The hypotenuse (longest side) of a right angled triangle can be derived using the Pythagoras' theorem as shown;
[tex]\begin{gathered} AC^2=AB^2+BC^2 \\ \text{Where AC is the hypotenuse, you now have;} \\ AC^2=6^2+9^2 \\ AC^2=36+81 \\ AC^2=117 \\ \text{Add the square root sign to both sides} \\ AC=\sqrt[]{117} \\ AC=10.8166 \\ AC=10.82\text{ (To 2 decimal places)} \end{gathered}[/tex]The answer is 10.82 inches, to 2 decimal places
Hi, I was absent today in class and I really need help with question 15, I will be much appreciated if you show work and the step so I can be more understanding thank you!
We have the following equation
[tex]\log _2(4x+10)-\log _2(x+1)=3[/tex]Now we solve for "x", we must use the logarithmic properties
[tex]undefined[/tex]Emma and her aunt shared 9 oranges each, how many oranges did they each get?
Answer:
4 and 1/2.
Step-by-step explanation:
There are 9 oranges, so there are not enough for both to get a whole amount.
They will split the last one into half, so they has 4 and 1/2 oranges each.
Answer: 4 and 1/2
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The parent function f(x)=x2 has been transformed to make the function g(x) by reflection f(x) over the x-axis , vertically shrinking by a factor of 1/2 and translating 2 units up. The equation for g(x) is expressed in which of the functions below
Given:
There are given that the parent function:
[tex]f(x)=x^2[/tex]Explanation:
According to the concept:
The function reflected over the x-axis means, we need to multiply with a negative sign.
That means:
[tex]g(x)=-x^2[/tex]And,
Vertically shrinking by a factor of 1/2 means, multiply by 1/2 in the entire function:
So,
[tex]g(x)=-\frac{1}{2}x^2[/tex]Then,
Translating 2 units up means, adding 2 in the entire function:
So,
[tex]g(x)=-\frac{1}{2}x^2+2[/tex]Final answer:
Hence, the correct option is C.
I NEED HELP PLEASE!!!!!!!!!!
a) The inverse of a statement : If If two angles are not supplementary then the angles are not a linear pair. FALSE
b) The converse of a statement : If the angles are a linear pair, then the two angles are supplementary. TRUE
c) The contrapositive of a statement : If the angles aren't supplementary, then they aren't linear pair . FALSE
The given statement is : If two angles are supplementary then the angles are a linear pair .
(a) The inverse of a statement : If If two angles are not supplementary then the angles are not a linear pair.
This statement is FALSE because supplementary angles do not have to be adjacent, whereas a linear pair must be adjacent and create a straight line. So, no, supplementary angles are not always linear pairs. However, linear pairs are always supplementary.
(b) The converse of a statement : If the angles are a linear pair, then the two angles are supplementary.
This statement is TRUE because in a linear pair, if the two angles have a common vertex and a common arm, then the non-common side makes a straight line and the sum of the measure of angles is 180°. Linear pairs are always supplementary.
(c) The contrapositive of a statement : If the angles aren't supplementary, then they aren't linear pair .
This statement is FALSE because if they are adjacent and share a vertex and one side. See the first picture below. They might not form a linear pair, like in a parallelogram.
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Can you help and explain Apply the zero peoduct theorem to solve for value of x[tex]x { = 9}^{2} [/tex][tex]27x {}^{2} = 9x[/tex]
Solution
We want to solve
[tex]27x^2=9x\text{ using zero product thorem}[/tex]The zero product property states that if a⋅b=0 then either a or b equal zero. This basic property helps us solve equations like (x+2)(x-5)=0.
For the question,
[tex]\begin{gathered} 27x^2=9x \\ \text{Divide both sides by }9 \\ 3x^2=x \\ \text{Subtract x from both sides} \\ 3x^2-x=0 \\ \text{Factorize} \\ x(3x-1)=0 \\ \text{Applying the zero theroem, we have} \\ x=0\text{ or 3x-1=0} \\ x=0\text{ or 3x = 1} \\ x=0\text{ or x = }\frac{1}{3} \end{gathered}[/tex]The answer is x = 0 and x = 1/3
The domain is ? Type your answer in interval notation
The graph of the function is
The domain of the function is determined as the x -value of the function that satisfy the given function.
[tex](-\infty,-4)\cup(-4,1)\cup(1,\infty)[/tex]Solve for x:
X=
100⁰
70°
x +41
Answer: x=107=0.7
Step-by-step explanation:
1001=70xMultiply both sides by 70.1001×70=xMultiply 1001 and 70 to get 10070.10070=xReduce the fraction 10070 to lowest terms by extracting and canceling out 10.107=xSwap sides so that all variable terms are on the left hand side.x=107
Erin spent $6.75 on art supplies and made cards to sell. On Monday she sold $3.50 worth of cards and on Tuesday she sold $5.25 worth of cards. What was Enn's overall profit or loss? o $1.75 loss o $2.00 profit 0 $8.75 loss O $15.50 profit
He spent $6.75 on art supplies and made the cards .
she sold the made cards on monday and tuesday.
Monday sales = $3.50
Tuesday sales = $5.25
Total sales = 3.50 + 5.25 = $8.75
profit = sales - cost
profit = 8.75 - 6.75 = $2.00
An automobile windshield wiper 11 inches long rotates through an angle of 60∘. If the rubber part of the blade covers only the last 10 inches of the wiper, find the area of the windshield cleaned by the windshield wiper. Answer exactly or round to the nearest tenth of a square inch
the area of the windshield, cleaned by the windshield wiper is mathematically given as 0.096inche^2
This is further explained below.
What is a windshield?The term "acute area of the windshield glazing" refers to the section of the windshield that measures eight and one-half inches by eleven inches and is located immediately in front of the driver's line of sight, as seen in the image.
Then, let's call the part of the windshield labeled "ABC" A.
[tex]A=\frac{1}{2} r^2 \theta[/tex]
Now, substituting the given values we get,
[tex]\begin{aligned}&A=\frac{1}{2} r^2 \theta \\&A=\frac{1}{2} \times(7)^2 \times \frac{\pi}{180} \\\end{aligned}$$[/tex]
A=0.4276
Then let the area of the windshield, ADE, be denoted by the letter A',
[tex]A^{\prime}=\frac{1}{2} r^2 \theta[/tex]
Now, after replacing those values with the ones we were provided,
[tex]\begin{aligned}&A^{\prime}=\frac{1}{2} r^2 \theta \\&A^{\prime}=\frac{1}{2} \times(1)^2 \times 60 \times \frac{\pi}{180} \\&A^{\prime}=0.5236\end{aligned}[/tex]
In conclusion, In order to calculate the area of the windshield, you need to take the difference between A and A'.
0.5236-0.4276=0.096
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What are the intercepts of 5x+y=5? Graph the equation.
The y-intercept is found replacing x = 0 into the equation as follows:
5*0 + y = 5
y = 5
Then, the line intercepts the y-axis at (0, 5)
The x-intercept is found replacing y = 0 into the equation as follows:
5x + 0 = 5
5x = 5
x = 5/5
x = 1
Then, the line intercepts the x-axis at (1, 0)
The line is graphed connecting these two points
What are the coordinates of P', the image of P(-4, 0) under the translation (x-3, y + 6)?
Answer:
I really don't understand much about math sometimes I need help
13B5Find the length of AC.A. AC = 3B. AC= 8C. AC = 12D. AC= 13.9
Question:
Find the length of AC.
Solution:
Applying the Pythagorean Theorem, we get:
[tex]AC\text{ = }\sqrt[]{CB^2_{}-AB^2}\text{ = }\sqrt[]{13^2_{}-5^2}[/tex]this is equivalent to:
[tex]AC\text{ = }\sqrt[]{13^2_{}-5^2}\text{ = }\sqrt[]{144}=12[/tex]then, we can conclude that the length of AC side is:
[tex]AC\text{ }=12[/tex]
which phrase best describesuse the commutative property to simplify the expression 1/4 + 1/3 + 3/4 communisim
By using commutative property the result after solving expression (1/4 + 1/3 + 3/4) will be 7/4.
What is the commutative property of addition?
The commutative property of addition for three numbers is given by -
a + (b + c) = (a + b) + c
Given is the following expression -
1/4 + 1/3 + 3/4
We have the following expression -
1/4 + 1/3 + 3/4
Now, lets solve the expression by adding first two terms first and than add the third term to result of the addition of first two terms. Mathematically -
(1/4 + 1/3) + 3/4
Let (1/4 + 3/4) = K
Than the expression becomes -
K + 3/4
Now, first solve K, we will get -
K = 1/4 + 3/4
K = 4/4 = 1
Now, adding the resultant [K] to third term -
1 + 3/4
1/1 + 3/4
(4 + 3)/4
7/4
So, using commutative property, we have solved the expression (1/4 + 1/3 + 3/4) and the final value will be 7/4.
Therefore, by using commutative property the result after solving expression (1/4 + 1/3 + 3/4) will be 7/4.
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express this number in standard form:[tex]1.304 \times {10}^{7} [/tex]
To write this in standard form, we need to look at the power of 10. In this case, it's a 7. Then, we need to shift the decimal point 7 places to the right:
[tex]1.304\cdot10^7=13,040,000[/tex]We can see that behind the 1 (where was the decimal point before) now there are 7 numbers, then what we do is correct.
I need help. The answers has to be exact so I can’t use decimals
Answer
The exact value of the lateral surface area = 395 cm²
The exact value of the total surface area = 572 cm²
Explanation
The solid shape is a cone with a height of 15 cm and the diameter of the base of the solid shape is 15 cm.
The Lateral Surface Area of the Solid Shape:
The formula to calculate the lateral surface area (LSA) of a cone is given by:
[tex]LSA=π(radius\times length)[/tex]The radius will be = diameter/2 = 15cm/2 = 7.5 cm
To find legth, we use Pythagoras rule:
[tex]\begin{gathered} l^2=h^2+r^2 \\ \\ l^2=15^2+7.5^2 \\ \\ l^2=225+56.25=281.25 \\ \\ l=\sqrt{281.25} \\ \\ l=16.77cm \end{gathered}[/tex]Put π = 3.14, r = 7.5 cm, and l = 16.77 cm into the lateral surface area formula:
[tex]\begin{gathered} LSA=3.14\times7.5cm\times16.77cm \\ \\ LSA=394.93\text{ }cm^2 \\ \\ LSA\approx395\text{ }cm^2 \end{gathered}[/tex]Therefore, The exact value of the lateral surface area = 395 cm²
Total Surface Area of the Solid Shape:
To find the exact value for the total surface area of the solid shape, we use the total surface area (TSA) formula of a cone which is:
[tex]TSA=\pi r^2+\pi rl[/tex]put π = 3.14, r = 7.5 cm, and l = 16.77 cm
[tex]\begin{gathered} TSA=(3.14\times(7.5cm)^2)+(3.14\times7.5cm\times16.77cm) \\ \\ TSA=176.63cm^2+394.93cm^2 \\ \\ TSA=571.56cm^2 \\ \\ TSA\approx572\text{ }cm^2 \end{gathered}[/tex]The exact value of the total surface area = 572 cm²
Write two equivalent fractions.
2/3
Answer:
5/10
15/30
Step-by-step explanation:
The triangles are similar, so the lengths of corresponding sides are in the same ratio.
One pair of corresponding sides is 5 and 10.
10 is twice 5.
5/10
The other pair of corresponding sides is 15 and ?.
? must be twice 15, so ? is 30.
15/30
A recipe for trail mix requires 5/6 cup of raisins for 1 batch. Alaina 1 2/3 cups of rasisins to make trial mic Enter tje number of batches of trial mix Alaina makes.
SOLUTION :
Step 1 :
In this question, we have that the recipe for trail mix requires
5/6 cup of raisins for 1 batch.
Then, Alaina uses
[tex]1\text{ }\frac{2}{3}\text{ cups of raisins to make trial mix.}[/tex]Step 2 :
To get the number of batches of trial mix Alaina makes, we have that :
[tex]\begin{gathered} 1\text{ }\frac{2}{3\text{ }}\text{ divided by }\frac{\text{ 5}}{6} \\ \frac{5}{3}\text{ x }\frac{6}{5}\text{ = }\frac{30}{15}\text{ = 2 batches} \end{gathered}[/tex]CONCLUSION :
There would be 2 batches .
Write the next 5 terms of this sequence. Given: a1=3 and d = 5
To find the number of term, we will use the formula;
[tex]U_{n\text{ = }}a+(n-1)d[/tex]when n= 1
[tex]U_1=\text{ 3 + (1-1)5}[/tex][tex]=\text{ 3+0}=3[/tex]for the second term
n = 2
[tex]U_2=\text{ 3 + (2-1)5}[/tex]= 3 + 5
=8
For n= 3
[tex]U_3=3+\text{ (3-1)5}[/tex]=3 + 2(5)
=3 + 10
=13
For n=4
[tex]U_4=3+(4-1)5[/tex]=3+3(5)
= 3 + 15
= 18
For n= 5
[tex]U_5=3+(5-1)5[/tex]= 3 + 4(5)
= 3 + 20
= 23
Therefore, the terms; 3, 8, 13, 18 and 23
please help me solve now
Answer:
(3000/(5-3))(3+5)
= (3000/2) 8
= 12000
Step-by-step explanation:
The weight (W kg) of a decaying radio active substance after n years is given by W= Wo(1/2)^n/100, where Wo kg is the initial weight of the substance. 1. Find the number of years for the radioactive substance to decay to half of its initial weight.
We have the equation:
[tex]W=W_0(\frac{1}{2})^{\frac{n}{100}}[/tex]And we want to find the value n, correspondign to the number of years necessary in order to the substance to decay in half.
Let's say that we have 1 Kg of the substance, this is Wo, the initial weight. Since we want to find the the decay of half the substance we use W = 1/2
And write:
[tex]\frac{1}{2}=1\cdot(\frac{1}{2})^{\frac{n}{100}}[/tex]Now we can use a property of logarithms:
[tex]\ln (a^b)=b\ln (a)[/tex]Thus applying natural log on both sides:
[tex]\ln (\frac{1}{2})=\ln (\frac{1}{2}^{\frac{n}{100}})[/tex]By the property:
[tex]\ln (\frac{1}{2})=\frac{n}{100}\ln (\frac{1}{2}^{})[/tex]We can divide on both sides by ln(1/2):
[tex]\begin{gathered} 1=\frac{n}{100} \\ n=100 \end{gathered}[/tex]The number of years for the radioactive substance to decay to half its initial weigh are 100 years.
The step to get rid of the ln(1/2) is:
[tex]\begin{gathered} \ln (\frac{1}{2})=\frac{n}{100}\ln (\frac{1}{2}^{}) \\ \frac{\ln (\frac{1}{2})}{\ln (\frac{1}{2})}=\frac{n}{100}\frac{\ln (\frac{1}{2}^{})}{\ln (\frac{1}{2})} \\ 1=\frac{n}{100}\cdot1 \\ 1=\frac{n}{100} \end{gathered}[/tex]
PLEASE HELP!!!
Can someone help me out with this math problem.(CALCULUS 2)
picture of problem attached below.
The centre of mass of 40g, (1,3); 30g, (2,-1); 70g, (0,0) and 50g (0,-2) is located at (10/19,-1/19).
The formula to find the coordinates (X,Y) of centre of mass of a discrete particles system is,
X = (m₁x₁+m₂x₂+m₃x₃+m₄x₄)/(m₁+m₂+m₃+m₄)
Y = (m₁y₁+m₂y₂+m₃y₃+m₄y₄)/(m₁+m₂+m₃+m₄)
As we know,
m = 40
m = 30
m = 70
m = 50
Putting all the values in the formula,
for X coordinate,
X = [(40×1)+(30×2)+(70×0)+(50×0)]/(40+30+70+50)
X =(40+60+0+0)/(190)
X = 100/190
X = 10/19
For Y coordinate,
Y = [(40×3)+(30×-1)+(70×0)+(50×-2)]/(40+30+70+50)
Y= (120-30+0-100)/(190)
Y = -10/190
Y = -1/19
So, the centre of mass of the discrete particle system is at (10/19,-1/19)
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Help with number 1 pls make sure when you’re done to highlight the answer in bold
Answer:
Step-by-step explanation:
[tex]undefined[/tex]According to the histogram, how many students live between 1 and 1.9 miles from school?
ANSWER
B. 25
EXPLANATION
We want to identify the number of students that live between 1 and 1.9 miles from school.
To do this, we have check the frequency corresponding to the bar for 1 - 1.9 miles on the frequency axis.
From the histogram, we see that the number of students that live between 1 and 1.9 miles from the school is 25.
The correct answer is option B.
can you help me with this place
The diameter of Keisha's favorite marble is 2.5cm
The radius of the sphere is the half of the diameter : Radius = Diameter/2
Given diameter of marble = 2.5 cm
So, radius = diameter/2
Radius of the marble = 2.5/2
Radius of the marble = 1.25 cm
The general expression for the volume of sphere with radius 'r' is :
[tex]\text{ Volume of Sphere =}\frac{4}{3}\Pi\times radius^3[/tex]So, the volume of one sphere is :
Substitute the value of r = 1.25 cm
[tex]\begin{gathered} \text{ Volume of Sphere =}\frac{4}{3}\Pi\times radius^3 \\ \text{ Volume of Sphere =}\frac{4}{3}\times3.14\times1.25^3 \\ \text{ Volume of Sphere = 8.18 cm}^3 \end{gathered}[/tex]As, Keisha take 6 marbles
So, the volume of 6 marbles = 8.18 x 6
Volume of 6 marbles = 49.08 cm³
It is given that : 1 cubic centimeter has the massof 2.6 grams
1 cm³ = 2.6 gm
As the volume of 6 marbles is 49.08cm³
So, The mass of 49.08cm³ = 49.08 x 2.6
The mass of 6 marbles = 127.608 gm
127.608 to the nearest whole number is 128
Mass of the 6 marbles is 128 gm
Answer : 128 gm
Help in solving question 5 please. System needs to be solved using the elimination method. Thanks!
Given: A system of linear equations in three variables x, y, and z as follows-
[tex]\begin{gathered} 2x+y-z=9 \\ -x+6y+2z=-17 \\ 5x+7y+z=4 \end{gathered}[/tex]Required: To solve the system using elimination.
Explanation: Let the given system as-
[tex]\begin{gathered} 2x+y-z=9\text{ ...}(1) \\ -x+6y+2z=-17\text{ ...}(2) \\ 5x+7y+z=4\text{ ...\lparen3\rparen} \end{gathered}[/tex]We can solve the system by reducing the system to a system of 2 variables. Suppose we would like to remove the variable z.
Multiplying equation (1) by 2, adding to equation (2) as follows-
[tex]\begin{gathered} (4x+2y-2z)+(-x+6y+2z)=18+(-17) \\ 3x+8y=1\text{ ...}(4) \end{gathered}[/tex]Now, add equations (1) and (3) as follows-
[tex]\begin{gathered} (2x+y-z)+(5x+7y+z)=9+4 \\ 7x+8y=13\text{ ...}(5) \end{gathered}[/tex]Now, equations (4) and (5) represent a system of linear equations in two variables. Subtracting the equations as follows-
[tex]\begin{gathered} (3x+8y)-(7x+8y)=1-13 \\ -4x=-12 \\ x=3 \end{gathered}[/tex]Substituting x=3 in equation (4)-
[tex]\begin{gathered} 9+8y=1 \\ 8y=-8 \\ y=-1 \end{gathered}[/tex]Substituting x=3 and y=-1 in equation (1) as follows-
[tex]\begin{gathered} 6-1-z=9 \\ z=-4 \end{gathered}[/tex]Final Answer: The solution to the system is-
[tex]\begin{gathered} x=3 \\ y=-1 \\ z=-4 \end{gathered}[/tex]Factor: x^6-5x^4-5+x
The value of the given expression x^6 -5x^4 - 5 + x simplified as; x^4(x^2 - 5) - (5 + x)
How to factor the expression?The statement is given as ;
Factor: [tex]x^6 -5x^4 - 5 + x[/tex]
From the given expression, we have
[tex]x^6 -5x^4 - 5 + x[/tex]
Group the expression in two part;
So, we have;
[tex]x^6 -5x^4 - 5 + x = (x^6 - 5x^4) - (5 + x)[/tex]
Now Factorize each group of the expression;
[tex]x^6 -5x^4 - 5 + x = x^4(x^2 - 5) - (5 + x)[/tex]
The given expression cannot be further simplified.
Hence, the value of [tex]x^6 -5x^4 - 5 + x is x^4(x^2 - 5) - (5 + x)[/tex]
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Write an equation of a line that passes through the point (7, 3) and is parallel to the line y = negative 2 over 3 x + 3.
We are asked to determine the equation of a line that is parallel to:
[tex]y=-\frac{2}{3}x+3[/tex]Two lines are parallel if their slopes are in the following relationship:
[tex]m_2=-\frac{1}{m_1}[/tex]Therefore, if m1 is the slope of the given line and m2 is the slope of the parallel line we may determine the value of the slope of the parallel line by replacing it in the relationship. Let's remember that when a line is written in the form:
[tex]y=mx+b[/tex]Where "m" is the slope. Therefore, m1 is -2/3. Replacing in the relationship we get:
[tex]m_2=-\frac{1}{-\frac{2}{3}}=\frac{3}{2}[/tex]Now, we go back to the general form of a line equation and replace the value of the new slope:
[tex]y=\frac{3}{2}x+b[/tex]The value "b" is the y-intercept and can be found using the point through which the line passes:
[tex]3=\frac{3}{2}(7)+b[/tex]Now we solve the operations:
[tex]3=\frac{21}{2}+b[/tex]Subtracting 21/2 from both sides:
[tex]3-\frac{21}{2}=b[/tex]Solving the operations:
[tex]-\frac{15}{2}=b[/tex]Now we replace in the line equation:
[tex]y=\frac{3}{2}x-\frac{15}{2}[/tex]And thus we get the equation of the parallel line.
Andrew has $9,000 in a savings account that earns 5% interest per year. How much will he have including interest in 1 year?
Andrew will have $9,450 in his savings account that earns 5% interest per year.
According to the question,
We have the following information:
Principal amount in Andrew's savings account = $9,000
Interest rate = 5% per year
Time = 1 year
We know that we use the following formula to find the simple interest on any amount:
Simple interest = (principal*rate*time)/100
Simple interest = (9000*1*5)/100
Simple interest = $450
Now, the total amount in his savings account will be the sum of the amount earned from the interest and the principal amount submitted by him.
Total amount = interest+principal
Total amount = 450+9000
Total amount = $9,450
Hence, he will have $9,450 in his savings account.
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The dollar value v(t) of a certain car model that is t years old is given by the following exponential function.v(t) = 19, 900 * (0.84) ^ tRound your answers to the nearest dollar as necessary.Find the initial value of the car and the value after 11 years.
Given
[tex]v(t)=19900(0.84)^t[/tex]a) The car has its original (initial) value when no time has passed since it was bought; in other words t=0. Then,
[tex]\text{ initial value: }v(0)=19900(0.84)^0=19900*1=19900[/tex]The initial value is 19900.
b) After 11 years, t=11; then,
[tex]\begin{gathered} v(11)=19900(0.84)^{11}=2923.64894... \\ \Rightarrow v(11)\approx2924 \end{gathered}[/tex]Rounded to the nearest tenth, the second answer is 2924
Solve the system of equations.y= x2 + 3x - 4y = 2x - 4A. (-1,6) and (0,4)O B. (-1,-6) and (0, -4)C. (0,-4) and (1, -2)O D. (0,4) and (1,-6)
Answer:
(0,-4) and (-1,-6) or B
Step-by-step explanation:
Notice that equation 1 and equation 2 are both equal to y.
Substitute equation 2 into equation 1:
[tex]2x-4=x^2+3x-4[/tex]
Simplify:
[tex]x^2+x=0[/tex]
Factor:
[tex]x(x+1)=0[/tex]
Notice that the zeros for x are x = 0 and x = -1.
Now plug both values into either equation 1 or 2 to find y:
[tex]y=0^2+3(0)-4 = -4[/tex]
[tex]y=(-1)^2+3(-1)-4=-6[/tex]
Therefore, our values are (0,-4) and (-1,-6) or option B