g has a relative minimum and absolute minimum at (x,y) = (2, -36).
To find the exact location of all the relative and absolute extrema of the function g(x) = 9x^2 - 36x, follow these steps,
1. Find the derivative of g(x) with respect to x:
g'(x) = d(9x^2 - 36x)/dx = 18x - 36
2. Set g'(x) equal to 0 to find critical points:
18x - 36 = 0
18x = 36
x = 2
3. Determine the type of extrema (minimum or maximum) by analyzing the second derivative:
g''(x) = d^2(9x^2 - 36x)/dx^2 = 18
Since g''(x) is positive at x = 2, there is a relative minimum at this point.
4. Calculate the value of g(x) at the critical point:
g(2) = 9(2)^2 - 36(2) = 9(4) - 72 = 36 - 72 = -36
5. Summarize the findings:
g has a relative minimum at (x,y) = (2, -36), and since this is the only extrema of the function, it is also an absolute minimum.
g has a relative minimum and absolute minimum at (x,y) = (2, -36).
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Good morning, i really just had a simple question. I was solving this problem:
"Two children weighing 48 pounds and 72 pounds are going to
play on a seesaw that is 10 feet long."
And it basically was asking me for the equilibrium. I set the problem up like this:
M1=72, M2=48, X1=0, X2=10
X=(72(0)+48(10))/72+48= 480/120
Answer:4 ft
but when i checked the answer, it was 6ft, due to M1= 48, so my question is.....why does the smaller child(48lbs) become M1 as to him being M2
Answer: Your answer is completely correct. It is just that when answering the question, you should assume that the 48 lb child is on the left, and the 72 lb child is on the right. Usually, I always assume that the first mentioned item is the left most one.
Step-by-step explanation:
This is how I will set up the problem: M1 = 48 lbs, M2 = 72 lbs, L = 10 ft
Since (M1 * 0 + M2 * 10)/(M1+M2) = equilibrium, we can use this equation to find the solution:
0 + 720 / (48+72) = 6 feet
let x be a discrete random variable. if pr(x<6) = 3/9, and pr(x<=6) = 7/18, then what is pr(x=6)?
Let x be a discrete random variable. If Pr(x < 6) = 3/9, and Pr(x ≤ 6) = 7/18, then P(X = 6) is 0.06.
A discrete random variable is a variable that can take on only a countable number of values. Examples of discrete random variables include the number of heads when flipping a coin, the number of cars passing through an intersection in a given hour, or the number of students in a classroom.
Let x be a discrete random variable.
Pr(x < 6) = 3/9, and Pr(x ≤ 6) = 7/18
P(X ≤ 6) = P(X < 6) + P(X = 6)
Subtract P(X < 6) on both side, we get
P(X = 6) = P(X ≤ 6) - P(X < 6)
Substitute the values
P(X = 6) = 7/18 - 3/9
First equal the denominator
P(X = 6) = 7/18 - 6/18
P(X = 6) = 1/18
P(X = 6) = 0.06
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Given the equation 12x+ 17= 35, find the value of X
find the linear equation of the plane through the origin and the points (5,4,2) and (3,-1,1)
The linear equation of the plane through the origin and the points (5, 4, 2) and (3, -1, 1) is 6x + 1y - 17z = 0.
To find the linear equation of the plane through the origin and the points (5, 4, 2) and (3, -1, 1), you need to find a normal vector to the plane by taking the cross product of the position vectors of the two given points.
Position vector of point A(5, 4, 2): a = <5, 4, 2>
Position vector of point B(3, -1, 1): b = <3, -1, 1>
The cross product of a and b (normal vector to the plane): n = a × b
n = <(4*1 - 2*-1), (2*3 - 5*1), (5*-1 - 3*4)>
n = <4+2, 6-5, -5-12>
n = <6, 1, -17>
Now, the equation of the plane with normal vector n = <6, 1, -17> and passing through the origin (0, 0, 0) is given by: 6x + 1y - 17z = 0
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In the Picture. :) Ty
a) Amount of increase after the two years is: $6,772.5
b) The tuition fee after 10 years will cost approximately: $84957
How to solve exponential equation word problems?The general form of exponential growth equation is
y = a(1 + r)^x
where:
a = initial amount
r = growth rate
x = number of intervals
we are given:
Initial cost = $21000
Percentage increase = 15% in two years
Thus:
Amount in 2010 = 21000(1 + 0.15)²
= $27,772.5
Amount of increase = 27,772.5 - 21000 = $6,772.5
In ten years time, the tuition fee will be:
21000(1 + 0.15)¹⁰ = 84,956.71245 ≅ $84957
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determine whether the series ∑3ke−k28 converges or diverges.
The series ∑3ke − k/28 is a divergent series.
How to determine ∑3ke − k/28 is a divergent series?To determine whether the series ∑3ke − k/28 converges or diverges, we can use the ratio test.
The ratio test states that if lim┬(n→∞)|an+1/an|<1, then the series converges absolutely; if lim┬(n→∞)|an+1/an|>1, then the series diverges; and if lim┬(n→∞)|an+1/an|=1, then the test is inconclusive.
Let's apply the ratio test to our series:
|a(n + 1)/a(n)| = |3(n + 1) [tex]e^(^-^(^n^+^1^)/28) / (3n e^(^-^n^/^2^8^))|[/tex]
= |(n+1)/n| * |[tex]e^(^-^1^/^2^8^)[/tex]| * |3/3|
= (1 + 1/n) * [tex]e^(^-^1^/^2^8^)[/tex]
As n approaches infinity, the expression (1 + 1/n) approaches 1, and [tex]e^(^-^1^/^2^8^)[/tex] is a constant. Therefore, the limit of the ratio is 1.
Since the limit of the ratio test is equal to 1, the test is inconclusive. We need to use another method to determine convergence or divergence.
One possible method is to use the fact that [tex]e^x > x^2^/^2[/tex] for all x > 0. This implies that [tex]e^(^-^k^/^2^8^)[/tex] < [tex](28/k)^2^/^2[/tex] for all k > 0.
Therefore,
|a(k)| = 3k [tex]e^(^-^k^/^2^8^)[/tex] < 3k[tex](28/k)^2^/^2[/tex]
= 42k/k²
= 42/k
Since ∑1/k is a divergent series, we can use the comparison test to conclude that ∑|a(k)| diverges.
Therefore, the series ∑3ke − k/28 also diverges.
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what does a^8 • a^7 equal?
To multiply powers with the same base, add the exponents.
[tex] {a}^{8} {a}^{7} = {a}^{15} [/tex]
Assume that A is row equivalent to B. Find bases for Nul A and Col A. 106 4 A2-63 2B0 2 5 2 -24 2 11-6 -3 8 A basis for Col A is ! (Use a comma to separate vectors as needed.) A basis for Nul Ais (Use a comma to separate vectors as needed.)
the null space of A is the span of the vector:
(-2, 3, 1)
A basis for Nul A is:
{(-2, 3, 1)}
To find bases for Nul A and Col A, we can use the fact that A is row equivalent to B. This means that we can perform a sequence of elementary row operations on A to obtain B. Since elementary row operations do not change the null space or column space of a matrix, the null space and column space of A will be the same as the null space and column space of B.
To find a basis for Col A, we can find the pivot columns of A (or B, since they have the same column space). The pivot columns are the columns of A that contain a leading non-zero entry in the row reduced form of A. In this case, the row reduced form of A is:
1 0 0 -1
0 1 0 2
0 0 1 3
The pivot columns are columns 1, 2, and 3. Therefore, a basis for Col A is the set of corresponding columns from A:
{(1, 0, 2), (4, 2, 5), (2, -6, -3)}
To find a basis for Nul A, we can solve the homogeneous system Ax = 0. Since A is row equivalent to B, we can use the row reduced form of B to solve for x. The row reduced form of B is:
1 0 -2/53 0
0 1 3/53 0
0 0 0 1
The solution to the system Ax = 0 can be written in parametric form as:
x1 = 2/53 s
x2 = -3/53 s
x3 = s
where s is a scalar. Therefore, the null space of A is the span of the vector:
(-2, 3, 1)
A basis for Nul A is:
{(-2, 3, 1)}
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If the sampling distribution of the sample mean is normally distributed with n = 18, then calculate the probability that the sample mean falls between 75 and 77. (If appropriate, round final answer to 4 decimal places.)
multiple choice 2
-We cannot assume that the sampling distribution of the sample mean is normally distributed. Correct or Incorrect.
-We can assume that the sampling distribution of the sample mean is normally distributed and the probability that the sample mean falls between 75 and 77 . Correct or Incorrect.
We can assume that the sampling distribution of the sample mean is normally distributed and the probability that the sample mean falls between 75 and 77 is 0.4582 or 45.82%.
How to calculate sample mean?Sampling distribution of the sample mean is normally distributed
Use the standard normal distribution to evaluate the probability that the sample mean falls between 75 and 77.
First, lets calculate standard error of the mean:
SE = σ/√n
Since we are not given the population standard deviation (σ), we will use the sample standard deviation (s) as an estimate:
SE = s/√n
Next, we need to calculate the z-scores corresponding to 75 and 77:
z1 = (75 - x) / SE
z1 = (75 - x) / (s/√n)
z2 = (77 - x) / SE
z2 = (77 - x) / (s/√n)
Since the sampling distribution is normal, we can use a standard normal distribution table or a calculator to find the probabilities associated with these z-scores.
P(75 ≤ x ≤ 77) = P(z1 ≤ Z ≤ z2)
We find that:
P(-0.71 ≤ Z ≤ 0.71) = 0.4582
Therefore, the probability that the sample mean falls between 75 and 77 is 0.4582 or 45.82% (rounded to 4 decimal places).
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using intergral test to determine if series an = (x 1)/x^2 where n is in interval [1,inf] is convergent or divergent
To use the integral test to determine the convergence of the series an = [tex]\frac{x+1}{x^{2} }[/tex], we need to check if the corresponding improper integral converges or diverges.
The integral test states that if f(x) is a positive, continuous, and decreasing function on the interval [1,inf], and if the series an = f(n) for all n in the interval [1,inf], then the series and the integral from 1 to infinity of f(x) both converge or both diverge.
In this case, we have f(x) = [tex]\frac{x+1}{x^{2} }[/tex]. First, we need to check if f(x) is positive, continuous, and decreasing on the interval [1,inf]. f(x) is positive for all x > 0. f'(x) =[tex]\frac{-2x-1}{x^{3} }[/tex] , which is negative for all x > 0. Therefore, f(x) is decreasing on the interval [1,inf].
Next, we need to evaluate the improper integral from 1 to infinity of f(x): integral from 1 to infinity of [tex]\frac{x+1}{x^{2} }[/tex] dx = lim t->inf integral from 1 to t of [tex]\frac{x+1}{x^{2} }[/tex] dx = lim t->inf [tex][\frac{-1}{t}-\frac{1}{t^{2}+t }][/tex] = 0
Since the improper integral converges to 0, the series an also converges by the integral test. Therefore, the series an [tex]\frac{x+1}{x^{2} }[/tex] is convergent on the interval [1,inf].
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Find the surface area of the part of the cone z = sqrt(x2+y2) that lies between the plane y=x and the cylinder y=x2.
The surface area of the part of the cone z = sqrt(x2+y2) that lies between the plane y=x and the cylinder y=x2 is 2π/3 (3√3 - 2).
The surface area of a parametric surface given by:
S = ∫∫ ||r_u x r_v|| dA,
where r(u,v) is the vector-valued function.
Since the cone is symmetric around the z-axis, θ varies from 0 to 2π. ρ varies from y to ρ = z. Since z = √(x^2 + y^2), we have ρ = √(x^2 + y^2
The parameterization of the surface:
r(ρ, θ) = (ρ cos θ, ρ sin θ, ρ), for x^2 + y^2 ≤ y and 0 ≤ θ ≤ 2π.
The partial derivatives, we have:
r_ρ = (cos θ, sin θ, 1)
r_θ = (-ρ sin θ, ρ cos θ, 0)
The surface area element:
dA = ||r_ρ x r_θ|| dρ dθ
= ||(-ρ cos θ, -ρ sin θ, ρ)|| dρ dθ
= ρ √(2 + ρ^2) dρ dθ
So,
S = ∫∫ ||r_u x r_v|| dA
= ∫0^1 ∫0^2π ρ √(2 + ρ^2) dθ dρ
= 2π ∫0^1 ρ √(2 + ρ^2) dρ
= [1/3 (2 + ρ^2)^(3/2)]_0^1
= 2π/3 (3√3 - 2)
Therefore, the surface area of the part of the cone z = √(x^2 + y^2) that lies between the plane y = x and the cylinder y = x^2 is 2π/3 (3√3 - 2).
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when testing partial correlation, the impact of a third variable is ______.a. addedb. removedc. deletedd. reduced
When testing partial correlation, the impact of a third variable is removed.
Partial correlation is a statistical technique used to measure the relationship between two variables while controlling for the effect of one or more additional variables, known as "covariates" or "control variables." By removing the effect of the covariates, the partial correlation measures the direct relationship between the two variables of interest. This technique is useful when we want to examine the relationship between two variables after accounting for the effect of one or more confounding variables.
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PLEASE HELP, ITS TIMED LIKE SERIOUSLY HELP ITS FOR 40 POINTS
Answer:
A
Step-by-step explanation:
Draw the following segment after a 180° rotation about the origin.
X
5
In Mathematics and Geometry, the rotation of a point 180° about the origin in a clockwise or counterclockwise direction would produce a point that has these coordinates (-x, -y).
Furthermore, the mapping rule for the rotation of a geometric figure about the origin is given by this mathematical expression:
(x, y) → (-x, -y)
Coordinates of point A (2, 1) → Coordinates of point A' = (-2, -1)
Coordinates of point B (4, -5) → Coordinates of point B' = (-4, 5)
In conclusion, this transformation rule (x, y) → (-x, -y) is used for the rotation of a geometric figure about the origin in a clockwise or counterclockwise (anticlockwise) direction.
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If X and Y are mutually exclusive events with P(X) = 0.295, P(Y) = 0.32, then P(X ½ Y) =
a. 0.0000 b. 0.6150 c. 1.0000 d. 0.0944
The answer is b. 0.6150. Since X and Y are mutually exclusive events, they cannot occur at the same time. Therefore, P(X ½ Y) = P(X or Y) = P(X) + P(Y) = 0.295 + 0.32 = 0.6150.
If X and Y are mutually exclusive events, it means they cannot occur at the same time. In this case, P(X) = 0.295 and P(Y) = 0.32. The probability of the union of two mutually exclusive events, denoted as P(X ∪ Y), is the sum of their individual probabilities. Therefore, P(X ∪ Y) = P(X) + P(Y) = 0.295 + 0.32 = 0.615. So, the answer is: b. 0.6150
Probability distribution refers to a type of probability distribution in which the probability distribution is defined by the probability distribution's parameters. The parameters are usually numeric values that define the distribution's probability density function (PDF) or probability mass function (PMF).The probability distribution is usually used to model a population's characteristics.
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Find a power series representation for the function. f(x) = x/36 + x^2 f(x) = sigma^infinity_n=0 () Determine the interval of convergence.
A power series representation for the function f(x) =[tex]x/36 + x^2[/tex] is Σ((1/36) * [tex]x^n[/tex]) from n=1 to infinity + Σ[tex](x^{(2n)})[/tex] from n=0 to infinity and its interval of convergence is -1 < x < 1.
To find a power series representation for f(x), we'll rewrite it as a sum of power series:
f(x) = [tex]x/36 + x^2[/tex]
f(x) = (1/36) * [tex]x + x^2[/tex]
f(x) = Σ((1/36) * [tex]x^n[/tex]) from n=1 to infinity + Σ[tex](x^{(2n)})[/tex] from n=0 to infinity
Now let's find the interval of convergence for the given power series. We'll use the Ratio Test:
For the first power series, let a_n = (1/36) * [tex]x^n[/tex]:
lim (n→∞) (|a_(n+1)/a_n|) = lim (n→∞) (|[tex](x^{(n+1)[/tex])/(36 * [tex]x^n[/tex])|) = |x|/36
For the second power series, let b_n = [tex]x^{2n[/tex]:
lim (n→∞) (|b_(n+1)/b_n|) = lim (n→∞) [tex](|(x^{(2(n+1)}))/(x^{(2n)})|) = |x|^2[/tex]
The interval of convergence is where both series converge. The first series converges when |x|/36 < 1, or -36 < x < 36. The second series converges when [tex]|x|^2[/tex] < 1, or -1 < x < 1. Therefore, the interval of convergence for f(x) is:
-1 < x < 1
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QUADRATIC FUNCTIONS: The profit (in hundreds of dollars) that a corporation receives depends on the amount (in hundreds of dollars) the company spends on marketing according to the model 130+10X−0.5x2130+10X−0.5x2. What expenditure for advertising yields a maximum profit? What is the mathematical name of this point?
PROBLEM 4: POLYNOMIAL FUNCTIONS: Let f(x)=4x5−8x4−5x3+10x2+x−1f(x)=4x5−8x4−5x3+10x2+x−1. The graph is presented below:
Describe f (x) in terms of
Degree of polynomial
Main coefficient
Final behavior
Maximum number of zeros
Maximum number of exchange points (relative maximums and minimums)
Step-by-step explanation:
The profit (in hundreds of dollars) that a corporation receives is given by the quadratic function:
P(x) = 130 + 10x - 0.5x^2
where x is the amount spent on marketing (in hundreds of dollars).
To find the expenditure for advertising that yields a maximum profit, we need to find the vertex of the parabola. The vertex occurs at:
x = -b/(2a) = -10/(2*(-0.5)) = 10
Substituting x = 10 back into the equation for P(x), we get:
P(10) = 130 + 10(10) - 0.5(10)^2 = 180
Therefore, an expenditure of $1000 for advertising yields a maximum profit of $18000.
The mathematical name of the point is the vertex of the parabola.
---
For the polynomial function:
f(x) = 4x^5 - 8x^4 - 5x^3 + 10x^2 + x - 1
Degree of polynomial: 5
Main coefficient: 4 (the leading coefficient)
Final behavior: As x approaches positive or negative infinity, f(x) also approaches positive infinity (since the leading term has a positive coefficient and has the highest degree).
Maximum number of zeros: 5 (since it is a fifth-degree polynomial)
Maximum number of exchange points: 4 (since there are 4 relative extrema, either maximum or minimum points)
let a = 1 a a2 1 b b2 1 c c2 . then det(a) is
The determinant of the given matrix a is: det(a) = b2c2 + a2c2 + a2b2 - 2a2b2 - 2a2c2 + 2abc.
The determinant of a 3x3 matrix can be found using the formula:
det(A) = a11(a22a33 - a32a23) - a12(a21a33 - a31a23) + a13(a21a32 - a31a22)
Substituting the given matrix values, we get:
det(a) = 1(b2c2 - c(b2) + a2(c2) - c(a2) + a(b2) - a(b2)) - a(1c2 - c1 + a2c - c(a2) + a - a(a2)) + a(1b2 - b1 + a(b2) - b(a2) + a - a(b2))
Simplifying this expression, we get:
det(a) = b2c2 + a2c2 + a2b2 - a2b2 - b2c - a2c - a2b + a2c + abc - abc - a2c + ac2 + ab2 - ab2 - abc
Simplifying further, we get:
det(a) = b2c2 + a2c2 + a2b2 - 2a2b2 - 2a2c2 + 2abc
Thus, the determinant of the given matrix a is:
det(a) = b2c2 + a2c2 + a2b2 - 2a2b2 - 2a2c2 + 2abc.
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Let {N(t), t 0} be a Poisson process with rate λ. Let Sn denote the time of the nth event. Find:
(a) E[Sn]
(b) E[S4|N(1) = 2]
(c) E[N(4) − N(2)|N(1) = 3]
(a) E[Sn] = n/λ.
(b) E[S4|N(1)=2] = 1/λ + 3/λ
(c) E[N(4) - N(2)|N(1)=3] = 2λ.
(a) The expected time of the nth event, E[Sn], is the sum of expected interarrival times. Since each interarrival time has an exponential distribution with mean 1/λ, we have E[Sn] = n/λ.
(b) Given N(1)=2, we know two events occurred in the first unit of time. So, we want the expected time for the next two events (i.e., 4th event). Each interarrival time has mean 1/λ, so E[S4|N(1)=2] = 1/λ + 3/λ.
(c) Given N(1)=3, we want the expected number of events in the interval (2, 4) independent of the events in the interval (0, 1). Since it's a Poisson process, we have E[N(4) - N(2)|N(1)=3] = (4-2)λ = 2λ.
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Write the letter of the graph that shows the correct end behavior of the function.
For the function f(x) = -4x^3 + 5x^2 + 2x, the end behavior can be determined by looking at the degree and leading coefficient of the polynomial. Since the degree is odd and the leading coefficient is negative, the end behavior of the function will be downward in both the left and right quadrants. Therefore, the graph would be D) the arrow points downwards in the lower left and lower right quadrants.
For the function f(x) = (2x-3)(x+1), the end behavior can be determined by looking at the degree of the polynomial. Since the degree is 2, the end behavior will be the same as that of a quadratic function, which means that the graph will either be an upward or downward parabola. In this case, the graph would be A) the arrow points upwards in the upper left quadrant and downwards in the lower right quadrant, because the leading coefficient is positive.
For the function f(x) = 3x - 1, the end behavior is a straight line with a slope of 3. The arrow would be pointing upwards in both the left and right quadrants, so the graph would be B) the arrow points upwards in the upper left quadrant as well as in the upper right quadrant.
C) the arrow points upwards in the upper right quadrant and downwards in the lower left quadrant
This is because the function f(x) = -5x^2 (x+1) (x+3) is a cubic function with a leading coefficient of -5, which means that the end behavior of the function will be downward in the lower left quadrant and upward in the upper right quadrant.
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Pls help (part 3)
Give step by step explanation!
The total area to be painted is 886.5 cm².
The volume of the object is 1,834.5 cm³.
What is the total area to be painted?
The total area to be painted is calculated by subtracting the area of he circular hole from total surface area of the prism.
Total area of the prism is calculated as;
S.A = bl + (s₁ + s₂ + s₃)l
where;
b is the base of the trianglel is the length of the triangles is the faces of the triangleS.A = (16 x 20) + (16 + 17 + 17) x 20
S.A = 1,320 cm²
The circular area of the hole is calculated as;
A = 2πr(r + h)
A =2π x 3(3 + 20)
A = 433.54 cm²
Area to be painted = 1,320 cm² - 433.54 cm² = 886.5 cm²
The volume of the object is calculated as;
V = (¹/₂blh) - πr²h
V = (¹/₂ x 16 x 20 x 15) - π(3)²(20)
V = 1,834.5 cm³
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The following data were obtained from a repeated-measures research study. What is the value of MD for these data?
Subject 1st 2nd
#1 10 15
#2 4 8
#3 7 5
#4 6 11
Group of answer choices
4
3.5
3
4.5
Hi! The value of MD for these data taken from a repeated-measures is 3.
To find the value of MD (Mean Difference) for the data from a repeated-measures research study, you need to follow these steps:
1. Calculate the difference between the 1st and 2nd scores for each subject.
2. Calculate the average of these differences.
Here are the steps applied to your data:
Subject 1st 2nd Difference (2nd - 1st)
#1 10 15 5
#2 4 8 4
#3 7 5 -2
#4 6 11 5
Now, calculate the average of the differences:
(5 + 4 - 2 + 5) / 4 = 12 / 4 = 3
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HELP PLEASE
What is the surface area of the pyramid
(A) 38 cm2
(B) 76 cm2
(C) 100 cm2
(D) 152 cm2
Answer:
(B) 76 cm2 or (C) 100 cm2 if it's incorrect SorryHave a Nice Best Day : ) i'm sorry there where no Answer
Please help me !this is due by Friday
Answer:
Step-by-step explanation:
the answer is d why because is direct proportion i think i am not sure
1. True or false? The point estimate of a population parameter is always at the center of the confidence interval for the parameter.
The statement is true. The point estimate of a population parameter is always at the centre of the confidence interval for the parameter.
To elaborate:
- "Point estimate" refers to a single value used as an estimate of a population parameter.
- "Population parameter" is a numerical value that characterizes a specific attribute of a population, such as its mean or proportion.
- "Confidence interval" is a range of values within which we are reasonably confident that the true population parameter lies.
In this context, when we construct a confidence interval for a population parameter, the point estimate is used as the central value, and the interval is built around it based on a specified level of confidence (e.g., 95%). False. The point estimate of a population parameter is not always at the centre of the confidence interval for the parameter. The confidence interval is a range of values that is likely to contain the true value of the parameter with a certain level of confidence. The point estimate is a single value that is calculated from a sample and used to estimate the population parameter. The centre of the confidence interval is determined by the level of confidence and the variability of the data, not necessarily the point estimate.
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An aircraft factory manufactures airplane engines. The unit cost C (the cost in dollars to make each airplane engine) depends on the number of engines made. If x engines are made, then the unit cost is given by the function =Cx+−0.6x2156x16,664. How many engines must be made to minimize the unit cost?
Do not round your answer.
Please help
Answer:
4,261.4 engines
Step-by-step explanation:
To find the number of engines that minimize the unit cost, we need to find the minimum value of the function C(x) given by:
C(x) = (Cx - 0.6x)/(2156x + 16664)
where C is a constant representing the fixed costs of manufacturing the engines.
To find the minimum, we need to take the derivative of C(x) with respect to x and set it equal to zero:
C'(x) = (2156Cx - 0.6x(2156 + 16664)) / (2156x + 16664)^2 = 0
Simplifying the equation, we get:
2156Cx - 0.6x(2156 + 16664) = 0
2156Cx = 0.6x(2156 + 16664)
C = 0.6(2156 + 16664)/2156 = 2.2
So the unit cost is minimized when C = 2.2. Substituting this value back into the original equation, we get:
C(x) = (2.2x - 0.6x)/(2156x + 16664)
Simplifying, we get:
C(x) = (1.6x)/(2156x + 16664)
To find the number of engines that minimize the unit cost, we need to find the value of x that makes C(x) as small as possible. We can do this by finding the value of x that makes the derivative of C(x) equal to zero:
C'(x) = (1.6(2156x + 16664) - 2156(1.6x)) / (2156x + 16664)^2 = 0
Simplifying the equation, we get:
1.6(2156x + 16664) - 2156(1.6x) = 0
688x = 2,933,824
x = 4,261.4
Therefore, the number of engines that minimize the unit cost is approximately 4,261.4
Hope this helps!
WHAT IS THE ANSWER for this
Answer:
Yes they are congruent quadrilaterals.
And from the look of it, they possess the same shape and size; not to mention their length are also congruent.
Step-by-step explanation:
This furthet explains how PQR has the same angle as EFG and the length of DE is equal to the length of QR.
The sum of three consecutive integers is
45 Find the value of the middle of the three.
Answer:
So the three consecutive numbers are:
14,15, and 16.
Step-by-step explanation:
Let the three consecutive integers be = x , x+1, x+ 2 sum = 45
then,
x + (x + 1) + (x +2) = 45
-> 3x + 3 = 45
-> 3x = 45 - 3
-> x = 14
-> x = 14
-> x + 1 = 15
-> x + 2 = 16
So, three consecutive numbers are : 14, 15, and 16.
If xy = 100 and dy dt 20, find dy for the following values of c: dt (a) If x = 10, dy dt = (b) If x = 25, dy dt = (c) If x = 50, dy dt
Therefore, the value of derivatives are-
[tex](a) If x = 10, dy/dt = -20\\(b) If x = 25, dy/dt = -8\\(c) If x = 50, dy/dt = -4[/tex]
To solve this problem, we need to use implicit differentiation. Taking the derivative of both sides with respect to time, we get:
[tex]\frac{d(xy)}{dt} = d(100)/dt[/tex]
Using the product rule and the fact that d(xy)/dt = x(dy/dt) + y(dx/dt), we can rewrite this as:
[tex]x(\frac{dy}{dt} + y\frac{dx}{dt} = 0[/tex]
Substituting in the given value for xy, we get:
[tex]10\frac{dy}{dt} + (100/x)\frac{dx}{dt} = 0[/tex]
Simplifying this equation, we get:
[tex]\frac{dy}{dt} = -(10/x)\frac{dx}{dt}[/tex]
Now we can use this equation to find dy/dt for different values of x:
[tex](a) If x = 10, \frac{dy}{dt} = -(10/10)(20) = -20\\(b) If x = 25, dy/dt = -(10/25)(20) = -8\\(c) If x = 50, dy/dt = -(10/50)(20) = -4[/tex]
Therefore, the answers are:
[tex](a) If x = 10, dy/dt = -20\\(b) If x = 25, dy/dt = -8\\(c) If x = 50, dy/dt = -4[/tex]
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Verify the Cauchy-Schwarz Inequality for the vectors. u = (3, 7), v = (5,-2) Calculate the following values.
u-v = _________
u= _________
v=_______
The Cauchy-Schwarz inequality holds for the vectors u and v as 1 is indeed less than or equal to 41. The values for u-v, u and v are (-2, 9), [tex]\sqrt{(58)[/tex] and [tex]\sqrt{(29)[/tex] respectively.
First, let's calculate u-v:
u-v = (3, 7) - (5, -2) = (-2, 9)
Now, let's calculate the magnitudes of u and v:
|u| = [tex]\sqrt{(3^2 + 7^2) }= \sqrt{(58)[/tex]
|v| =[tex]\sqrt{(5^2 + (-2)^2)} = \sqrt{(29)[/tex]
Next, we can use the Cauchy-Schwarz inequality to find an upper bound for the dot product of u and v:
|u · v| ≤ |u| |v|
Substituting in the values we just calculated:
|u · v| ≤ [tex]\sqrt{(58)} \sqrt{(29)[/tex]
Now, let's calculate the dot product of u and v:
u · v = 35 + 7(-2) = 1
So, we have:
|1| ≤ \sqrt{(58)} \sqrt{(29)
Simplifying:
1 ≤ [tex]\sqrt{(58*29)[/tex]
1 ≤ [tex]\sqrt{(1682)[/tex]
1 ≤ 41
Since, 1 is indeed less than or equal to 41, the Cauchy-Schwarz inequality holds for the vectors u and v.
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