Find the mode of the data.
Length (inches) of fish in tank:
2, 3, 1, 4, 5, 2, 2
Mode: [?] in.

Answer:

HCF=8

LCM=480

Step-by-step explanation:

prime factor trees

Answer:

60

Step-by-step explanation:

48=2×2×2×2×3

64=2×2×2×2×2×2

80=2×2×2×2×5

H.C.F.=2×2×2×2=16

L.C.M=2×2×2×2×2×2×3×5

L.C.M.÷H.C.F.=(2×2×2×2×2×2×3×5)/(2×2×2×2)=2×2×3×5=60

Answer: Should be (3, 1) :)

Step-by-step explanation:

Answer: (4,-8)

Step-by-step explanation:

you look at the point it is and flip it to a negative

Answer:

x=12

Step-by-step explanation:

since they are similar triangle .Use these ratios

9/6=x+9/14

do cross multiplication

6(x+9)=14*9

6x+54=126

6x=126-54

x=72/6

x=12

Answer:

x ≈ 69.6°

Step-by-step explanation:

The angle of elevation is the measure of angle x

Using the sine ratio in the right triangle

sin x = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{15}{16}[/tex] , then

x = [tex]sin^{-1}[/tex] ([tex]\frac{15}{16}[/tex] ) ≈ 69.6°

The angle of elevation is 69.6° ( to the nearest tenth )

Answer:

3/25

Step-by-step explanation:

Answer:

=325

Showing Work:

12%=12100

=0.12

=0.121×100100

=12100

=325

Answer:

72 m^3

Step-by-step explanation:

volume of the kiosk = volume of cylinder + volume of cone

volume of a cylinder = nr^2h

n = 3.14

r = radius = 5/2 = 2.5

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

3.14 x (2.5^2) x 3 = 58.88  

Volume of a cone = 1/3(nr^2h)

3.14 x 1/3 x (2.5^2) x 2 = 13.08

13.08 + 58.88 = 71.96

To round off to the nearest cubic meter, look at the first number after the decimal, if it is less than 5, add zero to the units term, If it is equal or greater than 5, add 1 to the units term.

= 72 m^3

Answer:

they are similar cuz it resembles a "z" pattern. The angles are so the same.

Answer:

4+5-1535648&574£abjibav fgjr

Answer:

D. x ≥ 1

Step-by-step explanation:

The graph shows a shaded circle which starts at 1. This implies that 1 is included in the possible values of x. The line goes from 1 towards our tight. This means that the possible values of x are greater than or equal to 1.

The inequality representing the graph would be:

x ≥ 1

To me, this means doing a righteous act has no constraint based on what situation anyone is in.

Answer:

i think let me see

Step-by-step explanation:

Answer:

[tex]x^2-10x+18=0[/tex]

a = -10 and b = 18.

Step-by-step explanation:

Let w represent the width of the rectangle.

We are given that the perimeter of the rectangle is 20 cm, this means that:

[tex]20=2(x + w)[/tex]

Let's put w in terms of x. Divide both sides by two:

[tex]10=x+w[/tex]

And solve for w:

[tex]w=10-x[/tex]

So, the rectangle measures x by (10 - x) cm.

According to the Pythagorean Theorem:

[tex]a^2+b^2=c^2[/tex]

a and b are the legs and c is the hypotenuse.

Substitute x for a, w for b, and 8 for c:

[tex]x^2+w^2=8^2[/tex]

Simplify and substitute:

[tex]x^2+(10-x)^2=64[/tex]

Square:

[tex]x^2+(100-20x+x^2)=64[/tex]

Isolate the equation. So:

[tex]2x^2-20x+36=0[/tex]

Since the leading coefficient is one, divide both sides by two:

[tex]x^2-10x+18=0[/tex]

Therefore, a = -10 and b = 18.

Answer:

Same side angles are supplementary

L+k=180

18x-18+72=180

18x=126

x=7

m∠18(7)-18

= 108°

---------------------

hope it helps...

have a grat day

Answer:

x = 12.35

Step-by-step explanation:

Tan(39) = 10/x

Tan(39) * x = 10

x = 10 / Tan(39)

x = 12.35

Hope this helps!

Answer:

Step-by-step explanation:

Remember SOHCAHTOA.

In this case, we use TOA.

tan(39) = 10/x

x = 10/tan(39)

x = 12.349

Answer:

The base of the ladder is 3.2 meters far from the wall.

Step-by-step explanation:

We need to calculate the base of a right triangle. The given information is:

h: hypotenuse = length of the ladder = 6 m      

b: is the base =?

θ: is the angle between the hypotenuse and the base = 58°

To find the base we can use the following trigonometric equation:

[tex]cos(\theta) = \frac{b}{h}[/tex]

[tex] b = cos(\theta)*h = cos(58)*6 = 3.2 m [/tex]

Therefore, the base of the ladder is 3.2 meters far from the wall.

I hope it helps you!

Answer:

It's indeed A. Yet I think of reporting multiple same questions as spam and nonsense titles.

but nah, I won't, would be kinda focused on the toxic part then :D

Answer:

$920

Step-by-step explanation:

800(1.15) = 920

Answer:

Step-by-step explanation:

answer for question no 3

answer for question no 4

Answer:

t=time

v=speed

t=k/v

8hr=k/36 mi/hr

k=288 mi

t=288 mi24 mi/hr =12 hours.

-------------------

The distance is 288 miles by multiplying 36 by 8.

divide that by 24 mph, and it is 12 hours.

Answer:

x = -1/2, x = -5    OR    x = -0.5 and x = -4

Step-by-step explanation:

I’ll just put a picture, I can’t fully explain digitally.    ;D

The coordinates of the enlarged and reflected triangle are A'(x, y) = (6, 3),  B'(x, y) = (3, 3) and C'(x, y) = (6, 0).

In this problem we find a triangle whose vertices have the following coordinates: A(x, y) = (1, 8), B(x, y) = (3, 8), C(x, y) = (1, 10), and we are asked to enlarge the triangle by a scale factor of - 1.5 and with a centre of enlargement at (3, 6). Please notice that the negative sign of the scale factor involves both enlargement and reflection. Then, the operation can be done by the following operation:

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]            (1)

Where:

If we know that O(x, y) = (3, 6), k = - 1.5, A(x, y) = (1, 8), B(x, y) = (3, 8) and C(x, y) = (1, 10), then the coordinates of the resulting expression:

A'(x, y) = (3, 6) + (- 1.5) · [(1, 8) - (3, 6)]

A'(x, y) = (3, 6) + (- 1.5) · (- 2, 2)

A'(x, y) = (3, 6) + (3, - 3)

A'(x, y) = (6, 3)

B'(x, y) = (3, 6) + (- 1.5) · [(3, 8) - (3, 6)]

B'(x, y) = (3, 6) + (- 1.5) · (0, 2)

B'(x, y) = (3, 6) + (0, - 3)

B'(x, y) = (3, 3)

C'(x, y) = (3, 6) + (- 1.5) · [(1, 10) - (3, 6)]

C'(x, y) = (3, 6) + (- 1.5) · (- 2, 4)

C'(x, y) = (3, 6) + (3, - 6)

C'(x, y) = (6, 0)

The coordinates of the enlarged and reflected triangle are A'(x, y) = (6, 3),  B'(x, y) = (3, 3) and C'(x, y) = (6, 0).

To learn more on rigid transformations: https://brainly.com/question/1761538

#SPJ1

Answer:

a) 40 is the interquartile range

descriptive statistics, the interquartile range, also called the midspread, middle 50%, or H‑spread, is a measure of statistical dispersion, being equal to the difference between 75th and 25th percentiles, or between upper and lower quartiles, IQR = Q₃ − Q₁.

b).

The first thing you always need to do before estimating fractions is to round each fraction either to the nearest 0, 1/2, or 1. Example #1. Estimate 3/7 + 5/9. Notice that 3/7 is close to 1/2 and 5/9 is also close to 1/2. Therefore, an estimate for 3/7 + 5/9 is 1/2 + 1/2 = 1.

Answer:

y=1x+27

y=1(3)+27

Y=30

Step-by-step explanation:

X=DAYS

M=DOLLARS

Hope this helps brotha

Answer:

b = 14

u = 4

Step-by-step explanation:

I manually counted because I forgot how to solve this. HAHA

Hope this helps

Answer:

y-y1=m(x-x1)

y-1/3=3/4(x-4)

y=3/4x-8/3

Answer:

a₄ = 123

Step-by-step explanation:

a₁ = 1

a₂ = (1)² + 2

a₂ = 3

a₃ = (3)² + 2

a₃ = 11

a₄ = (11)² + 2

a₄ = 123

Answer:

$77.90

Step-by-step explanation:

The range between the highest and lowest is 27.50 so the lowest should be 27.50 less than 105.40. 105.40-27.50=77.90

So the lowest pay is $77.90

Answer:

[tex]ML=9,MN=8[/tex]

[tex]MK=ML+LK[/tex]

[tex]9+-3+x[/tex]

[tex]=9-3+x[/tex]

[tex]MK=6+x[/tex]

[tex]ME=MN+NE[/tex]

[tex]ME=8+x[/tex]

Now using Secant secant theorem:-

[tex]ML*MK=MN*ME[/tex]

[tex]9(6+x)=8(8+x)[/tex]

[tex]54+9x=64+8x[/tex]

Subtracting 8x and 54 on both sides:-

[tex]54+9x-8x-54=64+8x-8x-54[/tex]

[tex]x=10[/tex]

[tex]KL=-3+x[/tex]

[tex]KL=-3+10[/tex]

[tex]KL=7[/tex]

so, your answer is C) 7

-------------------------

hope it helps....

Answer:

C.) 7

Step-by-step explanation:

I got it correct on founders edtell

Answer:

9 < √97 < 10

Step-by-step explanation:

√97 is a little less than √100

Which is 10

9 < √97 < 10

=====================================================

Explanation:

Consider that 81 < 97 < 100 is a true statement. Note the 81 and 100 are perfect squares such that 81 = 9^2 and 100 = 10^2

We can apply the square root to all three sides to get the following

[tex]81 < 97 < 100\\\\\sqrt{81} < \sqrt{97} < \sqrt{100}\\\\\sqrt{9^2} < \sqrt{97} < \sqrt{10^2}\\\\9 < \sqrt{97} < 10\\\\\text{The number }\sqrt{97} \text{ is between 9 and 10}\\\\[/tex]

Using a calculator, we can help verify this

[tex]\sqrt{97} \approx 9.85[/tex]