Find the midpoint of the segment with the following endpoints.
(5,5) and (10,8)

the lower limit of the 90% confidence interval is approximately -65.25, and the upper limit is approximately 13.65.

To construct a 90% confidence interval for the difference between the mean daily calorie consumption of females in September-February (μ₁) and the mean daily calorie consumption of females in March-August (μ₂), we can use the formula:

CI = ([tex]\bar{X_1}[/tex] - [tex]\bar{X_2}[/tex]) ± Z * √((s₁² / n₁) + (s₂² / n₂))

Where:

[tex]\bar{X_1}[/tex] and [tex]\bar{X_2}[/tex] are the sample means of calorie consumption for the two periods.

s₁ and s₂ are the sample standard deviations of calorie consumption for the two periods.

n₁ and n₂ are the sample sizes for the two periods.

Z is the z-score corresponding to the desired confidence level.

Given data:

[tex]\bar{X_1}[/tex] = 2387.1 (mean daily calorie consumption for September-February)

[tex]\bar{X_2}[/tex] = 2412.9 (mean daily calorie consumption for March-August)

s₁ = 210 (standard deviation for September-February)

s₂ = 267.5 (standard deviation for March-August)

n₁ = 260 (sample size for September-February)

n₂ = 300 (sample size for March-August)

Confidence level = 90%

First, we need to find the z-score corresponding to a 90% confidence level. The z-score can be found using a z-table or a calculator. For a 90% confidence level, the z-score is approximately 1.645.

Now, we can substitute the values into the formula to calculate the confidence interval:

CI = (2387.1 - 2412.9) ± 1.645 * √((210² / 260) + (267.5² / 300))

Calculating the values inside the square root:

√((210² / 260) + (267.5² / 300)) ≈ √(342.461538 + 238.083333) ≈ √(580.544872) ≈ 24.107

Substituting the values into the formula:

CI = -25.8 ± 1.645 * 24.107

Calculating the limits of the confidence interval:

Lower limit = -25.8 - 1.645 * 24.107 ≈ -65.246

Upper limit = -25.8 + 1.645 * 24.107 ≈ 13.646

Rounding the values to two decimal places:

Lower limit ≈ -65.25

Upper limit ≈ 13.65

Therefore, the lower limit of the 90% confidence interval is approximately -65.25, and the upper limit is approximately 13.65.

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The given problem involves hypothesis testing in statistics. The correct conclusion will depend on whether the null hypothesis is rejected or not.

(a) The null and alternative hypotheses can be determined as follows: OAH (One-sample test for proportion): P = 0 (H0) versus H P ≠ 0 (HA).

(b) The test statistic, denoted as Zo, needs to be computed using the given sample data.

(c) To determine the P-value, the calculated test statistic is compared to the appropriate distribution (e.g., standard normal distribution) based on the chosen significance level.

(d) Based on the P-value and the predetermined significance level, the null hypothesis is either rejected or not rejected. If the P-value is less than the significance level, the null hypothesis is rejected. Otherwise, the null hypothesis is not rejected.

The conclusion will depend on whether the null hypothesis is rejected or not and should be stated accordingly.

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The law of cosines can be used to find the missing angle when the lengths of three sides of a triangle are known. In this case, we want to find the measure of angle a, so we'll use the formula: cos(a) = (b² + c² - a²) / (2bc)where a is the side opposite angle a, b is the side opposite angle b, and c is the side opposite angle c.

To find angle a, we need to rearrange the formula: cos(a) = (b² + c² - a²) / (2bc)cos(a) = (7² + 13² - 10²) / (2 * 7 * 13)cos(a) = 0.81923077a = cos⁻¹(0.81923077)a ≈ 34.2°Therefore, m∠a is approximately 34.2 degrees.

When either the lengths of the two sides and the measure of the included angle (SAS) or the lengths of the three sides (SSS) are known, the Law of Cosines is used to determine the remaining parts of an oblique (non-right) triangle.

The square of a side of an oblique triangle is equal to the sum of the squares of the other two sides minus twice the product of the two sides if A, B, and C are the measures of the angles of the triangle and a, b, and c are the lengths of the sides opposite the corresponding angles.

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The series converges for x values within the interval (-29/7, -27/7), and the radius of convergence is 1/7.

We apply the ratio test to our series:[tex]|7^(^n^+^1^)[/tex] (x + 4)[tex]^(^n^+^1^)^) / √(n+1)] / [( (x +7^n 4))^n\sqrtn]|[/tex]

We take the limit as n approaches infinity:lim(n→∞) |[tex]7(x + 4) / √(n+1)| = |7(x + 4)|[/tex]

For the series to converge, |7(x + 4)| must be less than [tex]1.|7(x + 4)| < 1-1 < 7(x + 4) < 1-1/7 < x + 4 < 1/7-29/7 < x < -27/7[/tex]

In conclusion, the interval of convergence is (-29/7, -27/7), and the radius of convergence is the half-length of the interval, which is 1/7.

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can you show the picture please?

Answer:

100 more silver cars

Step-by-step explanation:

Right now the ratio of silver cars to green cars is 20:40 or 1:2, but if you add a hundred more silvers cars the ratio would 120:40 or 3:1.

1: no solution

2: infinitely many solutions

3: one solution

Answer:

5

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

Answer:

146

Step-by-step explanation:

[tex] = \sqrt{21316 } [/tex]

[tex] = \sqrt{4 \times 5329} [/tex]

[tex] = 2 \sqrt{5329} [/tex]

[tex] = 2 \sqrt{73 \times 73} [/tex]

[tex] = 2 \times 73[/tex]

[tex] = 146[/tex]

The first movie was ⅔ hours longer than the second one.

The difference in length between the two movies, we need to subtract the length of the second movie from the first.

we need to convert the mixed numbers to improper fractions to make the subtraction easier.

2 ⅓ hours can be written as 7/3 hours.

1 ⅘ hours can be written as 8/5 hours.

Now, we can subtract them

7/3 - 8/5

we need a common denominator. The least common multiple of 3 and 5 is 15.

(7/3) * (5/5) - (8/5) * (3/3) = 35/15 - 24/15 = 11/15

Therefore, the first movie was 11/15 hours (or approximately 44 minutes) longer than the second one

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Answer:

3.14 units squared

Step-by-step explanation:

A = pi r^2

A = pi (1) ^2

A = pi = 3.14

(Radius = diameter / 2)

Answer:

1

Step-by-step explanation:

put x = 3

8(1/2³) = 8/8 = 1

Answer:

D

Step-by-step explanation:

Answer:

1.5 feets by 3.5 feets

Step-by-step explanation:

Scale model = 1/8

Dimension of living room = 12 feets by 28 feets

The dimension of the model using the scale model given :

Scale model * dimension

1/8 * (12 feets by 28feets)

= 1.5 feets by 3.5 feets

The mean squares within is 0.7130044843.

The formula to calculate the mean squares within is given below:

Mean squares within (MSW) = SSW / (n - k), where n = Total number of observations, k = Total number of groups.

Here, Number of participants = 274, Number of groups = 5, SSD = 1, SSW = 192.

Now, the value of n and k can be calculated using the formula given below:

n = Number of participants = 274, k = Number of groups = 5.

Let's substitute the values in the formula of mean squares within:

Mean squares within (MSW) = SSW / (n - k)

MSW = 192 / (274 - 5)

MSW = 192 / 269

MSW = 0.7130044843

Hence, the mean squares within is 0.7130044843.

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Answer:

1. V=60m³ SA=94m²

2. V=32m³ SA=88m²

3. V=2000mm³ SA=1000mm²

4. SA=376.8cm² V=552.64cm³

5. SA=1130.4cm² V=1356.48mm³

Step-by-step explanation:

1. Volume=5*4*3=60m³

Surface Area=2*(3*4)+2*(5*3)+2*(4*5)=24+30+40=94m²

2. Volume=8*4*1=32cm³

Surface Area=2*(8*1)+2*(8*4)+2*(4*1)=16+64+8=88cm²

3. Volume=10*10*20=2000mm³

Surface Area=2*(10*10)+2*(20*10)+2*(20*10)=200+400+400=1000mm²

4. SA of the cylinder=(2πr*h)+(2*πr²)=(2*(3.14)*4*11)+(2*3.14*16)

=(276.32)+(100.48)=376.8cm²

Volume=hπr²=11*(3.14)*16=552.64cm³

5. SA of cylinder=(2πr*h)+(2*πr²)=(2*(3.14)*12*3)+(2*3.14*144)

=(904.32)+(226.08)=1130.4mm²

Volume=hπr²=3*(3.14)*144=1356.48mm³

Answer:

6y-6y, cancel it out to find x first.

-5x+6y=41

7x-6y=-43

2x=-2

Step-by-step explanation:

i hope this helps :)

Answer:

Step-by-step explanation:

The first step is to add the 2 equations This will eliminate the y terms  

( + 6y + -6y = 0).

So you are then left with 2x = -2

Answer: I think the answer would be 1/6

Step-by-step explanation:

If you notice, all of the numbers on the left model are 1/6 less than the one on the left. I don't know what type of answer they are looking for but the one on the left is 1.6 smaller than the one on the right:)

Answer:

Explanation:

292/100×9.9 = 2.92×9.9 = 28.908

30 is closest to 28.908

Answer:

b

Step-by-step explanation:

Step-by-step explanation:

(-2xy^3)^3

(-2(4)(-1)^3)^3

(-2(4)(-1))^3

(8)^3

512

Answer:

39,975

Step-by-step explanation:

There u go

Answer:

39,975

Step-by-step explanation:

Caculater

Answer:

19654,67397,67923,91945

Step-by-step explanation:

Ascending order mean arrange the number from smaller value to bigger value

Answer:

19654,67397,67923,91945

plz mark me as brainliest

Answer:

7

Step-by-step explanation:

Answer: your answer is B

Step-by-step explanation:

Im so sorry if im wrong, have a good day!

Answer:

y = (4x - 3)(3x + 2)

Step-by-step explanation:

Factorization is the process of taking like terms out of number such that one can rewrite an expression by its factors, or as the products of serval smaller expressions.

The first step to factoring an equation is to rewrite the linear term as the sum or difference of two other linear terms. One must do this in such as way that it shares a common factor with one of the other terms in the expression.

[tex]12x^2 -x - 6[/tex]

[tex]12x^2 -9x + 8x - 6[/tex]

Take out the common factor,

[tex]3x(4x-3)+2(4x-3)[/tex]

Factor,

[tex](3x+2)(4x-3)[/tex]

Answer:

the tree is 8ft long

Step-by-step explanation:

beans

To prove that a single point {a} is a closed set in Rⁿ, we need to show that its complement, denoted as Rⁿ \ {a}, is open.

Let's consider an arbitrary point x in the complement Rⁿ \ {a}. Since x is not equal to a, there exists a positive radius r such that the open ball B(x, r) centered at x with radius r does not contain a.

Now, let's show that B(x, r) is entirely contained within Rⁿ\ {a}. We need to demonstrate that for any point y in B(x, r), y is also in Rⁿ \ {a}.

If y is equal to x, then y is not equal to a since a is excluded from Rⁿ \ {a}. Therefore, y is in Rⁿ\ {a}.

If y is not equal to x, then we can consider the distance between y and a. Since y is in B(x, r), we have:

d(y, x) < r

However, since a is not in B(x, r), we have:

d(a, x) ≥ r

Now, let's consider the distance between y and a:

d(y, a) ≤ d(y, x) + d(x, a) < r + (d(a, x) - r) = d(a, x)

Since d(y, a) is strictly less than d(a, x), it follows that y is not equal to a. Therefore, y is in Rⁿ \ {a}.

This shows that for every point x in Rⁿ \ {a}, there exists an open ball B(x, r) that is entirely contained within Rⁿ \ {a}. Hence, Rⁿ\ {a} is open.

By the definition of a closed set, if the complement of a set is open, then the set itself is closed. Therefore, a single point {a} is a closed set in Rⁿ.

The question should be:

Prove that in Rⁿ , a single point {a} is a closed sets.please write your answer in detail

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