We have to find the sum of 219 and 763 . So , let's proceed :-
[tex]{:\implies \quad \sf 219+763}[/tex]
[tex]{:\implies \quad \sf (200+19)+(700+63)}[/tex]
[tex]{:\implies \quad \sf 200+19+700+63}[/tex]
[tex]{:\implies \quad \sf (200+700)+(19+63)}[/tex]
[tex]{:\implies \quad 900+82}[/tex]
[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{982}}}[/tex]
Hence , The required sum is 982 :D
The first triangle is dilated to form the second triangle Select True or Flause
Answer:
Statement 1 is false, statement 2 is true.
Step-by-step explanation:
The triangle has been dialated by a scale factor of 2.5
Allison measured a line to be 19.4 inches long. If the actual length of the line is 19.1
inches, then what was the percent error of the measurement, to the nearest tenth of a
percent?
It can be noted that the percentage error made by Allison will be 1.6%
How to solve the percentageFrom the information given, Allison measured a line to be 19.4 inches long and the actual length of the line is 19.1.
Therefore, the percentage error will be:
= (19.4 - 19.1)/19.1 × 100
= 0.3/19.1 × 100
= 1.6%
In conclusion, the correct option is 1.6%.
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please Help Me answer this question
Describe the transformations necessary to transform the graph of f(x) into that of g(x).
Answer:
Shift 3 units to the right.
Reflect over the x-axis
-6a+12=42. How do we do this equation
Answer: -5
Step-by-step explanation:
You have to find a. Here's some steps you can take.
1.) Subtract 12 on the left side of the equal sign to get -6a by itself. When subtracting 12 you must subtract 12 from 42 as well.
2.) Your new equation would be -6a = 30
3.) Now you need to get a by itself. How do we do that? By dividing -6a by -6. REMEMBER: You must also do the same to the right side of the equal sign which is 30 (30/-6)
4.) Your problem should end up looking like this: a = -5
Suppose you are dealt 6 cards from a standard 52-card deck. What is the probability that
you are dealt a 4-of-a-kind and a pair?
Answer: Approximately 0.00004597583714
===================================================
Explanation:
Four-of-a-kind is when you get four cards of the same value. One example is if we got four aces. Any four-of-a-kind already has two pairs built into it. I'm assuming your teacher wants four-of-a-kind and another different pair (we'll have 6 pairs all together).
In any suit there are 13 unique cards. So there are 13 choices to fill the first four slots to set up the four-of-a-kind.
-------------
After the four-of-a-kind is formed, we have 13-1 = 12 unique cards left in any given suit. Once that fifth card is chosen, we then have 4 C 2 = 6 ways to select that final card such that we get another pair. I'm using the nCr combination formula since order doesn't matter. The steps to calculating this value (and the other nCr value mentioned later) is shown in the attached image below.
Multiplying those values gets us 13*12*6 = 936 different six card hands such that we get four-of-a-kind and a different pair.
-------------
This is out of 52 C 6 = 20,358,520 different six card hands.
Divide the two values found
936/(20,358,520) = 0.00004597583714
2) Find the total cost (in dollars) of buying:
a) 8 pears at 50 cents each
b) p pears at 50 cents each
c) p pears at y cents each
Answer:
a=4
b=0.5p
c=py
Step-by-step explanation:
a) 8*0.5= 4
b) p*0.5= 0.5p
c) p*y= py
Hope this helps! :)
The length of a screw is 0.75 centimeter. How many screws
can be placed end to end to make a row that is
18 centimeters long?
round to the nearest whole %
1. What is the relative frequency for middle school students whose favorite sport is baseball?
2. What is the relative frequency for middle school students whose favorite sport is basketball?
3.What is the relative frequency for middle school students whose favorite sport is football?
4.What is the relative frequency for high school students whose favorite sport is baseball?
5.What is the relative frequency for high school students whose favorite sport is basketball?
6.What is the relative frequency for high school students whose favorite sport is football?
The relative frequency for middle school students whose favourite sport is baseball is 27%.
The relative frequency for middle school students whose favorite sport is basketball is 31%.
The relative frequency for middle school students whose favorite sport is football is 42%.
The relative frequency for high school students whose favorite sport is baseball is 44%.
The relative frequency for high school students whose favorite sport is basketball is 31%
The relative frequency for high school students whose favorite sport is football is 25%
What is relative frequency?
Relative frequency measures how often a value appears relative to the sum of the total values.
The relative frequency for middle school students whose favourite sport is baseball = 13/48 = 27%
The relative frequency for middle school students whose favorite sport is basketball = 15 / 48 = 31%
The relative frequency for middle school students whose favorite sport is football = 20 / 48 = 42%
The relative frequency for high school students whose favorite sport is baseball = 23 / 52 = 44%
The relative frequency for high school students whose favorite sport is basketball = 16 / 52 = 31%
The relative frequency for high school students whose favorite sport is football = 13 / 52 = 25%
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Benjamin is four years younger than Kevin Williams for years less than twice Benjamin’s age and William is 22 how old are Kevin and Benjamin
35 POINTS ALOT!
Describe your strategy to calculate the area of the shaded region. (5 pts)
b. Calculate the area of the shaded region. (5 pts)
Answer:
22.75 m^2
Step-by-step explanation:
Strategy: Find the area of the 2 triangles by finding the height of both of them and using the triangle formula.
Calculation:
(assuming both triangles are congruent)
7*((11-4.5)/2)/2*2
=3.25*7
=22.75
Answer:
22.75m^2
Step-by-step explanation:
A) area of rectangle - two trapezium
B) the way is given in image form and the final answer is= 77- 54.25 = 22.75m^2
Check Understanding
Shel has 11/8 pizzas to sell. How much pizza does he have? Write the mixed number
Answer:
1 3/8
Step-by-step explanation:
There 11 is greater than 8, so there is one whole pizza. 11-8=3 so there are 3 more out of those 8.
shoot me a comment if there are more questions, have a good day :)
plzzzzzzzzzzzzzzzzzzzzzzzzzzzzz help me
Answer:
248
Step-by-step explanation:
I'm not completely sure but hope this helps
Answer:
220 cm²
Step-by-step explanation:
area of rectangle:
Length * Width
18 * 11
198 cm²
Triangle area:
1/2 * base * height
1/2 * (18-7)(15-11)
1/2 * 11 * 4
22 cm²
So total area: 198 cm² + 22 cm² = 220 cm²
Question 2
Screenshot
Answer:
I think it's the second one.
2. Lawn tickets cost $30 each and seat tickets cost $50
each. The organizers want to make at least $14,000
from ticket sales.
If you know that exactly 200 seat tickets were sold,
what can you say about the number of lawn tickets?
In order to complete the target the person must have to sell 133 lawn tickets and 200 seat tickets.
What are arithmetic operations?The study of numbers and their operations, which are essential to all other branches of mathematics, falls under the umbrella of arithmetic operations. The four fundamental operations in these systems are addition, subtraction, multiplication, and division.
It is given that, tickets for the lawn cost $30 apiece, while those for seats cost $50 each. At least $14,000 is what the organizers want to make from ticket sales.
The amount earned from seat tickets,
=$50 × 200
=10000
The amount needed to complete the target,
=$14,000 - $10,000
=$4,000
If they earned $4,000 by selling lawn tickets. Since lawn tickets were $30, the formula to determine how many were sold is $4000 divided by $30.The number of lawn tickets is obtained as,
=4000/30
=133
Thus, the number of lawn tickets will be 200.
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round 5,565 to the hundreds
Answer:
5,600
Step-by-step explanation:
rounding by the nearest hundred would mean rounding up or down in the hundreds based off of thr tens. If the tens are above 50, you round up. if they are below 50, you round down
Answer:
The hundred place here is the the 2nd 5 to the left.
Rounding is when it’s 5 or above you go up, 4 or below you stay.
So 5565
In this case we look at the tenth place number which is 6 and since it’s 5 or above the hundreths place “5” goes up 1. Everything else below under th place turns 0.
So
5,600
This is a question for those of you interested in mathematics or are taking proof classes: when will you know when you are writing too much or too little in a proof? I'm taking a proof class right now, and my professor doesn't do a good job of explaining this to me and just shows/implies the right answer.
I don't think there's a set limit either way. As long as you make sure to discuss all the relevant key ideas and theorems, then you have formed a sufficient proof. Try to be as direct as possible and it doesn't hurt to take shortcuts now and then. Remember to always clearly state what the goal of the proof is, and set up the boundaries needed (eg: x is a nonzero real number). Also, make sure you connect the "given" to the thing to be proved. I've noticed a lot of students forget to do this.
If possible, try to explain the concept to someone outside the class so you can try to get a better handle on the proof. At the same time, you don't want to spend too much time going over the very fine details. Again it's all about balance in my mind.
Section 8.1 Introduction to the Laplace Transforms
Problem 6.
Prove that if
[tex]f(t)↔ F(s)[/tex]
then
[tex] {t}^{k} f(t)↔ {( - 1)}^{k} {F}^{k} (s).[/tex]
Hint: Assume that it's permissable to the differentiate the integral
[tex]F(s)={∫}^{ \infty } _{0} {e}^{ - st} f(t)dt[/tex]
with respect to s under the integral sign.
Let k = 1, for a start. By definition of the Laplace transform,
[tex]\displaystyle F(s) = \int_0^\infty f(t) e^{-st} \, dt[/tex]
Differentiate both sides with respect to s :
[tex]\displaystyle F'(s) = \frac{d}{ds} \int_0^\infty f(t) e^{-st} \, dt[/tex]
[tex]\displaystyle F'(s) = \int_0^\infty \frac{\partial}{\partial s} \left[f(t) e^{-st}\right] \, dt[/tex]
[tex]\displaystyle F'(s) = \int_0^\infty -t f(t) e^{-st} \, dt[/tex]
so that [tex]t f(t) \leftrightarrow (-1)^1 F^{(1)}(s) = -F'(s)[/tex] is indeed true.
Suppose the claim is true for arbitrary integer k = n, which is to say that [tex]t^n f(t) \leftrightarrow (-1)^n F^{(n)}(s)[/tex]. Then if k = n + 1, we have
[tex]F^{(n+1)}(s) = \dfrac{d}{ds} F^{(n)}(s)[/tex]
Consider the two cases:
• If k = n + 1 is even, then n is odd, so
[tex](-1)^n F^{(n)}(s) = -F^{(n)}(s) \leftrightarrow t^n f(t)[/tex]
and it follows that
[tex]F^{(n+1)}(s) = \displaystyle \frac{d}{ds} \left[-\int_0^\infty t^n f(t) e^{-st} \, dt \right][/tex]
[tex]F^{(n+1)}(s) = \displaystyle -\int_0^\infty \frac{\partial}{\partial s}\left[ t^n f(t) e^{-st} \right] \, dt[/tex]
[tex]F^{(n+1)}(s) = \displaystyle \frac{d}{ds} \left[-\int_0^\infty t^n f(t) e^{-st} \, dt \right][/tex]
[tex]F^{(n+1)}(s) = \displaystyle \int_0^\infty t^{n+1} f(t) e^{-st} \, dt[/tex]
[tex]\implies F^{(n+1)}(s) = (-1)^{n+1} F^{(n+1)}(s) \leftrightarrow t^{n+1}f(t)[/tex]
• Otherwise, if k = n + 1 is odd, then n is even, so
[tex](-1)^n F^{(n)}(s) = F^{(n)}(s) \leftrightarrow t^n f(t)[/tex]
The rest of the proof is the same as the previous case.
So we've proved the claim by induction:
• [tex]t f(t) \leftrightarrow -F(s)[/tex], and
• [tex]\bigg(t^n f(t) \leftrightarrow (-1)^n F^{(n)}(s)\bigg) \implies \bigg(t^{n+1} f(t) \leftrightarrow (-1)^{n+1} F^{(n+1)}(s)\bigg)[/tex]
what is the answer to this one 20x+12≥14x+30
x≤3
x≤7
x≥3
x≥7
Answer:
X≥3
Explanation:
20х+12≥14х+30
20Х+12-14Х≥30
20х-14х≥30-12
6Х≥30-12
6х≥18
х≥3
46.8 divided by 1.2 equals
Answer: 39
Step-by-step explanation: We have to move the decimal one place to the right to make 1.2 a whole number, so 12. You do the same thing to 46.8, so you get 468. Then you divide from there. 12 can go into 46 3 times. 12 x 3 = 36. you subtract to get 10, then bring down your 8, to get a new number of 108. 12 can go into 108 9 times. 12 x 9 = 108. Then you have a remainder of 0. Your product is 39.
Helpp please find the value of s! I will give brainlist
We have :
s - 39⁰+ s - 9⁰ = s + 29⁰
s + s - s = 29⁰ + 9⁰ + 39⁰
s = 77⁰
Answer: 77⁰
Ok done. Thank to me :>
Hey! can you help me with question number 2? I am really confused about it
Determine if the sequence below is arithmetic or geometric and determine the
common difference / ratio in simplest form.
12, 9, 6, ...
Answer: Arithmetic and 3
Step-by-step explanation:
12 - 9 = 3 9 - 6 = 3 The common difference is equal and is three and so it is an arithmetic sequence
12/9 = 4/3 9/6 = 3/2 The ratio is not equal so this is not a geometric sequence
Real world applications for 1 and 2-step equations
Answer:
pushing p turn me up p yea
Mrs. Moore has 91 pieces of candy to split among s students. Which expression shows how many pieces of candy each student will receive?
A. 91 - s
B. 91 × s
C. 91 ÷ s
D. 91 + s
Another way to say that someone is "splitting between" themselves and someone else is "dividing amongst" or "dividing between".
Answer:
C. 91 ÷ s
Step-by-step explanation:
Split among = ÷
Hence, the Answer = 91 ÷ s
~Lenvy~
Select the correct answer from each drop-down menu.
Martin purchased a condo below market value in 2001. He pald $92,500 for the condo even though the market value of the condo
higher. In 2014, Martin transferred to another city for work and had to sell his condo. The market value of his condo Increased ov
shown in the graph below, where the yaxis represents the market value of the condo, in dollars, and the x-axis represents the nu
since 2001.
Market Value of Martin's Condo
y
200,000
190,000
180,000
170,000
ue ($)
160,000
The linear function that represent the value of Martin condo is y = 2000x + 92500
Linear equation
A linear equation is in the form:
y = mx + b
Where y,x are variables, m is the rate of change and b is the y intercept.
Let y represent the market value of the condo after x years since 2001.
In 2001, the condo was $92500, hence b = 92500.
Let us assume the value increased by $2000 per year, hence:
The linear function that represent the value of Martin condo is y = 2000x + 92500
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100k value
5% per year
NOT!!! 2001
NOT!!!2014
Jennifer Brunner works 40 hours per week as a chef's assistant. At the rate of $7.30 per hour, what are her gross weekly earnings (in %)?
Answer:
292
Step-by-step explanation:
40 x $7.60 = 304
304=
304%
-Hunter
Ken built a square fence around his yard. He planted 4 trees on each side of the fence. What is the least number of trees Ken planted?
A. 4
B. 12
C. 19
D. 20
Answer:
12
Step-by-step explanation:
edge 1045
Calculate the probability of randomly selecting a vehicle with an engine between than 3.1 L and 4.2 L.
Using the normal distribution, it is found that there is a 0.7452 = 74.52% probability of randomly selecting a vehicle with an engine between than 3.1 L and 4.2 L.
Normal Probability DistributionIn a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.Researching the problem on the internet, it is found that:
The mean is [tex]\mu = 3.59804[/tex].The standard deviation is [tex]\sigma = 0.47986[/tex].The probability is the p-value of Z when X = 4.2 subtracted by the p-value of Z when X = 3.1, hence:
X = 4.2
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{4.2 - 3.59804}{0.47986}[/tex]
[tex]Z = 1.25[/tex]
[tex]Z = 1.25[/tex] has a p-value of 0.8944.
X = 3.1
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{3.1 - 3.59804}{0.47986}[/tex]
[tex]Z = -1.04[/tex]
[tex]Z = -1.04[/tex] has a p-value of 0.1492.
0.8944 - 0.1492 = 0.7452.
0.7452 = 74.52% probability of randomly selecting a vehicle with an engine between than 3.1 L and 4.2 L.
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Mr.kellsons storage closet is 3 ft long, 3 ft wide. and 7 ft high. Can she fit 67 that each have volume of 1 cubic foot in her closet. Explain your answer