Find the points at which the following surface has horizontal tangent planes z= sin 3x cos y in the region -π - π Choose the correct answer below. A. Points with x = 0, ±π and y = ±π/6, ±π/2, ±5π/6 or points with x = ±π/2 and y= 0, ±π/3, ± 2π/3, ±π.
B. Points with x= ±π/6, ±π/2, ±5π/6 and y = 0, ±π or points win x= 0, ±π/3, ±2π/3, ±π and y= ±π/2 C. Points with x= ±π/6, ±π/2, ±5π/6 and y= ±π/2 or points with x=0, ±π/3, ±2π/3, ±π and y=0, ±π
D. There are no points at which the surface has horizontal tangent planes.

The complete equation of each line for the given problem will be:

1. Perpendicular line:[tex]y = -1/2x + 1[/tex], 2. Parallel line:[tex]y = x + 2[/tex],

3. Perpendicular line: [tex]y = -x + 4[/tex], 4. Parallel line: [tex]y = -x + 4[/tex]

A line equation's slope-intercept form is provided by:

[tex]$y = mx + b$[/tex]

where b stands for the y-intercept, which is the y-coordinate of the point where the line crosses the y-axis, and m stands for the line's slope.

Alternatively, for the point-slope form of a line equation, it is given by:

[tex]$y - y_1 = m(x - x_1)$[/tex]

where, m represents the slope of the line, and  [tex](x_{1} , y_{1} )[/tex]represents a point on the line. When the slope of the line and a point on the line are known, this form is helpful..

1. Line  [tex]y=2x-7[/tex], has a slope of 2 (the coefficient of x), a line perpendicular to it will have a slope that is the opposite reciprocal of 2, which is [tex]-1/2[/tex], [tex](x_{1} , y_{1} )=(4,-1)[/tex]

Using, [tex]$y - y_1 = m(x - x_1)$[/tex]

[tex]y - (-1) = -1/2(x - 4)[/tex]

[tex]y + 1 = -1/2x + 2[/tex]

2. Line, [tex]y=x[/tex], has a slope of 1, a line parallel to it will have the same slope of 1, [tex](x_{1} , y_{1} )= (2,4)[/tex]

[tex]y - 4 = 1(x - 2)\\y - 4 = x - 2\\y = x + 2[/tex]

3. Line, [tex]y=x[/tex], has a slope of 1, a line perpendicular to it will have a slope that is the opposite reciprocal of 1, which is -1, [tex](x_{1} , y_{1} )= (2,2)[/tex]

[tex]y - 2 = -1(x - 2)\\y - 2 = -x + 2\\y = -x + 4[/tex]

4. Line,[tex]y=-x+10[/tex], has a slope of -1 (the coefficient of x), a line parallel to it will have the same slope of -1, [tex](x_{1} , y_{1} )= (-1,5)[/tex]

[tex]y - 5 = -1(x - (-1))\\y - 5 = -x - 1\\y = -x + 4[/tex]

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The series is given by ∑(14n(n+1)42^n) from n=1 to infinity is divergent.

The ratio test is a method used to determine whether an infinite series is convergent or divergent. To use the ratio test for determining the convergence or divergence of the given series, follow these steps:

1. Identify the general term: Here, the series is given by ∑(14n(n+1)42^n) from n=1 to infinity.

2. Calculate the ratio of consecutive terms: Find the limit as n approaches infinity of the absolute value of the ratio a_(n+1)/a_n, where a_n is the general term of the series.

  a_(n+1) = 14(n+1)((n+1)+1)42^(n+1)
  a_n = 14n(n+1)42^n

  a_(n+1)/a_n = [(14(n+1)((n+1)+1)42^(n+1)] / [14n(n+1)42^n]

3. Simplify the ratio: In this case, we have:

  a_(n+1)/a_n = [(14(n+1)(n+2)42^(n+1)] / [14n(n+1)42^n]
  a_(n+1)/a_n = [(n+1)(n+2)42] / [n(n+1)]
  a_(n+1)/a_n = (n+2)42 / n

4. Calculate the limit as n approaches infinity:

  lim (n->∞) (n+2)42 / n = 42

5. Apply the Ratio Test: If the limit is less than 1, the series converges; if the limit is greater than 1, the series diverges; if the limit equals 1, the test is inconclusive.

In this case, the limit is 42, which is greater than 1. Therefore, the series is divergent.

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The equation of line b is y = -3x.

An equation is a mathematical statement that expresses the equality of two expressions. It is a representation of a relationship between two or more variables, and it can be written using symbols, numbers, and/or words. Equations are used to describe physical and chemical processes, to calculate unknown values, and to solve problems. Equations are fundamental to all areas of mathematics, science, engineering, and technology.

The equation of line b can be determined by finding the negative reciprocal of the slope of line a. The equation of line a is y = 1/3x + 3, which has a slope of 1/3.

Therefore, the slope of line b is the negative reciprocal of 1/3, which is -3. The equation of line b can be determined by using the slope-intercept form, y = mx + b. Substituting m = -3 and b = 0, the equation of line b is y = -3x + 0. Therefore, the equation of line b is y = -3x.

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The equation cos(x - y) = cos(x) - cos(y) is not an identity.

To show that the equation cos(x - y) = cos(x) - cos(y) is not an identity, we need to find a value for x and a value for y such that the left and right sides of the equation are defined but not equal.

Let x = π/2 and y = 0. Then, we have:

cos(x - y) = cos(π/2 - 0) = cos(π/2) = 0

cos(x) - cos(y) = cos(π/2) - cos(0) = 0 - 1 = -1

Since 0 and -1 are not equal, we have found a value for x and a value for y such that the left and right sides of the equation are not equal. Therefore, the equation cos(x - y) = cos(x) - cos(y) is not an identity.

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Answer:50

Step-by-step explanation: speed = distance/time however we need to convert the minutes into hours so 300/60 which is = to 5
then you do 250/5 which is 50.

The length of the spiraling polar curve [tex]r = 65e^{(2\theta)}[/tex] from θ = 0 to θ = 2π is approximately 2.084×10⁷ units.

To find the length of the spiraling polar curve [tex]r = 65e^{(2\theta)}[/tex] from θ = 0 to θ = 2π, you can follow these steps:

1. Use the polar curve arc length formula:

[tex]L=\int \sqrt{r^2+\left(\frac{d r}{d \theta}\right)^2} d \theta[/tex] from θ = 0 to θ = 2π, where r is the polar curve equation and dr/dθ is its derivative with respect to θ.

2. Differentiate the given polar curve with respect to θ:

[tex]dr/d\theta = 130e^{2\theta}[/tex].

3. Calculate r² + (dr/dθ)²:

[tex](65e^{(2\theta)})^2 + (130e^{(2\theta)})^2 = 65^2 \times e^{(4\theta)} + 130^2 \times e^{(4\theta)}[/tex].

4. Factor the common term and simplify:

[tex]e^{(4\theta)}(65^2 + 130^2) = 21125  e^{(4\theta)}[/tex].

5. Now, find the square root of the expression:

[tex]\sqrt{(21125 \times e^{(4\theta)})} = 145.34 e^{(2\theta)}[/tex].

6. Integrate the expression with respect to θ from 0 to 2π:

[tex]\int145.34 e^{(2\theta)}d\theta[/tex] from θ = 0 to θ = 2π.

7. Perform the integration:

[tex](145.34/2) [e^{4\pi}-e^0][/tex] = 2.084×10⁷ units.

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Answers In Exact Order:

37 / 8, 91 / 20, 457 /100 (4.57), and 4543 / 1000 (4.543)

Step-by-step explanation:

In order to solve your question, we first convert the two decimals into fractions. This will be easier, since we can order fractions from least to greatest by their denominator.

1. To convert 4.57 to a fraction, we can place the decimal number over it's placed value. Like this: 0.3 - 3/10.

For this problem, we'll do the same with 4.57, like this:

457 / 100

Since 7 is in the hundredth place, the denominator will be 100.

You can also do the same with 4.543, which will be:

4543 / 1000

Like I said, 3 is in the thousandth place, and the denominator will be 1,000.

Now, since the two decimals are converted to fractions, we can do the easy part!

To order the fractions, we look at the denominator.

If you look at 37 / 8, the denominator is eight, which will go first, since it's the least.

Then take a look at 91 / 20. The denominator is twenty, and will go second.

After that, look at 457 / 100. The denominator is one hundred, and will go third.

Lastly, 4543 / 1000 will be the greatest, since the denominator is one thousand.

Hence, the order goes by:

37 / 8

91 / 20

457 / 100 (4.57)

4543 / 1000 (4.543)

Reply below if you have any questions or concerns.

You're welcome!

- Nerdworm

Answer:

Step-by-step explanation:

13

The values of m for which y=e^mx is a solution of the differential equation y"-5y'+6y=0 are m=-2 and m=-3 (option b).

To find the values of m, we first need to compute the first and second derivatives of y with respect to x:

1. First derivative: y'=me^mx
2. Second derivative: y"=m^2e^mx

Now, we substitute these derivatives into the given equation: m^2e^mx - 5(me^mx) + 6e^mx = 0. Factoring out e^mx, we get: e^mx(m^2 - 5m + 6) = 0. Since e^mx is never zero, the quadratic equation must equal zero: m^2 - 5m + 6 = 0. Factoring this quadratic equation gives (m-2)(m-3)=0, so m=-2 and m=-3 are the solutions.

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After observing the graphs generated by these simulations, you can draw the following conclusions:
1. As the sample size increases, the distribution of the sample mean becomes narrower, indicating that the sample mean estimates the true population mean more accurately.
2. Larger sample sizes result in lower variability of the sample mean, which means that it is less likely for extreme values to occur in larger samples.
3. The Central Limit Theorem holds true, which states that the distribution of the sample mean approaches a normal distribution as the sample size increases, regardless of the shape of the population distribution.

In the given problem, you are asked to simulate the sample mean of different sample sizes (100, 400, and 625) using the `simulate_sample_mean` function with 10,000 repetitions. Let me help you with the step-by-step explanation:

1. First, you simulated the sample mean for a sample size of 100 salaries:

```
simulate_sample_mean(salaries, 'salary', 100, 10000)
plots.xlim(50000, 100000)
```

2. Next, you need to do the same for sample sizes of 400 and 625 salaries. To do this, you will use the same `simulate_sample_mean` function but change the sample size parameter:

For sample size 400:

```
simulate_sample_mean(salaries, 'salary', 400, 10000)
plots.xlim(50000, 100000)
```

For sample size 625:

```
simulate_sample_mean(salaries, 'salary', 625, 10000)
plots.xlim(50000, 100000)

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To solve the initial-value problem 2xy' y = 6x, x > 0, y(4) = 24, we first need to separate the variables and integrate both sides.

Starting with the initial-value problem 2xy' y = 6x, we divide both sides by 2xy to get y'/y = 3/x.

Now, we integrate both sides with respect to x:
∫(y'/y) dx = ∫(3/x) dx
=> ln|y| = 3ln|x| + C
where C is the constant of integration.

Next, we can solve for y by exponentiating both sides:
|y| = e^(3ln|x|+C)
=>|y| = e^C * e^(ln|x|^3)
=>|y| = kx^3
where k = ± e^C.

To find the specific value of k, we can use the initial condition y(4) = 24:
|24| = k(4)^3
=>k = 3/8

So, the solution to the initial-value problem is:
y = 3/8 x^3 for x > 0, y(4) = 24.

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The trigonometry identity value of sin(A) is -3/5.

We have ,

Solving the trigonometry identity

From the question, we have the following parameters that can be used in our computation:

cos(A) = 4/5

sin^2(A) + cos^2(A) = 1

so, we get,

sin(A) = ± 3/5

The angle A is in Quadrant IV

The value of sin(A) has already been given

However, because the angle A is in Quadrant IV, the value of the trigonometry identity would be negative

(sine are negative in the 4th quadrants)

So, we have

sin(A) = -3/5

Hence, The trigonometry identity value of sin(A) is -3/5.

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The average value of the function f on the interval [−2, 2] is 2/9.

To find the average value fave of the function f on the interval [−2, 2], we need to use the formula:

fave = (1/(b-a)) × integral from a to b of f(x) dx

where a and b are the limits of the interval. So in this case, we have:

fave = (1/(2-(-2))) × integral from -2 to 2 of (x^2/(x³ - 10)²) dx

To solve the integral, we can use the substitution u = x³ - 10, which gives us:

du/dx = 3x²
dx = du/(3x²)

Substituting these values, we get:

fave = (1/4) × integral from -2 to 2 of ((1/3u²) × (du/3x²))

Now we can simplify this to:

fave = (1/36) × integral from -2 to 2 of (1/u²) du

Integrating, we get:

fave = (1/36) × (-1/u) from -2 to 2

Plugging in the limits of integration, we get:

fave = (1/36) × ((-1/(2³ - 10)) - (-1/((-2)³ - 10)))

Simplifying, we get:

fave = (1/36) × ((-1/-2) - (-1/-18))

fave = (1/36) × (8/18)

fave = 2/9

Therefore, the average value of the function f on the interval [−2, 2] is 2/9.

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The value of x is (5 ± √153)/4.

What is the area of a rectangle?

The area a rectangle occupies is the space it takes up inside the limitations of its four sides. The dimensions of a rectangle determine its area. In essence, the area of a rectangle is equal to the sum of its length and breadth.

Here, we have

Given: Area of rectangle = 61

Equation : A(x) = 2x² - 5x

We have to find the value of x.

A(x) = 16

16 = 2x² - 5x

2x² - 5x - 16 = 0

we apply here factorization and we get

= (-b ± √b²-4ac)/2a

=  (5 ± √5²+4(2)(16))/2(2)

= (5 ± √25+128)/4

= (5 ± √153)/4

Hence, the value of x is (5 ± √153)/4.

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The partial derivative of z with respect to x is -1/3, and the partial derivative of z with respect to y is -2/3.

If the equation F (x, y, z) = 0 determines z as a differentiable function of x and y, then we can apply the implicit function theorem to obtain the following equations:

partial z/ partial x = -Fx / Fz
partial z/ partial y = -Fy / Fz

where Fx, Fy, and Fz denote the partial derivatives of F with respect to x, y, and z, respectively. These equations hold at the points where Fz is not equal to 0.

To find the values of partial z/ partial x and partial z/partial y at a given point, we need to evaluate the partial derivatives of F at that point and substitute them into the above equations. For example, let's say we are given the point (1, 2, 3) and the equation F(x, y, z) = x^2 + y^2 + z^2 - 25 = 0.

At the point (1, 2, 3), we have:

Fx = 2x = 2
Fy = 2y = 4
Fz = 2z = 6

Since Fz is not equal to 0 at this point, we can use the above equations to find:

partial z/ partial x = -Fx / Fz = -2/6 = -1/3
partial z/ partial y = -Fy / Fz = -4/6 = -2/3

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To graph the equation x + 2y - 1 = 9, we can first rearrange it to solve for y:

x + 2y - 1 = 9

2y = 10 - x

y = (10 - x) / 2

Now we can pick three different values of x and find the corresponding values of y using this equation. Let's choose x = 0, x = 2, and x = 4:

When x = 0:

y = (10 - 0) / 2 = 5

So one point on the graph is (0, 5).

When x = 2:

y = (10 - 2) / 2 = 4

So another point on the graph is (2, 4).

When x = 4:

y = (10 - 4) / 2 = 3

So the third point on the graph is (4, 3).

To check if this equation is linear or nonlinear, we can see if it satisfies the property of linearity, which is that if we draw a line between any two points on the graph, all other points on the graph should lie on that same line.

Let's check if this holds true for the three points we've chosen:

If we plot these three points, we get:

   |

 6 |

   |     * (4, 3)

 5 |        

   |   * (2, 4)

 4 |

   | * (0, 5)

 3 +------------------

   0   2   4   6   8  10

Visually inspecting the plot, it looks like all three points do indeed lie on a straight line. Therefore, we can conclude that this equation is linear.

The 99% confidence interval for the population proportion is approximately (0.439, 0.561).

To construct a 99% confidence interval for the population proportion, we will use the following formula:

CI = p-hat ± Z × √[(p-hat × (1 - p-hat)) / n]

where CI represents the confidence interval, p-hat is the sample proportion, Z is the critical value for the desired confidence level, and n is the sample size.

Given the information, x = 125 and n = 250.

1. Calculate p-hat (sample proportion):
p-hat = x / n = 125 / 250 = 0.5

2. Determine the Z-value for a 99% confidence interval (use a Z-table or calculator):
Z = 2.576

3. Plug the values into the formula and calculate the confidence interval:

CI = 0.5 ± 2.576 × √[(0.5 × (1 - 0.5)) / 250]
CI = 0.5 ± 2.576 × √(0.5 × 0.5 / 250)
CI = 0.5 ± 2.576 × √(0.001)

Now, calculate the lower and upper bounds:

Lower bound = 0.5 - 2.576 × √(0.001) ≈ 0.439
Upper bound = 0.5 + 2.576 × √(0.001) ≈ 0.561

Therefore, the 99% confidence interval for the population proportion is approximately (0.439, 0.561).

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Based on the information, a table or chart is an effective means of listing all conceivable outcomes and their associated probability.

Because there are only two events (green or blue) and two trials, I would utilize a table or chart to determine the probable outcomes. A table or chart is an effective means of listing all conceivable outcomes and their associated probability.

Because each outcome is equally likely, it has a probability of 1/4.

Also,because there are four possible outcomes, each of which is equally likely, the likelihood of selecting two marbles of the same hue is 1/2. As a result, we can anticipate that we will select two marbles of the same color around 25 times out of 50 trials.

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The 25th percentile of the given set of data is option d , 3.

To find the 25th percentile, we need to first determine the position of the value that corresponds to the 25th percentile.

The formula to find the position is: (25/100) x (n+1), where n is the total number of values in the dataset.

In this case, n = 15, so the position is: (25/100) x (15+1) = 4.

This means that the value at the 4th position in the ordered set of data corresponds to the 25th percentile.

Looking at the ordered set, the 4th value is 3. Therefore, the answer is option d. 3.

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Answer:

√29 =c

Step-by-step explanation:

a^2+b^2=c^2

5^2+2^2=c^2

25+4=c^2

29=c^2

√29=c

The ratio of the velocities of the two waves is [tex]\frac{v2,1}{v3,2} = \frac{\frac{8}{k} }{\frac{2}{k} } = 4[/tex].

The wave speed is given by the ratio of the angular frequency to the wave number, v = w/k. The wave velocity, on the other hand, is the rate at which the wave energy or information is transmitted in a medium, and is given by the ratio of the wave amplitude to the wave number, V = A/k, where A is the wave amplitude.

For wave y1(x,t) = 8cos(3(2kx - wt)), the wave speed is v1 = [tex]\frac{w}{k} = \frac{3w}{2k}[/tex]

For wave y2(x,t) = 2cos(3kx + wt), the wave speed is v2 = .[tex]\frac{w}{k} = \frac{w}{k}[/tex]

Therefore, the ratio of the speeds of the two waves is [tex]\frac{v1}{v2} = \frac{3w}{2k} = \frac{3}{2}[/tex]

To find the wave velocities, we need to first determine the wave amplitude for each wave. The wave amplitude is the maximum displacement of the wave from its equilibrium position.

For wave y1(x,t) = 8cos(3(2kx - wt)), the amplitude is 8.

For wave y2(x,t) = 2cos(3kx + wt), the amplitude is 2.

Therefore, the ratio of the velocities of the two waves is [tex]\frac{v2,1}{v3,2} = \frac{\frac{8}{k} }{\frac{2}{k} } = 4[/tex].

The ratio of the velocities of the two waves is independent of their frequencies and depends only on the ratio of their amplitudes. This is because the wave velocity depends only on the properties of the medium through which the wave is propagating, while the frequency depends only on the source of the wave.

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Alternatively, we could also restrict the domain of f(x) to a range that excludes the values of x that produce non-unique values of y, such as x = -3, which produces a value of y = 2 for f(x).

what is domain ?

In mathematics, the domain of a function is the set of all possible input values (also called independent variables) for which the function is defined and produces a valid output. It is the set of values that we are allowed to input into the function.

In the given question,

For the inverse of f(x) = x² + 6x + 5 to be a function, we need to ensure that it passes the vertical line test. In other words, for every value of x, the inverse function should produce only one unique value of y.

To ensure that the inverse of f(x) is a function, we need to restrict the domain of f(x) to a range that produces only one value of y for each value of x. This means that we need to make sure that f(x) is one-to-one, or injective, meaning that no two distinct values of x can produce the same value of y.

To check if f(x) is injective, we can use the discriminant of the quadratic equation x² + 6x + 5 = y, which is b² - 4ac, where a = 1, b = 6, and c = 5. The discriminant is:

b² - 4ac = 6² - 4(1)(5) = 16

Since the discriminant is positive, there are two distinct real roots of the quadratic equation, which means that f(x) is not injective and therefore does not have an inverse that is a function.

To ensure that the inverse of f(x) is a function, we need to restrict the domain of f(x) to a range that produces only one value of y for each value of x. One way to do this is to restrict the domain of f(x) to only include the values of x for which the discriminant is non-negative, meaning that the quadratic equation x² + 6x + 5 = y has real roots. This can be expressed as:

b² - 4ac >= 0

6² - 4(1)(5) >= 0

16 >= 0

This inequality is true for all values of x, which means that we can restrict the domain of f(x) to the entire real line to ensure that the inverse of f(x) is a function. Alternatively, we could also restrict the domain of f(x) to a range that excludes the values of x that produce non-unique values of y, such as x = -3, which produces a value of y = 2 for f(x).

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The change in surface area dA is approximately equal to 8πrdr when the radius of a sphere changes by a small amount dr.

The surface area of a sphere with radius r is given by the formula:

A = 4πr^2

If the radius changes from r to r + dr, then the new surface area A' is given by:

A' = 4π(r + dr)^2

Expanding the expression for A', we get:

A' = 4π(r^2 + 2rdr + dr^2)

Subtracting the original surface area A from A', we get the change in surface area:

dA = A' - A = 4π(r^2 + 2rdr + dr^2) - 4πr^2

Simplifying the expression, we get:

dA = 4π(2rdr + dr^2)

Since we are only interested in the change in surface area for a small change in radius dr, we can ignore the term dr^2 and approximate the change in surface area as:

dA ≈ 8πrdr

Therefore, the change in surface area dA is approximately equal to 8πrdr when the radius of a sphere changes by a small amount dr.

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The trigonometric form of 9(cos 20°+i sin 20°)/5(cos 75 i sin 75°) is 9/5 (cos 305° + I sin 305°). So, the correct option is option 2. 9/5 (cos 305° + I sin 305°).

To find 9(cos 20°+i sin 20°)/5(cos 75°+i sin 75°) and write the result in trigonometric form, we will use the division property of complex numbers in polar form:

(9(cos 20°+i sin 20°))/ (5(cos 75°+i sin 75°)) = (9/5) * ((cos 20° + i sin 20°)/(cos 75° + i sin 75°))

To divide complex numbers in polar form,

we divide their magnitudes and subtract their angles:

Magnitude: 9/5
Angle: 20° - 75° = -55°

So, the result is:

9/5 (cos(-55°) + i sin(-55°))

However, we can also write the angle in the positive equivalent:

9/5 (cos(305°) + i sin(305°))

Thus, the answer is: 9/5 (cos 305° + I sin 305°).

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The area under the standard normal curve to the right of z = −2.25 is obtained to be 0.0122.

What is area?

An object's area is how much space it takes up in two dimensions. It is the measurement of the quantity of unit squares that completely cover the surface of a closed figure.

The area under the standard normal curve to the right of z = -2.25 can be found using a standard normal table or a calculator.

Using a standard normal table, we look up the area corresponding to z = -2.25, which is 0.0122.

This means that the area under the standard normal curve to the right of z = -2.25 is 0.0122.

Alternatively, we can use a calculator with a normal distribution function to find this area.

The command on the calculator would be normcdf(-2.25, 99), where the second argument is a very large number that is used to represent infinity.

Using this command, we get an answer of 0.0122, which agrees with the value found using the standard normal table.

In summary, the area under the standard normal curve to the right of z = -2.25 is 0.0122, which represents the probability that a standard normal variable is greater than -2.25.

Therefore, the area under the normal curve is 0.0122.

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To solve the differential equation 2yy' + 1 = y^2x, we can use separation of variables.

First, we can rearrange the equation to get:

2yy' = y^2x - 1

Next, we can divide both sides by y^2x - 1 to get:

(2y)/(y^2x - 1) dy/dx = 1

We can now integrate both sides with respect to x and y, respectively:

∫(2y)/(y^2x - 1) dy = ∫1 dx

For the left-hand side, we can use substitution by letting u = y^2x - 1, which means du/dy = 2yx.

Substituting this into the integral gives:

(1/2)∫du/u = (1/2)ln|y^2x - 1| + C1

For the right-hand side, we can integrate with respect to x:

∫1 dx = x + C2

Combining the two integrals gives:

(1/2)ln|y^2x - 1| + C1 = x + C2

We can simplify this to:

ln|y^2x - 1| = 2x + C

where C = 2C2 - C1.

Finally, we can exponentiate both sides to get rid of the natural logarithm:

|y^2x - 1| = e^(2x+C)

Since the absolute value of y^2x - 1 can be either positive or negative, we need to consider both cases:

y^2x - 1 = e^(2x+C) or y^2x - 1 = -e^(2x+C)

Solving for y in each case gives:

y = ±sqrt((e^(2x+C) + 1)/x)

Therefore, the general solution to the differential equation 2yy' + 1 = y^2x is:

y = ±sqrt((e^(2x+C) + 1)/x)

where C is a constant of integration.
Hello! To solve the given differential equation 2yy' = y^2x, you can follow these steps:

1. Divide both sides by y^2 to isolate y':

  y' = (x/2) * (1/y)

2. Now, we have a separable equation, so we can separate the variables by multiplying both sides by y:

  y dy = (x/2) dx

3. Integrate both sides with respect to their respective variables:

  ∫y dy = ∫(x/2) dx

  (1/2)y^2 = (1/4)x^2 + C₁

4. To solve for y, multiply both sides by 2:

  y^2 = (1/2)x^2 + 2C₁

5. Take the square root of both sides:

  y = ±√[(1/2)x^2 + 2C₁]

This is the general solution of the given differential equation, where C₁ is an arbitrary constant.

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There are 8 feet³ of these sheets will Jill need to cover the floor.

We have to given that;

Plywood is sold in 1/4 inch thick sheets that have a length of 8 feet and a width of 4 feet.

Hence, The volume of for sheets are,

⇒ 1/4 × 8 × 4

⇒ 8 feet³

Therefore, There are 8 feet³ of these sheets will Jill need to cover the floor.

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