Every atom contains a
.............. which is positively charged

An energy storage device composed of electrochemical cells is referred to as: battery.

A power source can be defined as a source of electrical energy that is used to power all electronic devices.

Generally, a power source can be classified into two (2) main categories and these include:

A battery refers to an energy storage device that comprises electrochemical cells and it serve as a source of direct current (DC). Also, sometimes a battery can be recharged when its electrochemical cells are still active.

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Answer:

Battery is an electrical energy storage device consisting of one or more electrochemical cells with external connections that provide power to electrical devices such as flashlights, smartphones, and electric cars.

Answer:

it is It will maintain its state of motion. because of newtons law states that any object in morion will stay in motion unless acted upon another force pushing against it

Explanation:

Answer:

It will maintain its state of motion.

Explanation:

Answer:

The moon's gravity pulls the Earth to make tides.

Explanation:

The Moons Gravity Pulls On The Earth With Different  Strenght Making High Tide And Low Tide.

Hope This Helps!

Answer:

Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Explanation:

Answer/Explanation:

Part 1: 13 chromosomes.

Reproductive cell, male or female, whose nucleus contains only one chromosome of each pair (they are said to be haploid n = 13) and which unites with the gamete of the opposite sex (fertilization) to give birth to an egg (zygote 2n = 26 ) diploid resulting from the association of the two gametes with each his half of the genetic capital.

2. The process of creating a new flower is called reproduction.

Human reproduction is the process by which a man and a woman engender a new individual. It is a method of sexual reproduction.

Sexual reproduction requires:

Explanation:

given

m=3500kg,h=4.0m,v=12m/s

ke=½mv²

½×3500×12²=3500×144÷2

=252,000j or 252j

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{42}{1.8} = 23.3333... \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

[tex]\boxed {\boxed {\sf C. \ 23.33 \ kg}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.

Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².

Substitute the values into the formula.

[tex]42 \ kg*m/s^1 = m * 1.8 \ m/s^2[/tex]

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}[/tex]

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m[/tex]

The units of meters per second squared cancel.

[tex]\frac {42 \ kg}{1.8 } =m[/tex]

[tex]23.3333333 \ kg=m[/tex]

Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.

[tex]23.33 \ kg \approx m[/tex]

The mass of the ball is approximately 23.33 kilograms.

The minimum force required to start this block moving is 370 N.

The given parameters;

The minimum force required to start this block moving is calculated as follows;

[tex]F= \mu_s F_n[/tex]

where;

[tex]F_n[/tex] is the normal force on the block which is equal to the weight of the block

[tex]F= \mu_s F_n \\\\F= \mu_s W\\\\F = 0.74 \times 500 \\\\F= 370 \ N[/tex]

Thus, the minimum force required to start this block moving is 370 N.

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The Big Bang theory allows finding the result for which particles were formed in the 1 s of the universe is:

The Big Bang theory says that the universe is formed about 14 billion years ago, of a structure that is very high energy.

Einstein's equation establishes the relationship between energy and matter, establishing that energy can be converted into matter.

              E = m c²

Where E is energy, m is mass, and c is the speed of light.

In the 1 s of the universe the energy density was so high that all subatomic particles were formed, the first being quarks.

When the universe cooled enough, the quarks combined to form protons and neutrons, from which atoms were formed.

In conclusion, using the Big Bang theory we can find the result for which particles were formed in the 1 s of the universe is:

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Answer: The area of the edge of a knife's blade is extremely small.  

Syringes are used to take blood for blood tests.  

When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside forces the liquid to go inside the straw.

Explanation:

Answer:

A. Fusion Reactions

Explanation:

Answer: One main reason, all three experts agree, is the phenomenon known as “windthrow” which uproots a tree. “The tree trunk acts as a lever and so the force applied to the roots and trunk increases with height,” says Foster. “Taller trees are more susceptible to windthrow.”

Answer : Lipids and carbohydrates are both made from carbon, hydrogen, and oxygen, but lipids have less oxygen (Option B)

Carbohydrates are biomolecules composed of carbon (C), hydrogen (H), and oxygen (O) in a 1:2:1 ratio, respectively.

Carbohydrates can be divided regarding the number of monomers in the biomolecule into monosaccharides, disaccharides, and polysaccharides.

Explanation:

hope this answer will helps you !

The value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].

According to the principle of conservation of linear momentum, the total momentum before and after collision is conversed.

[tex]m_av_a_1 + m_bv_b_1 = v(m_a + m_b)[/tex]

where;

since the train car A is at rest, [tex]v_a _1 = 0[/tex]

[tex]m_bv_b_1 = v(m_a + m_b)[/tex]

The relationship between the final velocity and initial velocity of the cars is given as;

[tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex]

Thus, the value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].

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Answer: the answer is the third option. Edge 2021

Explanation: i just answered the problem

Answer:

Answer:

72.936 Joule

Explanation:

Mechanical Energy = Potential Energy + Kinetic Energy

Kinetic Energy = (1/2) x m x V² = (1/2) x 1.8 x 4.8² = 20.736 J

Potential Energy = m x g x h = 1.8 x 10 x 2.9 = 52.2 J

Total Mechanical Energy = 20.736 + 52.2 = 72.936 Joule

Explanation:

Answer:

For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. The resultant force on the car is zero.

Explanation:

hope this helps

Answer:

zero

Explanation:

The acceleration of the car is zero, and and in this case the velocity is also zero. When your car is moving at constant velocity down a street, the net force must also be zero, according to Newton's First Law.

Answer:

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Answer:

Explanation:

The rotational velocity vector is directed away from the jar

The velocity of the red cart after the collision is 2 m/s

From the law of conservation of momentum, initial momentum of system = final momentum of system.

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.

Substituting the values of the variables into the equation, we have,

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄

4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s

16 kgm/s + 0 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s - 8 kgm/s =  (4 kg)v₃

(4 kg)v₃ = 8 kgm/s

Divide both sides by 4 kg, we have

v₃ = 8 kgm/s ÷ 4 kg

v₃ = 2 m/s

The velocity of the red cart after the collision is 2 m/s.

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Answer:

Δx=7.35m

Explanation:

This is a free fall problem (g= -9.8 m/s²).

Displacement: ? <--- what you're trying to find (max height)

Initial Velocity: 12 m/s

Final Velocity: 0 m/s <-- since the can will land back in your hands

Time: Missing <-- not needed to solve

Acceleration: -9.8 m/s²

The equation that you will use is vf²=vi²+2aΔx

Now plug the information into the equation!

(0m/s)²=(12m/s)²+2(-9.8m/s²)Δx

Multiply the 2 with the acceleration (-9.8m/s²)

(0m/s)²=(12m/s)²-19.6m/s²Δx

Now you need to square the final and initial velocity

0m/s=144m/s-19.6m/s²Δx

Move 144 to the other side of the equal sign

-144m/s=-19.6m/s²Δx

Divide both sides by -19.6m/s²

7.346m=Δx

You can round it to the tenth or hundreth place, up to you!

For this example, I'll round to the hundredth...

Δx=7.35m

I would double check this answer or review it yourself to see if it's correct.

Good luck with your studies!

The first resonant position below the open end of the resonance tube is; one-quarter of the wavelength

In the event of the first resonant position in a resonance tube, there will be a maximum air displacement which is only one antinode right at the open end where the motion is constrained.

However, there will be no displacement at the closed end which means another one node right at the closed end where air is halted.

This means that the standing wave will have one-quarter of the wavelength in the test tube.

Thus;

L = ¼λ

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Answer:

The expansion of the universe is accelerating.

Explanation:

Answer:

A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point.

Explanation:

The number of lead pellets to be added to the water to achieve the given equilibrium temperature is 451.54.

The given parameters;

Apply the principle of conservation of energy to determine the number of lead pellets to be added to given water to achieve the given equilibrium temperature.

Heat lost the lead = Heat absorbed by the water

[tex]m_lC_{l} \Delta t_l = m_wC_{w} \Delta t_w\\\\(n\times m)C_{l} \Delta t_l = m_wC_{w} \Delta t_w\\\\n(1.1)(0.129)(200 - 25) = (536)(4.184)(25-20)\\\\24.833n = 11,213.12\\\\n = \frac{11,213.12}{24.833} \\\\n = 451.54 \[/tex]

Thus, the number of lead pellets to be added to the water to achieve the given equilibrium temperature is 451.54.

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Answer:

W = F× d

= 300×750

= 225000

E = 225000

P = 300×750/25 = 9000

P = 300× 750/10 = 22500

Answer:coe?

Explanation:

Answer:

[tex]Q = 21.09 \times 10^{-8} C[/tex]

Explanation:

We know from theory that the magnitude of the force between two charges is measured by the expression

[tex]F=\frac1{4\pi\epsilon} \frac{Qq}{r^2}[/tex]

We know that two spheres have the same charge, and let's assume they're in a vacuum, so [tex]\epsilon = \epsilon_0 =8.85\times10^{-12} C^2/Nm^2[/tex]

At this point we can solve for Q

[tex]Q^2 = 4\pi\epsilon F r^2 = 4\pi \times (8.85 \times 10^-12)\times (6\times 10^-3) \times (2 \times 10^-1)^2 = 444.624 \times 10^{-17} = 4446.24\times 10^-16 C^2 \rightarrow Q = 21.09 \times 10^{-8} C[/tex]

Double check calculations for safety, as usual

Answer:

15N

Explanation:

mass=w/g 150N/m×0.1m

Ans=15N

Answer:

Both springs have a constant of 25Nm and the block is motionless. If the bottom spring is compressed 0.4m past its equilibrium and the block has a mass of 3kg, how far is the top spring stretched past its equilibrium?

g=10ms2

Possible Answers:

1.0m

0.8m

0.2m

0.4m

0.6m

Correct answer:

0.8m

Explanation:

Since the block is motionless, we know that our forces will cancel out:

Fnet=0

There are three forces in play: one from each spring, as well as the force of gravity. If we assume that forces pointing up are positive, we can write:

Fspring,top+Fspring,bot−mg=0

Plugging in expressions for each spring force, we get:

kxtop+kxbot−mg=0

Rearring for the displacement of the top spring, we get:

xtop=mg−kxbotk=(3kg)(10ms2)−(25Nm)(0.4m)25Nm

xtop=30N−10N25Nm=0.8m