Do all pls 20 points Combine Rationa

Answer:

x intercept = (7/3, 0)

y intercept = (0, -7/6)

slope = 1/2

Step-by-step explanation:

The required number of arrangements when all the three subject matters can be arranged anyhow is given by:

9! = 362880

i.  The required number of arrangements when French books are in the first position is given by:

3! * 2! * 4! = 1728

ii. the required number of arrangements is given by:

3! * 4! * 2! = 3456

iii.  the required number of arrangements when all the three subject matters can be arranged anyhow is given by:

9! = 362880

Given that there are e = 3

Mathematics books,

f = 4 French books, and

p = 2 Physics books to be arranged on a shelf.

The problem requires to calculate the number of different arrangements are possible in the following ways:

i. If the books in each particular subject must all stand together only the French books must be in the first position on the shelf whilst the others

ii. Must also always be together but not in the first position.

All the three subject matters can be arranged anyhow.

i. If the books in each particular subject must all stand together only the French books must be in the first position on the shelf whilst the others:

If the French books are always in the first position of the shelf, then the remaining 8 books can be arranged in 8! ways as they all have different titles. But there are 3! ways to arrange the mathematics books and 2! ways to arrange the physics books.

Therefore, the required number of arrangements when French books are in the first position is given by:

3! * 2! * 4! = 1728

ii. Must also always be together but not in the first position

If all the books of the same subject must be kept together, then there are 3! ways to arrange the mathematics books, 4! ways to arrange the French books, and 2! ways to arrange the physics books.

Therefore, the required number of arrangements is given by:

3! * 4! * 2! = 3456

iii. All the three subject matters can be arranged anyhow.

If all the three subject matters can be arranged anyhow, then the total number of books to be arranged is 9.

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A basis for W is {(0,-6,1,0), (0,9,0,1)}.

Matrix A is a singular matrix when k = 1.

To find the basis for the subspace W and determine the value of k for matrix A, let's go through each part separately.

Part 1: Basis for W

The subspace W is defined by the equation x – 3y + 92 = 0. In order to find a basis for W, we need to find two linearly independent vectors that satisfy this equation.

From the given options, the vectors {(0,6.1,0)} and {(0,-9,0,1)} do not satisfy the equation x – 3y + 92 = 0.

However, the vectors {(0,-6,1,0)} and {(0,9,0,1)} satisfy the equation x – 3y + 92 = 0. Therefore, a basis for W is {(0,-6,1,0), (0,9,0,1)}.

Part 2: Singular Matrix A

Matrix A = [k 2 10 7 1].

To determine if A is a singular matrix, we need to check if its determinant is equal to zero.

Calculating the determinant of A:

det(A) = k(21 - 710) - 2(27 - 101) + 10(27 - 101)

= k(-68) - 2(-14) + 10(4)

= -68k + 28 + 40

= -68k + 68

A is a singular matrix if det(A) = -68k + 68 = 0.

Solving the equation -68k + 68 = 0, we find k = 1.

Therefore, A is a singular matrix when k = 1.

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Dr. Ellison is wrong.

To determine if the equation y = -3x + 7 has a solution of (2, 13), we can substitute the values of x and y into the equation and check if it holds true.

Substituting x = 2 and y = 13 into the equation:

13 = -3(2) + 7

13 = -6 + 7

13 = 1

The equation does not hold true since 13 is not equal to 1.

Therefore, (2, 13) is not a solution to the equation y = -3x + 7.

Hence, Dr. Ellison is incorrect in stating that (2, 13) is a solution to the equation.

An equation is a mathematical statement that indicates that two expressions are equal. It consists of variables, constants, and mathematical operations such as addition, subtraction, multiplication, division, exponentiation, etc. Equations are used to represent relationships between quantities and to solve problems in various branches of mathematics and science.

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a) Therefore, the 50% confidence interval for the percentage of yellow peas in the population is approximately (0.47%, 3.93%).

b) Since the confidence interval does not contain the value of 20%, we can say that the results of the experiment do not support the expectation that 20% of the peas should be yellow.

c) The 90% confidence interval for the percentage of green peas in the population is approximately (95.87%, 99.53%).

The data given in the problem is:

Sample size (n) = 443 + 10 = 453

Number of yellow peas (x) = 10

Number of green peas (n-x) = 443

Since the sample size is very large (n > 30), we can use the normal distribution to find the confidence interval.

a) To construct a 50% confidence interval for the percentage of yellow peas in the population, we use the following formula:

Lower limit = p - z(α/2)√(p(1-p)/n)

Upper limit = p + z(α/2)√(p(1-p)/n)

where: p = x/n = 10/453 = 0.022 (proportion of yellow peas in the sample)

z(α/2) = z(0.25) = 0.674 (z-value for a 50% confidence level)

Plugging in the values, we get:

Lower limit = 0.022 - 0.674√(0.022(1-0.022)/453) ≈ 0.0047

Upper limit = 0.022 + 0.674√(0.022(1-0.022)/453) ≈ 0.0393

Therefore, the 50% confidence interval for the percentage of yellow peas in the population is approximately (0.47%, 3.93%).

b) Since the confidence interval does not contain the value of 20%, we can say that the results of the experiment do not support the expectation that 20% of the peas should be yellow.

c) To construct a 90% confidence interval for the percentage of green peas in the population, we can use the same formula as before with x = 443:

Lower limit = p - z(α/2)√(p(1-p)/n)

Upper limit = p + z(α/2)√(p(1-p)/n)where:

p = x/n = 443/453 = 0.977 (proportion of green peas in the sample)

z(α/2) = z(0.05) = 1.645 (z-value for a 90% confidence level)

Plugging in the values, we get:

Lower limit = 0.977 - 1.645√(0.977(1-0.977)/453) ≈ 0.9587

Upper limit = 0.977 + 1.645√(0.977(1-0.977)/453) ≈ 0.9953

Therefore, the 90% confidence interval for the percentage of green peas in the population is approximately (95.87%, 99.53%).

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Answer: B.)

Step-by-step explanation:

Answer: B

Step-by-step explanation:

Answer:

a few weeks

Step-by-step explanation:

Answer:

97/100

Step-by-step explanation:

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one ids attached to the event. If it doesn't a value of zero is attached to the event.

Probability that the DVRs is not faulty = total number of faulty videos / total number of videos

total number of faulty videos = 100 - 3 = 97

total number of videos = 100

97/100

Answer:

$50, 100

Step-by-step explanation:

Answer:

I think the answer could be y=3 or y=2

it could be something else tho im sorry

Answer:

y=2

Step-by-step explanation:

Answer:

First one:     -12 < -6

                    -6 > -12

Second one:

                     -8 > -10

                     -10 < -8

Step-by-step explanation:

Well you just compare them with greater then or less then signs.

Answer:edmentum

Step-by-step explanation:

Answer:

19.95

Step-by-step explanation:

5.7 times 3 = 17.1

5.7 ÷ 2 = 2.85

17.1 + 2.85 = 19.95

Answer:

Nice!

Step-by-step explanation:

The area of the surface is 2π(3√3 - 1). The surface area integral is given by A = ∬D √(1 + (dz/dx)² + (dz/dy)²) dA.

To find the area of the surface that lies within the cylinder x² + y² = 64 and is defined by z = xy, we can use the surface area integral.

The surface area integral is given by:

A = ∬D √(1 + (dz/dx)² + (dz/dy)²) dA

where D represents the region on the xy-plane that corresponds to the surface.

In this case, the region D is the circle with radius 8 (which is obtained by solving x² + y² = 64). To evaluate the integral, we need to determine the partial derivatives dz/dx and dz/dy.

Taking the partial derivative of z with respect to x:

∂z/∂x = y

Taking the partial derivative of z with respect to y:

∂z/∂y = x

Substituting these values into the surface area integral formula:

A = ∬D √(1 + y² + x²) dA

Since D is a circle with radius 8, we can express the integral in polar coordinates. The limits of integration for r are 0 to 8, and the limits of integration for θ are 0 to 2π.

A = ∫₀²π ∫₀⁸ √(1 + r²sin²θ + r²cos²θ) r dr dθ

Simplifying the expression under the square root:

A = ∫₀²π ∫₀⁸ √(1 + r²) r dr dθ

Now we can evaluate the integral:

A = ∫₀²π [(1/3)(1 + r²)^(3/2)]⁸₀ dθ

A = ∫₀²π (1/3)(9√3 - 1) dθ

A = (1/3)(9√3 - 1) ∫₀²π dθ

A = (1/3)(9√3 - 1)(2π - 0)

A = 2π(3√3 - 1)

The area of the surface is 2π(3√3 - 1).

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Answer:

8,088.8

Step-by-step explanation:

Answer without Explanation:

B

Answer:

23 [tex]\frac{1}{24}[/tex]

Step-by-step explanation:

you subtract 82 [tex]\frac{2}{3}[/tex] by 59 [tex]\frac{5}{8}[/tex] and you'll get the answer

Answer:

x=y−5z

Step-by-step explanation:

y=5z+x

Step 1: Flip the equation.

x+5z=y

Step 2: Add -5z to both sides.

x+5z+−5z=y+−5z

x=y−5z

Answer:

x=y−5z

plz mark me as brainliest

Answer:

x = ay - 5z

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

Answer:

dowload the link up the other one answer

Answer:

B 48 in.

Step-by-step explanation:

the formula is a=bh/2 and that formula will get you 48 in^2.

The probability that he weighs more than 81 kg given that he is above the average weight is 0.4532.

(a) Probability that male is heavier than 81 kg can be found using the z-score formula;

z = (x - μ) / σ = (81 - 75) / 8 = 0.75P(z > 0.75) = 1 - P(z < 0.75)

Now referring to z-tables, we find that P(z < 0.75) = 0.7734

Therefore, P(z > 0.75) = 1 - P(z < 0.75) = 1 - 0.7734 = 0.2266

Thus, the probability that the male is heavier than 81 kg is 0.2266.

(b) Let X be the weight of female and Y be the weight of male. We know that X ~ N(52, 6) and Y ~ N(75, 8)

Let Z = X - Y then, Z ~ N(52 - 75, sqrt(6^2 + 8^2)) = N(-23, 10)

Now, we need to find the probability that X > Y. i.e P(X - Y > 0)P(X - Y > 0) can be written as P(Z > -23/10)

Now, referring to the z-tables, we can find that P(Z > -2.3) = 0.9893

Therefore, P(X > Y) = P(X - Y > 0) = 0.9893.

(c) Given that male weight is above average weight, we need to find the probability that he weighs more than 81 kg i.e. P(Y > 81 | Y > 75)

This is conditional probability and can be found using Bayes' Theorem:

P(Y > 81 | Y > 75) = P(Y > 75 | Y > 81) * P(Y > 81) / P(Y > 75)

Now, P(Y > 75 | Y > 81) = 1, P(Y > 81) can be found as:

P(Y > 81) = P(Z > (81 - 75) / 8) = P(Z > 0.75) = 1 - P(Z < 0.75) = 1 - 0.7734 = 0.2266

Also,P(Y > 75) = P(Z > 0) = 0.5Therefore,P(Y > 81 | Y > 75) = 1 * 0.2266 / 0.5 = 0.4532

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The given information is that weights of females are normally distributed with mean 52kg and standard deviation 6kg. Weights of males are normally distributed with mean 75kg and standard deviation 8kg. One male and one female are chosen at random.

The probability that the male is heavier than 81kg is 0.2266.

The probability that the female is heavier than the male is 0.0107.

If the male is above average weight(75kg),then the probability that he is heavy than 81kg is 0.2266.

a) The weight of males is normally distributed with a mean of 75kg and a standard deviation of 8kg. The probability that the male is heavier than 81kg can be calculated as follows: z = (81 - 75) / 8

= 0.75P(Z > 0.75)

= 0.2266

Therefore, the probability that the male is heavier than 81 kg is 0.2266.

b) If X and Y are independent Normal random variables, then, for every ab e R, aX + bY has a Normal distribution. The weights of males and females are independent, normally distributed random variables with means of 75kg and 52kg and standard deviations of 8kg and 6kg respectively. Therefore, the difference in weights of the male and the female is a normally distributed random variable with mean μ = 75 - 52 = 23kg and standard deviation σ = √(8² + 6²) = √(100) = 10kg. Let Z be a standard normal variable. The probability that the female is heavier than the male can be calculated as follows:

P(X < Y) = P(X - Y < 0) = P[(X - Y - μ)/σ < (-23)/10] = P(Z < -2.3) = 0.0107

Therefore, the probability that the female is heavier than the male is 0.0107.

c) If the male is above average weight, then we can assume that he weighs 75 kg. The probability that he is heavier than 81 kg can be calculated as follows:

z = (81 - 75) / 8 = 0.75P(Z > 0.75) = 0.2266

Therefore, the probability that the male is above average weight and heavier than 81 kg is 0.2266.

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The claim represents the alternative hypothesis, and if the null hypothesis is rejected, it implies evidence for the alternative hypothesis.

The claim "the mean incubation period for the eggs of a species of bird is at least 31 days" represents the alternative hypothesis.

In hypothesis testing, the null hypothesis (H0) is the statement that is assumed to be true or the statement of no effect or no difference. The alternative hypothesis (Ha) is the statement that contradicts or opposes the null hypothesis and represents the possibility of an effect or a difference.

If a hypothesis test is performed and it rejects the null hypothesis (H0), it means that there is sufficient evidence to support the alternative hypothesis (Ha). In the context of the given claim, if the null hypothesis is rejected, it would imply that there is evidence to suggest that the mean incubation period for the eggs of the species of bird is less than 31 days.

On the other hand, if the hypothesis test fails to reject the null hypothesis (H0), it means that there is not enough evidence to support the alternative hypothesis (Ha). In the given claim, if the null hypothesis is not rejected, it would imply that there is not enough evidence to conclude that the mean incubation period for the eggs of the species of bird is less than 31 days.

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Answer:

b

Step-by-step explanation:

Answer:

i am pretty sure the answer is d

Step-by-step explanation:

let me know if this is wrong

I search it but I failed sorry

for not answering I just don't know

Complete question :

Determine the probability that two pears are selected The probability is(Simplity your answer.)

d) Determine the probability that a card containing a PEAR and then a card containing a question mark are selected

Answer:

(QQ, QP, QM, QP, PP, MP, QM, PM, MM) ;

Step-by-step explanation:

Given :

Marking on card :

Question mark = Q

Pear = P

Moon = M

Selecting two cards with replacement :

Sample space :

_____ Q ____ P _____ M

Q ___QQ ___QP ___ QM

P ___QP ____PP ___ MP

M__ QM ____PM ___MM

(QQ, QP, QM, QP, PP, MP, QM, PM, MM) ;

1/9 ;

2/9

P(selecting 2 pears) = (PP)

P(p) = required outcome / Total possible outcomes = 1 / 9

Card containing a pear and then a question mark ;

(PQ or QP).

P(p) = 1/3 ; P(Q) = 1/3

P(PQ) + P(QP)

(1/3 * 1/3) + (/3 * 1/3)

1/9 + 1/9

(1 + 1) / 9

= 2/9

Answer:

See solutions below

Step-by-step explanation:

Match the range of the function f(x)=x^2+2x-1 to its domain

Domains of the function are the input values x i.e 2, -2, 3 and 3

corresponding f(x) for each values are the range

when x = 2

f(2)=2^2+2(2)-1

f(2) = 4 + 4 - 1

f(2) = 7

when x = -2

f(-2)=(-2)^2+2(-2)-1

f(-2) = 4 - 4 - 1

f(-2) = -1

when x = 3

f(3)=3^2+2(3)-1

f(3) = 9 + 6 - 1

f(3) = 14

when x = -3

f(-3)=(-3)^2+2(-3)-1

f(-3) = 9 -6 - 1

f(-3) = 2

Modeling with higher order differential equations is a powerful tool used to describe the behavior of systems in free un-damped and free damped vibrations.

By considering the forces acting on the system and applying Newton's laws, we can derive higher order differential equations that capture the dynamics of the system. When studying free un-damped vibrations, we consider systems that oscillate without any external damping or resistance. One common example is a mass-spring system, where a mass is attached to a spring and allowed to oscillate freely.

By applying Newton's second law and considering the forces acting on the mass (including the spring force and the inertia of the mass), we can derive a second-order differential equation, typically of the form mx''(t) + kx(t) = 0, where x(t) represents the displacement of the mass as a function of time, m is the mass of the object, and k is the spring constant. Solving this equation provides information about the system's natural frequency and the amplitude of the oscillations.

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Answer:

a, d, e

Step-by-step explanation:

on usatestprep

The features of the function are given as follows:

Horizontal asymptote: y = 5.

Vertical asymptote: x = 2.

x-intercept: No x-intercept.

y-intercept: (0,-5).

Hole: No holes.

The horizontal asymptote is the limit of f(x) as x goes to infinity. To obtain this limit, we consider only the terms with the highest exponent of the numerator and of the denominator, hence:

here, we have,

g(x) = -5x/x -> y = 5 is the horizontal asymptote.

The vertical asymptote is the value of x for which the function is not defined, hence it is the zero of the denominator, thus:

x - 2 = 0 -> x = 2.

The x-intercept is the point (x,0), in which x is found when y = 0, hence:

-5x + 10 = 0

-5x = -10

5x = 10

x = 2.

However, the function is not defined at x = 2, meaning that it has no x-intercept.

The y-intercept is the value of y when x = 0, hence:

y = 10/-2 = -5.

The coordinates are (0,-5).

The entire function can be simplified as follows:

(-5x + 10)/(x - 2) = [-5(x - 2)]/(x - 2) = -5.

Meaning that the function has no holes.

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complete question:

Determine each feature of the graph of the given function.

f(x) = -5+10

2

Horizontal Asymptote: y =

Vertical Asymptote: x =

x-Intercept:

y-Intercept: (0,

Hole: (

,0)

No horizontal asymptote

No vertical asymptote

No x-intercept

No y-intercept

No hole