Explain how friction is involved in energy transformation.

Answer:

it’s 10ml

Explanation:

200/2 = 10

Answer:

24 atm

Explanation:

From Boyle's Law :

Given values :

Solving

New volume

So apply Boyles law

Answer:

280gr of salt

Explanation:

4.80 x ( 22.99 + 35.45) = 280gr

Simple as that

           

The mass of copper that will be produced from copper oxide is determined as 3.19 g.

The mass of copper that will be produced from copper oxide is calculated as follows;

2Cu + O₂  -----> 2CuO

2          1             2

2(63.5) ------------ 2(79.5)

x ---------------------- 4 g

x = (4 x 2 x 63.5)/(2 x 79.5)

x = 3.19 g

Thus, the mass of copper that will be produced from copper oxide is determined as 3.19 g.

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The students can determine which of the solutions contains salt through the conductive tester.

It is a solution containing ions are atoms that have gained or lost electrons to acquire a positive (lost electron) or negative (gained electron) charge.

An ionic solution would be able to conduct electricity whereas the covalent would not so if you have a conductivity tester which is available in most labs.

The students can distinguish between the 2 solutions through the conductive tester.

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Answer: See attached image

Explanation:

The value of density in the required units is [tex]\rm \rho = 2.4\times 10^{-5} lb/in^{3}[/tex]

Density, mass of a unit volume of a material substance. The formula for density is

d = M/V

where d is density, M is mass, and V is volume.

Density is commonly expressed in units of grams per cubic centimetre.

In the given question

Density given is 0.668 g/L

1 lb = 454grams.

1L = 1000 cm³

1 inch = 2.54 cm

Density in pounds per cubic inch =

[tex]\rm \rho = 0.668 \times \dfrac{(1 \;lb)(1 grams)}{454\; grams}\times \dfrac{(1 L)(2.54)^{3}(1 cm^{3})}{1000cm^{3}(1\;L)(1 in^{3})}[/tex]

[tex]\rm \rho = 2.4\times 10^{-5} lb/in^{3}[/tex]

Therefore the value of density in the required units is [tex]\rm \rho = 2.4\times 10^{-5} lb/in^{3}[/tex].

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The weight of an object is defined as the force of gravity on the object and may be calculated as the mass times the acceleration of gravity, w = mg. Since the weight is a force, its SI unit is the newton.

W = mg

Weight of object = mass of object × acceleration of gravity

The following compounds create solutions that are listed below

A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.

solvent: the substance in which a solute dissolves to produce a homogeneous mixture

solute: the substance that dissolves in a solvent to produce a homogeneous mixture

1. Nal and H₂O

It will form an ionic solution .

2. KBr and CH4

It will not form a solution

3. CO₂ and CF₄

It will not form a solution

4. LiCI and CCl₄

It will not form a solution

5. NH₃ and H₂O

It will also form a solution and liberate ions of ammonium

6.CO₂ and H₂O

It will form a solution named as carbonic acid

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The answer is 0.46 ml of the original H₂S0₄ and dilute to a final volume of 100 ml.

Normality is a measure of concentration equal to the gram equivalent weight per liter of solution.

Normality = Number of gram equivalents × [volume of solution in litres]⁻¹

Preparing 100. ml of 0.1 N H₂S0₄

Eq. wt. of H₂S0₄ = 98/2=49

density of H₂S0₄= 1.08

Purity =98%

1 N H₂S0₄ = 49 gH₂S0₄ / liter

1  gm equiv wt /L x 1 gm equiv. wt / 2 = 98 / 2 = 49 g)

0.1 N H2SO4 = 4.9 g / L

To make 100 ml (0.100 L) we would need 4.9 [tex]\rm \frac{g}{L}[/tex] x 0.1 L

= 0.49 g H₂S0₄/100ml

Original density = 1.08 g / ml

with a purity of 98%,

this converts to 1.08 g x 0.98 = 1.058 g /ml

0.49 g H₂S0₄ x 1 ml / 1.058 g = 0.46 ml of original H₂S0₄needed

Therefore to make the desired solution

Take 0.46 ml of the original H₂S0₄ and dilute to a final volume of 100 ml.

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For first order plot of ln( [tex]P_{SO_{2}Cl_{2}}[/tex]) vs time will be a straight line, which shows first order reaction

A first-order reaction can be defined as a chemical reaction in which the reaction rate is linearly dependent on the concentration of only one reactant. In other words, a first-order reaction is a chemical reaction in which the rate varies based on the changes in the concentration of only one of the reactants

Every mole of SO₂Cl₂ that dissociates results in a mole of SO₂ &Cl₂

[tex]\rm P_{total}= P_{Cl_{2}\\}+ P_{SO_{2}Cl_{2}}+ P_{SO_{2}}\\\\ P_{total} = P_{o}- \beta +\beta + \beta\\\\ P_{total} = P_{o}+\beta[/tex]

For first order plot of ln( [tex]P_{SO_{2}Cl_{2}}[/tex]) vs time will be a straight line.

t(hr)           [tex]P_{SO_{2}Cl_{2}}[/tex]                            ln([tex]P_{SO_{2}Cl_{2}}[/tex] )

0                11.07                                  2.404

3                 7.35                                 1.995

6                4.88                                 1.585

9                3.24                                 1.176

12                2.15                                 0.765

15                1.43                                 0.358

β = P(total) - P(initial)

[tex]\rm P_{SO_{2}Cl_{2}}[/tex] = P₀ - β

for t= 3

β =3.72

and

[tex]\rm P_{SO_{2}Cl_{2}}[/tex] = 7.35

For first order plot of ln( [tex]P_{SO_{2}Cl_{2}}[/tex]) vs time will be a straight line, which shows first order reaction.

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Answer:

it is a weak acid

acid

Explanation:

formaldehyde is a weak acid (pK greater than 13),

Convert temperature to Kelvin

Convert vol to L

Apply Charles law

Answer:

[tex]V_{1} = \text{400.0 mL}[/tex]

[tex]T_{1} = 225.0^{\circ}\text{C + 273.15 = 498.15 K}[/tex]

[tex]T_{2} = 127.0^{\circ}\text{C + 273.15 = 400.15 K}[/tex]

[tex]V_{2}[/tex]

[tex]\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}[/tex]

[tex]V_{2} = V_{1} \times \dfrac{T_{2}}{T_{1}}[/tex]

[tex]V_{2} = \text{400.0 mL} \times \dfrac{\text{400.15 K}}{\text{498.15 K}}[/tex]

[tex]\boxed{V_{2} = \text{321.3 mL}}[/tex]

Therefore, the volume of the gas at 127.0°C is 321.3 mL

[tex]\begin{gathered}\\\end{gathered}[/tex]

Grams are the unit of measurement of the mass or the weight of the substance. There are 1.17 gms of chlorine atoms in the sample.

The mass of the substance is the multiplication of the moles and the molar mass.

Barium chloride dissociates as:

BaCl₂ ⇄  Ba²⁺ + 2 Cl⁻

From the reaction, it can be said that 1 mole of barium chloride dissociates into 1-mole barium ion and 2 moles of chloride ions.

Moles of barium chloride are calculated as:

Moles = mass ÷ molar mass

= 3.45 gm ÷ 208.23 g/mol

= 0.016 moles

If 1 mole of Barium chloride has 2 moles then 0.016 moles of the sample will have, 0.0331 moles of chloride ions.

The mass of chlorine atoms is calculated as:

Mass = moles × molar mass

= 0.0331 × 35.45

= 1.17 gms

Therefore, 1.17 gms of chlorine atoms are present in barium chloride.

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Answer:

Increase of pressure increases the coordination number during crystallization e.g. by applying pressure the NaCl type crystal structure having 6:6 coordination number changes to CsCl type crystal having coordination number 8:8.

welc!! you Σ=)

Answer:

rsghkm vumm

Explanation:

el correo de confirmación con la que se ha enviado desde correo ok recibido gracias saludos María del Ca

Answer:

The nuclear composition of uranium-235 is 92 protons and 143 neutrons.

Explanation:

MgCl2(aq) + NaOH(aq) = Mg(OH)2(s) + NaCl. Both magnesium nitrate and sodium hydroxide solutions are colourless solutions. When they react with each other, a white precipitate (Mg(OH)2) and a colourless solution is given. Sodium chloride exists in the colourless aqueous solution.

The percent composition of Cesium and Fluorine in CsF are 87.493 % and 12.507 % respectively.

Percent composition is very simple. Percent composition tells you by mass what percent of each element is present in a compound.

Molecular mass of Cs = 132.9054519

Molecular mass of F = 18.9984032

Molecular mass of CsF = 132.9054519 + 18.9984032 = 151.9038551

CsF: Percent composition by element:

Cesium (Cs) =  [tex]\frac{32.9054519 X 100}{151.9038551}[/tex] = 87.493 %

Fluorine (F) =  [tex]\frac{18.9984032 X 100 }{151.9038551}[/tex]= 12.507 %

Hence, the percent composition of Cesium and Fluorine in CsF are 87.493 % and 12.507 % respectively.

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Answer:

Liquid–liquid extraction

Explanation:

Because:

Their roots are no longer in the soil. Thus, can't absorb water and mineral ions needed for plant growth via photosynthesis.

Hope this helps!

Answer:

Yes

Explanation:

Well this is because when a plant is planted water goes from the soil, into the roots then finally distributed to other parts of the plant.

So when plants have been plucked or uprooted water no longer has access to the plant which may result to the plant being dried up and will possibly die

Answer:

See below

Explanation:

The large bar magnet is positioned with S on the Left

  the small magnet will position itself similar this with N on the right   S on the left   (opposites attract)

Answer:  100 milligrams per dose

10 mg per kg. The drug of ten kilos so you do

10 mg * 10 kg = 100 mg per dose

Explanation:

The required formula of hydrate is MgSO₃.6H₂O.

The number of moles of water per mole of anhydrous solid (x) will be computed by dividing the number of moles of water by the number of moles of anhydrous solid (x) to find the hydrate's formula.

Moles will be calculated as:
n = W/M, where

Moles of MgSO₃ = 0.737g / 104.3g/mol = 0.007mol

Moles of H₂O = 0.763g / 18g/mol = 0.04 mol

Number of H₂O molecule = 0.04/0.007 = 5.7 = 6

So formula of hydrate is MgSO₃.6H₂O.

Hence required formula of hydrate compound is MgSO₃.6H₂O.

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The answer is CH₃-CH₂-CH₂-CH=CH₂ , Option C correctly represents the structural formula for pentene .

Any hydrocarbon containing one or more double bonds.

Alkenes are generally colorless non-polar compounds, somewhat similar to alkanes but more reactive.

The first few members of the series are gases or liquids at room temperature.

Pentenes are alkenes with the chemical formula C₅H₁₀.

Each contains one double bond within its molecular structure.

CH₃-CH₂-CH₂-CH=CH₂ , Option C correctly represents the structural formula for pentene .

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Answer:

2000pound

Explanation:

Manganese metal is produced from the manganese(III) oxide, Mn2O3, which is found in manganite, a manganese ore. The manganese is reduced from its +3 oxidation state in Mn2O3 to the zero oxidation state of the uncharged metal by reacting the Mn2O3 with a reducing agent such as aluminum or carbon. How many pounds of manganese are in 1.261 tons of Mn2O3? (1 ton = 2000 pounds)

About 40 different substances called organophosphorus compounds are registered in the United States as insecticides. They are considered less damaging to the environment than some other insecticides because they breakdown relatively rapidly in the environment. The first of these organophosphorus insecticides to be produced was tetraethyl pyrophosphate, TEPP, which is 33.11% carbon, 6.95% hydrogen, 38.59% oxygen, and 21.35% phosphorus. It has a molecular mass of 290.190.

A quantity can be converted from one unit of measurement to another while maintaining its value. There are 2522 pounds of manganese in 1.261 tons of [tex]\rm Mn_2O_3[/tex].

It is a fundamental idea that is applied in many different disciplines such as science, engineering, math and daily life. To complete a conversion, it is necessary to know the conversion factor – the numerical relationship between the two units of measurement. With the help of this factor, you are able to convert units while keeping the value constant.

To convert tons to pounds we need to know that 1 ton is equal to 2000 pounds.

Given that you have 1.261 tons of [tex]\rm Mn_2O_3[/tex], we can calculate the number of pounds as follows:

Number of pounds = 1.261 tons * 2000 pounds/ton

Number of pounds = 2522 pounds

Therefore, there are 2522 pounds of manganese in 1.261 tons of [tex]\rm Mn_2O_3[/tex].

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Answer:

Air resistance opposes the gravity in a falling object hence the object loses speed once it reaches terminal velocity.

According to the experim

Answer:

+ 47.68 Liter change in volume to final volume 129.68 L

Explanation:

P1V1/T1 = P2V2/T2     RE-ARRANGE TO:

P1V1/T1  * T2/P2  = V2         (T must be in Kelvin)

1.9 * 82 / (273.15 + 32.5)   *  (273.15-15.4)/ (770/760) = 129.68 L

129.68 - 82=47.68 L  change  

Answer:

0.0734 grams LiOH

Explanation:

The molarity formula looks like this:

Molarity (M) = moles / volume (L)

You are given the molarity and volume (in mL). Therefore, you can plug these values into the equation and solve for moles (after you convert from mL to L).

25 mL / 1,000 = 0.025 L

0.125 M = moles / 0.025 L

(0.125 M) x (0.025 L) = moles

0.003125 = moles

After using the molarity formula, we know that 0.003125 moles LiOH are needed to satisfy these conditions. Now, we can convert this to grams using the molar mass of LiOH. This can be determined using the values from the periodic table. Remember to write your conversion in a way that allows for the units to cancel out.

Molar Mass (LiOH) = 6.941 g/mol + 16.00 g/mol + 1.008 g/mol

Molar Mass (LiOH) = 23.499 g/mol

0.003125 moles           23.499 g
------------------------   x   -------------------  =  0.0734 grams LiOH
                                        1 mole

0.074 grams of lithium hydroxide are needed to make 25 ml of 0.125 M solution, according to the concept of molar concentration.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.

Here , in the problem mass is to be determined, hence the formula used is the first one mentioned.

Substituting values in the formula,mass=molar concentration×molar mass×volume in liters

∴0.125×23.95×0.025=0.074 g.

Hence, 0.074 g of lithium hydroxide are required to prepare 25 ml of 0.125 M solution.

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