potential configurations for a set of elements when the order of the selection is irrelevant. You can choose the components of combos in any order. Permutations and combinations can be mixed up.

Given:

A snack machine sells Crisps (C), Cereal Bars (B) and Soft Drinks (S).

Jesse buys 2 different drinks at random.

So, the possible combinations for the drinks she buys are:-

CB, CS, BC, BS, SC, SB

Since the order in which Jesse bought the drink does not matter, the possible combinations are

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Answer:

7.65643191

Step-by-step explanation:

2.3^2 = 5.29      √5.6 = 2.36643191324

5.29 + 2.36643191324 = 7.65643191

Answer:

Step-by-step explanation:

Let the number of small boxes is s and number of large boxes is l.

s and l are our variables.

Total number of boxes is 21:

This is your first equation.

The volume of a small box is a (since it is not given, if you have it please replace it with that number), and the volume of all small boxes is as.

The volume of a larger box is 14 cubic feet, and the volume of all large boxes is 14l cubic feet.

Total volume is 252 cubic feet, add the two volumes together:

And this is your second equation (don't forget to replace a with the volume of a small box).

Answer:

1a. BF, CG, DH.

1b. (1) ABF and DCG.

    (2) ADH and BCG.

1c. AD, AE, BC, BF, CE, DF.

2a. OP.

2b. JO, KP, LQ, MR.

2c. OPQ.

2d. JK, JN, KL, MN.

Step-by-step explanation:

A prism is a polyhedron that has:

Lines

Planes

A plane is a flat, two-dimensional surface that extends into infinity.  

A plane can be named by the letters naming three non-collinear points in the plane.

From inspection of the give diagram, the figure appears to be a rectangular prism with bases ABCD and EFGH.

1a. All segments that are parallel to AE are:

1b. Two examples of parallel planes:

1c. All segments that are skew to GH:

From inspection of the give diagram, the figure appears to be a pentagonal prism with bases JKLMN and OPQRS.

2a. All segments that are parallel to JK:

2b. All segments that are parallel to NS:

2c. A plane that is parallel to plane JKL:

2d. Four segments that are skew to RQ:

Answer:

4/3 i think

Step-by-step explanation:

Answer:

x = 0

Step-by-step explanation:

Substitute g(x) for x-5 in the equation,

x-5 = -5

collect like terms or add 5 to both sides

x = -5+5

x = 0

Answer:

do you speak English

Step-by-step explanation:

Amy weighs 150 pounds on earth and 350 on another planet. Find West lose weight on that planet if he weighs 130 pounds on earth.

Answer:

C

Step-by-step explanation:

The first term is 4x.  The first term is the product of 4 and x.

Answer:

21

Step-by-step explanation:

√441

Take factors of 441

-> 1,3,7,9,21,49,63,147,441

If you know all of them like this and it’s an odd number, find the middle value that doesn’t have a pair and it’s 21.

If you don’t just take a different value that has a square root. Let’s do 9.

Separate the root into √9*49

Woah, both of those are squares!!

Take the square root of both of those numbers

√9*√49

3*7=21, voila.

It is very easy, we just have to take the square root as it tells us in the problem:

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \red{ \sqrt{441 }} = \orange{21}[/tex]

You may ask ¿why 21?

[tex]\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \red{21 \times 21} = \orange{441} [/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf So , \: the \: result \: is \\ \sf \: \: \: \: \longmapsto \orange{21} [/tex]

Answer:

7.00

Step-by-step explanation:

36.8/ (11.5-6.25) = 7.00952380952                                                                                       Now just pick two first numbers two there you go.                                                                Dam being a 6 grader Wow

The slope of the function for pronghorn antelope is 60.78 which infers that the rate of speed of the pronghorn is 60.78 miles per hour.

7) The given function that represents the speed of the pronghorn is

y = 60.78x - 5.4

Comparing this function with the general equation of a straight line

y = mx + c we can conclude that the slope of the function is 60.78 .

So the Pronghorn's rate of speed is 60.78 miles per hour.

8) Now the speed of the cheetah is given in the form of a table.

Let us take any two points on the graph

(0.5,21.85) and (2,118.60)

Slope of the line passing through these two points

= (118.6-21.85)/(2-0.5)

=64.5

So the slope of the graph is 64.5 and the average rate of speed of the Cheetah is 64.5 miles per hour.

9) From the above two slopes and the rate of speed we can conclude that the speed of the cheetah is 64.5 mph which is greater than that of the pronghorn 's speed of 60.78 miles per hour.

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The test statistic, using the z-distribution, is given as follows:

z = 1.12.

At the null hypothesis, it is tested if there is not enough evidence that the proportion is greater than 20%, that is:

[tex]H_0: p \leq 0.2[/tex]

At the alternative hypothesis, it is tested if there is evidence that the proportion is greater than 20%, that is:

[tex]H_0: p > 0.2[/tex]

The test statistic is given by the equation presented as follows:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which the variables of the equation are listed as follows:

In the context of this problem, the values of these parameters are given as follows:

[tex]p = 0.2, n = 500, \overline{p} = \frac{110}{500} = 0.22[/tex]

Hence the test statistic is given as follows:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.22 - 0.2}{\sqrt{\frac{0.2(0.8)}{500}}}[/tex]

z = 1.12.

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The probability that it will rain in both cities is 0.35. It is independent.

Probability is the likelihood that a particular event will occur.

In this case, the probability of rain on a certain day is 70% in Yellow Falls and 50% in Copper Creek.

The probability that it will rain will be:

= P(Yellow Falls) × P(Copper Creek)

= 0.7 × 0.5

= 0.35

This is independent.

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Answer:

The number opposite the product of 1/15 and 1/16 will be 240.

Step-by-step explanation:

Algebra is the study of algebraic expressions, while logic is the manipulation of those concepts.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to answer the problem correctly and precisely.

The number opposite the product of 1/15 and 1/16 will be given as,

            1

_____________

     (1/15)*(1/16)

        1

     ____

     1/240

      240

Answer: Using SOH CAH TOA you get 10.24

Step-by-step explanation:

you can determine what the value of X is and it is 10.24

This is gotten by sin52=x/13

Because we are trying to get x which is opposite the angle, and we have the value of the hypotenuse already (13) we can using SOH that is  sin 52= x divided by 13

Cross multiply and you'll get 10.2441398

Answer:

A. yes, B. yes,C. yes

Step-by-step explanation:

A. (3,0) yes

b. (4,-2) yes

c. (5,-4)yes

The daily production level that will minimize the costs is 106300 units.

Given,

In the question:

The accountant for the factory says that the costs for producing x thousands of units a day can be approximated by the formula

C = 0.04x² -8.504x + 25302.

To find the daily production level that will minimize the costs.

Now, According to the question:

From the information, the function is given as

C = 0.04x² - 8.504x + 25302.

C = cost

From the function, the following can be deduced:

a = 0.04

b = 8.504

c = 25302

Then, -b/(2a) will be:

= -8.504 / (2 × 0.04)

= 106.300

Note that production level will minimize the cost in thousands.

The production level will now be:

= 106.300 × 1000

= 106300 units

Hence, The daily production level that will minimize the costs is 106300 units.

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1. The annual costs from the pothole damage is $156428.

2. The annual costs due to damage from

collisions is $72000 per year.

3. The project should be undertaken

1. The budget is given as $100,000

The number of cars hit potholes per week = 15

Number of cars hit potholes per year = 15*52.148

= 782.14 cars

Total amount of damage per year will be:

= 782.14 * 200 = $156428

2. Number of collusion at intersection per month = 1

Number of collusion at intersection per year = 1 * 12 = 12

Total cost of collusion at intersection per year = 12*6000

= $72000 per year

3. Saving on potholes = 156248 / 100000 = $ 1.56

Saving on collusion at intersection:

= 72000 / 100000

= $0.72

So from above, it is clear that if the budget is spent on potholes, more savings will be done. Thus the budget should be invested in potholes.

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The equation of the line in slope intercept form is y = 2x - 7..

The equation of a line can be represented in slope intercept form as follows;

y = mx + b

where

Therefore, the equation of the line that passes through  (5,3) and has a gradient of 2 can be found as follows;

m = 2

let's find the y-intercept using (5, 3)

3 = 2(5) + b

b = 3 - 10

b = -7

Therefore, the equation of the line is y = 2x - 7.

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When one flip three coins eight times, there no guarantee to get three heads at least once as the probability is low.

Probability is the occurence of likely events. It is the area of mathematics that deals with numerical estimates of the likelihood that an event will occur or that a statement is true.

An event's probability is a number between 0 and 1. In this case, 0 denotes the impossibility of the event and 1 represents certainty.

The probability of getting a head in a coin is 1/2.

Therefore, the probability of getting three heads on there flips will be:

= P(head)³

= 1/2 × 1/2 × 1/2

= 1/8

Therefore, the probability is low and the heads aren't guaranteed.

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Answer:

The number opposite the product of 1/15 and 1/16 will be 240

Step-by-step explanation:

          1

____________

  (1/15) x (1/16)

           1

____________

        1/240

        240

What is Algebra?

Algebra is the study of algebraic expressions, while logic is the manipulation of those concepts.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to answer the problem correctly and precisely.

The number opposite the product of 1/15 and 1/16 will be given as,

The higher F value means higher between-group variability relative to within-group variability. Option(b) is correct.

Analysis of variance (ANOVA) is a statistical formula used to compare variances between means (or averages) of different groups. It is used in a variety of scenarios to determine whether there is any difference in the means of different groups.

The F-value is the ratio of between-group and within-group variation. A high F-value indicates that the between-group variation is greater than the within-group variation. This can be interpreted as a statistically significant difference in the means of your groups.

A large f value (one greater than the F critical value found in a table) indicates that something is significant, whereas a small p-value indicates that all of your results are significant.

Therefore a higher F value the higher between-group variability relative to within-group variability.

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Solving a system of equations we will see that the song was used on 5 movies and 7 commercials

The variables we will use are:

We know that:

x = y + 2

and:

x*$30 + y*$110 = $760

So the system of equations is:

x = y + 2

x*$30 + y*$110 = $760

Replacing the first equation in the second one:

(y + 2)*$30 + y*$110 = $760

$60 + y*$30 + y*$110 = $760

y*$140 = $760 - $60

y*$140 = $700

y = $700/$140 = 5

Then the value of x is:

x = y + 2 = 5 + 2 = 7

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The average rate of flow of gasoline into the gas tank is 2.2 gallons per minute.

The average is the mean value of the data set values.

The mean is computed by dividing the total value by the number of items.

For the average rate of flow, divide the total gallons of gasoline filled by the driver, 8.8 gallons, by the number of minutes used in filling the tank.

In this case, the average rate of flow shows the speed that the driver used to fill the car with gasoline.

Starting time = 3:40 P.M.

Ending time = 3:44 P.M.

The difference in filling time = 4 minutes (3:44 - 3:40)

Total number of gallons of gasoline filled = 8.8 gallons

Average rate of flow of the gasoline = 2.2 gallons per minute (8.8/4)

Thus, at an average rate of 2.2 gallons per minute, the driver was able to fill his gas tank in 4 minutes.

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The slope of a line that passes through the points (1,−2) and (2,2) is 4.

The two given points are (1,-2) and (2,2).

We have to find out the slope of the line that passes through the two given points.

We know that the slope of a line passing through two points ([tex]x_{1} ,y_{1}[/tex]) and ([tex]x_{2} ,y_{2}[/tex]) is -

[tex]m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

Using this formula for the given points (1,-2) and (2,2), we can find out the slope of the line passing through them as -

[tex]m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }\\= > m = \frac{2-(-2)}{2-1}\\ = > m = \frac{4}{1}\\ = > m = 4[/tex]

Thus, the slope of a line that passes through the points (1,−2) and (2,2) is 4.

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The journal entries to record the sale of the equipment by Crane Company are as follows:

a) Sold for $44,000 on January 1, 2022:

Debit Cash $44,000

Credit Sales of Equipment $44,000

Debit Sale of Equipment $78,000

Credit Equipment $78,000

Debit Accumulated Depreciation $36,000

Credit Sale of Equipment $36,000

Debit Sale of Equipment $2,000

Credit Profit from Sale of Equipment $2,000

b) Sold for $44,000 on May 1, 2022:

Debit Cash $44,000

Credit Sales of Equipment $44,000

Debit Sale of Equipment $78,000

Credit Equipment $78,000

Debit Accumulated Depreciation $40,000

Credit Sale of Equipment $40,000

Debit Sale of Equipment $6,000

Credit Profit from Sale of Equipment $6,000

c) Sold for $20,000 on January 1, 2022:

Debit Cash $20,000

Credit Sales of Equipment $20,000

Debit Sale of Equipment $78,000

Credit Equipment $78,000

Debit Accumulated Depreciation $36,000

Credit Sale of Equipment $36,000

Debit Loss from Sale of Equipment $22,000

Credit Sale of Equipment $22,000

d) Sold for $20.000 on October 1. 2022:

Debit Cash $20,000

Credit Sales of Equipment $20,000

Debit Sale of Equipment $78,000

Credit Equipment $78,000

Debit Accumulated Depreciation $45,000

Credit Sale of Equipment $45,000

Debit Loss from Sale of Equipment $13,000

Credit Sale of Equipment $13,000

Cost of equipment = $78,000

Salvage value = $18,000

Depreciable amount = $60,000 ($78,000 - $18,000)

Purchase date = January 1, 2019

Estimated useful life = 5 years

Annual depreciation expense = $12,000 ($60,000/5)

a) Accumulated Depreciation to January 1, 2022 = $36,000 ($12,000 x 3)

Book value of equipment = $42,000 ($78,000 - $36,000)

Cash $44,000 Sales of Equipment $44,000

Sale of Equipment $78,000 Equipment $78,000

Accumulated Depreciation $36,000 Sale of Equipment $36,000

Sale of Equipment $2,000 Profit from Sale of Equipment $2,000

b) Accumulated Depreciation to May 1, 2022 = $40,000 ($12,000 x 3.333)

Book value of equipment = $38,000 ($78,000 - $40,000)

Cash $44,000 Sales of Equipment $44,000

Sale of Equipment $78,000 Equipment $78,000

Accumulated Depreciation $40,000 Sale of Equipment $40,000

Sale of Equipment $6,000 Profit from Sale of Equipment $6,000

c) Accumulated Depreciation to January 1, 2022 = $36,000 ($12,000 x 3)

Book value of equipment = $42,000 ($78,000 - $36,000)

Cash $20,000 Sales of Equipment $20,000

Sale of Equipment $78,000 Equipment $78,000

Accumulated Depreciation $36,000 Sale of Equipment $36,000

Loss from Sale of Equipment $22,000 Sale of Equipment $22,000

d) Accumulated Depreciation to January 1, 2022 = $45,000 ($12,000 x 3.75)

Book value of equipment = $33,000 ($78,000 - $45,000)

Cash $20,000 Sales of Equipment $20,000

Sale of Equipment $78,000 Equipment $78,000

Accumulated Depreciation $45,000 Sale of Equipment $45,000

Loss from Sale of Equipment $13,000 Sale of Equipment $13,000

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Value of m is -4

Value of x is 5

To solve linear equations, follow the following steps:

Equation 1.

2-6m = -4m+10

6m-4m = 2-10

2m = -8

m = -8/2

m = -4

Value of x is -4

Equation 2.

2.5+1.75 = -3.25+1.5x

1.5x = 4.25+3.25

1.5x = 7.5

x = 7.5/1.5

x = 5

Value of x is 5

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Using the factorization of polynomial, the factor of the given expression is (3x-4)(x+2).

In the given question we have to find the each polynomial expression of 3x^2+2x-8.

The given expression is 3x^2+2x-8.

Now finding the factor of the given expression.

The multiply of the first and third variable is 24. The middle term is 2.

So the possible factor is 6 and 4.

3x^2+2x-8 = 3x^2+(6-4)x-8

3x^2+2x-8 = 3x^2+6x-4x-8

3x^2+2x-8 = 3x(x+2)-4(x+2)

3x^2+2x-8 = (3x-4)(x+2)

Hence, the factor of the given expression is (3x-4)(x+2).

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The right expression is 3x^2+2x-8.

The best search engine for Musical Instrument and Sound Effects in MP3 Audio Online is MP3 realm.

MP3 is a digital audio coding format developed primarily by the Fraunhofer Society in Germany, with assistance from other digital scientists in the United States and elsewhere.

MP3 (MPEG-1 Audio Layer-3) is a standard technology and format for compressing a sound sequence into a small file (about one-twelfth the size of the original file) while maintaining the original level of sound quality when played. MP3 files, which take up very little hard drive space, are commonly used to store a song or an entire CD.

MP3 Realm is a music search engine that allows you to find MP3 tracks from all over the Internet.

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