Find the length of AB.
AB= [ ? ]in

Answer:

-36x+9

Step-by-step explanation:

so for this question they want you to simplify the expression and to do that you distribute -12 to what is in the parenthesis

-12x3x=-36x

-12x-3/4=9

so the answer is -36x+9

have a great day :D

Answer:

60

Explanation:

the formula for calculating the average grade would be the total score of all students ÷ the number of students. in this case, that would be:

(100 + 50 + 50 + 50 + 50) ÷ 5

= 300 ÷ 5

= 60

so, the average grade is 60.

i hope this helps! :D

Answer:

huh?

Step-by-step explanation:

Is this a question or what??

Answer:

It's called the cross multiply rule. The rule is shown below: This formula says that if the numerator of one fraction times the denominator of the other fraction equals the denominator of the first fraction times the numerator of the second fraction, then the fractions are equivalent.

Step-by-step explanation:

Answer:

The solution is (-4,-1)

Step-by-step explanation:

The solution to the system is where the two graphs intersect.

The lines intersect at x = -4 and y = -1

The solution is (-4,-1)

Answer:

SO WE KNOW THE RADIUS OF EACH SEMI CIRCLE IS 45. SO NOW :

YOU ARE GOING TO ADD THE AREA OF BOTH HALF CIRCLES TO THE AREA OF THE RECTANGLE.

= 26,217FT SQ.

Answer:

C, 19858.5 [tex]ft^2[/tex]

Step-by-step explanation:

Imagine that these are two semi-circles on either side of a rectangle

the diameter of the semi circle is 90, and the radius is half of the diameter.

this means the radius is 45 (for both circles)

so now lets apply that to the area of a full circle, [tex]\pi r^2[/tex]

replace r with the radius [tex]\pi 45^2[/tex]

using 3.14 as pi, your answer should be 6358.5

but now remember that his is the area of a full circle, not a semi circle, so we must divide by 2 to get the semi circle area, which would then be 3179.25

since there's two semi circles, you would multiply this by two and now you're back to 6358.5

if that was confusing you can think of it as a full circle split into two parts on either side of the rectangle rather than two semicircles, so the two split pieces would add together to make the area of a full circle

now calculate the area of the rectangle, which is length times width

150 * 90 = 13500

so add the area of the rectangle to the area of the two semicircles and the answer is 19,858.5 :)

Answer: 93 centimeters

Step-by-step explanation:  Its 93 cm because 2 metres is equivalent 200 cm, so 200-107= 93.

Answer:

13.2

Step-by-step explanation:

hope this helped

Answer:

13 3/4

Step-by-step explanation:

11 x 5/4 = 55/4 = 13 3/4

check:

13 3/4 x 4/5 = 55/4 x 4/5 = 210/20 = 11

Answer:

i think the answer is 174

Answer:

x=2

Step-by-step explanation:

divide -5 to both sides to isolate the x. two negatives make a positive therefore x=2.

i hope this helps :)

Answer:

2

Step-by-step explanation:

-10 divided by -5 is 2. Therefore, x=2.

Answer:

75

Step-by-step explanation:

Answer:

r * 10

Step-by-step explanation:

* stands for multiplying.

Answer:

100

Step-by-step explanation:

399/100= 3.99

im honestly not sure how to explain it.

Answer:

C

Step-by-step explanation:

Answer:

See bolded below.

Step-by-step explanation:

As you said, you only need help with no. 2:

a) Check the attachments for the lines

b) The equations are, respectively:

y = -4x + 1 [intersects parabola at 1 point]

Check:

[tex]\begin{bmatrix}y=\left(x-2\right)^2-3\\ y=-4x+1\end{bmatrix}[/tex]

[tex]\begin{bmatrix}-4x+1=\left(x-2\right)^2-3\end{bmatrix}[/tex]

[tex]\begin{bmatrix}-4x+1=x^2-4x+1\end{bmatrix}[/tex]

[tex]x^2=0, x = 0[/tex]

[tex]y=-4\cdot \:0+1 = 1[/tex]

[tex]y=1,\:x=0[/tex]

The point of intersection would be (0, 1)

y = -4x + 3 [intersects parabola at 2 points]

Check:

[tex]\begin{bmatrix}y=\left(x-2\right)^2-3\\ y=-4x+3\end{bmatrix}[/tex]

Subtract the 2 equations,

[tex]y=\left(x-2\right)^2-3\\-\\\underline{y=-4x+3}\\y-y=\left(x-2\right)^2-3-\left(-4x+3\right),\\0=x^2-2\\x = \sqrt{2}, x = - \sqrt{2} \\\\\mathrm{Plug\:the\:solutions\:}x=\sqrt{2},\:x=-\sqrt{2}\mathrm{\:into\:}y=\left(x-2\right)^2-3[/tex]

[tex]\begin{pmatrix}x=\sqrt{2},\:&y=3-4\sqrt{2}\\ x=-\sqrt{2},\:&y=3+4\sqrt{2}\end{pmatrix}[/tex]

Therefore the points of intersection are (√2, 3-4√2) and (-√2, 3+4√2) respectively

And finally we have the equation y = - 4x. It doesn't intersect the parabola.

c) The y-intercepts of such graphs are all less than or equal to 0.

Answer:

Insurance cost (last year)= £387.5

Step-by-step explanation:

Giving the following information:

Insurance cost= £465

Increase growth rate= 20% = 0.2

To calculate the cost of insurance last year, we need to use the following formula:

Insurance cost (last year)= insurance cost / (1 + insurance growth rate)

Insurance cost (last year)= 465 / (1 + 0.2)

Insurance cost (last year)= £387.5

The amount that Adele pay last year was:£387.5.

Using this formula

Amount paid= Insurance cost / (1 + Insurance growth rate percentage)

Where:

Insurance cost= £465

Increase growth rate percentage=20% or 0.20

Let plug in the formula

Amount paid= £465 / (1 + 0.20)

Amount paid= £465/1.20

Amount paid= £387.5

Inconclusion the amount that Adele pay last year was:£387.5.

Learn more about insurance here:https://brainly.com/question/25855858

Answer:

Up and to the left.

Step-by-step explanation:

I checked it on desmos graphing calculator

Answer:

1/6 inch per hour

Step-by-step explanation:

1/2 ÷3= 1/6

Answer:

C. 70 = 10x

E. 15x = 105

Step-by-step explanation:

x = 7

Using method of elimination;

A. X + 7 = 17

Substituting the value of x;

7 + 7 ≠ 17 (Incorrect option)

B. 7 = 17 - x

Substituting the value of x;

7 ≠ 17 - 7  (Incorrect option)

C. 70 = 10x

Substituting the value of x;

70 = 10 * 7  (Correct option)

D. X/35 = 5

Substituting the value of x;

7 / 35 ≠ 5  (Incorrect option)

E. 15x = 105

Substituting the value of x;

15 * 7 = 105  (Correct option)

Answer:

a) $520

b) $580

c) Interest amount is same each year

Step-by-step explanation:

Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals.

To find - a) How much money was in the account after one year?

              b) How much money was in the account after 4 years?

              c) Was the amount of money earned in interest the same or different each year?

Proof -

Here given that,

Principal amount = $500

rate of interest = 4% = 4/100 = 0.04

Now,

a)

Amount =  P [ 1 + RT ]

             = 500 [ 1 + 0.04(1)]

             = 500 [ 1 + 0.04] = 520

⇒Amount = $520

b)

Amount =  P [ 1 + RT ]

             = 500 [ 1 + 0.04(4)]

             = 500 [ 1 + 0.16] = 580

⇒Amount = $580

c)

In 2nd year,

Amount =  P [ 1 + RT ]

             = 500 [ 1 + 0.04(2)]

             = 500 [ 1 + 0.08] = 540

⇒Amount = $540

Now,

Interest in 1st year = 520 - 500 = 20

Interest in 2nd year = 540 - 520 = 20

So,

The interest amount  is same each year

Answer:

Let's call the number of boxes Maria started with:

There are 37 boxes

Step-by-step explanation:

Let's call the number of boxes Kayla started with:

Then we can write:

22

=

b

+

7

2

Where:

22

is the number of boxes Kayla has left.

(

b

+

7

)

is the number of boxes Kayla started with plus the

7

she bought

The division by

2

represents

1

2

of the total boxes Kayla had being destroyed by fire.

We can solve this by first multiplying each side of the equation by

2

to eliminate the fraction while keeping the equation balanced:

2

×

22

=

2

×

b

+

7

2

44

=

2

×

b

+

7

2

44

=

b

+

7

Now, subtract

7

from each side of the equation to solve for

b

while keeping the equation balanced:

44

−

7

=

b

+

7

−

7

37

=

b

+

0

37

=

b

b

=

37

Kayla started out with 37 boxes.

Answer:

$81.15

Step-by-step explanation:

Answer:

79

Step-by-step explanation:

Answer:

[tex]\angle EAB = 85[/tex]

Step-by-step explanation:

Given

[tex]\angle EBC = 148[/tex]

[tex]\angle ADC = 63[/tex]

See attachment for triangle

Required

Find EAB

[tex]\angle AEB = \angle ADC = 63[/tex]  --- corresponding angles

[tex]\angle ABE + \angle EBC = 180[/tex] --- angle on a straight line

So:

[tex]\angle ABE + 148 = 180[/tex]

This gives:

[tex]\angle ABE =- 148 + 180[/tex]

[tex]\angle ABE =32[/tex]

Considering: [tex]\triangle ABE[/tex]

[tex]\angle ABE +\angle AEB +\angle EAB = 180[/tex] --- angles ina triangle

So:

[tex]32 +63+\angle EAB = 180[/tex]

[tex]95+\angle EAB = 180[/tex]

Collect like terms

[tex]\angle EAB = 180-95[/tex]

[tex]\angle EAB = 85[/tex]

Answer:

look at the picture i sent............