Find the measure of one interior angle of a regular polygon with 13 sides

because the x values are identical the radius would be found by subtracting the y values.

6-2 = 4

the radius is 4

1. Both triangles are congruent by: a. angle-angle-side congruence theorem.

Using the trigonometric ratios, we have:

2. C. 9

3. C. 4√3

4. B. sin C

The angle-angle-side congruence theorem states that two triangles are congruent to each other if they both have two pairs of corresponding congruent angles and a pair of non-included congruent side.

To solve any right triangle, the following Trigonometric ratios can be employed:

sin ∅ = opp/hyp

cos ∅ = adj/hyp

tan ∅ = opp/adj.

1. Both triangles can be proven to be congruent based on: a. angle-angle-side congruence theorem.

2. Given the points, A(-2, 6) and B(-2, -3), the distance between both points is:

AB = |6 - (-3)| = 9 units

The answer is: C. 9

3. Apply the sine ratio:

sin 60 = opp/hyp = m/8

m = (sin 60)(8)

m = (√3/2)(8) [sin 60 = √3/2]

m = 4√3

The answer is: C. 4√3

4. Using the sine ratio:

sin C = opp/hyp = 8/17

The answer is: B. sin C

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(2, 8) and (-10, 2)

:)

The length of the other leg of the right triangle will be 13.86 cm.

The complete question is given below.

The triangle BCD ​ is a right triangle. The length of the hypotenuse is 19 centimeters. The length of one of the legs is 13 centimeters.

What is the length of the other leg?

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

Let the unknown sides be x. Then we have,

19² = 13² + x²

361 = 169 + x²

 x² = 361 – 169

 x² = 192

  x = 13.856 ≈ 13.86 cm

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Answer:

C 33.52 cm³

Step-by-step explanation:

Here, we have Radius(r)=2(Given)

Volume = 4/3 πr³

= 4/3 · 22/7 · 2³

= 33.5238

Round to the nearest tenth:
C 33.52 cm³

The area of the Triangle PQR which is in the circle,  is given as 784.25. See the computation below.

Mathematically speaking, a circle is a 2-dimensional shape whose boundaries are round and are equidistant from a fixed center.

The area of ΔPQR is given as ((√3)/4) x QR²

= (√3)/4) x (6√2 - 2√6)²

= 0.43301270189 x  (8.48528137424 x 4.89897948557)²

=  0.43301270189 x 1728

Area of ΔPQR = 784.25

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Answer:

a<-12

Step-by-step explanation:

The ratio of a : b : c in its simplest form is 5 : 12 : 30 respectively

So,

a / b = 1/6

b/c = 2/5

1/6 + 2/5

=(5 + 12) /30

a : b and b : c

= 5/30 and 12/30

Therefore,

a : b : c = 5 : 12 : 30

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Answer:

(4,-3)

Step-by-step explanation:

The scale factor is 1/3. So, multiply the numbers by 1/3.

12*1/3 is 4.

-9*1/3 is -3.

The new coordinates are (4,-3).

Answer: 78.09

Step-by-step explanation:

Seventy-eight is the whole number, so it goes to the left of the decimal point 78.09

Nine-hundredths is decimal, it goes two places to the right of the decimal point because it's hundredths 78.09

Answer:27?

Step-by-step explanation:

So since there needs to be 3 1/3ds in each cup you just multiply 3x9=27

Answer:

A

Step-by-step explanation:

Consider the left triangle within the big triangle.

Identity :

sin θ = opposite side / hypotenuse

=============================================================

Taking the sine value of the angle to find h :

⇒ sin37° = h/6

⇒ h = 6sin37°

Opposite 37 is h

Angle opposite 6 is 90

Sine rule:

h/sin37 = 6/sin90

xsin37

h = 6 x sin37/ sin90

h = 3.6108....

h = 3.6 to 1dp

A) 6xsin37= 3.6108...

B) 10xsin37 =6.018...

C) 6x 10 xsin37 = 36.108...

D) 10 x 6 x sin37 = 36.108...

Thus, answer is A

Hope this helps!

Answer:

Step-by-step explanation:

Givens

Formula

Linda's speed * t + martin's speed * t = 855

s1 * t + s2 *t = 855

Solution

35*t + 60*t = 855t                Combine the left

95t = 855                              Divide both sides by 95

95t/95 = 855/95

t = 9

Answer

They will meet in 9 hours.

Answer:

Option (D) is correct, 9 hours.

Answer:

120 = L+2W

LW =area.

to maximize area with given fencing that would make Width = 30 feet and length = 60

A= LW = (120-2W)W = 120W -2W^2

A' = 120-4W =0

W = 30

L=120-2(30) = 60 feet

W by L is 30 by 60 feet for max area

Answer:

  11.57%

Step-by-step explanation:

The probability of rolling two 3s is the product of the probability of rolling two 3s and two not-3s, and the number of ways that combination of rolls can appear.

__

Of the four die rolls, we want two of them to be 3s. The 3s can appear anywhere in the sequence. For example, we could have 33xx, or xx33, or any of a number of other combinations (where x is a "not 3"). The total number of ways two 3s can appear an a sequence of 4 rolls is ...

  C(4, 2) = 4!/(2!(4 -2)!) = 4·3/(2·1) = 6

__

The probability of rolling a 3 on a fair 6-sided die with one face labeled 3 is presumed to be 1/6. Then the probability of rolling something else is ...

  1 -1/6 = 5/6

So, two 3s and two not-3s in a given sequence have a probability of ...

  (1/6)(1/6)(5/6)(5/6) = 25/1296

__

The probability that four rolls of the die will show exactly two 3s is the product of the probability it can happen and the number of ways it can happen:

  (25/1296) × 6 = 25/216 ≈ 11.57%

_____

The attachment shows the probability function of a calculator gives the same result.

The area of the arrow given in the figure is 610 square cm

The given figure is made up of rectangle and triangle. The area is expressed as:

Area = Area of rectangle + area of triangle

Substitute the given parameters

Area of the arrow = (15*20) + 0.5(31 * 20)

Area of the arrow = 300 + 310
Area of the arrow = 610 square cm

Hence the area of the arrow given in the figure is 610 square cm

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Answer:

Hold its nose

Step-by-step explanation:

You can actually de-scent a skunk if it is the powerful defensive odor you are referring to. When you have a skunk de-scented, they are no longer able to spray, and at this point they are now similar to having a pet cat or dog; lovable and highly desire affection and attention from their owners.

The height of the pile is 150.7 mm, and the volume is V = 6,830,477.5 mm³.

We know that each paper is 0.55mm thick, then if we pile 274 of these, the height of the pile will be:

H = 0.55mm*274 = 150.7mm

Now we want to get the volume of the pile of paper. Remember that for a rectangular prism of height H, width W, and length L, the volume is:

V = H*W*L

In this case, we have:

Then the volume is:

V = (150.7mm)*(185 mm)*(245 mm) = 6,830,477.5 mm³

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The amount received by Ahmed is 168 gm.

The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity. Ratios can be classified into two types. One is part to part ratio and the other is part to whole ratio.

Here, let the amount received by Ahmed be 7x

          and amount received by Babar be 3x

       Total amount of sweets = 240 gm

Now, according to question,

           7x + 3x = 240

              10x = 240

               x = 240/10

              x = 24

Thus, the amount received by Ahmed is 7 X 24 = 168 gm and amount received by Babar = 3 X 24 = 72 gm.

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Answer:  1/20

Step-by-step explanation:

Given: Number of red marbles in bag = 4

Number of blue marbles in bag = 3

Number of yellow marbles in bag = 3

Total marbles = 3+3+4=10

Hope this helps!!!!

The area of the sector shown in the diagram below is A = 136.8 cm²

The formula for calculating the area of a sector is expressed as:

A = r²Ф/2

Given the following

radius = 14cm

Ф = π/6

Substitute

A = (14)²π/12

A = 196(3.14)/2

A = 136.8 cm²

Hence the area of the sector shown in the diagram below is A = 136.8 cm²

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Three selected options are as follows:

Distance is a numerical measurement of how far apart objects or points are. In Physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria.

Here, put the values in option substitute  in given equation D(t)

Option 1: At t = 0 hour,

              D (0) = 300 X 0 + 125 = 125 ≠ 300    Option Incorrect

Option 2 : At t = 2 hours,

                D(2) = 300 X 2 + 125 = 725  Option Correct.

Option 3: At t = 2.5 hours,

               D(2.5) = 875  Option Incorrect

Option 4: At t = 3 hours,

               D(3) = 875 Option Correct

Option 5: At t = 6 hours,

                D(6) = 75 X 6 + 612.5 = 450 + 612.5

                        = 1062.5 miles  Option Correct

Thus, Option two, four and five are correct.

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Answer:

40

Step-by-step explanation:

14 = 35% of x

35% = 0.35

So lets make an equation and solve for x:

14 = 0.35x

x = 14÷0.35

x = 40

To check our answer let's put it back into the question :

35% of 40 = 14

10% = 4 , 30% = 12 , 5% = 2

35% = 12+2 = 14 ✅

Hope this helped and have a good day

Answer:

53500

Step-by-step explanation:

if we take 2,000 and multiply it by 0.07 the resulting percentage equates to 140, or $140, add 140 to 2,000 and multiply by 25 will yield 53500

Answer:

The mean is 23

The median is 22

Step-by-step explanation:

To find the mean you have to do 2 steps:

Step 1: Add up all your numbers:

31 + 14 + 26 + 17 + 32 + 18

= 138

Step 2: Divide you answer by how many numbers there are(6):

138 ÷ 6

= 23

Now to find you median

First put the numbers in order:

14, 17, 18, 26, 31, 32

Now grab the middle number and since there are an even amount of numbers grab the 2 middle numbers:

14, 17, 18, 26, 31, 32

Now add the 2 numbers:

18 + 26

= 44

The last step is to divide your answer by 2:

44 ÷ 2

= 22

The Sine or Sinθ in a right-angle triangle is the ratio of its perpendicular to its Hypotenuse. The correct option is B.

The Sine or Sinθ in a right-angle triangle is the ratio of its perpendicular to its Hypotenuse. it is given as,

Sin(θ) = Perpendicular/Hypotenuse

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The hypotenuse is the longest side of the triangle.

In the ΔGEF, the value of Sin(E) is,

Sin(E) = GF/GE

In the ΔDEF, the value of Sin(E) is,

Sin(E) = FD/FE

Hence, the correct option is B.

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Maintain the same constraints on edge capacity, skew symmetry, and flow conservation in the ordinary maximum-flow problem on a flow network of comparable size.

A flow network is a directed graph with each edge having a capacity and each edge receiving a flow, according to graph theory. The amount of flow on an edge must not exceed the edge's capacity.

Let's suppose the network flow is given by;

G = (V, E)

With edge capacity:

c: E → R

And vertex capacity:

d: V → R

Maintain the same constraints on edge capacity, skew symmetry, and flow conservation.

Consider the new stipulation: for each:

v ∈V

So,

[tex]\rm \sum_{u \in v } \{ f(u,v)|f(u,v) > 0 \} \leq d(v)[/tex]

Thus, if maintain the same constraints on edge capacity, skew symmetry, and flow conservation the ordinary maximum-flow problem on a flow network of comparable size.

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Answer:

reflection

Step-by-step explanation:

its like a mirror, if it were rotated, they wouldnt line up as the same image. think of this like looking in a mirror! :)