find the area of the semi circle please ​

Find The Area Of The Semi Circle Please

Answers

Answer 1

Answer:

58.4197cm^2

Step-by-step explanation

cirlce area formula: [tex]\pi[/tex]r^2

r= 6.1

[tex]\pi[/tex]=3.14

Now plug numbers into the formula

area of circle:

= (3.14)(6.1^2)

=(3.14)(37.21)

= 116.8394cm^2  ------> area of full circle

now divide by 2, to find area of semi circle

116.8394/2= 58.4197cm^2

Answer 2

[tex] \huge\fbox\red{A}\fbox\pink{n}\fbox\purple{S}\fbox\green{w}\fbox\blue{E}\fbox\orange{r}[/tex]

area of semicircle is 58.572 m²

[tex] \huge \sf { \fcolorbox{green}{g}{Explanation :- }}[/tex]

[tex] \huge \underline{\large \fbox \red{Concept : }}[/tex]

We have to find the area of semicircle

So firstly we need to find the area of circle. because the semicircle of circle is the half of area of circle so first we find the area of circle then divide by 1 /2 then we get the area of semicircle.

We have given the radius of circle is 6.1 m

[tex]\huge\mathfrak\red{Solution : }[/tex]

[tex] \mathfrak \green{Area \: of \: circle = π × ( radius) ²}[/tex]

[tex]\mapsto \: \: \small \: \: \: \: \: \mathfrak \blue{ = \frac{22}{7} \: \times( 6.1 \: m)^{2} } \\ [/tex]

[tex]\mapsto \small \: \: \: \: \: \mathfrak \blue{ = \frac{22}{7} \: \times37.21 \: m {}^{2} } \\ [/tex]

[tex]\mapsto \: \small\: \: \: \: \: \: \mathfrak \blue{ = 116.94 \: m {}^{2} }[/tex]

Therefore,

[tex]\small \mathfrak \red{Area \: of \: semicircle = \frac{1}{2} \times area \: of \: circle}[/tex]

[tex] \small \mathfrak \green{ = \frac{1}{2} \times 116.94 \: cm \: {}^{2} } \\ [/tex]

[tex]\mapsto \: \small\: \: \: \: \: \: \mathfrak { = 58.472\: m {}^{2} }[/tex]

[tex] {\underline {\fbox\red{Hence, the area of semicircle is 58.572 m²}}}[/tex]


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Step-by-step explanation:

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Step-by-step explanation:

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...

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Answers

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Step-by-step explanation:

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Hey mate....

Step-by-step explanation:

This is ur answer......

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Hope it helps!

mark me brainliest plz......

Follow me! ;)

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Answers

Answer:

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Please see the attached picture for the full solution.

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Answers

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Answers

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Answers

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