difference between simple machine and complex machine?​

Answers

Answer 1

Answer:

a simple machine has way less parts than a complex machine like just one pulley or lever. A complex machine has multiple different parts that lead up to one thing being done in the long run.

Explanation:


Related Questions

3. Mount Everest, an eastern Himalayan peak on the Tibet-Nepal border, was discovered to be the world's highest mountain in March 1856. The Survey Department of the Government of India computed its height to be 29,002 ft. Express this height in scientific notation.

Answers

Answer:

   h = 2,9002 10⁴ ft

Explanation:

Scientific notation is a method to write very large and small numbers clearly, the figure is written with an integer and the other figures in decimals, with an exponent so that the number does not change.

If it is necessary to approximate a figure, the criterion is if the next figure is greater than or equal to five, the figure rises by one unit.

Mount Everest height

 

    h = 29002 ft

    h = 2,9002 10⁴ ft

if we approximate three significant figures that

     h = 2.90 10⁴ ft

Answer:

[tex]2.9002 \cdot 10^{4} ft[/tex]

Explanation:

To express the height 29,002 in scientific notation we need to move the decimal point four places to the left and express the answer into a base-ten power, as follows:

[tex]29,002 = 2.9002 \cdot 10^{4}[/tex]

The answer expressed in scientific notation results in 2.9002 times a ten to the fourth power, as a result of the four movements of the decimal point.  

   

I hope it helps you!                

What distance is required for a train to stop if its initial velocity is 23 m/s and its
deceleration is 0.25 m/s²? (Assume the train decelerates at a constant rate.)

Answers

-- The train starts at 23 m/s and slows down by 0.25 m/s every second.

So it'll take (23/0.25) = 92 seconds to stop.

-- Its average speed during that time will be (1/2)(23+0) = 11.5 m/s

-- Moving at an average speed of 11.5 m/s for 92 sec, the train will cover

(11.5 m/s) x (92 sec)  =  1,058 meters .

The distance required for the train to travel before stopping is 1,058 m.

The given parameters;

initial velocity of the train, u = 23 m/s

deceleration of the train, a = 0.25 m/s

The distance traveled by the train is calculated as follows;

[tex]v^2 = u^2 -2as[/tex]

where;

v is the final velocity of the train

The final velocity of the train is zero when the train stops

[tex]v^2 = u^2 -2as\\\\0 = 23^2 - 2(0.25)s\\\\0.5s = 529\\\\s = \frac{529}{0.5} \\\\s = 1,058 \ m[/tex]

Thus, the distance required for the train to travel before stopping is 1,058 m.

Learn more here: https://brainly.com/question/23852683

a car ends up at x = -245 m after a displacement of -103 m. what was its initial position?

Answers

Answer:

-142m

Explanation:

To find the initial position of the car, we can add the displacement.

-245 + 103 = -142

Best of Luck!

m1=200g m2=150g
find the acceleration
the track is horizontal and frictionless

Answers

Answer:

50 or 1.3333

Explanation: Explanation you cancel out the mass and the force to see what your acceleration would be or you could divide F by M

Why do oil tankers sit lower in water

Answers

When a lower tank is damaged, the incoming sea water pushes the oil in the damaged tank up into the ballast tank. Because of the hydrostatic pressure, there is an automatic transfer out of the damaged tank. The double-hull design is aimed at the probability of zero outflow.

You're driving your car at a constant speed in a straight line which of the following can be used to cause your car to experience a centripetal acceleration
A)brake pedal
B) steering wheel
C)gas pedal
D)All of the above

Answers

The answer is B. Centripetal acceleration is when you accelerate in a circle which the steering wheel is the only one that can cause you to accelerate like that.

What is the weight of a body at a centre of Earth​

Answers

The weight of a body placed at centre of Earth is 0. Because the mass at the exact cenrte of the earth is zero.
the weight of the earth is 0

a pulling force carried by a rope is called what

Answers

Answer:

The pulling force that acts along a stretched flexible connector, such as a rope or cable, is called tension, T. When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

Explanation:

please can i have help with this question ​

Answers

Opposites attract so north goes to south and Vice versa. When the same poles are facing each other they push away when they are opposites they attract.

explain how the air balloon moves up and down.
Explain in terms of density

Answers

The heat in the air ballon from the flame will create moisture in the ballon and make it rise

Answer:

hope it helps ....

Explanation:

The inside air that has been heated rises due to the difference of density between the hot and cold air particles. The heated air, the air that is inside the balloon, is less dense than the cool air, the air outside of the balloon. ... You can see that the bigger the volume gets, the smaller the density is.

HELLO! Please Help me.
I can't do it! it's Science ​

Answers

Answer:

9V

Explanation:

V=IR

V=2.5*3.6

V=9

Answer:

9V

Explanation:

V =IR

V =2.5 * 3.6

V = 9V

16. True/False: Protons are exchanged between objects by induction

Answers

False: only electrons move through induction.

Light is produced by which fundamental force?
strong nuclear
electromagnetic
weak nuclear
gravitational

Answers

Answer:

ans: Electromagnetic

Answer:

B on edg.

Explanation:

is isopropyl alcohol a element compound or mixture

Answers

Answer:

Isopropyl is an element compound.

Explanation:

The radius of Mars is 3.4 x 10^6m and the period of Mars's rotation is 24 hours. What is the radial accelerations (in m/s^2) of an object on the ground at its equator?
A. 0.018m/s^2
B. 0.136m/s^2
C. 0.068m/s^2
D. 0.376m/s^2

Answers

Answer:

Option A: 0.018m/s^2

Explanation:

Formula for radial acceleration is;

α_r = ω²r

Now, ω = 2π/T

We're given T = 24 hours. Converting to seconds is; T = 24 × 60 × 60 seconds

ω = 2π/(24 × 60 × 60)

We are given radius = 3.4 × 10^(6) m

Thus;

α_r = (2π/(24 × 60 × 60))² × 3.4 × 10^(6)

α_r = 0.018 m/s²

Who am I answer key

Answers

Answer:

huh

Explanation:

Which has more inertia, a car with a mass of 900kg or a car with a mass of 1,500kg. Explain your answer.

Answers

Answer:

Which has more inertia - a car with a mass of 900kg or a car with a mass of 1500kg - explain. The bigger the mass - the larger the inertia but you need to exert more force to start the movement.

Explanation:

Plz help meeeeeeeeeeeeeeeeeee ahhhhhhhhh ❤️

Answers

Answer:

option 4

Explanation:

i just saw it from google

The amount of matter in a substance or object is called:
??? What the answer

Answers

Answer:

mass!!

Explanation:

Cody’s car accelerates from 0M/S 245 in/at Northwoods and 15 seconds what is the acceleration of the car

Answers

Answer:

3m/s^2

Explanation:

Acceleration is change in velocity / time = 45/15 = 3m/s^2

Mass refers to the gravitational force on the matter in contact with the surface of a planet. true or false

Answers

Answer:

False

Explanation:

The mass of something does not depend on gravity. A planet has a constant gravitational force. Earth's is 9,80 N/kg. The moon, on the other hand, is 1,6 N/kg. the number of kilograms of something doesn't change if you go from one planet to another and since mass is measured in kilograms, mass doesn't change, therefore it does not refer to gravity. Mass refers to the quantity of matter in an object. It is weight that refers to the gravitational force on an object, since it is measured in newtons, and the amount of newtons per kilogram changes from planet to planet due to different gravity constants

Which words help you to determine the meaning of the word decelerate in paragraph 3

Answers

Answer:

the words

Explanation:

Answer:

Pressing the brake pedal

Explanation:

Decelerate sounds a lot like the word accelerate, but we know that the speed is decreasing, so it would have to be going down, getting slower, so whichever sounds like a good example of speed decreasing should be a good answer!

Which force is involved in kicking a ball?

1. Frictional force

2. Pushing force

Answers

Answer:

Pushing force

Explanation:

You technically push a ball when kicking it.

When do we use Aerobic respiration & anaerobic respiration?

Answers

Answer:

the process by which organisms use oxygen to turn fuel, such as fats and sugars, into chemical energy. anaerobic respiration does not use oxygen. Respiration is used by all cells to turn fuel into energy that can be used to power cellular processes.

if two objects are repelled from each other which force most likely caused this?

A. gravitational

B. weak nuclear

C. electromagnetic

D. strong nuclear

Answers

C. electromagnetic

Answer:

it's C! electromagnetic

Explanation:

4. Why do chemists use relative masses of atoms compared to a reference isotope rather than the
actual masses of the atoms?
a. The actual mass of an electron is very large compared to the actual mass of a proton.
b. The actual masses of atoms are very small and difficult to work with.
c. The number of subatomic particles in atoms of different elements varies.
d. The actual masses of protons, electrons, and neutrons are not known.

Answers

Answer:

B

Explanation:

Answer:

answer is B

Explanation:

took the test

A. 2kg

B. 6kg

C. 8kg

D. 14kg

Answers

Answer:

A

Explanation:

We know the force is (16N-12), which is 4N, and we know the acceleration is 2 m/s^2. Meaning, we can solve the formula m = F / a (mass equals force divided by acceleration), and we get 2kg.

Why does sonar use ultrasound rather than sound?

Answers

Answer;  Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances.

Answer:

Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances

Explanation:

A force of 75 N at an angle of 15° to the direction of motion moves a chair 3 m. Which change would result in more work being done on the chair?

Answers

Answer:

Decreasing the angle to 10

Explanation:

Edge 2020

Dos pilotos suicidas, que están inicialmente a una distancia de 500 m entre sí, deciden chocar directamente de frente arrancando ambos desde el reposo. Ambos autos pueden desarrollar una aceleración máxima constante de 15 m/s2 . Si el piloto A arranca un segundo antes que el piloto B, encuentra: a) la posición donde los autos chocan, medida a partir de la posición donde arranca el piloto A, y b) la rapidez relativa de la colisión (la rapidez de B con respecto a A justo antes de la colisión, ó viceversa).

Answers

Answer:

a) El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A es de aproximadamente 293,14 metros.

b) La velocidad del automóvil A, en relación con la velocidad del automóvil B, es de 15 m / s

Explanation:

Los parámetros del movimiento son;

La distancia entre ambos coches = 500 m

La aceleración de ambos coches = 15 m / s²

La dirección de movimiento de ambos coches = uno hacia el otro

La hora de inicio del conductor A = Un segundo antes de la hora de inicio del conductor B

Por lo tanto, de la ecuación de movimiento, tenemos;

s = u · t + 1/2 · a · t²

v² = u² + 2 · a · s

Dónde;

u = La velocidad inicial de los autos = 0 (los autos parten del reposo)

t = El tiempo de movimiento de una aceleración dada

a = La aceleración = 15 m / s²

s = La distancia recorrida en el tiempo t

Por lo tanto, para el controlador A, tenemos;

s₁ = 0 × (t + 1) + 1/2 × 15 × (t + 1) ² = 7.5 × (t + 1) ²

s₁ = 7.5 × (t + 1) ²

Para el conductor B, tenemos;

s₂ = 0 × t + 1/2 × 15 × t² = 7.5 × t²

s₂ = 7,5 × t²

Dado que ambos chocan a lo largo del camino de 500 m, tenemos;

s₁ + s₂ = 500 metros

∴ 7.5 × (t + 1) ² + 7.5 × t² = 500

∵ s₁ + s₂ = 7.5 × (t + 1) ² + 7.5 × t²

Lo que da;

15 · t² + 15 · t + 7.5 = 500

15 · t² + 15 · t - 492,5 = 0

Resolver usando la aplicación en línea da; t = -6,25181 o t = 5,25181

Dado que t es un número natural, tenemos el valor correcto para t = 5.25181 segundos

a) Por tanto, el punto de colisión de los dos coches desde donde parte el conductor del coche A es;

s₁ = 7.5 × (t + 1) ² = 7.5 × (5.25181 + 1) ² ≈ 293.14 metros

El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A ≈ 293,14 metros

b) La semilla de A en el punto de colisión se da de la siguiente manera

Velocidad, v₁ = u + a × (t + 1) = 0 + 15 × (5.25181 + 1) ≈ 93.78

v₁ ≈ 93,78 m / s

La semilla de B en el punto de colisión también se da de la siguiente manera

Velocidad, v = u + a × (t) = 0 + 15 × 5.25181 ≈ 78.78

v₁ ≈ 78,78 m / s

Por lo tanto, la velocidad del automóvil A, en relación con la velocidad del automóvil B, [tex]v_{relative}[/tex] se da como sigue;

 = v₁ - v₂ = 93,78 m / s - 78,78 m / s = 15 m / s

la velocidad del automóvil A, relativa a la velocidad del automóvil B = 15 m/s.

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