find the range of each function:
f(x) = 2^x

[tex]f(x) = - 5 \leqslant x \leqslant 4[/tex]
please give me explaination
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The income a person must make to be in the highest income bracket $4420.09 using standard deviation

What is standard deviation?
The standard deviation is a statistician's way of gauging how much a group of numbers can vary or be dispersed. The values tend to be close to the set's mean when the standard deviation is low, while the values are dispersed over a larger range when the standard deviation is high.

As per the question,  

mean = u = $3398

standard deviation = σ = $571

Using standard normal

P(Z > z) = 3.67%

1 - P(Z < z) = 0.0367

P(Z < z) = 1 - 0.0367

P(Z < 1.79) = 0.9633

z = 1.79

Using z-score formula,

x = z * σ + u

x = 1.79 * 571 + 3398

= 4420.09

Hence the total income is  $4420.09 using standard deviation.

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The solution of m for question 6 and the value of z for question 10 does not exist.

According to the question,

We have the following information,

6) 1/3 + 2m/3 = 2m/3-2/3

Now, moving the terms with the same variables in one side:

2m/3-2m/3+1/3 = -2/3

Now, when 2m/3 is subtracted from 2m/3 then we have no variable left.

So, the solution of this equation does not exist.

10) 2.5(2z+5) = 5(z+2.5)

Now, multiplying the numbers outside the bracket into bracket:

5z+12.5 = 5z+12.5

Moving the terms with the same variables on one side:

5z-5z+12.5 = 12.5

Now, when 5z is subtracted from5z then we have no variable left.

So, the solution of this equation does not exist.

Hence, the solutions of the equation 6 and equation 10 does not exist.

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Cost of total 12 chocolate crackle is $8.875

What is multiplication and division?

Multiplication and division are two of the basic arithmetic operations . in multiplication we find the product of two numbers. And division is splitting a number in equal given part.

We are given cost of 24 chocolate crackel

The total cost comes out to be $17.75

a) To make 12 chocolate crackle we require material of exactly half cost

Which will be $8.875

b) To make 6 chocolate crackle we will require material of exactly one fourth of the cost which will be $4.435

c) To make 36 chocolate crackle we will require material of exactly one and half cost

Which will be $26.625

d) To find the cost of one chocolate we divide the cost of 24 chocolate Crackle by 24 we get the cost of 1 chocolate crackel as $0.739

e) The cost of one chocolate crackel in cents is $74 cents

Hence, Cost of total 12 chocolate crackle is $8.875

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the base-ten representation for 19! = 121,6T5,100,40M,832,000 then

H+M+T =12

19! has three 5s so it will end with three 0s.

Hence H = 0

19! = 121,6T5,100,40M,832,000 = 121,6T5,100,40M,832 * 1000

19! has many 2s. So M832 will be divisible by 16 (last 4 digits).

So M000 + 832 is divisible by 16. 832 is completely divisible by 16. Since 16*5 = 80, 8000 must be divisible by 16.

M = 8

19! = 121,6T5,100,408,832,000

Since 19! is divisible by 9, sum of all digits must be divisible by 9.

1+2+1+6+T+5+1+4+8+8+3+2 = T + 41

To make this divisible by 9, T must be 4.

H+M+T = 0 + 8 + 4 = 12

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The quotient of [tex]12\frac{3}{8}[/tex] ÷ [tex]2\frac{3}{4}[/tex] is 4 1/2.

The quotient of [tex]9\frac{2}{5}[/tex] ÷ [tex]1\frac{3}{10}[/tex] is 7 3/13

The quotient of [tex]7\frac{1}{4}[/tex] ÷ [tex]1\frac{7}{8}[/tex] is 1 13/15

The quotient of [tex]8\frac{5}{6}[/tex] ÷ [tex]2\frac{1}{4}[/tex] is3 25/27

The quotient of [tex]5\frac{4}{7}[/tex] ÷ [tex]2\frac{10}{21}[/tex] is 2 1/4

The quotient of [tex]12\frac{5}{8}[/tex] ÷ [tex]3\frac{19}{24}[/tex] is 3 30 / 91

The quotient of [tex]7\frac{5}{6}[/tex]  ÷ [tex]3\frac{1}{2}[/tex]is 2 5/21

The quotient of [tex]14\frac{2}{3}[/tex]  ÷[tex]2\frac{2}{9}[/tex]is 6 3/5

A quotient is the result of a division process. Division is the mathematical operation that is used to part a number into equal groups using another number. The sign that is used to represent division is ÷.

A mixed number is a fraction that is made up of a whole number and a proper fraction. An example of a mixed number is 1 1/2.

[tex]12\frac{3}{8}[/tex] ÷ [tex]2\frac{3}{4}[/tex]

99 / 8÷ 11/4

99 / 8 x 4/11 = 9/2 = [tex]4\frac{1}{2}[/tex]

[tex]9\frac{2}{5}[/tex] ÷ [tex]1\frac{3}{10}[/tex]

47 / 5 ÷ 13/10

47 / 5 x 10/13 = 94 / 13 = 7 3/13

[tex]7\frac{1}{4}[/tex] ÷ [tex]1\frac{7}{8}[/tex]

29 / 4 ÷ 15/8

29 / 4 x 8/15 = 58 / 15 = 1 13/15

[tex]8\frac{5}{6}[/tex] ÷ [tex]2\frac{1}{4}[/tex]

53 / 6 ÷ 9/4

53 / 6 x 4/9 = 106 / 27 = 3 25/27

[tex]5\frac{4}{7}[/tex] ÷ [tex]2\frac{10}{21}[/tex]

39 / 7  ÷ 52/21

39 / 7 x 21/52 = 117 / 52 = 2 1/4

[tex]12\frac{5}{8}[/tex] ÷ [tex]3\frac{19}{24}[/tex]

101 / 8  ÷91 / 24

101 / 8  x 24/91 = 303 / 91 = 3 30 / 91

[tex]7\frac{5}{6}[/tex]  ÷ [tex]3\frac{1}{2}[/tex]

47 / 6 ÷ 7/2

47 / 6 x 2/7 =  47 / 21 = 2 5/21

[tex]14\frac{2}{3}[/tex]  ÷[tex]2\frac{2}{9}[/tex]

44 / 3 ÷ 20/9

44 / 3 x 9/20 = 33/5 = 6 3/5

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In the given right-angled triangle, the sine, cosine, and tan of the angle A are: sin A =0.88, cos A = 0.4705, tan A= 1.875

We have a right angles triangle ABC with AC as the hypotenuse and AB and AC as the other two sides.

Given, hypotenuse AC=34, side BC = 30, side AB = 16

∴From the formulae for evaluating sin, cos, and tan of an angle

sin A[tex]=\frac{opposite}{hypotenuse}= \frac{BC}{AC}=\frac{30}{34}=\frac{15}{17}=0.88[/tex]     (1)

cos A[tex]= \frac{adjacent}{hypotenuse} =\frac{16}{34}=\frac{8}{17}=0.4705[/tex]          (2)

tan A[tex]=\frac{OppositeSide}{AdjacentSide}=\frac{30}{16}=\frac{15}{8}=1.875[/tex]           (3)

Thus sin A= 0.88, cos A= 0.4705, tan A= 1.875

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The simplest form is [tex]\frac{11}{2}[/tex] .

fraction, In arithmetic, a number expressed as a quotient, in which a numerator is divided by a denominator. In a simple fraction, both are integers. A complex fraction has a fraction in the numerator or denominator. In a proper fraction, the numerator is less than the denominator.

Given that,

−2(−1 1/4)

Multiplying the numerator with numerator and denominator with denominator. According to integer multiplication of two negative terms is always positive.

= [tex]\frac{22}{4}[/tex]

The simplest form =  [tex]\frac{11}{2}[/tex]

Hence, The simplest form is [tex]\frac{11}{2}[/tex] .

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The value of x, y, z is -18000/83, -30000/83, 297000/83 respectively.

This problem is solve by substitution method.

what is substitution method?

Substitution method is the algebraic method to solve simultaneous linear equations. As the word says, in this method, the value of one variable from one equation is substituted in the other equation.

Given,

x+y+z=3000

5x−3y=0

x−10.5y−z=0

Solve x+y+z=3000 for x.

x=−y−z+3000

Substitute −y−z+3000 for x in the second and third equation.

5(−y−z+3000)−3y=0

−y−z+3000−10.5y−z=0

Solve these equations for y and z respectively.

y=1875−5/8z

z=1500-23/4y

Substitute 1875−5/8z for y in the equation z=1500−23/4y

​z=1500−23/4(1875-5/8z)

z= 297000/83

put this value in y = 1875- 5/8z

y= -30000/83

substitute the value of y and z in equation one

x= -18000/83

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Answer:

n= 3

Step-by-step explanation:

3(n+3)= -4n+30

3n+9= -4n +30 expand

7n+9 = 30 +4n to both sides

7n = 21 -9 from both sides

n= 3 divide by 7 on both sides

The given vertices when plotted gives a parallelogram.

In Euclidean geometry, a parallelogram is a simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.

To solve this problem, we simply need to plot the vertices and check if the opposite sides are equal to each other.

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Step-by-step explanation:

the picture asks for similar things as your text but got other numbers.

let's do both.

first the picture :

find g(0) and one value of x for which g(x) = 0.

g(0) means that x = 0.

so, we find x = 0 on the x-axis (it is where the y-axis intersects) and then go straight up or down until we meet or intersect the function curve.

in our case we go up and intersect the curve at y = 2.

and that is the result.

y = g(x), it is a named variable for the function result, nothing else.

so,

y = g(0) = 2

to find a value of x for which g(x) = 0 means we go along the x-axis (these are all the points for which y = 0) until the x-axis intersects with the curve.

and that is here at x = -1.

now for your text :

we repeat the same principles.

but now, we need to use imaginary lines that go parallel to the x- and y-axis.

your text now calls the function h(x), but since I have no other information, I assume it is the same line function in the picture.

for which value of x is h(x) = -4 ?

remember, y is just the variable that stands for the function result.

so, we are asking for

y = h(x) = -4

imagine a horizontal line through y = -4.

where does it intercept the line h(x) ?

at that point we go straight up or down (in our case up) to the x-axis and read the x-value there : -3

so,

y = h(-3) = -4

to find h(1) we find x = 1 on the x-axis, and from there we go straight up or down (in our case up) parallel to the y-axis until we intersect the function curve.

from there we go straight left out right (in our case left) to the y-axis and read the y-value there : 4

so,

y = h(1) = 4

The person's average speed is 15.65 miles per minute.

The definition of the average is the mean value, which is the ratio of the sum of the values in a given set to the total number of values in the set. The mean is typically meant when the word "average" is used in a mathematical context, especially when no other context is provided. Divide the total by the quantity of numbers after averaging the numbers. (The value(s) total divided by the value(s) total).

Given Data

A person walked 2.5 miles in 45 minutes, then jogged 1.5 more miles in 20 minutes.

Speed = [tex]\frac{Distance}{Time}[/tex]

Speed while walking = 18

Speed while jogging = 13.3

Average = [tex]\frac{18 +13.3}{2}[/tex]

Average = [tex]\frac{31.3}{2}[/tex]

Average = 15.65

The person's average speed is 15.65 miles per minute.

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The equation  y + 2x = 3 best represents the relationship between x and y in the graph.

We are provided with the graph shown in question. We were supposed  to find the equation of the line shown in the graph. From this graph we can clearly see that the line is passing through ( 1.5 , 0 ) and ( 0 , 3 ).

The equation of line passing through two points is given below:

[tex](y - y_{1}) = (\frac{y_{2}-y_{1} }{x_{2}-x_{1} }) (x - x_{1} )[/tex]

As the line is passing through points  ( 1.5 , 0 ) and ( 0 , 3 ) , so we can write the above equation as

( y - 0 ) = ( ( 3 - 0 )/( 0 - 1.5 ) ) ( x - 1.5 )

y = -2 ( x - 1.5 )

y = -2x + 3

y + 2x = 3

The required equation of line is y + 2x = 3 i.e., this equation best represents the relationship between x and y in the graph.

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Answer:

Step-by-step explanation:

Answer:

Rhoda

Step-by-step explanation:

sub same values of x into both expressions. The expressions are equivalent if the values of the expressions are equal

Solving for n for n in the formula A = yn + y is expressed as: n = A/y - 1.

Solving for the formula for a variable, means we should make the variable the subject of the formula by isolating the variable to one side of the equation to determine its value.

Given the equation of the formula, A = yn + y, to solve for n, follow the steps below:

A = y(n + 1)

Divide both sides by y:

A/y = y(n + 1)/y [division property of equality]

A/y = n + 1

Subtract 1 from both sides:

A/y - 1 = n + 1 - 1 [subtraction property of equality]

A/y - 1 = n

n = A/y - 1

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It is to be noted that Option A is the most appropriate choice of origin and scale for this graph.

In mathematics, a graph is defined as a graphical representation or diagram that organizes facts or values. The graph's points frequently reflect the relationship between two or more objects.

Note that we are given the following:

Week:     2      3      4      5      6     7       8

Minutes: 300 450 600 750 900 1050 1200

The difference between two cumulative weeks is one week, while the difference between two cumulative minutes is 150.

Plotting the graph between minutes and weeks we can get the most suitable scale is

x-axis scale:  1 unit = 1 week

y-axis scale:  1 unit = 150 minutes

Assuming we extend the table to the left to reflect the origin, we'll obtain

Week     0   1      2...............8

Minutes 0   150  300..........1200

Hence, The origin ⇒ (0 weeks, 0 minutes)

From the above, therefore, the most suitable choice of origin and scale is:

x-axis scale: 1 unit = 1 week

y-axis scale: 1 unit = 150 minutes

origin:          (0 weeks, 0 minutes)

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The scale on the x-axis should be 1 unit equal to 1 week and the scale on the y- axis should be 1 unit = 150 minutes. Option A is correct.

The graph is a demonstration of curves that gives the relationship between the x and y-axis.

Here,
As observing the data, the data mentioned in the table is represents the linear relationship.
Slope of the function = 450 - 300 / 3 - 2 = 150
This implies that for 1 week there is 150 minutes on the graph of the relationship,

Thus, the scale on the x-axis should be 1 unit equal to 1 week and the scale on the y- axis should be 1 unit = 150 minutes.

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The likelihood or probability that the population mean evidence-based reading and writing test score of 533 will be within 10 points of the sample mean test score provided by a sample of 49 test takers is 0.274.

From the given information, we have:

The population mean, μ = 533

The sample size, n = 49

The population standard deviation, σ = 100

The standard deviation for X  is:

= 100/√49 = 14.2857142857

Normal distribution with mean 533 and SD of 12.3091

P( 523 <x< 543 )

Z = 10 ÷ 14.2857142857

Z = 0.7, - 0.7

P( z < 0.7 ) - P( z < - 0.7 )

= 0.75804 - 0.48393

= 0.27411

The required probability is 0.274.

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The complete question is mentioned below:

A certain organization reported the following scores for two parts of the scholastic Aptitude test ( SAT)

Evidence-based Reading and writing: 533

Mathematics  : 527

Assume the population standard deviation for each part is σ = 100.

What is the probability a sample of 49 test takers will provide a sample mean test score within 10 points of the population mean of 533 on the Evidence-based Reading and Writing part of the test?

Answer:

He is expected to pay $2.73

Explanation:

We can solve this, by adding 0.39 7 times:

Thus, 7 pound of bananas cost $2.73

By working with the given mixed numbers, we will get that for the project they need (4 + 1/4) yards of metal.

At this point, we have two pieces that measures (1 + 1/6) yd and (3/12) yd, adding that length we get a total length:

L = (1 + 1/6) yd + (3/12) yd = (1 + 2/12) yd + 3/12yd = (1 + 5/12) yd

Now we know that we need 3 times that amount of metal for the project, then the total amount of metal that we need is:

3*L = 3*(1 + 5/12) yd = (3 + 15/12) yd

We can write this as a mixed number as:

(3 + 12/12yd + 3/12yd) = (4 + 3/12)yd = (4 + 1/4) yd

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The point slope equation of the line that passes through the points (-4,8) and (4,4) is x + 2y = 12   .

The point slope form of the line passing through the points (x₁,y₁) having slope as m is given by the formula .

y-y₁ = m(x-x₁)

In the question ,

it is given that

the required line passes through the points (-4,8) and (4,4) ,

So , the slope(m) is = (4-8)/(4-(-4)

= -4/8

= -1/2

the equation of the line passing through (4,4) and slope as -1/2 in the point slope form is

(y-4) = -1/2(x-4)

y - 4 = (-x + 4)/2

2y-8 = -x + 4

x + 2y = 12

Therefore , The point slope equation of the line that passes through the points (-4,8) and (4,4) is x + 2y = 12    .

The given question is incomplete , the complete question is

Write the point slope equation of the line that passes through the points (-4,8) and (4,4) .

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Answer:

y - 4 = -1/2 (x-4)

Step-by-step explanation:

thats the answer on khan

Answer:

Tori studies 4 subjects (including Chemistry)

Answer:

3.5

Step-by-step explanation:

find the ratio between any two corresponding sides. for example : 1.4/2 = 0.7

this should be the same number for all sides

thus 5 * 0.7 = 3.5

Answer:

23456892245u

Step-by-step explanation:

Allah sh all will am am well ram chirac flow

Answer: x = -2     y = 2

Step-by-step explanation:

There are different ways to solve systems of equations. I will set them equal to each other.

First, I have to divide 2 from both sides of the first equation, which gives

y = -4x - 6

Now I can set them equal to each other and solve for x.

-4x - 6 = 2x^2 + 4 x + 2

0 = 2x^2 + 8x + 8

Now we factor it. If you cannot see the factors right away, you can use the quadratic formula, but I see that

(2x+4)(x+2) = 2x^2 + 8x + 8 = 0

so, because (2x+4)(x+2) = 0, one (or both) of the parenthesis must equal zero.

Solve for each parenthesis.

2x+4=0  =>   2x = -4  =>   x = -2

x+2=0  =>   x = -2

As we see here, there is only one value for x. Now we can plug it into either one of the original equations. I'll do the first since there are no squares.

2y = -8(-2) -12

2y = 16 - 12

2y = 4

y = 2

Sum expressions are true and some are false.

What does a math expression mean?

a) Calculate the sum or difference =   15. 02

Check equivalency =  True

Answer: True

b)Calculate the sum or difference = 15.02

Check equivalency = False

Answer: False

c)

Calculate the sum or difference = 15.02

Check equivalency =True

Answer: True

d)

Calculate the sum or difference = 3.02+12

Calculate the sum or difference = 15.02

Check equivalency: True

Answer: True

e)

Calculate the sum or difference = 1.5 + 13.8

Calculate the sum or difference = 15.3

Check equivalency: False

Answer: False

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Answer:

v = 9

Step-by-step explanation:

2(3v + 8)  = 70  Distribute the 2

2(3v) + 2(8) = 70

6v + 16 = 70  Subtract 16 from both sides

6v = 54  Divide both sides by 6

v = 9

============================================================

Explanation:

m = 1 is the given slope

(x1,y1) = (6,-2) and (x2,y2) = (h,-3) are the two points on a line of slope 1.

Let's use the slope formula to find h

[tex](x_1,y_1) = (6,-2) \text{ and } (x_2,y_2) = (h,-3)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\1 = \frac{-3 - (-2)}{h - 6}\\\\1 = \frac{-3 + 2}{h - 6}\\\\1 = \frac{-1}{h-6}\\\\1(h-6) = -1\\\\h-6 = -1\\\\h = -1+6\\\\h = 5[/tex]

------------------

The point (h,-3) updates to (5,-3).

The slope of the line through (6,-2) and (5,-3) is 1.

Use the slope formula to confirm this.

[tex](x_1,y_1) = (6,-2) \text{ and } (x_2,y_2) = (5,-3)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-3 - (-2)}{5 - 6}\\\\m = \frac{-3 + 2}{5 - 6}\\\\m = \frac{-1}{-1}\\\\m = 1\\\\[/tex]

The answer is confirmed.

Answer:

We're given a least-squares regression equation that we can use to predict weight (in kilograms) from a given length (in centimeters). The question asks to predict the weight of a fish that is 70cm long, so let's plug in 70 for "length" and solve for the predicted weight: logweight = 3.08  (log length) -5.07

(logweight) 3.08 (log 70) - 5.07

(logweight) ≈ 3.08 (1.84) - 5.07

log weight ≈ 0.613

Next, we use the fact that these are base 10 logarithms and the definition of a logarithm to solve for the predicted weight:

log₁₀ (weight) ≈ 0.613

Taking logarithms on both sides

weight ≈ 10₀.₆₁₃

weight ≈ 4.1

According to this model, the predicted weight for a 70 cm long Florida bass is about 4.1kg.

​