Answer:
The angle is approximately 111.199 degrees.
Step-by-step explanation:
Cosine is adjacent over hypotenuse.
The hypotenuse is the longest side of the triangle.
In this cos the hypoteneuse is a. However, we can only use cos on right triangles and on the angles that are not 90 degrees. In this case, p would be the 90 degree angle if we could use cosine.
In this case, you need the law of cosines, not cosine. The law of cosine says [tex]c=\sqrt{a^2+b^2-2 a b cosp}[/tex] where c is the side opposite to the angle, a and b are the sides adjacent to the angle, and p is the angle. The law of cosine works for all the triangles.
Plugging in the numbers:
[tex]5.3=\sqrt{3.6^2+2.8^2-2*3.6*2.8* cosp}\\5.3^2=20.8-20.16* cosp}\\7.29=-20.16*cosp\\cos^{-1}\frac{7.29}{ -20.16}=p\\p=111.198929[/tex]
A line connects the midpoint of BC (point E), with point D in the square ABCD shown below. Calculate the area of the acquired trapezoid shape of the square has a side of 4 m.
The area of the trapezoid formed is equal to 12 square meters.
The area of the trapezium is calculated by using the formula.
A =(a + b) × h / 2
In the given trapezium the length of the parallel sides are:
2 m and 4 meters.
The distance between the parallel sides is 4 m
Area of the trapezium = (2+4) × 4÷2 = 12 square meters
A trapezoid is a quadrilateral that has at least one pair of parallel sides.
A trapezoid is a convex quadrilateral by definition in Euclidean geometry. The parallel sides serve as the trapezoid's bases. The remaining two sides are referred to as the lateral sides or the legs if they are parallel; otherwise, the trapezoid appears to be a parallelogram, with two pairs of bases.
Therefore the area of the trapezium is 12 square meters .
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Given f(x)=2x-5, what would be the expression for f(t-1)?
A f(t-1)=2t-3.
B f(t-1)=21-5
C
f(t-1)=2t-7
A sweater priced at 34.99 is on sale for 25% off, find the cost with 7.5% sales tax.
Answer:
$24.27
Step-by-step explanation:
Original price: $
34.99
Discount percentage:
25
%
Results
Discount:
$8.75
Final Price:
$26.24
Details
Discount = Original Price x Discount %/100
Discount = 34.99 × 25/100
Discount = 34.99 x 0.25
You save = $8.75
Final Price = Original Price - Discount
Final Price = 34.99 - 8.7475
Final Price = $26.24
- 7.5% = $24.27
The cost of the sweater after a 25% of discount and 7.5% of sales tax will be 28.21.
What is the percentage?The amount of any product is given as though it was a proportion of a hundred. The ratio can be expressed as a quarter of 100. The phrase % translates to one hundred percent. It is symbolized by the character '%'.
The percentage is given as,
Percentage (P) = [Final value - Initial value] / Initial value x 100
A sweater priced at 34.99 is on sale for 25% off. Then the cost after the discount is calculated as,
⇒ (1 - 0.25) x 34.99
⇒ 26.24
If the sales tax is 7.5%. Then the cost after the sales tax is given as,
⇒ (1 + 0.075) x 26.2425
⇒ 28.21
The cost of the sweater after a 25% of discount and 7.5% of sales tax will be 28.21.
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On Mars, the temperature can get cold really quickly. Yesterday, the temperature
dropped 528 degrees in 8 hours straight. What integer represents the average temperature per hour change during the 8 hours
4224 hours integer represents the average temperature per hour change during the 8 hours.
What is the short definition of temperature?
Temperature is a unit of measurement that can be expressed on a variety of scales, including Fahrenheit and Celsius. Temperature shows the direction of the spontaneous flow of heat energy, i.e., from a hotter body (one with a higher temperature) to a colder body.the temperature dropped = 528 degrees
total time = 8 hours
the average temperature per hour change during the 8 hours = 528 * 8
= 4224 hours
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please help and show steps please
Answer:
Step-by-step explanation:
f(x)=3x
2
+9x−16
Quadratic polynomial can be factored using the transformation ax
2
+bx+c=a(x−x
1
)(x−x
2
), where x
1
and x
2
are the solutions of the quadratic equation ax
2
+bx+c=0.
3x
2
+9x−16=0
All equations of the form ax
2
+bx+c=0 can be solved using the quadratic formula:
2a
−b±
b
2
−4ac
. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=
2×3
−9±
9
2
−4×3(−16)
Square 9.
x=
2×3
−9±
81−4×3(−16)
Multiply −4 times 3.
x=
2×3
−9±
81−12(−16)
Multiply −12 times −16.
x=
2×3
−9±
81+192
Add 81 to 192.
x=
2×3
−9±
273
Multiply 2 times 3.
x=
6
−9±
273
Now solve the equation x=
6
−9±
273
when ± is plus. Add −9 to
273
.
x=
6
273
−9
Divide −9+
273
by 6.
x=
6
273
−
2
3
Now solve the equation x=
6
−9±
273
when ± is minus. Subtract
273
from −9.
A line passes through the points (0, 0) and (–17, –11). What is its equation in slope-intercept form?
Write your answer using integers, proper fractions, and improper fractions in simplest form
A line passes through the points (0, 0) and (–17, –11). The equation in the slope-intercept form will be y=9/5x+0
What is a straight line?A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:
A linear equation has the form y = mx + b in the slope-intercept format. X and Y are the variables in the equation. The values m and b represent the line's slope (m) and the value of y when x is 0.
[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]
It is given that, the line passes through the points (0, 0) and (–17, –11).
The slope of the line is,
m = (5+4)/(5-0)
m= 9/5
The equation of the line passes through the point as,
(y-y₁)=m(x-x₁)
(y-0)=9/5(x-0)
5(y-0)=9(x-0)
5y=9x+0
y=9/5x+0
Thus, a line passes through the points (0, 0) and (–17, –11). The equation in the slope-intercept form will be y=9/5x+0
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Four boxes are sliding with constant speed before each box experiences an unbalanced force of 8 n. Which box would experience the greatest acceleration when the unbalanced force is applied?.
The greatest acceleration when the unbalanced force is applied will be experienced by the least weighted box ( i.e., the mass of 2 kg)
Acceleration: it is defined as rate of change of velocity with respect to time.
Unbalanced Force: it means that the force applied in one direction is greatest than the force applied in the opposite direction.
Given that, F = 8n.
let us assume that the boxes are of 2kg, 4 kg, 6 kg and 8 kg.
According to the 2nd law of motion: the external unbalanced force is directly proportional to rate of change of momentum or Force is equal to the product of mass and acceleration.
F = m × a
⇒ a = F/ m
where, F is Force, m is mass and a is acceleration.
Now, acceleration of the box of 2kg = 8÷2 = 4 m/s²
acceleration of the box of 4kg = 8÷ 4 = 2 m/m²
acceleration of the box of 6 kg = 8÷ 6 = 1.34 m/s²
acceleration of the box of 8kg = 8÷ 8 = 1 m/s²
∴ the box with mass of 2kg experience the greatest acceleration.
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7 Résoudre les équations d'inconnue x suivantes:
a.-2x + 7 = -x +9
c.4x +15=2x+6
b. 8x+26=5x+14
d. 7x+31= 16x +17
Answer:
A)
[tex]\sf -2x+7=-x+9[/tex]
[tex]\sf -2x+7-7=-x+9-7[/tex]
[tex]\sf -2x=-x+2[/tex]
[tex]\sf -2x+x=-x+2+x[/tex]
[tex]\sf -x=2[/tex]
[tex]\sf \cfrac{-x}{-1}=\cfrac{2}{-1}[/tex]
[tex]\boxed{\sf x=-2}[/tex]
____________________
B)
[tex]\sf 4x +15=2x+6[/tex]
[tex]\sf 4x+15-15=2x+6-15[/tex]
[tex]\sf 4x=2x-9[/tex]
[tex]\sf 4x-2x=2x-9-2x[/tex]
[tex]\sf 2x=-9[/tex]
[tex]\sf \cfrac{2x}{2}=\cfrac{-9}{2}[/tex]
[tex]\boxed{\sf x=-\cfrac{9}{2}}[/tex]
____________________
C)
[tex]\sf 8x+26=5x+14[/tex]
[tex]\sf 8x+26-26=5x+14-26[/tex]
[tex]\sf 8x=5x-12[/tex]
[tex]\sf 8x-5x=5x-12-5x[/tex]
[tex]\sf 3x=-12[/tex]
[tex]\sf \cfrac{3x}{3}=\cfrac{-12}{3}[/tex]
[tex]\boxed{\sf x=-4}[/tex]
____________________
D)
[tex]\sf 7x+31=16x+17[/tex]
[tex]\sf 7x+31-31=16x+17-31[/tex]
[tex]\sf 7x=16x-14[/tex]
[tex]\sf 7x-16x=16x-14-16x[/tex]
[tex]\sf -9x=-14[/tex]
[tex]\sf \cfrac{-9x}{-9}=\cfrac{-14}{-9}[/tex]
[tex]\boxed{\sf x=\cfrac{14}{9}}[/tex]
Which statements about this situation are true?
Answer:
D) Alan was farther away from Madison when he started driving
F) Alan and Andrew started the same distance from Madison
Step-by-step explanation:
Hopefully I got them all!!!
5. USE STRUCTURE What values of a, b, c,
and d will make the equation have one
solution? Then alter your equation so that
it has no solution. Finally, alter the
equation again so that it has infinitely
many solutions.
ax + b = cx+ 8
Many solutions for a = c and b = 8.
No solution for a = c and b ≠ 8.
One solution for a ≠ c, b can be anything.
What is solution of equations?
Any value of the variable that makes the Left Hand Side (LHS) and the Right Hand Side (RHS) of the equation equal is considered a solution to the problem. Finding the solution or solutions to an equation is known as solving it.
The two sides of the equation must be identical for all values of x if
ax + b = cx + 8 has an unlimited number of solutions. This suggests that
a = c and b = 8.
The two sides of the equation cannot be equal for any value of x if
ax + b = cx + 8 has no solutions. The only way this is possible is if
a = c and b ≠ 8, therefore b can be anything other than 8.
If there is exactly one solution to the equation ax + b = cx + 8, then a ≠ c, meaning that 'a' can be anything other than c. In this situation, 'b' is not constrained in any way (b can be anything).
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Twice a number subtracted from 10 is 14
Let the number be x
10 - 2x = 14
2x = -4
x = -2
Eve is organizing a race to raise money for a local children's hospital. She makes $20 for each 5K participant and $45 for each 10K participant. Her goal is to raise $9,500.
If x represents the number of participants in the 5K race and y represents the number of participants in the 10K race, the linear equation for the given scenario is
x + y = . If Eve raises exactly $9,500, is it possible for there to be 220 participants in the 5K race?
(yes/no)
No It is not possible to have 220 participants in the 5k race.
How to determine the number of participants in the racesInformation from the question
She makes $20 for each 5K participant
$45 for each 10K participant.
x represents the number of participants in the 5K race
y represents the number of participants in the 10K race
Eve raises exactly $9,500, is it possible for there to be 220 participants in the 5K race = ?
From the question
$20 for each 5K participant and x represents the number of participants in the 5K race. = 20x
$45 for each 10K participant and y represents the number of participants in the 10K race = 45y
Eve raises exactly $9,500 means the sum of amount from 5k and 10k is 9500 = 20x + 45y = 9500
if Eve raise 220 participants in the 5k race then the equation will be
20 * 220 + 45y = 9500
4400 + 45y = 9500
45y = 9500 - 4400
45y = 5100
y = 113.333
The participants are human being and cannot be represented as fractions hence 220 is impossible for the 5k race
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(4,-2) with a scale factor of 1.5
3x-2y>2 graphs and solution
The graph of the inequality 3x - 2y > 2 is attached below.
We are given an inequality. The inequality is given below.
3x - 2y > 2
First of all, we will simplify the inequality. We need to keep the variable "y" on one side of the inequality. The inequality is modified as given below.
3x - 2y > 2
3x > 2 + 2y
3x - 2 > 2y
2y < 3x - 2
y < (3x - 2)/2
Now, to draw the graph of the inequality. We will first find the equation of the straight line corresponding to the given inequality.
y = (3x - 2)/2
We will draw a dotted line according to the above equation. Now, we will shade the area that satisfies the inequality. Hence, the graph is obtained.
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Find the angle between the following two vectors.
< 8, 3 > and < 4, −3 >
The angle between the two vectors < 8, 3 > and < 4, −3 > is 57.43°
How to determine the angle between the following two vectors?Given: vectors < 8, 3 > and < 4, −3 >
To find the angle between two vectors, we can use the dot product method:
First, you will compute the dot product and magnitudes of both vectors. Thus,
Let a = < 8, 3 > and b = < 4, −3 >
a · b = <8, 3> ·<4, -3> = 8(4) + (3)(-3) = 32-9 = 23
|a| = √(8² + 3²) = √(64+9) = √73
|b| = √(4² + (-3)²) = √(16 + 9) = √25 = 5
By using the angle between two vectors formula using dot product,
θ = cos⁻¹ [ (a · b) / (|a| |b|) ]
θ = cos⁻¹ (23 / √73 · 5)
θ = cos⁻¹ (23/42.72) = 57.43°
Therefore, the angle between the following two vectors is 57.43°
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solve x-6y=9 to find x coordinates
_ _ _ _ _ _ _ _ _ _ _ _ _
| | | _ _ _ | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | _ _ _ _ _ _ | | _ _ _| | | | _ _ _ _ _ _
| _ _ _ _ _ _ _ _| | _ _ _ _ _ _| | _ _ _ _ _ _ _ _|
The slope is 1/6x
You have to re-arranged the problem
x - 6y = 9 --> 6y = x - 9
6y = x - 9
__ ____ ----> y = 1/6x - 3/2
6 6
A wooden door costs AED 600 plus a 12% tax. What is the price of the door including the tax?
Answer:
672
Step-by-step explanation:
600+ .12(600)
600 + 72 = 672
question is on image
Answer:
y= -3/4 x + 8
Step-by-step explanation:
y-2 = -3/4 (x-8)
y-2 = -3/4 x + 6
y = -3/4 x + 6 + 2
y = -3/4 x + 8
karen buys four movie tickets for $\$10.50$ each and two buckets of popcorn for $\$5.50$ each. how many dollars does she spend for the movie tickets and the popcorn? express your answer as a decimal to the nearest hundredth.
Karen spent $42.00 on movie ticket and $11.00 on popcorn.
Firstly calculating the amount spent on movie tickets
Cost of one movie ticket = $10.50
Cost of four movie tickets = 4×10.5
Performing multiplication on Right Hand Side of the equation
Cost of four movie tickets = $42.00
Now calculating the amount spent on popcorn
Cost on one bucket of popcorn = $5.50
Cost of two buckets of popcorn = 2 × 5.50
Performing multiplication on Right Hand Side of the equation
Cost of two buckets of popcorn = $11.00
Hence, the cost spent on movie tickets and popcorn is $42.00 and $11.00 respectively.
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If the expression [tex]\sqrt{25x^5y^5}/xy^4[/tex] is written in the form ax^by^c. then what is the product of a, b and c?
The product of a, b, and c is -45/4.
What is multiplication?Multiplication is the process of adding a number up to a given number.
The given expression is [tex]\frac{\sqrt{25x^5y^5}}{xy^4}[/tex].
Rewrite the expression as follows,
[tex]\frac{\sqrt{25x^5y^5}}{xy^4}[/tex]
[tex]=\frac{5x^{\frac{5}{2}}y^{\frac{5}{2}}}{xy^4}\\=5x^{\frac{5}{2}-1}y^{\frac{5}{2}-4}\\=5x^{\frac{3}{2}}y^{-\frac{3}{2}}[/tex]
The values of a, b, and c are 5, 3/2, -3/2.
The product of a, b, and c is,
5 × 3/2 × (-3/2)
= -45/4
Hence, the product of a, b, and c is -45/4.
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What is the solution of the system? Solve using matrices. ( -3x + 2y = 10 -4x + 3y = 2 (-26 -34) (-34 -26) (26 34) O( no solution)
x + 2y = -1,, x-3y=-2
(-7 ,3)(3,-7) (7,-3)(no solution)
Inverse Matrices and Systems
Answer:
(a) (-26, -34)
Step-by-step explanation:
You want the solution to the system of equations ...
-3x +2y = 10-4x +3y = 2apparently using inverse matrices.
Matrix equationThe system can be represented by the matrix equation ...
AX = B
where A is the 2×2 matrix of coefficients, X is the 2×1 variable vector, and B is the 2×1 matrix of constants.
The solution to this system is found by multiplying on the left by the inverse of A:
A⁻¹·AX = A⁻¹·B
X = A⁻¹·B
The attachment shows the result of making this calculation:
[tex]\boxed{X=\left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}-26\\-34\end{array}\right]}[/tex]
developing proof: what’s wrong with the triangles? explain.
For the given triangles , developing proof is not possible due to following reasons:
First triangle : 21 + 25 < 48 not true.
Second triangle : Interior angle 130° > Exterior angle 125°
As given in the question,
For the given triangles developing proof is not possible due to following reasons:
First triangle:
Measure of three sides are given as 21, 25 , and 48.
As per the property to form a triangle : Sum of two sides is always greater than the third side.
Here, 21 + 25 < 48 .
Above mention property does not satisfied by given triangle.
Second triangle:
In a triangle, measure of exterior angle is always greater the opposite interior angles.
Here, measure of interior angle 130° > measure of exterior angle 125°
Does not satisfy the relation of exterior angles with interior angle.
Therefore, for the given triangles , developing proof is not possible due to following reasons:
First triangle : 21 + 25 < 48 not true.
Second triangle : Interior angle 130° > Exterior angle 125°.
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931.9572 Find the digits in the hundreds place, in the hundredths place, and in the ten thousandths place for the following number.
HELP NOWWWW LOOK AT IMAGE NOWW
After multiplying the simplified expression is [tex]\frac{-x+5}{2x + 6}[/tex] ; x ≠ -3 , 3 , -2 , -5 , the correct option is (b) .
In the question ,
it is given that ,
the expression is (x²-25)/(2x²+10x+12) × (-x²+x+6)/(x²+2x-15)
we need to find the value of the expression after multiplication .
= (x²-25)/(2x²+10x+12) × (-x²+x+6)/(x²+2x-15)
On splitting the given quadratic equation into factors , we get
= (x+5)(x-5)/2(x+3)(x+2) × -(x+2)(x-3)/(x-3)(x+5)
= [tex]\frac{(x+5)(x-5)}{2(x+3)(x+2)}[/tex] × [tex]\frac{-(x+2)(x-3)}{(x-3)(x+5)}[/tex]
After cancelling out the common factors , we get
= -(x - 5)/2(x + 3)
= -x+5 / 2x + 6
= [tex]\frac{-x+5}{2x + 6}[/tex] : x ≠ -3 , 3 , -2 , -5
Therefore , After multiplying the simplified expression is [tex]\frac{-x+5}{2x + 6}[/tex] ; x ≠ -3 , 3 , -2 , -5 .
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2 Which ordered pairs represent vertices of the
polygon?
Circle THREE correct answers.
(-11, 13)
(1, -1)
(1/4 , 2 2/1)
(1,-3)
The ordered pairs representing the vertices of a polygon are
(-11, 13) , (1, -1) and (1,-3).
Given, the ordered pairs representing the vertices of the polygon.
as, the given ordered pairs are
(-11, 13) , (1, -1) , (1/4 , 2(2/1)) , (1,-3).
Now, from the given ordered pairs
the pairs which are representing the vertices of a polygon are
(-11, 13) , (1, -1) and (1,-3).
So, the ordered pairs representing the vertices of a polygon are (-11, 13) ,
(1, -1) and (1,-3).
Hence, the ordered pairs representing the vertices of a polygon are
(-11, 13) , (1, -1) and (1,-3).
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what is the ratio of james wins to james play
Answer:
Step-by-step explanation:
the international average salary income database provides a comparison of average salaries for various professions. the data are gathered from publications and reports obtained directly from government agencies (such as the u.s. bureau of labor statistics) or from the international labour organization. suppose you are told that a computer programmer in canada who makes $2,063.30 has a z-score of 0.50 relative to other computer programmers in canada and that the standard deviation of the salary of computer programmers in canada is $458.60. the average salary, then, for computer programmers in canada is . suppose you are also told that a computer programmer in portugal who makes $1,387.40 has a z-score of 2.00 relative to other computer programmers in portugal and that the mean of the salary of computer programmers in portugal is $925. the standard deviation of the salary, then, for computer programmers in portugal is
The instance has a mean of 1834 and a standard deviation of 231.2, respectively.
Given data;
A comparison of typical earnings for different professions can be found in the international average salary income database. The information is acquired from publications and reports that were obtained directly from governmental organizations, like the US Bureau of Labor Statistics or the ILO. Consider being informed that the standard deviation of the income of computer programmers in Canada is $458.60 and that a computer programmer in Canada making $2,063.30 has a z-score of 0.50 in comparison to other programmers in Canada. Consequently, the typical pay for computer programmers in Canada is. Assume you are also informed that the mean wage for computer programmers in Portugal is $1,387.40 and that a computer programmer in Portugal who earns $1,387.40 has a z-core of 2.00 in comparison to other computer programmers in Portugal is $925.
Since, the salaries are relative and we know that the z-score is given by;
z = X - μ / σ
0.50 = 2063.30 - μ / 458.60
μ = 2063.30 - 229.3
μ = 1834
As, the salaries are relevant so;
2 = 1387.40 - 925 / σ
σ = 462.4/2
σ = 231.2
Hence, the mean and standard deviation of the case is 1834 and 231.2 respectively.
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i need help fast please !
Joelle is working on a school report in a word processor. She wants to place an oversized image which is 30.51 cm wide so that it appears centered on the page. The width of the page is 21.59 cm In the program, horizontal positions to the right of the leftmost edge of the page are positive.
What horizontal position for the left edge of the image should Joelle use to center the image?
The horizontal position for the left edge of the image should Joelle use to center the image is -4.46 cm .
In the question ,
it is given that ,
the length of the over sized image = 30.51 cm and
the length of the page = 21.59 cm
to find the margin , we subtract the width of the word processor page from the width of the oversized image.
that is
margin = 30.51 - 21.59 = 8.92 cm
Since , we have margin on two side ,that is horizontal positions to the left most side and horizontal positions to the right of the left most edge of the page . we divide 8.92 by 2 .
= 8.92/2
= 4.46 cm
it is given that the horizontal positions to the right of the leftmost edge of the page are positive,
So , horizontal position for the left edge of the image which Joelle should use to center the image would the negative .
the horizontal position is -4.46 cm .
Therefore , The horizontal position for the left edge of the image should Joelle use to center the image is -4.46 cm .
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Joe bought 5 1/4-pounds of trail mix for $24.94. What is the price per pound of the trail mix?
Answer:
Step-by-step explanation:
probably close to 5$