Element A has two isotopes. The first isotope is present 19.52% of the time and has a mass of 265.1.
The second isotope has a mass of 182.27. Calculate the atomic mass of element A. (To two decimals
places)

Answers

Answer 1

The atomic mass of element A is 198.39 (to two decimal places).

To calculate the atomic mass of element A, we need to consider the relative abundance of each isotope and its corresponding mass. The atomic mass is the weighted average of the masses of all the isotopes, taking into account their relative abundance.

Given:

Isotope 1: Relative abundance = 19.52%, Mass = 265.1

Isotope 2: Relative abundance = 100% - 19.52% = 80.48%, Mass = 182.27

To calculate the atomic mass, we multiply the relative abundance of each isotope by its mass and sum up the results.

Atomic mass = (Relative abundance of Isotope 1 * Mass of Isotope 1) + (Relative abundance of Isotope 2 * Mass of Isotope 2)

Atomic mass = (19.52/100 * 265.1) + (80.48/100 * 182.27)

Calculating the values:

Atomic mass = (0.1952 * 265.1) + (0.8048 * 182.27)

Atomic mass = 51.72752 + 146.661296

Atomic mass = 198.388816

Rounding to two decimal places, the atomic mass of element A is 198.39.

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Why does n - hexane not dissolve in water?

Due to a large difference in polarity between the two compounds, n-Hexane does not dissolve in water.

Water is a polar molecule, which means that one end of it (the hydrogen side) has a slight positive charge and the other end (the oxygen side) has a slight negative charge. The unequal distribution of electrons within the water molecule, which produces a dipole moment, is the cause of this polarity.

N-Hexane, on the other hand, is a nonpolar molecule. The electrons are uniformly distributed throughout the molecule, which is made up of carbon and hydrogen atoms bound together in a straight chain. N-Hexane lacks a substantial dipole moment as a result.

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The number of particles contained in a sample is measured in terms of the mole. One mole of a compound is the quantity of that substance that has a mass in grams equal to its relative atomic or molecular mass (atomic weight).To find the number of moles of (NH₄)₃PO₄, we'll need to use the Avogadro constant, which is 6.02 x 10²³. We can use the formula:moles = particles ÷ Avogadro constantThe number of particles is given as 2.60 x 10²³. Substituting the values:moles = 2.60 x 10²³ ÷ 6.02 x 10²³moles = 0.432Molar massNow that we have the number of moles of (NH₄)₃PO₄, we can compute its mass. The molecular mass of (NH₄)₃PO₄ is 149.0 g/mol. We can use the formula:mass = moles x molecular mass Substituting the values:mass = 0.432 x 149.0mass = 64.7 grams

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