Evaluate cos 17x/6

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The value of cos(17π/6) = cos(5π/6) = -√3/2.

Hence, cos(17π/6) evaluates to -√3/2.

To evaluate cos(17π/6), we can use the unit circle and the properties of cosine.

First, let's determine the reference angle.

The reference angle is the acute angle formed between the terminal side of the given angle and the x-axis.

The angle 17π/6 is greater than 2π, which means it completes more than one full revolution around the unit circle.

To find the reference angle, we can subtract 2π (or 12π/6) from 17π/6:

17π/6 - 12π/6 = 5π/6

Now, we can evaluate the cosine of the reference angle (5π/6).

In the unit circle, the reference angle 5π/6 corresponds to the point (cos(5π/6), sin(5π/6)).

The cosine value is represented by the x-coordinate of this point.

For the reference angle 5π/6, the x-coordinate is -√3/2.

Therefore, cos(17π/6) = cos(5π/6) = -√3/2.

Hence, cos(17π/6) evaluates to -√3/2.

For similar question on trigonometric functions.

https://brainly.com/question/6904750

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Question: How do you evaluate

cos

(17π/6)

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