Answers
Answer:
R = 4.77 ohms
Explanation:
Four resistors are given such that,
R₁ = 2 ohms
R₂ = 3 ohms
R₃ = 5 ohms
R₄ = 10 ohms
Here, R₁ and R₂ in series. The equivalent is given by :
R₁₂ = R₁ + R₂
= 2 + 5
R₁₂ = 7 ohms
Similarly, R₃ and R₄ are in series. so,
R₃₄ = R₃ + R₄
= 10+5
R₃₄ = 15 ohms
Now, R₁₂ and R₃₄ are in parallel. So,
[tex]\dfrac{1}{R}=\dfrac{1}{R_{12}}+\dfrac{1}{R_{34}}\\\\\dfrac{1}{R}=\dfrac{1}{7}+\dfrac{1}{15}\\\\R=4.77\ \Omega[/tex]
So, the equivalent resistance s 4.77 ohms.
Related Questions
Explain concept of donor levels and accepter levels in extrinsic semiconductors and How can Fermi level be defined for conductors , insulators and semiconductors when temperature increases above zero Kelvin.
Answers
Answer:
DONORS: If the material for which it substitutes has more electrons than the original
ACCEPTORS: If the replacement material has fewer electrons than the original material
Fermi level: the point where the probability of finding the last electron is ½
Explanation:
When in a semiconductor material a small fraction of an element is replaced by another with different valences, an excess charge is created.
If the material for which it substitutes has more electrons than the original, there is an excess of electrons, these excess electrons are weakly bound in the material and their orbits are large, in an energy versus moment diagram their energy places them a little more below the conduction band, these materials are called DONORS.
If the replacement material has fewer electrons than the original material, one electron is missing to complete the bonds, so there is a movement of the other electrons, an easier way to analyze this movement of the (n-1) electrons is to suppose that The missing charge has a positive charge and to study its movement, this positive charge is called a hole, its binding energy is small so the orbit of the hole is large, in an energy diagram it is located a little above the band of valence, these are called ACCEPTORS
The Fermi level is defined as the point where the probability of finding the last electron is ½, when the temperature is changed the density of states of the bands changes, therefore the location point moves, but its [probability remains ½
A 1.50 kg ball moving at 4.50 m/s is caught by a 60.0 kg man while the man is standing on ice. How fast will the man / ball combination be moving after the ball is caught by the man?
Answers
Answer:
Explanation:
The Law of Momentum Conservation applies, and the formula for us here specific to this problem is:
[tex][(m_bv_b)+(m_mv_m)]_b=[(m_b+m_m)v_{both}]_a[/tex] and filling in:
[(1.50*4.50)+60.0*0)] = [(1.50 + 60.0)v] and
6.75 + 0 = 61.5v so
v = .110 m/s in the same direction as the ball
A cubic box has a 0.8 meter side. Find the volume of air in the box in cubic meter?
Answers
Answer:
[tex]V=0.512\ m^3[/tex]
Explanation:
Given that,
The side of a cubic box, s = 0.8 m
We need to find the volume of air in the box.
We know that,
The volume of a cube is given by :
[tex]V=s^3[/tex]
So,
[tex]V=0.8^3\\\\V=0.8\times 0.8\times 0.8\\\\=0.512\ m^3[/tex]
So, the volume of air in the box is [tex]0.512\ m^3[/tex].
An ohmic dipole of resistance 100 ohm is crossed by a current of intensity 120 ma. Calculates the voltage across this chemical dipole
Answers
Answer:
12.0 Volt
Explanation:
Step 1: Given data
Resistance of the ohmic dipole (R): 100 Ohm
Intensity of current (I): 120 mA (0.120 A)
Step 2: Calculate the voltage (V) across this chemical dipole
To calculate the voltage across the ohmic dipole, we will use Ohm's law.
I = V/R
V = I × R
V = 0.120 A × 100 Ohm = 12.0 V
convert 3 hours 30 minutes into second
Answers
Answer:
9000 SECONDS
Explanation:3 hours=180 mins
180+30=210mins
150x60=12600secs
During the Egg Drop lab sim you manipulated several variables like height, egg mass and impact surface. If you dropped a large egg from 10 meters which one condition would allow the best chance for the egg to survive unbroken?
Answers
Answer:
An egg with a thick shell.
Explanation:
Hope this helps.
1. At what angle of release did the sepak takraw ball travel farthest? ______ 2. How will you compare the range (horizontal distance) travelled by the ball at angles of 25º and 65º? How about at angles of 40º and 50º? ________________________________________________________________________ 3. At what angle of release did the ball reach the maximum height?_________ 4. How will you compare the height reached by the ball at 25º, 45º and 65º? _______________________________________________________________________ 5. How will you explain the relationship between the angle of release to the height of the projectile? How about angle of release and range before it reaches the farthest distance?
Answers
Answer:
1) θ = 45, b) R₄₀ = R₅₀ = (v₀² / g) 0.985, R₂₅ = R₆₅ = (v₀² / g) 0.766
3) θ = 90º, d) y₂₅ = (v₀ / 2g) 0.179, y₄₅ = (v₀ / 2g) 0.5, y₆₅ = (v₀ / 2g) 0.821
Explanation:
This is a projectile throwing exercise, let's use the relations
R = [tex]\frac{v_o^2 \ sin \ 2\theta }{g}[/tex]
1) the angle for a maximum reach (R) is θ = 45
R = v₀²/g
2) let's compare the scopes
θ = 25º
R₂₅ = (v₀² /g) sin 2 25
R₂₅ = (v₀² /g) 0.766
θ = 65º
R₆₅ = (v₀² / g) sin 2 65
R₆₅ = (v₀² / g) 0.766
θ = 40º
R₄₀ = (v₀²/g) sin 2 40
R₄₀ = (v₀²/ g) 0.985
θ = 50
R₅₀ = (v₀²/g) sin 2 50
R₅₀ = (v₀² / g) 0.985
we can see that it has the same scope
R₄₀ = R₅₀ = (v₀² / g) 0.985
R₂₅ = R₆₅ = (v₀² / g) 0.766
3) the maximum height is reached when the vertical speed is zero
[tex]v_y^2 = v_{oy}^2 - 2 g y[/tex]
v_y = 0
y = [tex]\frac{v_{oy}^2}{2g}[/tex]
y = (v₀² /2g) ( sin θ)²
therefore the height is maximum for θ = 90º
4) θ = 25º
y₂₅ = (v₀ / 2g) (sin 25)²
y₂₅ = (v₀ / 2g) 0.179
θ = 45º
y₄₅ = (v₀ / 2g) (sin 45)²
y₄₅ = (v₀ / 2g) 0.5
θ = 65º
y₆₀ = (v₀ / 2g) (sin 65)²
y₆₅ = (v₀ / 2g) 0.821
5) It is appreciated that as the launch angle increases the height increases, the maximum is when the movement is vertical
For the launch angle, the reach has a maximum for the angle of 45º, this is due to the symmetry of the sine function around this value.
Write the formula of gravitational force between two bodies of masses x and y kept at a distance r
Answers
Answer:
F=Gxy/r^2
Explanation:
F=Gm1m2/d^2
F=Gxy/r^2
How much power is required to do 180 J of work in 2.4s?
Answers
p = w / t
p = 180 / 2.4
p = 75
The power required to do 180 J of work in 2.4 s is 75 W.
What is power?Power can be defined as the rate at which work is done.
To calculate the power, we use the formula below
Formula:
P = E/t............. Equation 1Where:
P = PowerE = Energy or workt = Time.From the question,
Given:
E = 180 Jt = 2.4 sSubstitute these values into equation 1
P = 180/2.4P = 75 W.Hence, the power required to do 180 J of work in 2.4 s is 75 W.
Learn more about power here: https://brainly.com/question/24858512
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Craig is modeling the discovery of electromagnetism. Which procedure should he use?
A. moving a magnet into a coil of wire in a closed circuit
B. moving a magnet into a coil of wire in an open circuit
C. bringing a compass near a wire that has no electric current
D. bringing a compass near a wire that has an electric current
Answers
Answer:
A
Explanation:
moving a magnet into a coil of wire in a closed circuit
Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism. Option A is correct.
What is electromagnetism ?The physical interplay of electric charges, magnetic moments, and the electromagnetic field is known as electromagnetism.
The electromagnetic field can be static, moving slowly, or forming waves.
Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism.
Hence, option A is correct.
To learn more about the electromagnetism, refer to the link;
https://brainly.com/question/3427992
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To clean the floor, David exerts a 40 N force on a broom handle to push it 2 m. If the broom handle makes a 40° angle with the floor, what is the work done by David on the broom? If the broom handle were angled at 65° would David do more or less work? Explain your answer. Use the Guess method.
Answers
Answer:
Explanation:
Work done = Force * Displacement
There is no displacement vertical so only the horizontal part of force did work.
The horizontal force = Force * cos(angle with floor)
Work done = 40*cos(40°)*2
= 61.28 J
As cos(65°) is less than cos(40°), work done will be less at 65°.
31) A box is pushed, up a ramp, at constant velocity with a force of 14 N.
What is the magnitude of the friction force working on the box? *
Answers
The magnitude of the frictional force working on the box is 14 N.
According to Newtons's first law, an object will continue in its state of rest or state of uniform motion unless it is acted upon by an unbalanced force. This means that motion or acceleration is caused by an unbalanced force.
Since the box is moving at constant velocity, the frictional force on the box and the force that moves the box forward are exactly equal in magnitude but opposite in direction.
Learn more: https://brainly.com/question/9352088?
for the light bulb to produce the aame illuminace with the candle to the screen, the luminous intensity of the bulb is _______ that of the candle?
Answers
Answer:
9 times
Explanation:
luminosity decreases to the square of the distance
Scientists today use satellites as well as telescopes to observe the universe. Suggest one way
that developments in equipment have changed the information scientists collect about
planets.
Answers
Answer:
Rovers, unmanned space probes, modern instruments,
Explanation:
HELP ME ILL MARK U THE BRAINLIEST
the crane takes 2.5s to raise the box 3.0 m. Calculate the power output of the crane
Answers
Answer:
Power = 1800 W
Explanation:
Power = work / time
Power = 4500 / 2.5
Power = 1800 W
Calculate the force that is applied on this 0.25 kg ball, as it goes down to hit the ground.
(given gravity= 9.8 m/s2).
Answers
Answer:
F = 2.45 N
Explanation:
m = 0.25 kg
a = 9.8 m/s^2
F = ma
F = (0.25)(9.8)
F = 2.45 N
The absorption of a photon causes a hydrogen atom
to change from the n = 2 to the n = 3 energy state.
What is the energy of the absorbed photon?
A) 4.9 eV
C) 1.9 eV
B) 3.4 eV
D) 10.2 eV
Answers
4.9 eV is the correct answer
Hope it helps you ^ _ ^
if you can't test an explanation through experiment,
A) the phenomena let's not have occurred in the physical world
B) people will disagree on whether the explanation is correct
C) your observation must not have really occurred
D) a group of scientists will vote on their favorite explanation
Answers
Answer:
B
Explanation:
Which of the following describes a mixture?( 2 A combination of two or more substances O A combination of two sources of energy An object made of the same substance A substance that is made up of matter
Answers
Answer:
A combination of two or more substances.
an object of volume 1m3 and density of 500kg/m3 float in water what volume of water is displaced
Answers
Answer:
[tex]0.5\; \rm m^{3}[/tex].
Explanation:
Calculate the mass of this object:
[tex]\begin{aligned}& m(\text{object}) \\ &= \rho(\text{object}) \cdot V(\text{object}) \\ &= 500\; \rm kg \cdot m^{-3} \times 1\; \rm m^{3} = 500\; \rm kg\end{aligned}[/tex].
Multiple the mass of this object by the gravitational field strength, [tex]g[/tex], to find the weight of this object: [tex]W(\text{object}) = m(\text{object}) \cdot g[/tex].
Since this object is floating in water, the buoyancy force on it should be equal to its weight:
[tex]F(\text{buoyancy}) = W(\text{object}) = m(\text{object}) \cdot g[/tex].
By Archimedes' Principle, the weight of the water that this object displaces would be equal to [tex]F(\text{buoyancy})[/tex], the size of buoyancy force on this object,
Hence, the weight of water displaced would be [tex]W(\text{object}) = m(\text{object}) \cdot g[/tex].
Divide this weight by [tex]g[/tex] to find the mass of water displaced:
[tex]\begin{aligned} & m(\text{water displaced}) \\ &= \frac{W(\text{water displaced})}{g} \\ &= \frac{m(\text{object}) \cdot g}{g} = m(\text{object}) = 500\; \rm kg\end{aligned}[/tex].
Assume that the density of water is [tex]\rho(\text{water}) = 1000\; \rm kg \cdot m^{-3}[/tex]. The volume of water displaced would be:
[tex]\begin{aligned}& V(\text{water displaced}) \\ &= \frac{m(\text{water displaced})}{\rho(\text{water})} \\ &= \frac{500\; \rm kg}{1000\; \rm kg \cdot m^{-3}} = 0.5\; \rm m^{3}\end{aligned}[/tex].
what is the momentum of an object weighing 7.5 kg moving at 1.6 m/s?
Answers
Answer:
[tex]momentum = mass \times velocity \\ = 7.5 \times 1.6 \\ = 12 \: kg {ms}^{ - 1} [/tex]
Mass is 7.5 kg
Velocity is 1.6 m/s
we know that,
momentum = mass × velocity
or; momentum =7. 5 kg × 1. 6 m/s
or; momentum = 12 kgms^1
You can do only number 1 only
Answers
For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C
t = Q / I
From question:
Q = 100C
I = 0.1A
Therefore, time, t = 100 / 0.1 = 1000 s
What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4
Answers
Answer:
[tex]x = 2\sqrt 2[/tex]
Explanation:
Given
[tex]Hypotenuse = 4[/tex]
Required
Find x
Since the triangle is a 45-45-90 triangle, the following relationship exists
[tex]x^2 + x^2 = 4^2[/tex] --- i.e. the other legs are equal
So, we have:
[tex]2x^2 = 16[/tex]
Divide both sides by 2
[tex]x^2=8[/tex]
Take square roots of both sides
[tex]x = \sqrt 8[/tex]
Simplify
[tex]x = 2\sqrt 2[/tex]
Answer:
7√2
Explanation:
Explique cómo es que las estrellas emiten una radiación, específicamente qué es lo que sucede a nivel atómico
Answers
Answer:
Las estrellas se forman debido a la unión de pequeños elementos y partículas como el hidrógeno y el helio que experimentan una fusión nuclear en el núcleo debido a la intensa presión para formar un nuevo átomo (como dos hidrógeno que se combinan para formar un átomo de helio) que es un proceso. que requiere una gran cantidad de energía para comenzar, por lo que cada reacción de fusión produce una gran cantidad de energía que puede mantener la reacción y equilibra la fuerza gravitacional que atrae las masas de las partículas hacia el centro de la estrella
A medida que la energía de la estrella se irradia, la superficie de la estrella cede la energía en forma de calor y luz de manera que debido a la alta temperatura de las partículas de los átomos de los elementos se mueven muy rápida y energéticamente para emitir fotones rápidamente. (alta frecuencia) que se ve como el alto brillo de la estrella
Explanation:
How are galaxies named?
Answers
Answer:
Some galaxies are given descriptive names (e.g. "Andromeda", "Whirlpool") if they are particularly distinctive in location or appearance. But most galaxies are known from their designation in a catalogue. One of the earliest catalogues of objects in the sky was made by Charles Messier.
A 5L container has a
Answers
Answer:a gas at pressure of 0.8 m column of H g
Explanation:I thinkHELP ME PLEAASSEEE ILL MARK U THE BRAINLIEST
Answers
Answer:
Gravitational energy and kinetic energy
A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains in static equilibrium. What is the mass of the meterstick
Answers
A man who weighs 75kg on the surface of the earth whose mass is 6*10^24kg. If the radius of earth is 6480km ,calculate the force of attraction between them.
Answers
Answer:
718.02N is the answer to the question
A jetliner can fly 8.0 hours on a full load of fuel. Without any wind it flies at a speed of 2.42 x 102 m/s. The plane is to make a round-trip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a 40.7-m/s wind from the jet stream, which blows from west to east. What is the maximum distance (in kilometers) that the plane can travel due west and just be able to return home
Answers
Answer:
3386.23 Km
Explanation:
Without any wind interference the speed of the plane, it flies at 2.42 x 102 m/s or 242 m/s
The magnitude of the velocity of the air = 40.7-m/s
The time taken, for the plane to fly due west, tw = distance, x ÷ (speed of the plane without wind interference, up - the magnitude of the velocity of the air, ua).......... (equation 1)
The time taken, for the plane to fly due east, te = distance, x ÷ (speed of the plane without wind interference, up + the magnitude of the velocity of the air, ua).......... (equation 2)
To calculate the total time, t, the plane can fly to cover east and west distances, we add equation 1 and 2 together
t = (x ÷ (up - ua)) + (x ÷ (up + ua))
Making distance x, the subject of the formula we have:
x = t ( up²- ua²) ÷ 2up
note t = 8.0 hours which is (8 x 60 x 60) seconds = 28,800
So, x = 28,800 ((242 m/s)² - (40.7-m/s)²)÷ 2(242 m/s)
x= 1,638,936,288 ÷ 484
= 3386.23 Km