find four consecutive odd integers such that the sum of twice the smallest and the largest is 11 more than the sum of the middle two integers

Answer:

I believe that's the solution!

sorry for my letters...

Answer:

Second quadrant

Step-by-step explanation:

Quadrant I ranges from [tex]0^\circ<\theta<90^\circ[/tex]

Quadrant II ranges from [tex]90^\circ<\theta<180^\circ[/tex]

Quadrant III ranges from [tex]180^\circ<\theta<270^\circ[/tex]

Quadrant IV ranges from [tex]270^\circ<\theta<360^\circ[/tex]

Answer:

a

Step-by-step explanation:

5/3 is 1.6666667

8/5 is 1.6

therefore 5/3 > 8/5

Answer:

1. 103        

2. 156

3. 114
4. 115.14

5. 140

6. 123.8

7. 120.28

8. 107

Step-by-step explanation:

Answer:

hope it helps you :)) !

Answer: 10

Step-by-step explanation:

Step-by-step explanation:

[tex]y = \frac{4}{x} + \sqrt{x + 0.2} - 5x[/tex]

[tex]x = \frac{4}{5} [/tex]

[tex]y = \frac{4}{1} \div \frac{4}{5} + \sqrt{ \frac{4}{5} + 0.2} - 5 \times \frac{4}{5} [/tex]

[tex] \frac{4}{1} \times \frac{5}{4} + \sqrt{0.8 + 0.2} - 4[/tex]

[tex]5 + \sqrt{1} - 4[/tex]

[tex]5 + 1 - 4 \\ 6 - 4 = 2[/tex]

Answer:

276.25

Step-by-step explanation:

37.50 x 5.5 = 206.25

206.25+ 70 = 276.25

The required length of side OQ is given as 80 units, as of the given conditions.

In a right-angled triangle, its sides, such as hypotenuse, perpendicular, and base are Pythagorean triplets.

here,
From the figure,
Applying Pythagoras' theorem,
OQ² = OR² + RQ²
OQ = √[48² + 64²]
OQ = 80 units

Thus,  the required length of side OQ is given as 80 units, as of the given conditions.

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Answer:

5.524 in 2 significant figures rounding the value to 2 non zero numbers.

5.524 = 5.5 (2 significant figures)

Answer: 36/5= 7.2 days to complete sanaya work day

Step-by-step explanation:

Answer:

1) slope form
2) standard form

3)slope form

4)standard form

5) none of theese

6)point slope form

Step-by-step explanation:

Answer:

2 : 3

Step-by-step explanation:

bananas to apples = 8 : 12

simplify by dividing both values by highest common factor of 4:

8 ÷ 4 : 12 ÷ 4 = 2 : 3

Answer:

$240000

Step-by-step explanation:

[tex]p = 200000[/tex]

[tex]t = 4[/tex]

[tex]r = 5 \: percent\: per \: anum[/tex]

[tex]si = \frac{p \times r \times t}{100} [/tex]

[tex] = \frac{200000 \times 5 \times 4}{100} [/tex]

[tex] = 2000 \times 5 \times 4[/tex]

[tex] = 2000 \times 20[/tex]

[tex] = 40000[/tex]

[tex]amount = si + principle[/tex]

[tex] = 200000 + 40000 = 240000[/tex]

The total amount after 4 years is $240,000

Simple interest rate is the interest that is paid only on the principal portion of a the amount that is saved.

Total amount = principal + interest

Interest = principal x time x interest rate

200,000 x 0.05 x 4 = $40,000

Total amount = 200,000 + 40,000 = $240,000

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Answer:

  a.  2/5; reduction

Step-by-step explanation:

It appears that C is the center of dilation, so C' and C are coincident. The scale factor is ...

  P'C'/PC = 4/10 = 2/5 . . . scale factor

The scale factor is less than 1, so the dilation is a reduction in size.

It should be noted that the probability that a student will earn at least one 5 will be 0.3152.

Test P(x). P(at least one 5)

1. 0.4. 0.2

2. 0.45. 0.36

3. 0.15. 0.488

Therefore, the probability that a student in the AP curriculum will earn at least one 5 will be:

= (0.4 × 0.2) + (0.45 × 0.36) + (0.15 × 0.488)

= 0.3152

In conclusion, the correct option is 0.3152.

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taking a peek at the picture, we can see that the U-turn or vertex occurs at the point (2 , -9), and we can also see that the graph passes through the point say (5 , 0).

[tex]~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{vertex}{(2~~,~-9)}\qquad y=a(x-2)^2-9\qquad \qquad \textit{we know that} \begin{cases} x=5\\ y=0 \end{cases} \\\\\\ 0=a(5-2)^2-9\implies 9=9a\implies \cfrac{9}{9}=a\implies 1=a~\hfill \\\\\\ y=1(x-2)^2-9\implies \boxed{y=(x-2)^2-9}[/tex]

Answer:

a 31. w 55. X 60 y 46

Step-by-step explanation:

Answers in angles

i d k

Step-by-step explanation:

   Option (A) will be the answer.

        (Example: Translation, Rotation and Reflection)

Given in the question,

Since, image quadrilateral MOPS is formed by the translation of quadrilateral CAWT by 7 units right and 5 units down,

It's a rigid transformation having measures of all interior angles unchanged.

By the definition of rigid transformation → ∠M ≅ ∠C

          Therefore, option (A) will be the answer.

Learn more about the transformation here,

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Answer:

square root of 4 is 2, 1/2 of 2 is 1

Step-by-step explanation:

Answer:

C 30 degrees

Step-by-step explanation:

Sum of interior angles of a triangle = 180°

⇒ ∠UST + 78 + 72 = 180

⇒ ∠UST = 180 - 78 - 72

⇒ ∠UST = 30°

Answer:

sin theta = .923

Step-by-step explanation:

see image. An angle in standard position has one side glued to the x-axis, and the other side-the terminal side- rotating around the origin. When it gets to (-5, 12) in your problem, it stops there. 5, 12are the legs of a right triangle and they are recognizable as part of a pythagorean triple 5,12,13. So the hypotenuse is 13. Sin is OPP/HYP. So that is 12/13. Its in the 2nd quadrant, so it should be positive. We used the reference angle, bc the actual angle is the >90° angle from the positive x-axis to thru (-5,12). It calcs the same tho.

sin theta = 12/13

= 0.923

Answer:

  (c)  0.923

Step-by-step explanation:

The coordinates of a point on the unit circle are (cos(θ), sin(θ)). That is, the y-coordinate of a point on the terminal ray will have the same sign as the sine of the angle. Here, the sign of the sine is positive, eliminating the first two answer choices.

We know that cos(θ) < sin(θ) for reference angles greater than 45°, where both values are √2/2 ≈ 0.707. Since 5 < 12, that means the angle of interest here will have a sine that is more than 0.707. Only one of the positive answer choices is in this range: sin(θ) ≈ 0.923.

_____

Additional comment

The value of sin(θ) is precisely ...

  sin(θ) = y/√(x²+y²) = 12/√(25+144) = 12/13

  sin(θ) = 0.923076...(6-digit repeat)

The equation of a line that is tangent to the graph of f and parallel to the given line is; y = 3x + 2 and y = 3x - 2

The given equation of the line is 3x - y + 3 = 0

In slope intercept form, this can be rewritten as;

y = 3x + 3

Therefore, the slope of this line will be 3 since in y = mx + c, m is the slope. Thus, the slope of the parallel line will be  3

We will be looking for the value of x when the derivative of f(x) equals 3.

f(x) = x³ and so f'(x) = 3x²

Thus;

3x² = 3

x² = 3/3

x² = 1

x = 1 or -1

Thus;

y = 1³ or y =-1³

y = 1 or -1

Equation of tangent is;

y - 1 = 3(x - 1)

y - 1 = 3x - 3

y = 3x - 2

or y - (-1) = 3(x - (-1))

y + 1 = 3x + 3

y = 3x + 2

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The value for the given right triangle of [tex]x[/tex] is [tex]\pm \sqrt{2}[/tex].

By Pythagorean theorem and some algebraic handling, we have the following second order polynomial:

[tex](x-1)^{2}+(x+1)^{2} = 2.5^{2}[/tex] (1)

Where [tex]x[/tex] is the desired variable.

[tex](x^{2}-2\cdot x +1)+(x^{2}+2\cdot x +1) = 2.5^{2}[/tex]

[tex]2\cdot x^{2}+2 = 2.5^{2}[/tex]

[tex]2\cdot x^{2}-4.25= 0[/tex]

[tex]x = \pm \sqrt{2}[/tex]

The value for the given right triangle of [tex]x[/tex] is [tex]\pm \sqrt{2}[/tex]. [tex]\blacksquare[/tex]

The statement is incomplete. Correct form is shown below:

Suppose you are given a triangle with hypotenuse of length 2.5 and legs of length [tex]x-1[/tex] and [tex]x+1[/tex]. Determine the value of [tex]x[/tex].

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Answer:

$54

Step-by-step explanation:

Original Price = $90

Discounted = 40%

Percent to decimal 40% = .40

$90 x .40=36 ( 36 is the Discount)

$90 - 36=54

Sale Price = $54

Hence, Sale Price = $54

[RevyBreeze]

Answer:

We cant see the writing it is too small

Step-by-step explanation:

Answer:

-6

Step-by-step explanation:

Answer:

-6

Step-by-step explanation:

3(-2)(-1)(-1)= -6

[RevyBreeze]

Answer:

m<C = 62°

Step-by-step explanation:

[tex]m[tex]m [tex]x+20+3x=180[/tex]

[tex]4x=160,[/tex]  [tex]x=40[/tex]

[tex]m [tex]118+m [tex]m [tex]m

Explanation:

When x is zero or larger, then |x| = x.

An example: |9| = 9

This applies to |3x| as well, so |3x| = 3x when [tex]x \ge 0[/tex]