Answer:
$7.25 + $4.25 + 6.00 = $17.50
Step-by-step explanation:
7.25 + 4.25= 11.50 + 6.00= 17.50
The perimeter of a regular octagon is 96 mm. How long each side?
Answer:
12
Step-by-step explanation:
regular implies that all sides are equal
8 sides
total of 96
96/8
12
which systems have infinite solution? check all that apply
A. y = 0.5x + 2.75 and 2y = x + 2.75
B. y = 0.5x + 2.75 and y - 0.5x = 2.75
C. y = 0.5x + 2.75 and 0.5x + y = 2.75
D. y = 0.5x + 2.75 and y = 0.5(x + 5.5)
E. y = 0.5x + 2.75 and y = -2(-0.25x) + 2.75
Answer:
B
Step-by-step explanation:
Answer:
Ok got it
Step-by-step explanation:
the answers are y = 0.5x + 2.75 and y – 0.5x = 2.75
y = 0.5x + 2.75 and y = 0.5(x + 5.5)
y = 0.5x + 2.75 and y = –2(–0.25x )+ 2.75
There are 380 light bulbs lined up in a row in a long room.
Each bulb has its own switch and is currently switched off.
Each bulb is numbered consecutively from 1 to 380. You
first flip every switch. You then flip the switch on every
second bulb(turning off 2, 4,6...). You then flip the switch
on every third bulb (3, 6, 9...). This continues until you
have gone through the process 380 times.
Bulb 2 was activated 760 times throughout the process.
How to calculate how many times light bulb #2 was activated?To calculate how many times light bulb #2 was activated, we must identify how many times it is activated in each process.
Based on the information provided, bulb two has the following activity.
Power on oncePower off onceAccording to the above, bulb #2 is activated 2 times each process. So to know how many times it is activated in total, we must multiply the number of times it is activated in each process by the total number of processes (380).
380 × 2 = 760
Note: This question is incomplete because the question is missing. Here is the question:
After repeating this process 380 times, how many times was light bulb 2 activated?Learn more about light bubs in: https://brainly.com/question/4723473
find the smallest possible value of n for which 99n is multiple of 24
Answer:
99 is not multiple of 24 you will get it wrong if you think it is
Step-by-step explanation:
Answer:
The answer is 8.
Jeff is buying books at a used bookstore he wants to approximate the total cost of his purchase before checking out which amount is the most reasonable approximation of the total price of the five books
Answer:
$35.00
Step-by-step explanation:
I just did it rn
Rajeev started to move from point A towards point B exactly an hour after Rohit started from B in the opposite direction but at a speed twice as much as that of rohit.By the time rohit covers ⅙ of the distance between the point B and A Rajeev also covers the same distance.
Speed is the rate of change of distance over time
It takes Rohit 2 hours to cover the same distance
How to determine the timeRepresent Rajeev with A, and Rohit with B
Speed is calculated as:
[tex]Speed = \frac{Distance}{Time}[/tex]
Rohit covers 1/6 of the distance between point AB
So, we have:
[tex]S_B = \frac{AB/6}{T_B}[/tex]
Make T the subject
[tex]T_B = \frac{AB/6}{S_B}[/tex]
[tex]T_B = \frac{AB}{6S_B}[/tex]
Rajeev's speed is twice that of Rohit.
So, we have:
[tex]S_A = 2 * S_B[/tex]
[tex]S_A = \frac{AB}{T_A}[/tex]
So, the time taken by Rajiv to cover 1/6 of the distance is:
[tex]T_A = \frac{AB}{12S_B}[/tex]
The difference between the time is given as 1.
So, we have:
[tex]\frac{AB}{6S_B} - \frac{AB}{12S_B} = 1[/tex]
Multiply through by 12SB
[tex]2AB - AB = 12S_B[/tex]
[tex]AB = 12S_B[/tex]
Recall that:
[tex]T_B = \frac{AB}{6S_B}[/tex]
So, we have:
[tex]T_B =\frac{12S_B}{6S_B}[/tex]
[tex]T_B = 2[/tex]
Hence, it takes Rohit 2 hours to cover the same distance
Read more about speed at:
https://brainly.com/question/4931057
Section 8.1 Introduction to the Laplace Transforms
Problem 1.
Find the Laplace transforms of the following functions by evaluating the integral
[tex]F(s) = {∫}^{ \infty } _{0} {e}^{ - st} f(t)dt[/tex]
[tex](a)t[/tex]
[tex](b) {te}^{ - t} [/tex]
[tex](c) {sinh} \: bt[/tex]
[tex](d) {e}^{2t} - {3e}^{t} [/tex]
[tex](e) {t}^{2} [/tex]
For the integrals in (a), (b), and (e), you'll end up integrating by parts.
(a)
[tex]\displaystyle \int_0^\infty t e^{-st} \, dt[/tex]
Let
[tex]u = t \implies du = dt[/tex]
[tex]dv = e^{-st} \, dt \implies v = -\dfrac1s e^{-st}[/tex]
Then
[tex]\displaystyle \int_0^\infty t e^{-st} \, dt = uv\bigg|_{t=0}^{t\to\infty} - \int_0^\infty v\, du[/tex]
[tex]\displaystyle \int_0^\infty t e^{-st} \, dt = \left(-\frac1s te^{-st}\right)\bigg|_0^\infty + \frac1s \int_0^\infty e^{-st} \, dt[/tex]
[tex]\displaystyle \int_0^\infty t e^{-st} \, dt = -\frac1s \left(\lim_{t\to\infty} te^{-st} - 0\right) + \frac1s \int_0^\infty e^{-st} \, dt[/tex]
[tex]\displaystyle \int_0^\infty t e^{-st} \, dt = \frac1s \int_0^\infty e^{-st} \, dt[/tex]
[tex]\displaystyle \int_0^\infty t e^{-st} \, dt = -\frac1{s^2} e^{-st} \bigg|_0^\infty e^{-st} \, dt[/tex]
[tex]\displaystyle \int_0^\infty t e^{-st} \, dt = -\frac1{s^2} \left(\lim_{t\to\infty}e^{-st} - 1\right) = \boxed{\frac1{s^2}}[/tex]
(b)
[tex]\displaystyle \int_0^\infty t e^{-t} e^{-st} \, dt = \int_0^\infty t e^{-(s+1)t} \, dt[/tex]
Let
[tex]u = t \implies du = dt[/tex]
[tex]dv = e^{-(s+1)t} \, dt \implies v = -\dfrac1{s+1} e^{-(s+1)}t[/tex]
Then
[tex]\displaystyle \int_0^\infty t e^{-(s+1)t} \, dt = -\dfrac1{s+1} te^{-(s+1)t} \bigg|_0^\infty + \frac1{s+1} \int_0^\infty e^{-(s+1)t} \, dt[/tex]
[tex]\displaystyle \int_0^\infty t e^{-(s+1)t} \, dt = -\dfrac1{s+1} \left(\lim_{t\to\infty}te^{-(s+1)t} - 0\right) + \frac1{s+1} \int_0^\infty e^{-(s+1)t} \, dt[/tex]
[tex]\displaystyle \int_0^\infty t e^{-(s+1)t} \, dt = \frac1{s+1} \int_0^\infty e^{-(s+1)t} \, dt[/tex]
[tex]\displaystyle \int_0^\infty t e^{-(s+1)t} \, dt = -\frac1{(s+1)^2} e^{-(s+1)t} \bigg|_0^\infty[/tex]
[tex]\displaystyle \int_0^\infty t e^{-(s+1)t} \, dt = -\frac1{(s+1)^2} \left(\lim_{t\to\infty}e^{-(s+1)t} - 1\right) = \boxed{\frac1{(s+1)^2}}[/tex]
(e)
[tex]\displaystyle \int_0^\infty t^2 e^{-st} \, dt[/tex]
Let
[tex]u = t^2 \implies du = 2t \, dt[/tex]
[tex]dv = e^{-st} \, dt \implies v = -\dfrac1s e^{-st}[/tex]
Then
[tex]\displaystyle \int_0^\infty t^2 e^{-st} \, dt = -\frac1s t^2 e^{-st} \bigg|_0^\infty + \frac2s \int_0^\infty t e^{-st} \, dt[/tex]
[tex]\displaystyle \int_0^\infty t^2 e^{-st} \, dt = -\frac1s \left(\lim_{t\to\infty} t^2 e^{-st} - 0\right) + \frac2s \int_0^\infty t e^{-st} \, dt[/tex]
[tex]\displaystyle \int_0^\infty t^2 e^{-st} \, dt = \frac2s \int_0^\infty t e^{-st} \, dt[/tex]
The remaining integral is the transform we found in (a), so
[tex]\displaystyle \int_0^\infty t^2 e^{-st} \, dt = \frac2s \times \frac1{s^2} = \boxed{\frac2{s^3}}[/tex]
Computing the integrals in (c) and (d) is much more immediate.
(c)
[tex]\displaystyle \int_0^\infty \sinh(bt) e^{-st} \, dt = \int_0^\infty \frac{e^{bt}-e^{-bt}}2 \times e^{-st} \, dt[/tex]
[tex]\displaystyle \int_0^\infty \sinh(bt) e^{-st} \, dt = \frac12 \int_0^\infty \left(e^{(b-s)t} - e^{(b+s)t}\right) \, dt[/tex]
[tex]\displaystyle \int_0^\infty \sinh(bt) e^{-st} \, dt = \frac12 \left(\frac1{b-s} e^{(b-s)t} - \frac1{b+s} e^{(b+s)t}\right) \bigg|_0^\infty[/tex]
[tex]\displaystyle \int_0^\infty \sinh(bt) e^{-st} \, dt = \frac12 \left[\lim_{t\to\infty}\left(\frac1{b-s} e^{(b-s)t} - \frac1{b+s} e^{(b+s)t}\right) - \left(\frac1{b-s} - \frac1{b+s}\right)\right][/tex]
[tex]\displaystyle \int_0^\infty \sinh(bt) e^{-st} \, dt = \frac12 \left(\frac1{b+s} - \frac1{b-s}\right) = \boxed{\frac{s}{s^2-b^2}}[/tex]
(d)
[tex]\displaystyle \int_0^\infty (e^{2t} - 3e^t) e^{-st} \, dt = \int_0^\infty \left(e^{(2-s)t} - 3e^{(1-s)t}\right) \, dt[/tex]
[tex]\displaystyle \int_0^\infty (e^{2t} - 3e^t) e^{-st} \, dt = \left( \frac1{2-s} e^{(2-s)t} - \frac3{1-s} e^{(1-s)t} \right) \bigg|_0^\infty[/tex]
[tex]\displaystyle \int_0^\infty (e^{2t} - 3e^t) e^{-st} \, dt = \lim_{t\to\infty} \left( \frac1{2-s} e^{(2-s)t} - \frac3{1-s} e^{(1-s)t} \right) - \left( \frac1{2-s} - \frac3{1-s} \right)[/tex]
[tex]\displaystyle \int_0^\infty (e^{2t} - 3e^t) e^{-st} \, dt = \frac3{1-s} - \frac1{2-s} = \boxed{-\frac{2s-5}{s^2-3s+2}}[/tex]
Does anyone know the answer to this question?
Answer:
4
Step-by-step explanation:
You can set up the equation as 5x-3=2x+9. Subtract 2x from both sides, then add three to both sides which gives you 3x=12. Divide both sides by 3, and you get x=4.
The radius of a circle is 4 inches. How would you calculate the circumference?
A. π · 4² in.²
B. 2 · π· 4 in.
C. π · 8² in.²
D. 2· π · 8 in.
Step-by-step explanation:
the formula for the circumference of a circle is
2×pi×r
so, B is correct : 2×pi×4 in
help plssssssssssssssssss
Answer:
35x + 14
Step-by-step explanation:
multiply in the brackets
5x × 7 = 35x
(+)2 × 7 = (+)14
PLEASE HELP ASAP! I am so confused by this for some reason.
=====================================================
Explanation:
You can use your calculator to make short work of this problem. Simply plot the parabola and use the "minimum" feature on the calculator to spot the lowest point (specifically the coordinates of that point).
However, I have a feeling your teacher wants you to use a bit of math here. So I'll focus on another approach instead.
---------
The parabolic equation is of the form y = ax^2+bx+c
In this case, we have
a = 0.3b = -192c = 40357Use the values of 'a' and b to find the x coordinate of the vertex h
h = -b/(2a)
h = -(-192)/(2*0.3)
h = 320
The x coordinate of the vertex is 320.
Plug this into the original equation to find the y coordinate of the vertex.
y = 0.3x^2 - 192x + 40357
y = 0.3(320)^2 - 192(320) + 40357
y = 9637 which is the minimum unit cost, in dollars.
The vertex is (h,k) = (320, 9637). It is the lowest point on this parabola.
Interpretation: If the company made 320 cars, then the unit cost (aka cost per car) is the smallest at $9637 per car.
7x - 5y = -24
-9x + 5y = 18
Answer:
Nothing further can be done with this topic. Please check the expression entered or try another topic.
7x−5y=−24−9x+5y=187x-5y=-24-9x+5y=18
Answer:
Assuming this is a system of equations...
Point form > (3, 9)
Equation form > x = 3, y = 9
Step-by-step explanation:
So we need to solve for x in 7x - 5y = -24
Add 5y to both sides
7x = -24 + 5y
-9x + 5y = 18
Divide each term by 7
7x/7 = -24/7 + 4y/7
-9x + 5y = 18
x = -24/7 + 5y/7
-9x + 5y = 18
Now we need to replace all occurences of x with -24/7 + 5y/7
-9(-24/7 + 5y/7) + 5y = 18
x = -24/7 + 5y/7
So lets focus on simplifying -9(-24/7 + 5y/7) + 5y
Apply the distributive property
-9(-24/7) - 9 5y/7 + 5y = 18
Now multiply -9(-24/7)
So -1 by -9
9(24/7) - 9 5y/7 + 5y = 18
Combine 9 and 24/7
9 * 24/7 - 9 5y/7 + 5y = 18
Then Multiply 9 by 24
216/7 - 9 5y/7 + 5y = 18
Now we multiply -9 5y/7
So Combine -9 and 5y/7
216/7 + -9(5y)/7 + 5y = 18
Now Multiply 5 by -9
216/7 + -45y/7 + 5y = 18
Move the negative
216/7 - 45y/7 + 5y = 18
Now we need to multiply by 7/7 to make 5y a fraction with a common denom.
216/7 - 45y/7 + 5y * 7/7 = 18
Combine
216/7 + -45y + 5y * 7/7 = 18
Combine further
216 - 45y + 5y * 7/7 = 18
Multiply
216 - 45y + 35y
Add
216 - 10y/7 = 18
Factor 2 out of the equation
2(108) - 10y/7 = 18
Factor more
2(108) + 2(-5y)/7 = 18
Factor further
2(108 - 5y)/7 = 18
Now we want to solve for y in 2(108 - 5y)/7 = 18
Multiply both sides by 7 then simplify.
2(108 - 5y) * 7/7 = 18 * 7
2 * 108 + 2 (-5y) = 18 * 7
Multiply
216 + 2 (-5y) = 18 * 7
Multiply again
216 - 10y = 18 * 7
Reorder 216 and -10y
-10y + 216 = 18 * 7
Simplify the right side
-10y + 216 = 126
Now we need to solve for y
So lets move all terms not containing y to the right side.
-10y = 126 - 216 (Subtract 216 from both sides)
-10y = -90
Divide each term by -10
-10y/-10 = -90/-10
Simplify the left side
-90/10
And the right side
y = 9
x = -24/7 + 5y/7
Now replace y with 9
-24/7 + 5(9)/7
Simplify the right side
-24 + 5(9)/7
Multiply
-24 + 45
Add
21/7
x = 3
Therefore x = 3, y = 9 > (3, 9)
Consider five circles with radii of 1, 2, 4, 8, and 16 inches.
a. Complete the table.
b. Compare the areas and circumferences. What happens to the circumference of a circle when you double the radius? What happens to the area?
c. What happens when you triple the radius?
Please answer all questions or just the table, because I need help. Thanx!
Answer:
a) 2. 4pi (in) , 4pi
3. 8pi , 16pi
4. 16pi, 64pi
5. 32 pi , 256pi
Step-by-step explanation:
b) when radius increase , the areas and circumferences increase to
circumference = 2 pi * radius ; so if you double the radius , circumference will be double
area = pi * radius * radius ; if you double the radius , area will be 2^2 or 4 times
c) circumference will be triple and
area will be 3^2 or 9 times
4) In addition to using graphs, you should also be able to use a table to determine values in an equation. Fill in the following table based on your equation in question three defined the cost for these amount of loaves of bread that you buy.
(Equation is question 3 is y=1.60x+0)
5) where would you break even? In other words, how many loaves of bread would you need to buy where it would be the same cost to make those loaves of bread yourself? Look for the intersection of the two equations when you graph them on desmos.
How much would it cost to buy that many loaves of bread?
6) Give three advantages and three disadvantages to buying a bread maker. Would you choose to buy the bread maker or not? How did you make your decision?
It would take 125 loaves at a cost of $200 for the breadmaker and store bought bread to cost the same.
Linear equationA linear equation is in the form:
y = mx + b
where y, x are variables, m is the rate of change and b is the y intercept.
Let x represent the rate of cost of one loaf and y represent the total cost, hence:
y = 0.8x + 100
The rate of cost of one loaf is $0.8 and the start up cost is $100.
For the second bread it is given by:
y = 1.6x
For both cost to be the same:
1.6x = 0.8x + 100
x = 125
a = 1.6(4) = $6.4
b = 1.6(8) = $12.8
c = 1.6(12) = $19.2
It would take 125 loaves at a cost of $200 for the breadmaker and store bought bread to cost the same.
Find out more on Linear equation at: https://brainly.com/question/13763238
Is anybody able to help me with this?
Answer:
Step-by-step explanation:
Using the net below, find the surface area
of the rectangular prism.
7 cm
3 cm
7 cm
5 cm
5 cm
3 cm
3 cm
3 cm
Surface Area
Answer:
the surface area of the rectangular prism is 142cm³
Step-by-step explanation:
35+15+21+21+35+15
How can you use
ratios to determine if a
relationship is
proportional?
Proportions are corresponding assuming they address a similar relationship. One method for checking whether two proportions are corresponding is to keep in touch with them as divisions and afterward decrease them. Assuming the decreased divisions are something similar, your proportions are relative.
Answer:
Ratios are proportional if they represent the same relationship. One way to see if two ratios are proportional is to write them as fractions and then reduce them. If the reduced fractions are the same, your ratios are proportional.
Step-by-step explanation:
What is the value of triangle?
Answer:
the area of the triangle is 36
Help with math?Please? ANYONE
Answer:
(-1, 1)
Step-by-step explanation:
Hi there!
We want to solve the system of equations given as:
2x-3y=-5
3x+y=-2
Let's solve this equation by substitution, where we will set one variable equal to an expression containing the other variable, substitute the expression as the variable that it equals, solve for the other variable (the variable that the expression contains), and then use the value of the solved variable to find the value of the first variable
In the second equation, we have y by itself; therefore, if we subtract 3x from both sides, then we will get an expression that y is equal to.
So subtract 3x from both sides
y=-3x-2
Now substitute -3x-2 as y in the first equation.
It will look something like this:
2x - 3(-3x-2)=-5
Now do the distributive property.
2x+9x+6=-5
Combine like terms
11x+6=-5
Subtract 6 from both sides
11x=-11
Divide both sides by 11
x=-1
Now substitute -1 as x in the equation y=-3x-2 to solve for y:
y=-3(-1)-2
multiply
y=3-2
Subtract
y=1
The answer is x=-1, y=1; this can also be written as an ordered pair, which would be (-1, 1)
Hope this helps!
If you would like to see another problem for additional practice, take a look here: https://brainly.com/question/19212538
[tex]\begin{cases} 2x-3y=-5\\ 3x+y=-2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 2x-3y=-5\implies 2x=3y-5\implies x=\cfrac{3y-5}{2} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting on the 2nd equation}}{3\left( \cfrac{3y-5}{2} \right)+y=-2}\implies \cfrac{3(3y-5)}{2}+y=-2 \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( \cfrac{3(3y-5)}{2}+y \right)}=2(-2)\implies 3(3y-5)+2y=-4 \\\\\\ 9y-15+2y=-4\implies 11y-15=-4\implies 11y=11[/tex]
[tex]y=\cfrac{11}{11}\implies \blacktriangleright y=1 \blacktriangleleft \\\\\\ \stackrel{\textit{since we know that}}{x=\cfrac{3y-5}{2}}\implies x=\cfrac{3(1)-5}{2}\implies x=\cfrac{-2}{2}\implies \blacktriangleright x=-1 \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (-1~~,~~1)~\hfill[/tex]
9. Suppose you are comparing frequency data for two different
groups, 25 managers and 150 blue collar workers. Why would a
relative frequency distribution be better than a frequency
distribution?
ents
Answer:
A relative frequency distribution is better for comparison between groups whose numbers are different, since ratios are readily comparable.
Step-by-step explanation:
(1−x21)5)=?
can someone help me
Answer:
answer is 105 hope u like it
Calculus AB Homework, does anyone know how to do this...
(a) f(x) is continuous at x = 1 if the limits of f(x) from either side of x = 1 both exist and are equal:
[tex]\displaystyle \lim_{x\to1^-}f(x) = \lim_{x\to1} (2x-x^2) = 1[/tex]
[tex]\displaystyle \lim_{x\to1^+}f(x) = \lim_{x\to1} (x^2+kx+p) = 1 + k + p[/tex]
So we must have 1 + k + p = 1, or k + p = 0.
f(x) is differentiable at x = 1 if the derivative at x = 1 exists; in order for the derivative to exist, the following one-sided limits must also exist and be equal:
[tex]\displaystyle \lim_{x\to1^-}f'(x) = \lim_{x\to1^+}f'(x)[/tex]
Note that the derivative of each piece computed here only exists on the given open-ended domain - we don't know for sure that the derivative *does* exist at x = 1 just yet:
[tex]f(x) = \begin{cases}2x-x^2 & \text{for }x\le1 \\ x^2+kx+p & \text{for }x>1\end{cases} \implies f'(x) = \begin{cases}2 - 2x & \text{for }x < 1 \\ ? & \text{for }x = 1 \\ 2x + k & \text{for }x > 1 \end{cases}[/tex]
Compute the one-sided limits of f '(x) :
[tex]\displaystyle \lim_{x\to1^-}f'(x) = \lim_{x\to1} (2 - 2x) = 0[/tex]
[tex]\displaystyle \lim_{x\to1^+}f'(x) = \lim_{x\to1} (2x+k) = 2 + k[/tex]
So if f '(1) exists, we must have 2 + k = 0, or k = -2, which in turn means p = 2, and these values tell us that we have f '(1) = 0.
(b) Find the critical points of f(x), where its derivative vanishes. We know that f '(1) = 0. To assess whether this is a turning point of f(x), we check the sign of f '(x) to the left and right of x = 1.
• When e.g. x = 0, we have f '(0) = 2 - 2•0 = 2 > 0
• When e.g. x = 2, we have f '(2) = 2•2 - 2 = 2 > 0
The sign of f '(x) doesn't change as we pass over x = 1, so this critical point is not a turning point. However, since f '(x) is positive to the left and right of x = 1, this means that f(x) is increasing on (-∞, 1) and (1, ∞).
(c) The graph of f(x) has possible inflection points wherever f ''(x) = 0 or is non-existent. Differentiating f '(x), we get
[tex]f'(x) = \begin{cases}2-2x & \text{for }x<1 \\ 0 & \text{for }x=1 \\ 2x+k & \text{for }x>1\end{cases} \implies f''(x) = \begin{cases}- 2 & \text{for }x < 1 \\ ? & \text{for }x = 1 \\ 2 & \text{for }x > 1 \end{cases}[/tex]
Clearly f ''(x) ≠ 0 if x < 1 or if x > 1.
It is also impossible to choose a value of f ''(1) that makes f ''(x) continuous, or equivalently that makes f(x) twice-differentiable. In short, f ''(1) does not exist, so we have a single potential inflection point at x = 1.
From the above, we know that f ''(x) < 0 for x < 1, and f ''(x) > 0 for x > 1. This indicates a change in the concavity of f(x), which means x = 1 is the only inflection point.
Find the difference between 3x+5 and 10x-4.
Answer:
7x+9
Step-by-step explanation:
10x- 3x=7x
5--4=9
so you just bring them together so 7x+9
what is the wavelength of a wave that has a frequency of 15 Hz and a speed of 2 m/s?
Wavelength=speed/frequency
=2/15
=0.1333 m
PLEASE HELP I'LL DO ANYTHING
Simplify the expression
1/5 (5x + 9) + 4/5 (1 - 9x)
Step-by-step explanation:
Use the Distributive Property:
[tex]1/5(5x+9)+4/5(1-9x)[/tex]
[tex]x+1.8+4/5-7.2x[/tex]
Combine Like-Terms:
[tex]-6.2x+2.6[/tex]
It takes Jada 20 minutes to walk to school. It takes Andre 80 percentage as long to walk to school.How long does it take Andre to walk to school?
Answer:
16 minutes
Step-by-step explanation:
multiply 20 by 80% (20 times .80)
HELP PLS - ITS DUE TMR
6.Name two streets that intersect.
7.Name two streets that are parallel
Answer:
6.Elm and Oak intersect
7.Birch and Maple are parallel
Step-by-step explanation:
If Elm and Oak continue, they will intersect with each other
Birch and Maple have same distance consistently between them
Find the area and circumference of this circle. Write your answer correct to the nearest hundredth
Answer:
Step-by-step explanation:
So we have that the diameter is 30, meaning the radius is 15.
Area: [tex]A=\pi r^{2}=\pi \cdot 15^{2}=225\pi \approx 706.86[/tex]
Circumference: [tex]C=2\pi r=2\pi \cdot 15 = 30\pi \approx 94.25[/tex]
express 7 1/2% to fraction
Answer:
15/2 is the answer to the question
Answer:
15/2
Step-by-step explanation: