Find the diameter and the radius of the circle 13yd

Answers

Answer 1

Answer:

52

Step-by-step explanation:

This is because the formula is dr


Related Questions

Un aventurero realiza 2/5 de un viaje en todo terreno,1/3 a caballo y el resto andando. Si la caminata ha sido de 80 km, ¿cuál es la longitud total de su recorrido?

Answers

Answer:

Todo terreno+ caballo+caminado=distancia ; (2/5)d+(1/3)d+80=d

Step-by-step explanation:

For the functions f(x) = x+2 and g(x) = x^2 - 3 which expression has the greatest value?
A. f(g(1))
B. f(g(-2))
C. g(f(-4))
D. g(f(-2))

2. Find g(f(-4)) when f(x)= 4x+5 and g(x) = 4x^2 -5x - 3
A. 9
B.8
C.329
D.536

Answers

The expression which has the greatest value is; Choice B: f(g(-2))

The value of g(f(-4)) when f(x)= 4x+5 and g(x) = 4x^2 -5x - 3 is; 586

The value of functions

Question 1;

From the information given;

g(f(x)) = x²+4x +1

f(g(x)) = x² -1.

Hence, from the options given; upon substitution, it follows that the expression with the greatest value is;

f(g(-2)) = (-2)² -1 = 4-1 = 3.

Question 2;

From the task content;

g(f(x)) = 64x² + 140x + 122

Hence, upon substitution of -4 into the function;

g(f(-4)) = 64(-4)² + 140(-4) + 122

g(f(-4)) = 586

Read more on functions of functions;

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Will give 50points Pleasee help urgent!

Answers

Answer:

a = 10; a = 2

Step-by-step explanation:

Step 1: Use the Pythagorean theorem to solve this equation

    1. Orignal eqaution: (a + 2)² + (a - 5)² = (a + 3)²

    2. Expand (a + 2)² + (a - 5)² which will give us 2a² - 6a + 29

    3. Expand (a + 3)² giving us a² + 6a + 9

    4. Simplified equation: 2a² - 6a + 29 = a² + 6a + 9

Step 2: Subtract 9 from both sides

    1. 2a² - 6a + 29 - 9 = a² + 6a + 9 - 9

    2. Simplify: 2a² - 6a + 20 = a² + 6a

Step 3: Subtract 6a from both sides

    1. 2a² - 6a + 20 - 6a = a² + 6a - 6a

    2. Simplify: 2a² -12a + 20 = a²

Step 4: Subtract a2 from both sides

    1. 2a² - 12a + 20 - a² = a² - a²

    2. Simplify: a² - 12a + 20 = 0

Step 5: Use the quadratic formula to solve for a

    1. Quadratic formula: a = -b += √b² - 4ac/2a

    2. Plug in the correct values: a = -(-12) += √(-12)² + 4(1)(20)/2(1)

    3. Simplify the numerator and denominator: 12 += 8/2

    4. Final equation: a = 12 - 8/2  or a = 12 + 8/2

    5. Hence, the answer is 10 or 2

What is the slope of the line that passes through the points (-2,9) and (8,34)?
Write your answer in simplest form.

Answers

Answer:

2.5

Step-by-step explanation:

y=ax+b

9= -2a+b <=> b= 9+2a

34=8a+b = 8a+9+2a = 10a + 9

a = (34-9)/10 = 2.5

Answer:

m = 2.5

Step-by-step explanation:

Use the slope formula:

m = (y₂ - y₁)/(x₂ - x₁)m = (34 - 9)/(8 - (-2)) = 25/10 = 2.5

calculate each of the following
9/25÷3/50​

Answers

Answer:

6

Step-by-step explanation:

First divide 9 by 25 to get 0.36 and then divide 3 by 50 to get 0.36 . Finally divide the first result which os 0.36 by the second result which is 0.06 to get 6

find the value of x.​

Answers

Answer:

x = 145

Step-by-step explanation:

The sum of the angles of a quadrilateral is 360

35+x+35+x = 360

2x+70 = 360

Subtract 70 from each side

2x+70-70 = 360-70

2x = 290

Divide by 2

2x/2 =290/2

x = 145

Answer:

x=145

(145+145+35+35=360)

Step-by-step explanation:

This question is very simple to answer if you remember that all parallelograms have two pairs of equal and opposite angles, and that the four angles in any quadrilateral must add up to 360 degrees.


HELP Solve the system of equations using the substitution method.
-7x - 4y = -11
y = x

Answers

Answer:

y = - 7/4 x + 1 1 / 4

Step-by-step explanation:

Let f be the function given by f(x)=3ln⁡(2+x2)cos⁡x. What is the average value of f on the closed interval 2≤x≤6?

Answers

The average value of f(x) over [2, 6] is given by the definite integral,

[tex]\displaystyle f_{\rm ave[2,6]} = \frac1{6-2} \int_2^6 3\ln(2+x^3)\cos(x) \, dx[/tex]

and is approximately -1.67284.

The approximate average value of the function in the closed interval [2,6] is -1.628.

It is given that the f is the function given by:  [tex]\rm f(x) = 3ln(2+x^2)cosx[/tex]

It is required to find the average value of f in the closed interval [2,6]

What is integration?

It is defined as the mathematical approach to calculating the smaller parts or components.

We have function f:

[tex]\rm f(x) = 3ln(2+x^2)cosx[/tex]

For the average value in [2,6]

We integrate the function with lower limit 2 and higher limit 6.

[tex]\rm \int_{2}^{6}f(x) =\int_{2}^{6}( 3ln(2+x^2)cosx)\\[/tex]

The average value of the above function:

[tex]\rm =\frac{1}{6-2} \int_{2}^{6}( 3ln(2+x^2)cosx)\\[/tex]

Further solving:

[tex]\rm =\frac{3}{4} \int_{2}^{6}( ln(2+x^2)cosx)\\[/tex]

Further solving and applying limits we get:

[tex]=\frac{3}{4}\times-2.2304[/tex]

= -1.628

Thus, the approximate value of the function in the closed interval [2,6]

is -1.628.

Learn more about the integration here:

https://brainly.com/question/14502499

Billy has a credit card with a current balance of $3,500 and a 16% APR. With his current monthly payment, he will be able to pay off this debt in 15 months. But Billy just learned that he is getting a raise at work. If he puts all of the extra income from his raise into his monthly credit card payment, how much additional monthly income would he require from his raise to pay off the credit card in 12 months?

Answers

Answer:

It's A :)

Step-by-step explanation:

ur welcome

Answer:

✅ A. $58.57

i took the test⬇️

The pair of values below is from an inverse variation. Find the missing value.
(4,17). (8,y)

Answers

Answer:

8.5

Step-by-step explanation:

For inverse variation of (x, y), x*y = constant

so 4*17 = 8*y

y = 4*17/8 = 17/2 = 8.5

Use the given information to prove the following theorem.
If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.
We let be any point on line , but different from point .

Answers

Let's proof

PQ is the perpendicular bisector Hence

CQ=DQ(Bisected sides)

Now apply Pythagorean theorem

[tex]\\ \tt\hookrightarrow PQ^2+QD^2=PD^2[/tex]--(1)

[tex]\\ \tt\hookrightarrow PQ^2+CQ^2=PC^2[/tex]

As QD=CD

[tex]\\ \tt\hookrightarrow PQ^2+QD^2=PC^2[/tex]--(2)

From (1) and (2)

[tex]\\ \tt\hookrightarrow PC^2=PD^2[/tex]

[tex]\\ \tt\hookrightarrow PC=PD[/tex]

Answer:

Given [tex]\overline{\rm PQ}[/tex] is the [tex]\perp[/tex] bisector of [tex]\overline{\rm CD}[/tex]

⇒  [tex]\overline{\rm CQ}=\overline{\rm CD}[/tex]

⇒ ΔPQD ≅ ΔPQC

⇒ CP = PD

Step-by-step explanation:

Given [tex]\overline{\rm PQ}[/tex] is the [tex]\perp[/tex] bisector of [tex]\overline{\rm CD}[/tex]

⇒  [tex]\overline{\rm CQ}=\overline{\rm CD}[/tex]

⇒ ΔPQD ≅ ΔPQC

⇒ CP = PD

Divide.
2x4 + 11x3 + 13x2 + 2x - 8 = x +4

Answers

Answer:

x=-55

Step-by-step explanation:

(2)(4)+(11)(3)+(13)(2)+2x−8=x+4

Simplify both sides of the equation.

8+33+26+2x+−8=x+4

Combine like terms

(2x)+(8+33+26+−8)=x+4

2x+59=x+4

2x+59=x+4

Subtract from both sides

2x+59−x=x+4−x

x+59=4

Subtract 59 from both sides

x+59−59=4−59

x=−55

help plsssssssssssssss

Answers

Answer:

63x + 18

Step-by-step explanation:

9 multiply 7x to give 63x

and 9 multiplies 2 to give 18

Answer:

Option C. 63x +18 is correct.

Step-by-step explanation:

7x ×9= 63x

2×9=18

=63x + 18

Hope it helps.......

Number 3
Number 2 is done but part of it

Answers

Answer:

I believe the answer is B.1

Which values are greater than -2?
-5 -4 -3 -2 -1 0 1 2 3 4 5
WILL MARK BRAINLIEST

Answers

Answer:

-1, 0, 1, 2, 3, 4, 5 are the values greater than -2

Step-by-step explanation:

Let's imagine a number line.

Numbers that are bigger are on the right side of the number line.

The numbers to the right of -2 are:

-1       one greater0       two greater1        three greater2       +43       +5 4       +65       +7

And so on...

Numbers that would be less than -2 will be on the left side

-3      1 less-4      2 less

etc...

-Chetan K

Answer:

-1,0,1,2,3,4,5

ep-by-step explanation:

think of it on a number line

There is exactly
1 pair of parallel sides in the following shape.

What is the area of the shape?


Answers

The given properties of one pair of parallel sides in the four sided

quadrilateral, indicates that the shape is a trapezium.

Response:

The area of the shape is 35 square unit

How can the area of the given quadrilateral be calculated?

Given that the side with length 6 is parallel to the side with length 8, we

and that the figure is four sided, we have;

The given figure is a trapezium;

[tex]Area \ of \ a \ trapezium = \mathbf{ \dfrac{a + b }{2} \times h}[/tex]

Where;

a and b = The lengths of the parallel sides

h = The height of the figure = 5

Which gives;

[tex]Area = \dfrac{6 + 8 }{2} \times 5 = \mathbf{35}[/tex]

The area of the shape = 35 square unit

Learn more about trapeziums here:

https://brainly.com/question/96136

Answer:35 sq units

Step-by-step explanation:

How do you do this? Please help.​

Answers

So the purple and red ones on top should be switched and the orange and green ones on the bottom should be switched. The two blue ones in the corners are correct.

10. There are 100 patients willing to join a study trying out a new drug for high
blood pressure. Of these participants, 42 are male and 58 are female. If two
people are chosen at random, what the probability that both are female?

Answers

Answer:

551/1650

Step-by-step explanation:

(58/100)(57/99)=551/1650

Seven times the product of negative six and a number

Answers

7 times -6x, because “a number” can be replaced with x

Hi!

I can help you with joy! :)

7 times the product of -6 and a number. Let the number be

a. Now, "the product of" means we multiply.

Multiply -6 times a: -6a

If you notice, we write the number before the variable.

Now, multiply 7 times -6a:

7(-6a)

Simplify:

-42a

I hope this helps!

Have a Great Day!

-Content Girl

[tex]\bf{Mysterious^a^n^d\:M^a^gi^ca^l[/tex]

If (-3, y) lies on the graph of y = (1/2)^x, then y =
-8
8
1/8

Answers

y = (1/2)^-3 = 8
the answer is 8

plsss help!!!!! Mhanifa​

Answers

Answer:

See below

Step-by-step explanation:

Total number of ornaments:

24 + 12 + 8 + 19 = 63

a)

P(gold) = gold / total = 12/63 = 4/21

b)

P(silver) = silver/total = 24/63 = 8/21

c)

P(gold or silver) = (12 + 24)/63 = 36/63 = 4/7

Answer:

8)

total ornament: 24 + 12 + 8 + 19 = 63

a. probability its a gold ornament: [tex]\frac{12}{63}[/tex] → [tex]\frac{4}{21}[/tex]

b. probability its a silver ornament: [tex]\frac{24}{63}[/tex] → [tex]\frac{8}{21}[/tex]

c. probability she will get gold or silver ornament:   [tex]\frac{24}{63}[/tex] +  [tex]\frac{12}{63}[/tex] = [tex]\frac{4}{7}[/tex]

Use the fact that the quantity of a radioactive substance after t years is given by
q = q0(2−t/k),
where q0 is the original amount of radioactive material and k is its half-life (the number of years it takes for half the radioactive substance to decay).

The half-life of strontium-90 is 25 years. Find the amount of strontium-90 remaining after 20 years if
q0 = 87 kg.
(Round your answer to the nearest kg.)

Answers

Answer:

  50 kg

Step-by-step explanation:

Put the given numbers into the given formula and do the arithmetic.

  q = q0(2^(-t/k))

  q = (87 kg)(2^(-20/25)) = (87 kg)(0.574349)

  q ≈ 50 kg

The amount remaining after 20 years is about 50 kg.

Find slope: PLEASE HELP !

Answers

Take 2 points

(-7,4)(2,6)

Slope:-

[tex]\\ \rm\hookrightarrow m=\dfrac{6-4}{2+7}[/tex]

[tex]\\ \rm\hookrightarrow m=\dfrac{2}{9}[/tex]

[tex]\\ \rm\hookrightarrow m=0.2[/tex]

Find the Value of y when y=3x+45 and x=7

102

15

35

66

Answers

Answer:

y = 66

Step-by-step explanation:

y=3x+45

putting the value of x in equation which is 7 .

=> y = 3(7)+45

=> y = 21+45

=> y = 66

Find the area of the shaded region.

Answers

Answer:

56

Step-by-step explanation:

8 x 8 = 64

4 x 4 = 16

16/2 = 8

64-8 =56

If (2^a)=(3^b), what is the ratio of a to b?
Please use logarithms in the solution and explain.

Answers

Answer:

Step-by-step explanation:

Taking the log of both sides, we get:

a log 2 = b log 3

                                                                     b log 3

Dividing both sides by log 2 yields  a = ------------------

                                                                       log 2

Finally, dividing both sides by b yields the desired ratio, a/b:

a         log 3

---- = --------------

b         log 2

What is the area of the drawing of the trophy shown?​

Answers

Answer:

The area of the drawing is 12 Squares

A daycare charges a base fee of $25 per week plus $3/hour for a child.

Write an equation that relates the weekly charge C (in dollars) to the number, x, hours, that a child is in daycare​

Answers

Given :-A daycare charges a base fee of $25 per week plus $3/hour for a child.

To Find :-To write a equation that relates the weekly charge C (in dollars) to the number, x, hours, that a child is in daycare .

Solution :-

According to the question ,

The base price is $25 per week . And per hour charge is $3/hour .

So as per the question if we assume that the babysitter looked after the child for x hours in a week then , the total charge will be ,

→ Charge = $3/hr * x hr= $3x

So the total cost for a week , will be ,

→ Total cost = Base price + Charge

→ Total cost = $25 + $3x

And in the question we are told to assume total cost to be $C . Therefore ,

→ $C = $ (25 +3x)

C = 25 + 3x

Hence the required equation is C = 25 + 3x.

I hope this helps.

Consider in the figure below.
The perpendicular bisectors of its sides are , , and . They meet at a single point .
(In other words, is the circumcenter of .)
Suppose , , and .
Find , , and .
Note that the figure is not drawn to scale.

Answers

Here BD is perpendicular bisector

So

UB=BV=74

[tex]\\ \tt\hookrightarrow UV=74+74=148[/tex]

Apply Pythagorean theorem

[tex]\\ \tt\hookrightarrow BD^2=UD^2-UB^2=UD^2-VD^2[/tex]

UD=VD=78=TD

[tex]\\ \tt\hookrightarrow TC^2=TD^2-CD^2[/tex]

[tex]\\ \tt\hookrightarrow TC^2=78^2-30^2[/tex]

[tex]\\ \tt\hookrightarrow TC^2=6084-900=5184[/tex]

[tex]\\ \tt\hookrightarrow TC=72[/tex]

Answer:

UV = 148

VD = 78

TC = 72

Step-by-step explanation:

BD is the perpendicular bisector of side UV.

Therefore, ΔUDV is an isosceles triangle.

This implies that UD = VD and BV = UB so UV = 2 x BV

Given that UD = 78, and UD = VD, then VD = 78Given that BV = 74, and BV = UB, then UV = 2 x 74 = 148

ΔUDC is a right triangle.

Given CD = 30 and UD = 78,

and using Pythagoras' Theorem, we can calculate UC:

UC = √(UD² - CD²)

⇒ UC = √(78² - 30²)

⇒ UC = 72

CD is the perpendicular bisector of side UT.

Therefore, ΔUDT is an isosceles triangle, so UC = TC

Since UC = 72, then TC = 72

Help me please please please

Answers

Answer:

  GPA ≈ 2.67

Step-by-step explanation:

Grade points are weighted by credit hours:

  GPA = ∑(grade points×credit hours) / ∑(credit hours)

  GPA = (3×2 +2×4 +4×3 +2×3)/(2 +4 +3 +3)

  = (6 +8 +12 +6)/12 = 32/12 = 2 2/3

  GPA ≈ 2.67

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