Answers
The charge on the capacitor 2 (C₂) is 48μF.
Analysis of the circuit diagramIn the circuit diagram, C₁ and C₂ are in series connection, while C₃ is parallel to C₁ and C₂.
Same charge flows in a series arrangement (charge on C₁ = charge on C₂).Same voltage flows in a parallel arrangement (voltage on C₁, C₂ = voltage on C₃).Charge on capacitor C₁ and C₂[tex]Q_1 = Q_2 = Q\\\\V = \frac{Q}{C_1} + \frac{Q}{C_2} \\\\V = Q(\frac{1}{C_1}+ \frac{1}{C_2} )\\\\V = Q(\frac{C_2 + C_1}{C_1 C_2} )\\\\Q = V(\frac{C_1 C_2}{C_2+ C_1} )\\\\Q = 24 \times (\frac{6\times 10^{-6} \times 3 \times 10^{-6}}{6\times 10^{-6} \ + \ 3\times 10^{-6}} )\\\\Q = \frac{4.32 \times 10^{-10}}{9\times 10^{-6}} \\\\Q = 4.8\times 10^{-5} \ C\\\\Q = 48 \ \mu C[/tex]
Thus, the charge on the capacitor 2 (C₂) is 48μF.
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Related Questions
what is the relationship between distance, average speed and time
Answers
Answer:
average speed= total distance/total time
Explanation:
Related to the distance traveled by the object which means, it is only represented by the magnitude and direction of travel is not important. so average speed= total distance/total time
A copper wire has a diameter of 1.947 mm. What magnitude current flows when the drift velocity is 1.79 mm/s
Answers
Answer:
72.5 A
Explanation:
There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.
V = πr²h . . . . . volume of a cylinder
V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s
Then the charge flow rate is ...
(13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s
The magnitude of the current is about 72.5 amperes.
______
Additional comment
The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.
In a pulley system, two blocks are connected by a rope as shown below. The coefficient of static friction between block A and the surface is 0.8. Block A has a mass of 20kg. What is the minimum mass that block B can have so that block A moves?
Answers
Hi there!
We can begin by doing a summation of forces for each block.
Block A:
This block has the force of tension (in direction of acceleration +) and static friction (opposite direction -) acting on it. Thus:
[tex]\Sigma F_A = T - F_s\\\\m_Aa = T - \mu m_Ag[/tex]
Block B:
This block has the force of tension (opposite of acc. -) and gravity (in direction of acc +), working on it.
[tex]\Sigma F_B = m_Bg - T\\\\ m_Ba = m_Bg - T[/tex]
Add both of the expressions and solve for the maximum mass of Block B.
[tex]\Sigma F = m_Bg - T + T - \mu m_Ag\\\\a(m_A + m_B) = m_Bg - \mu m_Ag[/tex]
To find the minimum value, we can set a = 0, so:
[tex]0 = m_Bg - \mu m_Ag\\\\\mu m_Ag = m_B g\\\\0.8(20)(9.8) = m_B (9.8)\\\\m_B = \frac{0.8(20)(9.8)}{9.8)} = \boxed{16 kg}[/tex]
The block must weigh > 16 kg for block A to move.
A bullet is shot vertically upward with an initial velocity of 128 ft/s. The bullet's height after t seconds is y(t) = 128t - 16t2. What is the height of the bullet at the time the velocity is 0 ft/s?
Answers
The height of the bullet when the velocity is zero is 256 ft.
Height of the bullet when the velocity is zeroThe height of the bullet when the velocity is zero is determined by taking derivative of the function as shown below;
[tex]v = \frac{dy}{dt} = 128 -32t \\\\when \ v \ is \ zero\\\\v = 0\\\\128 - 32t = 0\\\\32t = 128\\\\t = \frac{128}{32} \\\\t = 4 \ s[/tex]
The height of the bullet at this time is calculated as follows;
[tex]y(4) = 128(4) - 16(4)^2\\\\y(4) = 256 \ ft[/tex]
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A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.
d. At what angle do the cars move after the collision? (2 points)
Answers
Given :-
A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.To Find :-
At what angle do the cars move after the collision?Solution :-
Here it's given that a car of mass 1000kg moving with velocity of 25m/s North . Another car of mass 1200kg is moving with velocity 30m/s East.
So that ,
[tex]v_{1}= 25m/s \ E= 25 \hat{i} m/s [/tex]
And ,
[tex]v_{2}= 30m/s \ N = 30 \hat{j} m/s [/tex]
See attachment .
From Triangle law of vector addition , the resultant of both vectors will be given by third side of the triangle taken in opposite direction.
So , if the resultant velocity makes an angle [tex]\theta[/tex] . Then ,
[tex] tan\theta = \dfrac{v_2}{v_1} [/tex]
Substituting the respective values,
[tex]tan\theta =\dfrac{30m/s}{25m/s} [/tex]
Simplify ,
[tex]tan\theta =\dfrac{6}{5}[/tex]
Take arctan both sides ,
[tex]\theta = tan^{-1}\bigg(\dfrac{6}{5}\bigg)[/tex]
Hence the cars move at an angle of tan-¹(6/5) NE after the collision .
pysics question can anyone answer me this question
Answers
Answer:
Im pretty sure they're equal, i could be wrong though. Hope i helped have an amazing day :D
Explanation:
Answer:
B: equal
Explanation:
Peak expiratory flow readings are Higher in the morning; lower in the evening Lower when patients are well; higher when patient's airway is constricted Lower in the morning; higher in the evening Higher when patients are well; lower when patient's airway is constricted
Answers
Peak expiratory flow readings are higher when patients are well, but lower when a patient's airway is constricted.
What is the peak expiratory flow?This term is used in medicine to refer to the maximum rate of a person's exhalation or to how fast and how long can they exhale.
This rate is measured by using the peak expiratory flow test that requires you to deeply inhale and then exhale as fast as hard as possible.
What does the peak expiratory flow indicate?This rate is closely related to the amount of air flowing out of the lungs. This implies the peak expiratory flow is lower if there is a disease such as asthma that can constrict the airways.
Learn more about asthma in: https://brainly.com/question/7646693
Activity 5: My FB (Faulty Block)
Directions: Given the illustration of the fault blocks below, draw how it looks like
after acted upon by stress forces. Draw the direction of forces acting on each type
of stress force in the fault blocks and identify the type of stress acting on the
block.
Answers
Explanation: i can’t see the image
What is the difference between molecules and
compounds?
Answers
Answer:
All compounds can be classified as molecules, but not all molecules can be called compounds. Molecules are formed by two or more atoms that are bonded by chemical bonding's. Compounds are constructed by two or more elements where the elements are mixed in fixed ratios.
Answer:
Molecules are formed by two or more atoms that are bonded by chemical bondings.
Compounds are constructed by two or more elements where the elements are mixed in fixed ratios
*All compounds can be classified as molecules, but not all molecules can be called compounds.
Explanation:
pls brainliest if you don't mind
anyway i hope this helped have an awesome day bye byee
A ray of light bends upon entering a new medium. What is the phenomenon called?
Answers
Explanation:
refraction is the change in direction of a wave passing from one medium to another or from a gradual change in the medium.
i’m kinda stuck right now…
Answers
Number 2 is 20 N to the right
Number 3 is 30 N up
Both are unbalanced
A 1,200 kg car accelerates at 3 m/s2. What net force is the car experiencing during this
acceleration?
0 3600 N
0 2000 N
2400 N
O ON
Answers
Answer:
3600 N
Explanation:
F=ma
1200*3 = 3600
Can a convex mirror form a real image?
Answers
Answer:
yes !
Explanation:
a mirror transforms and flips , but nonetheless produces a real image.
I am confused how to find the final velocity after the collision of the block?
Answers
Answer:
kmvmm x=0
l
V
V
0 = kmvm = x=0
Explanation:
A 200g ball is accelerated from 5m/s to 25m/s in 0.3sec. What force was applied?
Answers
Answer:
30N
Explanation:
30N of force was applied
quizlet
HITLOW
SS
1/6
A5 kg body is having a Kinetic energy of 250 J. What is the velocity of the body?
15 m/s
20 m/s
40 m/s
10 m/s
ME
Answers
Answer:
10 m/s
Explanation:
KE = 1/2 • m • v^2
250 J = 1/2 • 5 kg • v^2
(2 • 250 J / 5 kg )^1/2 = v
(100)^1/2 = v
10 = v
GIVING BRAINIEST TO FAST ANSWER!!!!
How does the sun's energy help maintain Earth's energy budget? (3 points)
A part of it is trapped by carbon dioxide and methane.
A part of it heats up Earth's land and water equally.
All of it is turned back towards space.
All of it is trapped by the clouds.
Answers
So that's means the answer is the second one
A ball is thrown 125 meters upward and then falls the same distance back to Earth. Neglecting air resistance, its total time in the air is
Answers
Answer:
the ball is in the air for 10 seconds
Explanation:
let gravity = 10m/s/s
height = 1/2 acceleration • time^2
125 m = 1/2 • 10 m/s/s • time ^2
125m = 5 m/s/s • time^2
25s = time^2
5 s = time
5 seconds is the time required for half of the flight
time total = 2 • time
time total = 2 • 5s
time total = 10 s
3) A square coil of sides 0.40 m carries a current of 3.0 A in a uniform magnetic field of 5.0 mT. the plane of the coil is parallel to the magnetic field as shown in figure below.
a) Calculate the force on each side of the coil.
b) What is the resultant effect of the force on the coil?
c) What happen to the coil?
Answers
The largest identified asteroid is Ceres and is about three times the size of the Moon.
True
or
False
Answers
[tex]false[/tex]
Hope it helps you
7 principles of Exercise and Sports Training
Answers
Answer: individuality, specificity, progression, overload, adaptation, recovery, and reversibility.
Explanation:
individuality, specificity, progression, overload, adaptation, recovery, and reversibility.
Answer:
1. individuality
2. specificity
3. overload
4. adaptation
5. recovery
6. reversibility
7. progression
Explanation:
I learned this last year.
3. A wooden block is at rest on a wooden inclined
plane. As the angle the plane makes with the
horizontal is increased, the magnitude of the
force of static friction between the block and
the plane
(1) decreases
(2) increases
(3) remains the same
Answers
As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases
Static frictional forceSince the static frictional force between the block and the plane is given by F = μN where
μ = coefficient of static friction and N = normal force on plane = component of weight of block perpendicular to the plane = Wcosθ where W = weight of block and θ = angle of inclined planeNow, F = μN
F = μWcosθ
Since μ and W are constant, we see that
F ∝ cosθ and cosθ ∝ θ
So, F ∝ θ
Since the static frictional force is directly proportional to the angle the plane makes with the horizontal, when the angle the plane makes with the horizontal is increased, the static friction between the block and the plane increases.
So, As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases
Learn more about static frictional force here:
https://brainly.com/question/25958331
Which statement describes the density of the inner planets?
All the inner planets are dense.
The inner planets are less dense than the outer planets.
Earth is dense, while the other inner planets are not.
Mercury and Venus are dense, while Earth and Mars are no
Answers
Answer:
The inner planets are less dense than the outer planets
Please brainliest my answer iam begging you for god sake
Answer:
The inner planets are less dense than the outer planets .
Explanation:
Please Mark Me As a brainliestA ball is placed at the top of a hill then released. After 5 seconds it has a speed of 20 m/s. What is the average acceleration of the ball
Answers
Answer:2
Explanation:When the ball is released from the top of the hill then it's initial velocity (u)=0 And it's final velocity will be after 5 second (v)=2.
Answer:
Explanation:
a ball is placed at the top of the hill and then released after five seconds and has a speed of 20 m/s. What is the average acceleration of the ball?
What does acid rain look like so that anyone can recognize it?
Answers
One day, the distance between the crests of the waves at sea is 2.5m. The shortest time between the lowest and highest positions of the floating boat was 0.625 seconds.
a) Calculate the wave period.
b) Calculate the speed of the wave.
Answers
Answer:
1.25 sec, 2 m/s
Explanation:
Period = 2 * 0.625 sec = 1.25 sec
speed = 2.5/1.25 = 2 m/s
Really need help! ;(
Could you please explain it? :)
GIVING 10 POINTS
Answers
Answer:b
Explanation: If you look at the line on the graph, you can see that it is going downward, meaning it has a negative slope, and choice b is the only one that has a negative slope
Explanation:
In the formula y=mx+b, m stands for the slope while b stands for the y-intercept.
The slope, in this case, is negative one. You can see this by finding two points on the line and using the slope formula
y(2)-y(1)
————
x(2)-x(1)
As for the y-intercept. That is just the point at which the line crosses the y-axis. In this case, the line intercepts at y=0. So, you do not need to put anything in for ‘b’
So, when m=-1 and b=0, your equation is y=-x
the nuclues of an atom contains which subatomic particles
Answers
Protons are massive, positively charged
nuclear particles.
The net force on an object is
Answers
Answer:
Net Force. when all combinations of force acting on an object. Force. A push or pull
So it's the third answer
( the combination of all forces acting on it )
What is the velocity (in metres per second) of a Canadian
Forces CF-18 fighter jet that travels 8.864 km [S] in
0.297 min?
Answers
Answer:
497 m/s
Explanation:
(8.864 x 10^3 m)/(0.297 * 60 sec) = 497 m/s
The velocity (in metres per second) of a Canadian Forces CF-18 fighter jet would be 497.41 meters/second.
What is speed?The total distance covered by any object per unit of time is known as speed.
As given in the problem we have to find out the velocity (in meters per second) of a Canadian Forces CF-18 fighter jet that travels 8.864 kilometers [S] in 0.297 minutes,
The distance traveled by the CF-18 fighter jet = 8.864 kilometers
1 kilometer = 1000 meters
8.864 kilometers = 8.864× 1000 meters
=8864 meters
The time taken by CF-18 fighter jet = 0.297 minutes
1 minute = 60 seconds
0.297 minutes = 0.297 ×60 seconds
=17.82 seconds
The velocity of the CF-18 fighter jet =8864 meters/17.82 seconds
= 497.41 meters/second
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