explain how to multiply rational expressions

Answer: The both involve writing a rate

I hope this helps i would appreciate brainliest if possible :)

Answer: Y=7x+19

Step-by-step explanation:

got no time for explain hope this helper

9514 1404 393

Answer:

  y -5 = 7(x +2)

Step-by-step explanation:

Values for the slope and a point are given. That makes it convenient to use the point-slope form of the equation for a line:

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

  y -5 = 7(x +2) . . . . . . line with slope 7 through point (-2, 5)

__

Sometimes, you want the slope-intercept form of the equation. That can be found by solving for y

  y -5 = 7x +14 . . . . . . . . eliminate parentheses

  y = 7x +19 . . . . . . . . . . add 5 to both sides

__

In standard form, the same line has equation ...

  7x -y = -19

Answer:

5

Step-by-step explanation:

set up point slope form

y + 8 = 2(x-1)

set y to zero

0+8=2(x-1)

8=2x-2

10= 2x

x = 5

Answer:

B) 2x + 3 = 2x + 4 - 1

Step-by-step explanation:

A) 3x + 4 = 5x - 1

2x = 5

x = 2/5

B) 2x + 3 = 2x + 3

True

C) 5x = 10

x = 2

D) -3x + 1 = -3x - 5

False

Equivalent expressions are simply expressions that have the same value, irrespective of their form.

The equivalent expression of [tex]\mathbf{6x(3x + 11)}[/tex] is [tex]\mathbf{18x^2 + 66x}[/tex]

The expression is given as:

[tex]\mathbf{6x(3x + 11)}[/tex]

Start by opening the brackets; i.e. apply distributive property

[tex]\mathbf{6x(3x + 11) = 6x \times 3x + 6x \tiimes 11}[/tex]

Evaluate all products

[tex]\mathbf{6x(3x + 11) = 18x^2 + 66x}[/tex]

The expression cannot be further simplified.

Hence, the equivalent of [tex]\mathbf{6x(3x + 11)}[/tex] is [tex]\mathbf{18x^2 + 66x}[/tex]

Read more about equivalent expressions at:

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Answer:

Well I’m not sure what Answers do you want

Step-by-step explanation:

Answer:

161oz = 10.0625 (then you round)

Step-by-step explanation:

Answer:

5. is III. Since there is a vertical asymptote at x= -3 and hole at x=0

Answer:

7

Step-by-step explanation:

Working backwards:

19 + 9 = 28

28/ 4 = 7

Checking work:

7 x 4 = 28

28 - 9 = 19

Answer:

[tex]3\dfrac{1}{4} \ \ or \ \ 3,25[/tex]

Step-by-step explanation:

[tex]\displaystyle12 \frac{3}{8} -9\frac{1}{8} =12-9+\frac{3}{8} -\frac{1}{8} =3+\frac{2}{8} =3\frac{1}{4} \ \ or \ \ 3,25[/tex]

Answer:

  0 and 1

Step-by-step explanation:

The scale of the graph is not marked, so we assume each grid line represents 1 unit. The leftmost crossing of the x-axis is between 0 and 1.

_____

Additional comment

The other real zero is between 2 and 3. If this is a polynomial function, it will have additional complex zeros.

Answer:

8

Step-by-step explanation:

11-3=8

11-3=8 must subtract for anser

Answer:

Parallel lines: Line B and C

Perpendicular lines: Line A and B; Line A and C

Step-by-step explanation:

To answer this question, we only need to find the slope of each equation. The formula for slope is attached in a picture.

LINE A

Substituting the first line into the formula, we will get...

(2 - 5)/(0 -(-4))

-3/4

LINE B

Substituting the second line's points into the formula we will get...

(2 - 6)/(3 - 6)

-4/-3

4/3

LINE C

Substituting the third line's points into the formula we will get...

(3 -(-1)/(0 -(-3))

4/3

So, parallel lines have the same slope, right? Since line b and line c have the same slope, they are parallel.

And, perpendicular lines have negative reciprocal slopes, right? (reciprocal means x/y -> y/x) Since -3/4 and 4/3 are negative reciprocals of each other, they are perpendicular.

Therefore...

Parallel lines: Line B and C

Perpendicular lines: Line A and B; Line A and C

Answer:

D. 604.8

Step-by-step explanation:

Answer: these are correct

1,750

14,000,000

1,120,000

604.8

[tex]2x^2 -5x-8 =0\\\\\implies x = \dfrac{ -(-5) \pm \sqrt{(-5)^2 - 4\cdot 2 \cdot (-8)}}{2 \cdot 2}\\\\\\\implies x = \dfrac{5 \pm \sqrt{89}}{4}\\\\\\\text{Hence}~ x = \dfrac{5 + \sqrt{89}}{4},~~ x = \dfrac{5 - \sqrt{89}}{4}[/tex]

Answer:

[tex]\sf \boxed{\sf x=\frac{5+\sqrt{89}}{4}}[/tex]

[tex]\sf \boxed{\sf x=\frac{5-\sqrt{89}}{4}}[/tex]

[tex]\sf 2x^2-5x-8=0[/tex]

☁ We'll solve this equation using The Quadratic Formula:

[tex]\boxed{\sf \cfrac{-b\pm \sqrt{b^2-4ac}}{2a}}[/tex]

A= 2, b= -5, c= -8

[tex]\sf x=\cfrac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\times \:2\left(-8\right)}}{2\times \:2}[/tex]

[tex]\mapsto \sf \sqrt{\left(-5\right)^2-4\times \:2\left(-8\right)}[/tex]

[tex]**\sf \left(-5\right)^2=5^2[/tex]

[tex]\mapsto \sf \sqrt{5^2+4\times \:2\times \:8}[/tex]

[tex]\mapsto \sf \sqrt{5^2+64}[/tex]

[tex]\mapsto \sf \sqrt{89}[/tex]

______________

[tex]\sf x=\cfrac{-\left(-5\right)\pm \sqrt{89}}{2\times \:2}[/tex]

☁ Now, we'll Separate solutions, first, we'll solve the equation when ± is plus:

[tex]\mapsto \sf \cfrac{-\left(-5\right)+\sqrt{89}}{2\times \:2}[/tex]

☁ Multiply 2*2 =4

[tex]\boxed{\sf \cfrac{5+\sqrt{89}}{4}}[/tex]

_________________

☁ Now solve the equation when ± is minus:

[tex]\mapsto \sf \cfrac{-\left(-5\right)-\sqrt{89}}{2\times \:2}[/tex]

☁  Multiply 2*2 =4

[tex]\boxed{\sf \cfrac{5-\sqrt{89}}{4}}[/tex]

[tex]\sf Solution \:1:\boxed{\sf x=\frac{5+\sqrt{89}}{4}}[/tex]

[tex]\sf Solution \:2:\boxed{\sf x=\frac{5-\sqrt{89}}{4}}[/tex]

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Answer:

I think the answer would be A

Answer:

I and II

Step-by-step explanation:

All trapezoids have a midsegment. The base angles of isosceles trapezoids are always congruent. Because the top and bottom side are parallel, the same side interior angles are supplementary not complementary.

Answer:

Y=5 y=-3

Step-by-step explanation:

Two real solutions:

y =(2+√64)/2=1+4= 5.000

or:

y =(2-√64)/2=1-4= -3.000

Answer:

[tex]11[/tex]

Step-by-step explanation:

[tex]\sf{Use\: the\: distance\: formula\: to\: determine\: the\: distance\: between\: two\: points.[/tex]

[tex]\sf{Distance=\sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}[/tex]

[tex]\mathrm{Plug\:the\:points}[/tex]

[tex]\sqrt{\left(4-\left(-7\right)\right)^2+\left(5-5\right)^2}[/tex]

[tex](4+7)^2=11^2\\(5-5)^2=0[/tex]

[tex]\sqrt{11^2+0}[/tex]

[tex]11^2+0=11^2\\\sqrt{11^2}[/tex]

[tex]\mathrm{Apply\:radical\:rule:\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\:\mathrm{is\ greater\ than \:or\ equal\: to \:0}[/tex]

[tex]=11[/tex]

Answer:

Step-by-step explanation:

here you go m = (y2-y1)/(x2-x1)

  = (11-(-9))/(3-(-1))

  = 20/4

  = 5

Answer:

The final velocity, V, of an object under constant acceleration can be found using the formula V2=v2+2as , where v is the initial velocity in meters per second, a is acceleration in meters per second, and s is the distance in meters.

Answer:

y = 9/10x - 7/5

Step-by-step explanation:

Slope = 9/10

Point (6,4)

y-intercept = 4 - (9/10)(6) = 4 - 54/10

= - 7/5

Answer:

$11

Step-by-step explanation:

This is because If you subtract 19 from 30 your answer will be 19.

Answer:

x=6

Step-by-step explanation:

907 - 43 = 864 / 2 = 432: 907 - 432 = 475

The garden table costs $432.

The bench costs $475.

475 + 432 = 907

I hope this helps! :)

Answer:

75 miles

Step-by-step explanation:

We know that she has driven 120 miles before the first stop.

Then she drives for 1/4 of the the distance she has already driven (120 miles). One fourth of 120 is 30.

So now, she's driven for 120 + 30 miles, or 150 miles.

She drives for another 2/3 of the distance she's traveled (150 miles). Two thirds of 150 is 100.

So now, she's driven for 150 + 100 miles, or 250 miles.

What we need to find out now is how much of the trip has she traveled.

We know that the entire distance she has driven is 55 miles more than 1 ⅔ of the remaining trip. So, in other words, the distance she has traveled minus 55 is equal to 1 2/3 of the trip.

To put this in an equation:

250 - 55 = 1 2/3t

t = the whole trip

Now, we solve for t.

250 - 55 = 195

1 2/3 = 5/3

so, 195 = 5/3t

t = 325

We subtract what she has already driven to the total to get the remaining distance.

325 - 250 = 75

Answer:

d .  37/12 unit^2.

Step-by-step explanation:

d) First find the points of intersection of the the 2 graphs, by solving them simultaneously:

x^3 = x^2 + 2x

x^3 - x^2 - 2x) = 0

x(x^2 - x - 2) = 0

x(x - 2)(x + 1) = 0

So they intersect at x = -1, x = 0 and x = 2.

Take the area from x = 0 to x = 2)

           2                        2

Area =  ∫ x^2 + 2x dx -   ∫  x^3 dx

            0                       0

   2

=  [ x^3/3 + x^2 ) - x^4/4]

   0

=   ((8/3 + 4) - 0) - (16/4 - 0) -

=   8/3 unit^2

Now calculate the area  from x = -1 to x = 0.

   0

=    (x^3/3 + x^2 ) - x^4/4 )

   -1

=   (( 0 +1/3 - 1) ) - (0 - 1/4)

=  5/12 unit^2

So the total area of the region =  8/3 + 5/12 = 37/12 unit^2.

Answer:

that have no answer so sorry