FLUID P IS WATER AND FLUID Q IS MERCURY. IF THE SPECIFIC GRAVITY OF MERCURY IS 13.6 AND ATMOSPHERIC PRESSURE IS 101.3 kPa. What's the absolute pressure at A when h¹= 15cm and h²= 30cm

FLUID P IS WATER AND FLUID Q IS MERCURY. IF THE SPECIFIC GRAVITY OF MERCURY IS 13.6 AND ATMOSPHERIC PRESSURE

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Answer 1

Answer:

A mercury manometer is used to measure the pressure difference in vessels A and B. Determine the pressure difference (PA – PB) in Pascals.Liquid in vessels A and B is oil with SG = 0.85,I think this is the answer

Answer 2

The absolute pressure in the fluid at A is about 59.984 kPa

How can the absolute pressure in a fluid be calculated?

The absolute pressure at the point A can be calculated using the formula P = Patm + ρ·g·h, where P is the absolute pressure, Patm is the atmospheric pressure, ρ is the density of the fluids, g is the acceleration due to gravity, h is the height of the fluid column above point A

The height of the two fluid columns are;

A column of water, h₁ = 15 cm

A column of mercury, h₂ = 30 cm

Density of water ≈ 1,000 kg/m³

Density of mercury ≈ 13,600 kg/m³

Acceleration due to gravity, g ≈ 9.8 m/s²

P = Patm - ρ·g·h

P + ρ·g·h = Patm, therefore;

P + 1000 kg/m³×9.8 m/s²×0.15 m + 13,600 kg/m³×9.8 m/s²×0.30 m = 101.3 kPa

P + 1000 kg/m³×9.8 m/s²×0.15 m + 13,600 kg/m³×9.8 m/s²×0.30 m = 101.3

P + 1.47 kPa + 39.984 kPa = 101.3 kPa

P = 101.3 kPa - 1.47 kPa - 39.984 kPa = 59.846 kPa

The absolute pressure, at A is about 59.984 kPa

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