Answer:
no it is not different because it harf
A population of values has a normal distribution with μ = 21.9 μ = 21.9 and σ = 47.4 σ = 47.4 . You intend to draw a random sample of size n = 96 n = 96 . Find the probability that a single randomly selected value is between 12.7 and 20.4. P(12.7 < X < 20.4) = Find the probability that a sample of size n = 96 n = 96 is randomly selected with a mean between 12.7 and 20.4. P(12.7 < M < 20.4) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Answer:
Olá, boa tarde. Caso precise, estou a disposição para a realização de trabalhos acadêmicos, entre em contato comigo, Fernanda 21994321300
Explanation:
A government audit panel of 4 professionals is to be constituted from 6 senior auditors and 5 chartered accountants. Selection is random. (a) Determine the probability of the panel consisting of at least 3 senior auditors; (b) What is the probability of the panel consisting of at most 2 senior auditors.?
a) The probability of the panel consisting of at least 3 senior auditors is of: 0.3485 = 34.85%.
b) The probability of the panel consisting of at most 2 senior auditors is of: 0.6515 = 65.15%.
What is the hypergeometric distribution formula?The mass probability formula is presented as follows:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.N is the size of the population.n is the size of the sample.k is the total number of desired outcomes.The values of these parameters for this problem are given as follows:
[tex]N = 11, k = 6, n = 4[/tex]
The probability of the panel consisting of at least 3 senior auditors is given as follows:
P(X ≥ 3) = P(X = 3) + P(X = 4)
In which:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 3) = h(3,11,4,6) = \frac{C_{6,3}C_{5,1}}{C_{11,4}} = 0.303[/tex]
[tex]P(X = 4) = h(4,11,4,6) = \frac{C_{6,4}C_{5,0}}{C_{11,4}} = 0.0455[/tex]
Then the probability is of:
P(X ≥ 3) = P(X = 3) + P(X = 4) = 0.303 + 0.0455 = 0.3485 = 34.85%.
The probability of at most 2 senior auditors is of:
P(X ≥ 2) = 1 - P(X ≥ 3) = 1 - 0.3485 = 0.6515 = 65.15%.
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A good study group moderator will
Ask a strong opening question
b. Keep the group discussion on track
c. Validate group member statements
d. All of these
e. None of these
Please select the best answer from the choices provided
Answer:
D
Explanation:
i did the test
The following data points represent the number of songs each member of the band Python Sunboat has written.
5, 2, 9, 21, 12, 35,2,9,21,12,35, comma, 2, comma, 9, comma, 21, comma, 12, comma, 3
Find the median number of songs.
\qquad
songs
Answer:
7
Explanation:
6. The training will help me ask my supervisor when I am unsure of how to do a task safely.
(1 point)
A. Strongly Agree
B. Agree
C. Neutral
D. Disagree
E. Strongly Disagree
how to develop an e portfolio
Answer:
1. Decide on the purpose of your e portfolio. Ask yourself why you are creating the e portfolio. Consider what you want to communicate and the audience you are targeting.
2. Gather the content you want to include in your e portfolio. This could include resumes, work samples, awards, certifications, and other relevant documents.
3. Choose a platform for your e portfolio. There are many online tools that can help you create an e portfolio, such as WordPress, Weebly, Wix, and Squarespace.
4. Design your e portfolio. Consider the overall look and feel that you want to achieve. Think about the colors, fonts, and images you want to use.
5. Upload your content to your e portfolio. Make sure to include descriptions and captions for each item.
6. Test your e portfolio. Check for any errors or typos and make sure that all links are working properly.
7. Publish your e portfolio. Once you are satisfied with the final product, you can share it with your intended audience.
Explanation:
The television show began at 10:00 P.M. and ended at 10:30 P.M. How long did the television show last
ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ
Answer:
ok
Explanation:
Out of 848 items checked out of a public library, 335 were fiction books, 244 were non-fiction books, and 269 were videos (of any genre). What is the probability that a randomly-selected item was not a video?
Answer:
579/848 = 68.3%
Explanation:
848-269 = 579 non-video options
out of 848 possible outcomes
Explain how using non-local resources has affected the United States both environmentally and economically.
Answer:
Possible economic consequences of using non-local resources include increased costs of resources, loss of jobs, increased security risks, and a trade deficit.
Explanation:
The environmental and economic effects of how using non-local resources have affected the United States are:
increased costs of resources, loss of jobs, increased security risks, trade deficit. What is an Economy?This refers to the wealth distribution of a particular place based on its job provision, income, and other factors.
Hence, we can see that when non-local resources have been used in the United States of America, this has led to several effects such as increased costs of resources, loss of jobs, etc
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What must students do with the 10 grid-ins on the math section of the PSAT?
A. Mark the correct answer on a grid
B. Mark the incorrect answer on a grid
C. Arrive at an answer by creating a grid
D. Arrive at an answer and put it in a grid
An action which students must do with the 10 grid-ins on the math section of the PSAT is to: D. arrive at an answer and put it in a grid.
What is PSAT?PSAT is an acronym for Preliminary Scholastic Aptitude Test and it can be defined as type of multiple-choice test that is designed and developed to test the knowledge of high school students on a particular subject.
This ultimately implies that, an action which students must perform with the 10 grid-ins on the math section of the PSAT is to arrive at an answer and put it in a grid.
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The parallelogram shown below has an area of
60 units?
b
10
11
Find the missing base.
b=
units
Answer:
81 units po
Explanation:
sana makatulong
2. A conservative investor has $100,000 to invest. The investor has decided to use three vehicles for generating income: Municipal bonds, a certificate of deposit (CD), and a money market account. After reading a financial newsletter, the investor also has identified several additional restrictions on the investments: O a. No more than 40 percent of investment should be in bonds b. The proportion allocated to the money market account will be at least double the amount in the CD c. The annual return will be 8% for bonds, 9% for the CD and 7% for the money market account. Assume that the investor wants to maximize the total annual return Accessibility: Investigate Get genuine Office Then, formulate the LP model for this problem, ignoring any transaction costs and the potential for different investment
The LP model for the problem is x, y, z ≥ 0.
What is an investor?An investor is a person or organization that uses its own money or money borrowed from others with the intention of making a profit.
Decision variables:
Let x be the amount invested in municipal bonds
Let y be the amount invested in the CD
Let z be the amount invested in the money market account
The investor has $100,000 to invest, so x + y + z ≤ 100,000
The investor wants to invest no more than 40% of the total amount in bonds, which translates to x ≤ 0.4 * (100,000) = 40,000
The LP model can be written as:
maximize 8x + 9y + 7z
subject to
x + y + z ≤ 100,000
x ≤ 40,000
z ≥ 2y
x, y, z ≥ 0
Therefore, the LP model for the problem is x, y, z ≥ 0.
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lObjective 6-6) The following are various management assertions (a. through m.)
related to sales and accounts receivable.
Management Assertion
a. Recorded sales transactions have occurred.
b. There are no liens or other restrictions on accounts receivable.
c. All sales transactions have been recorded.
d. Receivables are appropriately classified as to trade and other receivables in the financial statements and are clearly described.
e. Sales transactions have been recorded in the proper period.
f. Accounts receivable are recorded at the correct amounts.
g. Sales transactions have been recorded in the appropriate accounts.
h. All required disclosures about sales and receivables have been made.
i. All accounts receivable have been recorded.
j. Disclosures related to receivables are at the correct amounts.
k. Sales transactions have been recorded at the correct amounts.
1. Recorded accounts receivable exist.
m. Disclosures related to sales and receivables relate to the entity.
a. Explain the differences among management assertions about classes of transactions and events, management assertions about account balances, and management assertions about presentation and disclosure.
b. For each assertion, indicate whether it is an assertion about classes of transactions and events, an assertion about account balances, or an assertion about presentation and disclosure.
c. Indicate the name of the assertion made by management. (Hint: See Table 6-2
Answer:
m. Disclosures related to sales and receivables relate to the entity. a. Explain the differences among management assertions about classes of transactions and ...
Explanation:
Guidewords are located at the bottom of a dictionary page.
Please select the best answer from the choices provided
T
F
(Answer is false.)
Answer:
Why are you giving us the answer..?
Answer:
FALSE
Explanation:
edg 2021
Determine the area under the standard normal curve that lies to the left (a) Z= 1.34, (b) The area to the left of 2 = – 0.25 is (Round to four decimal places as needed.) (c) The area to the left of Z = 1.66 is 0.949 (Round to four decimal places as needed.)
The areas under the standard normal curve is determined as follows:
(a) Using a standard normal distribution table, the area to the left of Z = 1.34 is 0.9099. (to four decimal places)
(b) Using a standard normal distribution table, the area to the left of Z = -0.25 is 0.4013 (to four decimal places)
(c) Using a standard normal distribution table, the area to the left of Z = 1.66 is 0.9515 (to four decimal places).
What does Area under the Standard Normal Curve mean and why is it important?The area under the standard normal curve represents the probability of a standard normal variable taking a value within a certain range.
It is important because it allows us to calculate probabilities and make statistical inferences using the standard normal distribution, which is a fundamental concept in statistical analysis. It is also used in many fields such as finance, engineering, and social sciences to model and analyze data.
One real-life application of the standard normal curve is in finance, where it is used to model stock prices and calculate the probabilities of different investment outcomes.
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Marisol pours water into a large oven-safe glass bowl until it is about one-fourth full. She then places a small, heavy cup inside the glass bowl. The cup is heavy enough that it does not float. She makes sure that no water enters the small cup when she places it in the bowl. She then places the oven-safe bowl with the water and cup on an electric burner. Finally, she turns the burner on to low.
Part A
What will happen to the water in terms of phase changes when Marisol turns on the stove?
Part B
Marisol covers the bowl with plastic wrap and then places ice on top of the plastic wrap. Write a hypothesis predicting how the plastic wrap and ice cubes will affect the water vapor in the large bowl.
Part C
The image shows what happens when Marisol completes her setup.Write down what you observe in the image. Explain the processes that occur in the bowl and result in what you see.
- The picture here is for Part C -
The water in the bowl will start to heat up when Marisol switches on the stove. The water molecules will receive kinetic energy as a result, which will speed up their movement.
What is Part C of Image?Depending on the system's temperature and pressure, the water's molecules will start to vibrate more quickly as its temperature rises. This could eventually cause the water to boil.
Part B: I predict that the ice cubes and plastic wrap will alter the water vapor in the large bowl by causing condensation to form on the plastic wrap's underside.
Part C: I see a large bowl of water with a small cup floating in it in the image. The plastic wrap that is covering the bowl has a film of dampness on the underside.
Therefore, The water in the bowl will start to heat up when Marisol switches on the stove. The water molecules will receive kinetic energy as a result, which will speed up their movement.
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A restaurant serviced 730 customers at the first week and
696 customers at the second week. If the difference between
the first week and the second week is 4% of the third week,
how many customers did the restaurant service at the third
week?
ANSWER:
850customers were served in the third week.
Explanation:
First week = 730 customers
Second week = 696 customers
Difference between the first and second week = 730 - 696
= 34
4/100 x (customers served in the third week) = 34
4 x customers served in the third week = 34 x 100
4 x customers served in the third week = 3400
customers served in the third week = 3400/4
customers served in the third week = 850
Write your answer in simplest form.
Be sure to include the correct unit in your answer.
Answer:
The answer is 3mm.
Explanation:
Number of College Faculty The number of
faculty listed for a variety of private colleges that offer
only bachelor’s degrees is listed below. Use these data
to construct a frequency distribution with 7 classes, a
histogram, a frequency polygon, and an ogive. Discuss
the shape of this distribution. What proportion of
schools have 180 or more faculty?
165 221 218 206 138 135 224 204
70 210 207 154 155 82 120 116
176 162 225 214 93 389 77 135
221 161 128 310
A frequency polygon displays class frequencies while an ogive displays cumulative frequencies.
Is an ogive and a frequency polygon the same?A frequency polygon is a line graph while an orgive is a histogram . A frequency polygon displays class frequencies while an orgive displays cumulative frequencies there is no difference between a frequency polygon and ogive.The area under the frequency polygon is the same as the area under the histogram and is, therefore, equal to the frequency values that would be displayed in a distribution table. The frequency polygon also shows the shape of the distribution of the data, and in this case, it resembles a bell curve.The frequency polygon is a curve that is drawn on the x-axis and the y-axis. The x-axis represents the values in the dataset, while the y-axis shows the number of occurrences of each distinct category.An Ogive Chart is a curve of the cumulative frequency distribution or cumulative relative frequency distribution. For drawing such a curve, the frequencies must be expressed as a percentage of the total frequency.Procedure to find 5 number summary -
Step 1: First we need to arrange the date set in ascending order.
Step 2: Find minimum and maximum number in the data set.
Step 3: Find Median.
Median = Median is the center element (Ascending order)
Step 4: Find Q1 and Q2
Q1 is the median in the lower half of the data, and Q3 is the median in the upper half of data.
Now, consider the given numbers -
224, 203, 207, 201, 212, 225, 196, 221, 210, 195, 206, 206, 221, 191, 217
Here,
Ascending order : 191, 195, 196, 201, 203, 206, 206, 207, 210, 212, 217, 221, 221, 224, 225
Minimum : 191
Maximum : 225
First Quartile(Q1) : 201
Third Quartile(Q2) : 221
Median : 207
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1. The point of an argument can also be called its
Assume that when adults with smartphones are randomly selected, 49% use them in meetings or classes. If 15 adult smartphone users are randomly selected find the probability that fewer than 3 of them use their smartphones in meetings or classes.
The probability that fewer than 3 of the 15 smartphone users use their phones in meetings or classes is 7.46%.
What is the binomial probability theorem?The binomial probability formula.
P(X = k) = [tex]^nC_r[/tex] [tex]P^k[/tex] [tex](1 - P)^{n - k}[/tex]
where n is the sample size, k is the number of successes, P is the probability of success, (P - 1) is the failure.
We have,
The required probability.
P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)
Where X is the number of smartphone users out of 15 who use their phones in meetings or classes.
Now,
Using the binomial probability.
P(X = k) = [tex]^nC_r[/tex] [tex]P^k[/tex] [tex](1 - P)^{n - k}[/tex]
where n is the sample size, k is the number of successes (using their smartphones in meetings or classes), p is the probability of success (49%), and (n choose k) is the number of ways to choose k successes out of n trials.
We get,
P(X = 0) = [tex]^{15}C_0[/tex] x [tex]0.49^0[/tex] x [tex]0.51^{15}[/tex] = 0.0018
P(X = 1) = [tex]^{15}C_1[/tex] x [tex]0.49^1[/tex] x [tex]0.15^{14}[/tex] = 0.0149
P(X = 2) = [tex]^{15}C_2 \times 0.49^2 \times 0.49^{13}[/tex] = 0.0579
The probability of fewer than 3 smartphone users using their phones in meetings or classes.
P(X < 3)
= P(X = 0) + P(X = 1) + P(X = 2)
= 0.0018 + 0.0149 + 0.0579
= 0.0746
= 0.0746 x 100
= 7.46%
Thus,
The probability that fewer than 3 of the 15 smartphone users use their phones in meetings or classes is 7.46%.
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Heather had a pot filled with salt water. She could not see the salt inside the water, but she could taste that the water was salty. Heather heated the pot using a stovetop until all of the water evaporated. The bottom of the pot was covered with white salt crystals, but the water had all turned into water vapor that Heather could not see. Which of these is true about the salt left in the pot after the water evaporated? A. The salt is made of the same particles as it was before the water evaporated. B. The salt is not made of particles because it was invisible when it was dissolved in water. C. The salt particles absorbed the water particles as the water changed into a gas. D. The salt is now made of particles, but it was not made of particles when it was dissolved.
Answer:
A the salt is made of the same particles
3. An AP coordinator in an urban school district mandates that AP students take a practice exam, called a Mock Exam, in the spring to help identify student potential scores on the upcoming exam in May. A random sample of AP students' Mock Exams was taken and the scores recorded. The results for 28 of the students were found to be: 58, 97, 64, 57, 76, 66, 71, 75, 74, 95, 60, 74, 80, 77, 68, 52, 88, 63, 70, 71, 74, 83, 63, 81, 65, 73, 71, 82 (a) Construct a 90% confidence interval for the mean score on the AP Mock Exams given in this district
Answer:
Since this is means data and we do not know the populations standard deviation, a t-interval
needs to be used. The justification is found in checking the conditions needed for a t-interval. The
problem stated it was a random sample so we will assume this is sufficient. Since the sample size is
slightly under 30, we will still check for the data being roughly normal. Either a boxplot or normal
probability plot would suffice. In both cases there is no reason to doubt the sample data are roughly
normally distributed so we can proceed to the calculations.
The interval would be (69, 76)
Explanation:
Hope this helps if this happens to be wrong tell me
3450 x 24 = ? Max you answer
Answer:
82,800
Explanation:
Answer:
82800
Explanation:
In which type of US election is it possible for the winning candidate to get fewer popular votes than the opposing candidate
A. most state government elections
B. House elections
C. Senate elections
D. most local government elections
E. presidential elections
Answer:
The correct answer is E)Presidential elections.
The presidential election is not determined by popular vote. Rather, it is determined by a system known as the electoral college. The electoral college system involves each state having a certain number of electoral votes roughly based on their population size. In this system, states with larger populations have more electoral votes.
In the electoral college, a candidate must receive 270 electoral votes in order to become president. If a candidate reaches this threshold they win, regardless of the popular vote results.
All of the other elections mentioned in the answer choices are determined by popular vote.
Explanation:
Answer: Presidential Elections
Explanation:
Hepepepepepep yoooo so
Helppp
Answer:
bru
Explanation:
the average age of a vehicle registerd in the united state in 8 year or 96 month . assume the standard deviation is 16 month .if random sample 36 month is selected .find the probabilty that the mean of their age a. betwen 90 and 100
Answer: The average age of a vehicle registered in the United States is 8 years or 96 months. Assume the standard deviation is 16 months. If a random sample of 36 vehicles is selected, find the probability that the mean of their age is between 90 and 100 months.
---------------------------
Find the t-scores of 90 and 100.
---------------------------
t(90) = (90-96)/[16/sqrt(36)]
= -6/(16/6) = - 2.25
---------------------------
t(100) = (100-96)/[16/36)] = 4*6/16 = 1.5
----------------------------
P(90 < t-bar < 100) = P(-2.25< t < 1.5) = tcdf(-2.25,1.5,35) = 0.9133
========================
Happy Holidays
Muhammad Zayaan Yasir
Explanation:
A card is drawn from a pack of 52 cards. What is the
probability that the card will be odd numbered?
Answer:
more infromation
Explanation:
This data set shows the ages of the last 12 winners of a
prestigious film award for Actress in a Leading Role.
61, 32, 33, 45, 29, 62, 22, 44, 54, 26, 28, 60
Calculate the statistics of mean and standard deviation
of the data set. Round to the nearest hundredth, if
necessary.
O mean 38.50 and standard deviation - 14.89
O mean 38.50 and standard deviation = 40
O mean = 41.33 and standard deviation = 40
mean 41.33 and standard deviation - 14.89
Answer:
D. mean is 41.33, and standard deviation is 14.89
Explanation:
Given the data set: 61, 32, 33, 45, 29, 62, 22, 44, 54, 26, 28, 60 of 12 winners.
i. The mean of the data set = [tex]\frac{sum of data set}{number of data set}[/tex]
= [tex]\frac{61 + 32 + 33 + 45 + 29 + 62 + 22 + 44 + 54 + 26 + 28 + 60}{12}[/tex]
= [tex]\frac{496}{12}[/tex]
= 41.3333
The mean of the data set = 41.33
ii. Standard deviation = [tex]\sqrt{\frac{Sum(x_{i} - U) ^{2} }{N} }[/tex]
Where: [tex]x_{i}[/tex] is the value of each data set given, U is the mean, N is the number of data set.
Sum ([tex]x_{i}[/tex] - U) = [tex](61 - 41.33)^{2}[/tex] + [tex](32 - 41.33)^{2}[/tex] + [tex](33 - 41.33)^{2}[/tex] + [tex](45 - 41.33)^{2}[/tex] + [tex](29 - 41.33)^{2}[/tex] + [tex](62 - 41.33)^{2}[/tex] + [tex](22 - 41.33)^{2}[/tex] + [tex](44 - 41.33)^{2}[/tex] + [tex](54 - 41.33)^{2}[/tex] + [tex](26 - 41.33)^{2}[/tex] + [tex](28 -41.33)^{2}[/tex] + [tex](60 - 41.33)^{2}[/tex]
= 386.91 + 87.05 + 69.39 + 13.47 + 152.03 + 427.25 + 373.65 + 7.13 + 160.53 + 235.01 + 177.69 + 348.57
= 2438.68
Standard deviation = [tex]\sqrt{\frac{2438.68}{12} }[/tex]
= 14.26
Therefore, the statistics mean is 41.33 and standard deviation is 14.89
Answer:
D
Explanation: