Find an ordered pair (x,y) that is a solution to the equation.
x-2y=6
Answers
[tex]\large\underline{\underline{\red{\sf \blue{\longmapsto} Step-by-step\: Explanation:-}}}[/tex]
Given linear equⁿ : x - 2y = 6 .
So , on drawing its graph , the points though which it passes , the coordinates of that particular point will be a solution for this linear equⁿ .
Here , taking the given equⁿ & drawing its graph ,
⇒ x - 2y = 6 .
⇒ x = 6 + 2y .
Now , for a given value of y , x will also have some values .
[tex]\boxed{\begin{tabular}{|c|c|c|}\cline{1-3} \bf x & 6 & 8 \\ \cline{1-3} \bf y & 0 & 1 \\\cline{1-3} \end{tabular}}[/tex]
Now , it's clear that the required order pair which will be solution of the equⁿ can be ( 6 , 0 ) or ( 8 , 1 ) . But since it is a straight line it will have infinite number of solutions .
[ Also Refer to graph in the attachment ]
The ordered pair which will be the solution of the equation can be ( 6, 0 ) or ( 8, 1 ).
Given that,
Equation; [tex]\rm x-2y =6[/tex]
We have to determine,
An ordered pair (x, y) is a solution to the equation?
According to the question,
An ordered pair refers to a number written in a certain order. An ordered pair is used to show the position on a graph,
Where the "x" (horizontal) value is first, and the "y" (vertical) value is second. Also in the co-ordinate system, ordered pair is used to locate a point.
The points through which it passes, the coordinates of that particular point will be a solution for this linear equation.
Here, taking the given equation & drawing its graph,
Equation; [tex]\rm x-2y =6[/tex]
The equation can also be written as,
[tex]\rm x-2y =6\\\\x = 6+2y[/tex]
An ordered pair of the solution is found when substitute y = 0,
[tex]\rm x = 6+2y \\\\x= 6+2(0)\\\\x = 6+0\\\\x = 6[/tex]
And another ordered pair of the solution is found when substitute y = 1,
[tex]\rm x = 6+2y \\\\x= 6+2(1)\\\\x = 6+2\\\\x = 8[/tex]
Hence, the required order pair which will be the solution of the equation can be ( 6, 0 ) or ( 8, 1 ).
For more details refer to the link given below.
https://brainly.com/question/12926248
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if a box of toffies can be divided among 24 children each will get 4 how many toffies will each get if the number of children is reduced 24
Answers
Given : A box of toffies can be divided among 24 and children each will get 4 .
To Find : Number of toffies will each get if the number of children is reduced 24
Solution : If toffies are distributed among the children and each child gets 4 , then the total number of toffies will be equal to , 24 × 4 = 96 toffies .
Again it is given that the toffies are redistributed among 24 children . So the number of toffies each will get will be equal to ,
=[tex]\bf \cancel{\dfrac{96}{24}}[/tex]
=[tex]\Large\boxed{\red{\bf 4 }}[/tex]
Hence the required answer is 4 .
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Suppose a standard dartboard is hung at standard height so that the bull's-eye is 11 feet from a wall to its left.
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Does Samuel's dart land on the dartboard?
Answers
Answer:
Yes, Samuel dart does land on the dart board
Step-by-step explanation:
The given parameters are;
The height from the floor to the bulls eye = 5 feet 8 inches
The size of the standard board = 18 inches diameter
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The distance the dart Samuel throws land from the left wall = 11.5 feet
The distance above the ground, the dart Samuel throws land = 5.5 feet
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The equation of the circle representing the dart board = (x - 11)² + (y - 5.67)² = 0.75² = 0.5625
The unit of the radius is in feet
The position of Samuel's dart is represented by the coordinate, (11.5, 5.5)
Plugging in the coordinates of the position of Samuel's dart into the equation of the circle of the dart board gives;
(11.5 - 11)² + (5.5 - 5.67)² = 0.2789 ≈ 0.528²
Therefore, given that the square of the distance of the position of Samuel's dart is less than the square of the radius of the dart board, we have;
Yes, Samuel dart does land on the dart board.
From the parameters given to find out if Samuel's dart landed on the dartboard, we can say that;
Samuel's dart does not land on the dartboard.
We are given;
Height from the floor to the bulls eye = 5 ft 8 in = 5.67 ft
Diameter of the standard dartboard = 18 in = 1.5 ft
Thus, radius; r = 1.5/2 = 0.75 ft
Distance of the bulls eye from the wall to the left = 11 ft
Distance of dart thrown by Samuel from the left wall = 11.5 ft
Height of dart thrown by Samuel above the ground = 5.5 ft
We know that general equation of a circle is;
(x - a)² + (y - b)² = r²
Since Height from the floor to the bulls eye is 5.67ft,then a = 5.67 ft
And also since Distance of the bulls eye from the wall to the left = 11 ft, then b = 11 ft
Thus;
(x - 11)² + (y - 5.67)² = 0.75²
(x - 11)² + (y - 5.67)² = 0.5625
Now, since he throws a dart at the dartboard that lands at a point 11.5 feet from the left wall and 5.5 feet above the floor. Thus;
r² = (11.5 - 11)² + (5.5 - 5.67)²
r² = 0.2789
r² of 0.2789 gotten here is lesser than 0.5625 gotten earlier, we can conclude that Samuel's dart does not land on the dart board.
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